Midterm Question 3

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Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiple, lowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(a, b), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited
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Hidden content!
#include ** **  *  **  ** **
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int main(void)
{
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answered by (-304 points)
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Hidden content!
#include<stdio.h>

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Hidden content!
#include<stdio.h>
int main(){
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Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
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scanf("%d",&b);

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}
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Hidden content!
#include <stdio.h>\

int main()

{
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    return 0;

}
answered by (-249 points)
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Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
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}




}
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
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}
answered by (-16 points)
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Hidden content!
#include<stdio.h>
int main()
{
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}
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Hidden content!
#include * *   *      * **
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}
answered by (90 points)
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prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

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}
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