1 like 1 dislike
6.5k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiplelowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(ab), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited

edited by | 6.5k views

36 Answers

0 like 0 dislike
Hidden content!
#include * * * * * **
//gcd and lcm
int main(void)
{
*** * *** * * ** ** ** n,m,i,gcd, j,k,lcm;
* * ** ** **** ** * * ** * * &n, &m);
** ** * * **** **** * i<=n * * **** * i<=m; i++)
* *** * * ** **** ***
* * * * * **** * ** * *** * *** ** *** ** **** ** * m%i==0)
* **** ** *** * * * ** * **** ********** * * * * *** * * *****
*** *** ** ** ** *
* *** * * ** ** * * * * * ", gcd);

** * * * * * * k>=n && k>=m; k--)
**** * ** ***
** * * ***** ** * * * ***** ** * * ** ** k%m==0)
** ** * **** * * *
*** * ******

* * * * * *** * * *** * ** * ** * *


***** *** ** * * ** 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
***** * ** *** ** * ** * ** a,b,tmp,x,y;
** * *** * * * *** * * *** * %d", &x ,&y);
****** **** * * **** ** * ** **
** *** * * ** * * ****
*** ** * ***** * * * * * {
* ****** * ** *** * ** *** * ** **** **
* * * * ***** * * * * * ***** *** *
* **** *** ** * * * * ** ** * ** **** * *
* * * * **** ** ** *
*** ******* * ** * ***** %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
**** * * *** * ** * ** **** a,b;
* * * *** ** *** * ** gcd,lcm;
* * ** *** * ** * *** * * ** %d",&a,&b);

* *** ***** ***** * ** * ag=a,bg=b;
*** * * ** ** ** * * * * * * *
*** * * * ***** * *** * * * ** ** * *
** ** * * ** * ** ** ** *** * *** * * temp;
** * * * ** * * * * * ** * * * ** *** * * * bg=ag, ag=temp;
* **** *** ** ** * * *

** * *** ** *** * ** **** i=1,al=a,bl=b;
* * * * *** * ** *** al%bl!=0 ) {
** * *** ** *** ******* ** * **** *** ** ** *
* * * * * * * * ** ****** * * ** *** * * * *
**** *** ***

** * ** * ** ** *** ** ** * %d",bg,al);
* * ** *** * * ******* 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
*** ** ** * ** *** * * * ** * ** * * * *
**** ***** ***** * *** * *** * * * * * ** *** ** ** * *** ** * ** *** * * ** ********** **** * **** *
* **** * * * * * ** *** * **** ** * *** ** * ** ** * *** **** * *** * * ** **** * * * * * *
** ** *** **** * * * ** * * ** * ** ** * * ** * ** * ** * * * * ** * * ** * * * ** ***** * * *** *
* ** ****** ** ******** ** *** * ** *** * ** * * * ** *** * ** * ** * * **** * *** ** ***** *** ** * *** ******** ** * * ***
**** ** **** **** * ** ******** * *** * ** * * * ** ** ******* *** *** * * * * * *** ** * * * * *** * *** * * * *** ",i);
* * ********* * * * * ** ***** * ** *** ** **** * * * ** * * * ** * * * * *** ** ******* ***** ** ** * * *** *
*** * ** ** ** * * * **** * ** * ** *** ** * ** ** * ** ** * ****** * *** *** * * * *** *** * *** **** * *
** ** *** * *** *** ** *** *** *** *** *** **
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
* ** * **** * ** * * * ** ** ** *
** * * * ***** **** ** * * * * ** * * ** * * * * ** ***
* * * * *** **** * * ** ** * *
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
* * * ** ** * *** *** * * ** %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
** ** *** * ** *** ** ****** * ***** ** *
**** * ** ** ** **** *** * ** **** ** * **** (flagGCD1==0)
** * ***** *** *** * **** * *** **** *** *
**** * * ** *********** * ** ***** * * ** ** ** ** * ***** *
* ** * *** ** * *** * **** * * * * *** ** * * * ** * * * (flagGCD2==0)
* *** *** **** * * * ****** * * * * * * * *** ** * **** * *
**** * * * * * * * * * * * *** ** * ** * *** ** * * * * **** * * ** * ** * *** * ** * ",i);
* * * * * * *** * ***** ** * * ** ***** ** ** ** *** * *** **** ** * * *** * ** * * **
*** * * ** ** * * ****** * * ** ** ** * * * * ** ** * ****** ****
** *********** * * * * * * * ****** *
    }

    //LCM
    for (j=1;j;j++)
    {
* **** * ** ** * ** **** * * * *** * * *
* *** * * **** * ** * ** * *** * * * (k=1;k;k++)
* * * * ********* *** ** * * * * * *** * **** *
** ** *** *** * * * * * *** *** * ** ***** *** * * **** * ***
** **** **** ** * * ** * ** *** ** ****** ** * * * * * (flagLCM2==flagLCM1)
* ** * **** * *** * * ** * ** **** * ******* ** * * * **
** * * * *** * * * * ** * * * ** * * * * * * ** ** *** ** * * ** * * *** * *** **** ******
** ** * ** ******** * *** ** ** ** * * * * ** * ** * *** * * *** * ******* * * * * **
* * ** * ** * * * ** **** * * ** * * ** * *** * * ** **
***** *** * ** ** ***** * * * ***** **** ** ** * * ** * * (flagLCM2>flagLCM1)
*** **** * ** * * * * ** ** * * * **** * ** ******** * **
** ** ** * ** ***** **** * * ** * ** * * *** ** ***** **** **** * **** * *** * ***
**** **** **** * *** *** ** ** *** * **** ** ** * **** * ********** **
* *** * *** * * *** **** *** ** *
* * **** * * * **** * *** ** * * *** * ** *** * *** (flagLCM2==flagLCM1)
** * ** * **** * * * * **** * * * * ****** **
* * **** * * * *** **** * * *** * * * ** **** * * *** * ** ** * **
* ** *** * * * ** **** * *** * ** * ** * * * * *
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* *** ** * ** * * ***** ** * ****** ***
**** *** * **** * *** **** * ** * * ** *** ** ** *** * *** * ** **** * * * ** **** * * * ** *
** ** ** *** **** *** ** **** * ***** * * * * * ***** ** * * **** ** *** ** * *** * *** ** * ** *** * ** * * ** * * * **
* * **** * *** * ******* * *** * **** * * * * * * * **** ***** * * * *** ** ** **** ** * **** *** ** * ****
** * * * ** *** * * *** * * * ** ** **** * *** *** * * * ** * *** * ** * * * *** * ** ******* *** *** * * ** ** * * *** ** * ****
* * * *** **** * * **** * **** *** ** ** * ** **** *** *** ** **** * * * * **** ** ** * * * * ** *** * * *** * * * *
* ** * ** ** *** ** * *** * * ***** **** * * ** ** * * * ** * * * * * * * **** * * * * * * **
* ** ** * ** ** * ** * ** ** * * ** ** * ** ** * ** ***** *** * ***** ** ** * *** * ** * ** * ** * *
** * ** * ******* ** **** *** * ***
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
**** *** ** ** * * ** * * **** **** * * ** *
* ** * * * * * ****** ** *** ** ** ** * ****** **
* * ** **** * * *** * *** * * ** ***** ** * *
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
*** *** * * *** *** *** * a,b,smaller,i;

* * * ** * * **** * ** * * * ** * * * **

**** ****** ** * * *** ** **
** ** * * * **** ****** * * * * ** * ** * * **
*** * ** * * * * *
** * ** * ** ** ** * * * * * * * *

** ** * * * * ** ** * * * * ** * *
* *** * **** *** * **** **** ** *** * * *** * ** && b%i==0)
**** *** * * * *** ** * * ***** * ** * * ** * ** * ***** * * * *** *

***** * ** * ** * * **** **** * ** * *** * %d",i,(a/i)*b);

* * **** * ** *** * ** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
*** * * * *** * * i,n1,n2,a,gcd,lcd;
* * *** **** * *** ** * *
* ** *** * **** * * ** * ** %d",&n1,&n2);
* * **** ** *** * *** * * *** ** || i<=n2; i++)
* ** **** * ** ** * * **** *
** *** * ** *** * * * * * *** *** * * * * && n2%i==0)
*** * * * *** * **** * * *** * * * * * * ******
* *** *** * * * * ** ** * *** ** * * * * * **** *** **
* **** * * **** * ** ** **** *** * ** ****
** * ****** ** **
* * * * * * * * * ***** && a>=n2;a--)
    {
* *** ** **** * * * ********** **** * ** ******* && a%n2==0)
* * * *** * * * * * ** * * ** ** * ** * *** * *
* ** ** * * ** * ** * *** * *** ** * * * ** ** * * ** ** ** *** *** *
** * ** ** * * * * ** ** ****** ** **** **
* *** ** * *** ** * ** * ** *
** ****** * * * ** %d",gcd,lcd);
* * * * * *** ***** 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** ** ** ** ***
int main (){
int i,j,k;
* * * * * *
* * * * * * ** * * ** ** *
** *** ** ***
******* ** **** * ** ** ******** * ** *** * ** * *
* * * ** * **** *
* * ** * ** * ** *


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

* ** * * * *** **** i;
*** * *** ** * * ** * * result=1;
* * ** * *** * **** * * * * ** *****
* * * * * *** ******* *** * **** * * ** ** && a2%i==0){
* ****** * * *** ** * * * * * ** ** * ** ** *** ** *** * = i;
**** * * * * **** * ** * * ** ** * * ****
** ** ** ** ** ** ** *

** * ***** * ** *** *** result;
}
int Get_LCM(int a1,int a2){

** ** * ** * * ****** i;
* ** * * ** * result=1;
* *** *** * * ** ** * * * * *** * **
** * * * * * * ** ** * * * ** ** * *** **** && i%a2==0){
** * * *** ** *** *** *** * * * ** ** ** * *** ** ***** * * * ** * = i;
** *** *** * * * * * * **** * *
** **** ** * * * * *

* ** *** * ** ** * *** result;
}


int main(){

* * ** * * * ** ** **** * ** ** *** **** * ***

* ** *** *** * * * *** * *
* * * ** * *** ** * *



** ** **** ****** * * **** * %d", GDC, LCM);
* * ** * **** * ******* 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.50
©2016-2025

Related questions

0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 2.6k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 11.6k views
0 like 0 dislike
21 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 4.5k views
0 like 0 dislike
22 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 4.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users