1 like 1 dislike
9.6k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiplelowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(ab), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited

edited by | 9.6k views

36 Answers

0 like 0 dislike
Hidden content!
#include **** **** *
//gcd and lcm
int main(void)
{
* * * ** *** ****** *** n,m,i,gcd, j,k,lcm;
* **** * * * * * ** ****** * * * &n, &m);
* ** * * * ****** ** * * * * i<=n * * * i<=m; i++)
***** ** * * * *
* *** * ** **** * ** * * * * **** * * * * *** * ** m%i==0)
* * * * ** * * * * **** * * * ** *** * ***** ** ** * **
* ***** * * *** ** ** *
** *** * * * ** ** * * ** ", gcd);

*** * * **** * ** *** ** k>=n && k>=m; k--)
** * * * ** ** * *
** * **** * * *** * * * ****** * k%m==0)
* ** *** * ** ****** * **
** * * ** *** ***

**** * ** * * * * * ** * **** * * *** *


** **** ** * * ** ** ** * 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
*** * * * * ** * ** ** * * a,b,tmp,x,y;
*** * ** **** **** ** *** ** * *** %d", &x ,&y);
* * * * * * ** ** ** **
* * * ** ** **
* * ** * ** ** *** ** * {
** *** ** * * * * *** ** ** * ** ** *
*** ** * * *** *** ** ** ** * ** * * *** ** * * ***
* **** ** * ** * * ** *** * ** *** * * * ******
** *** ** ** * *
* *** * ** * * **** * * * ** ** ** %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
* * ** * * ** * a,b;
* * * * * *** * *** ** gcd,lcm;
* **** * * * * * **** * * ** * ** %d",&a,&b);

* *** ** ** * * ** * **** * ag=a,bg=b;
** ******** * * * * ** * **
****** * * * * ** * * * **** * ********* ** ***
**** * ** * *** ** * * ** * ******** * **** ** * temp;
* * * ** * ** * * **** * *** * * * * ** ** bg=ag, ag=temp;
* **** ********* ****** **

* **** * **** * ** ** * * ** i=1,al=a,bl=b;
**** * *** * **** * * ** al%bl!=0 ) {
** ** * **** ** ** ** * *** * *** * **** * * ***** **
* *** * ** **** *** * * * ****** * *
* ** * * *** * *

*** **** **** * * * * * * * ** %d",bg,al);
* * * ** * * * ** **** * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* *** **** *** * * * * * ** * ******** ****
* * ** ** * ** * ** **** * * *** * *** **** * * * * * * * ** * ***** *** ** * ** * * **
* * **** ***** ** *** * ** *********** ** ** ** **** ** ** **** * * ** * * * ** ** ** ** ** **** * * * * *
* ** * * ** *** ** ***** * * * *** * * ** **** ** *** **** * * ****** *** * ***** * ** * **** ** ** ****
* ** * * * ** *** * **** * * ** * ** * * * ** ** * ** ***** **** ** *** * * * * ***** * * * ** ** ** * * * * * * * * * ******* *
* *** ** * * * ** * * ** *** * ** * * * * *** * * * ** *** * * *** **** **** * *** ** ** ** **** * ** ** ** * ** * ** * ",i);
* * * *** * ** ** * ** ** *** * ** ** * * * * ********* * ** **** *** ** * ** * ***** * ** ***** * * ** * *** **
** * * ** * *** **** * ****** ***** ** ** ** * * * ** **** * ** **** ** ***** ** * ** ** * * * * * ** ** *
* *** * * ** * ***** ** * ** ** ** * **
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
* **** * **** *** ** **** * * * * *
* * *** * ** ** * * **** ********* * * ** ** **** * ***
* ** *** *** * ******** * ** * *** ***** *
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
** ** **** ************ * * * * %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
* ** * * * * * *** * * ** ** * ****
* * * ** * ****** * * ** * ** *** ** **** * (flagGCD1==0)
* * *** * ** * ***** * ** * *
** * * * * * ** *** * * * *** ** **** ** ** *** * * ***** **** **
** **** * ****** * ***** * ** * ** ** *** ** * * *** * ** * * * (flagGCD2==0)
* * *** ** *** * *** * * *** * * * ** ** * ** ** * * ** ** * ** ***
* * * ***** * ** **** * *** *** * ** ** * * *** ** * * * ** *** * ** * ** * ** ** ** * ",i);
** ** * ***** **** **** * ****** * **** ** * **** ** * ** ** ** ** *** ** * * * * * * * **
*** ** ** ** * ***** *** * ** ** ****** ** ** *** * *
* ** * * ** * * ** **** ** * * * * **
    }

    //LCM
    for (j=1;j;j++)
    {
* ** * * * ** * * * * * **** *** * * * ** ***
** *** *** **** * ** *** **** ** * ** (k=1;k;k++)
* * ***** **** *** ****** ** ** *** * * ****
***** * ** ** * ** * * **** * * *** *** *** * **** *** * * * ** **
** ** * *** * * * *** ** * * ** * * * **** * **** ** ***** ****** (flagLCM2==flagLCM1)
** * * * * ** * ****** ** *** ** ** **** **** * ** **
*** *** * * ** * * ***** * * *** * ** ** ****** * ** ** * * ******** ** *** *** * * ** ** ** **
** * * * * *** ***** * ** * * ****** * ********** * * * ** * * ** * ** ***
* ** *** * ** * ** *** ** * ** *** ** ** * * * ** **** ** * *** ** ** **
* * * ** * ** * * * * * * * ** * * **** * *** * * * * ** (flagLCM2>flagLCM1)
* * * * ** * ** ******* * * **** * *** ****** * ** *** * ** *
* ** * * ** *** * * ** * *** *** *** * ** * * * * ** ** * * * ** *** ** * ** *** ***
*** ** ** * **** * ** * * * * * * * ** * *** *****
***** *** ***** ** * * * * **** * *
* * *** * *** * ** * *** * ** **** * * * * * (flagLCM2==flagLCM1)
* * * * * * * ** * ** * * *** * * * **
* ******** * *** *** * ** * **** * * *** * * ** * * ** **** ****** *
* ** ** * * *** * * * **** * ** * ***** * ** ** *
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* * * *** ** * * ****** ** ** * ** ** ***
** ** ** * * * *** ***** ** ** ** ****** * ** *** ***** * **
** ***** * *** * * * * **** * * ** ** *** ** * ** *** **** * * ** *** * * * ** ** * * * * * **** ** * ** * *
* * * *** *** * * * ** ** * * * * * ***** * **** ** ** *** * **** * * ** *** * ** * ** * *** ** **** ****** * * ** * *
* *** ***** ******** * ** * ** ****** * * * ** * ***** **** ** ** *** ** * ** * ** **** ** ** ** * ** ** * ***
* ***** ** * ** * ** ********* * *** * * ** * ** * * * ** * ******** * ** ** ********* *** * * * * * * *** ** * * **** ***** ***** ** **
* ** * * **** ** * ** * *** * ** * *** * ** ** * ** ** * **** * * **** * ** *** * ************** ** *
* *** * * *** ** ** *** * * ** ** * **** ** * * * *** * * * ** * * * ***** * *** ***** **
******* ** *** **** ** * *** * * *** * *** *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
** * * ** ** **** ** *** ** ***** * ** * *** * **
* * ** * * ** * * * ** ** * * * * * *** *** *
* *** * * ** ** *** ** * ****** * ** ** * *** *
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* *** * **** * *** * a,b,smaller,i;

* ** *** * **** ** ** * * * * ** ** *** **

***** *** ***** * *** * *
* ***** ** * * * ** *** * ** * ** ** * *
** * *** *** * * * * *
* * *** * ** ** * ** * * * ** ***

* *** * ** ** * ** * * *** *** ****** * * * * *
*** * * * * * ** * * *** * * * * ** ***** * && b%i==0)
** ***** ** * * ** ** *** ** * * ** ** *** * * * * ** * * *

** * ** * * ** **** * * *** *** *** * * * * * ** * *** %d",i,(a/i)*b);

**** ** * ** * * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
* *** * ** * ** * ***** *** i,n1,n2,a,gcd,lcd;
* *** *** * *** * *** * **
**** *** * ******* ** * * ** * * ** %d",&n1,&n2);
** ********** * ** ** * * ** * || i<=n2; i++)
* **** * ** *** * *** *
*** * ** * *** * * *** ** * ** * * * * ***** *** * && n2%i==0)
* **** ** ** ** **** ** ** **
****** * ** * ** ** *** * * **** * ***** *** * *** * *** *
*** * *** * **** ** ** ** * *** * ** * **
* ***** ******* * *
**** * * *** **** * *** * ***** * && a>=n2;a--)
    {
* **** ** * * ** * * ** ** *** ** * ** ** && a%n2==0)
* * * * *** *** *** * * * * * *** *
* * ***** * * * ** * ** ** * ***** * *** ***** * *** *
** *** * * ** ** * **** * * ** ** * ** *
*** ** * * ** * * * *
** * * * *** ** * ** ** * ***** %d",gcd,lcd);
* ** * ** *** ** * 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * **
int main (){
int i,j,k;
* **** ** *** * ******* ***
* * ** * ** ** * * *** * ** *
* * * *** *** *
* ** * ** *** *** **** ** * * **** ** * *
** * * * * * *** *
***** * ** ***** ***


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

** * ** * **** ** * i;
** ** *** ** * ******* * result=1;
* * * ** **** * ** *** ** **
*** * *** ** **** * ** * * * ** * ** **** * *** && a2%i==0){
* ** * *** * * ** * * ** ** ** ***** ** * ** * **** * * *** * * * * = i;
* * * * * ** * * ** * * * * * ** * * ****
* *** ** * * * * **

*** * * **** * **** *** ** * result;
}
int Get_LCM(int a1,int a2){

* ** * ** * * *** ****** i;
* ** ****** * * ** * result=1;
** * ** * ** ** ** ******* ** * * * *** *
*** * ** **** * * * * * ***** ** ** * * *** *** && i%a2==0){
* * * ** *** ** * * *** *** * * *** * ** * ** ** * * ** * ** ** = i;
******* **** * ** *** * * **** ** ** **** **
* * ** ** **** *

** * * * * *** result;
}


int main(){

* * *** *** *** * ******* ** ****** **** * * ** *

*** **** *** * * * **** ****
**** ** * * ** * * ***



** *** ******* *** * * * * %d", GDC, LCM);
* ** * * **** * ****** 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.65
©2016-2026

Related questions

0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 3.9k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 16.2k views
0 like 0 dislike
21 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 6.4k views
0 like 0 dislike
22 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 6.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users