1 like 1 dislike
11.5k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiplelowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(ab), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited

edited by | 11.5k views

36 Answers

0 like 0 dislike
Hidden content!
#include * * * * **
//gcd and lcm
int main(void)
{
*** ** *** * * * *** n,m,i,gcd, j,k,lcm;
*** * ** **** ** * **** * * &n, &m);
* * ** * * ****** * *** i<=n * * ** i<=m; i++)
**** ** ** ** ** * * * *
** ** * * * **** ****** * **** *** * * ** ** ** m%i==0)
* ** *** * *** ***** ****** ** ** *** * * ** ** * * *
** * * * * * **** * *
** * ** ** ***** ***** * **** * * ", gcd);

* * * *** * * * * ** ** * ** k>=n && k>=m; k--)
* *** ** * * **** ** * *
** ** * * ** * *** * * * * k%m==0)
**** *** * ** * *** *
* * * ** * * ******

*** **** * * * ** * *** ***** *** * ** *


* ** ** * ** * * * ** 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
* *** **** ** * *** **** * a,b,tmp,x,y;
* * **** * * * ** ** ******** ** * * %d", &x ,&y);
** * ***** **** ** ** ** *
* * * * * ** ****** * * ** *
*** * **** ******** ** * {
***** ** * * * * * ** ** * **** * * ** *
* ******* ***** ** ***** * * ** ** *****
** * * ** * ** * * ** *** * ** *** * *** * **
*** * ** *** **** ***
*** ****** ** ******* ** * * %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
** *** ** * *** ** ** * a,b;
**** *** ** *** * * * * gcd,lcm;
** * * ** * ** * **** * **** %d",&a,&b);

* * ** * ** *** * ag=a,bg=b;
** *** ** *** ** **** *** * **
*** * * * * ** ** ********* ****** *** ****
* ** ** * * ** * *** *** * ** ** * * * temp;
* **** ** ** ** * * * * ** ** ** ** * *** * ** bg=ag, ag=temp;
* * * ** *** * ** ****

* ** ** * ** *** * ** ***** i=1,al=a,bl=b;
******** ***** * ** ** * al%bl!=0 ) {
** * ** * ** * *** ** *** ** *** * * **
* ** ** *** * * * * ** * **** * * ** *** *
* ** *** * * ***

* * * * * ** * * * * * * %d",bg,al);
** * * * * * **** * ** ** ** 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
** * ** * ** * * * * * * * ***** * * * ** * **
*** ** ** * ** * * * ** * ** *** * * * ** * * * * *** *** ***** ** * ** * * *** *****
*** * *** * * * ** * ** * ** ******* * *** * ** * ****** ** * * * * * ** * *** * **** ***
** * * ** ** *** * **** * * * ** **** ** ** * * * * * *** * * *** ***** * ** ** ** *** * * * * ** ***** **
*** ** ** * *** * * * * ** * * * * ** ** ** * * * ** ** *** * * ** ****** * * * ** * *** * * * * * ** * ** * * * *** * ***** * ****
* ** ********* ***** * * * * *** * * * * ** ** * ** ******* * * * *** * ******* * ***** **** * * ** * ** *** * ** * ** **** ",i);
* * * * * *** **** *** ** ** * *** **** * * **** * *** * * * * * ** ** ** **** *** * * *** **** * ** ** *****
* * * ** * * * ** *** *** * * **** * * * *** ** * ** ** * * * ** ** ** ** **** *** * * **
******* * ** * * * *** * ** * ** * **** *** ****
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
* * ** * **** ** * * *** * ** ** *******
* * * * * * * ** ** ** * * *** * * * **** ** * ** * * ** ***
** *** * *** ** * * ** ** * *** **** * **
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
* * *** ** * * **** *** %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
** * * * * *** **** * **** * *** *** * *** * * ** ** * **
***** * * * ** * ** ** * * ***** * * ** (flagGCD1==0)
** ** *** * *** ** * ***** ***** *** * *** *
* ** ** * ** * * ******* * * ** ** **** * * ** * **** * ***
* **** * * **** *** ** * ** * *** ** *** * * ***** **** **** * *** (flagGCD2==0)
* *** ****** * * ** * * ** ** * * * ** **** * *** ***
** ***** * * * *** * ***** * * * * * * *** *** * ** ** * * * * * * * *** **** * * ** * *** ",i);
*** * *** * *** * * * **** * ** * *** ** ** * ** * ** * * * ** ** * ** * *** * * *****
** *** ****** * ** * * *** ** * ***** * ** * * ** *** ***
*** * * ** ** ** * * * ** * *** *** *****
    }

    //LCM
    for (j=1;j;j++)
    {
* ****** * * * ** ** * *** ** * * * **** *** **** * ***
* ** * ** *** * * *** * ** * * * * * (k=1;k;k++)
** **** ** **** ** * *** * ** * *** * **** *
** **** ** * ** ** ** ** ***** ***** ****** * * *** * ** * * * ** * **** ** *
* **** * * *** * ** * ** ** * ** *** ** * * ****** ** * *** ** (flagLCM2==flagLCM1)
* * *** ***** ** * ***** * * ** * * ** * **** * * *** *** *
* ** * * *** * * * * ** * * * * * * * * ** * *** * * * **** * *** **** ** * *** ** * ** ** * **
** * ** *** ******** ** * * **** ******** * * *** * ** * ** * * * ** ** * ** ** * *
*** **** * ** ** * ****** ** * ** ** * *** ** *** ** *** * * * * * * ***
** * * * *** ** *** ** * * * *** * * *** *** * * * * * * (flagLCM2>flagLCM1)
***** *** * * * * ** *** * *** ** * *** *** * * * * ***** * **** *** * *
* ** **** * * ** * * ** ** ** * ***** *** *** ** ** ** *** * ** * ****** * ** * * ***** *
*** * * * *** * * * * * * * * **** * *** * ***** ** * * ** **** ***
* *** * *** *** *** *** * * * *** *** * * **
** * * *** * * ** * ******* *** * * (flagLCM2==flagLCM1)
** * ** ** * ** *** * ** * ***** *** ** *
* ** ** ** *** ****** ** * * ** **** ** * ** **** ******** ** **
* * * ** * ** ****** *** * *********
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
***** *** * *** *** * ** * * * * * **
*** * ***** * *** * * * **** * ** * ***** **** ** * *** * * * ** * * * ** * ******* **
* * *** ** *** * * ** * * ** * * * ** ** * **** *** *** * * * * * * ** * * *** ** ** ** **** * ** * * ** ** * **
** ** *** * ** * * ** ** * * * * * **** * ** * *** *** ***** **** ** * * * * * ** * * ** **** *
* ** * * * ** *** ** * * *** * * *** ** ** * *** * ** * ** * ***** * *** ** ** ** ** * ***** ** * *** * ** * * *** *
* ** ************ * ** *** * * * * * * * * *** * * * * * * * **** * * **** *** * * * ** * ** * * ** ** * *** * * *** * * * *
********** ****** * ** ** * ** ** ** * **** * * * * *** ** * * * ** ** *** * * * * * * * ** ***** * * *** * *** * **
** * * * ** * * *** * * * * *** *** ** ** * ****** ** * * ** **** * **** *** **** * ** ** * *** * * * ** * ** *
* * * ******** ** ** * * *** ** ** * * * ****
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
* ** * * * * * ***** * **** * ** ** * ** *
* ** ** ** *** ****** * ** ** ** *** * ** *** ** *** **** **** **
** * ** *** *** ** * ** *** ** * ** ******
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** * * **** * ** a,b,smaller,i;

*** **** *** * ** * *** * * * * *** ** *** *

** * * * * ** * ** * **
* ***** * * * ** * * * ** *** * **** *** * ** **
* ** **** ** ** ** **
*** *** *** * *** * * ** * * **** * *** **

** ** * * ** * ** **** * ** * ** ********
* *** * **** * * *** * * * **** **** * ** *** && b%i==0)
* *** * *** ** *** ***** **** * ** *** * ** **** ** * * *

* *** * **** *** * * * * * * * * * ** * * %d",i,(a/i)*b);

* ** *** ** * **** * ** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
** **** *** ** * ** i,n1,n2,a,gcd,lcd;
* **** ** * *** * ** *** ***
** ** *** * * **** ****** *** %d",&n1,&n2);
* * ** *** * *** ** ** * *** ** ** * || i<=n2; i++)
* ** * ** ** * **
** ** * ** ** * *** ** *** * *** * * * * && n2%i==0)
* * * ** ***** * *** ** ** * ****** * *** *
** * *** ** * * * ** * * * * *** * ** ** * * ** * **
****** *** * ** ** * * * *** * * ** **
* * * * * ******* ***
* * **** * * * * ** * *** && a>=n2;a--)
    {
** * * ****** ***** * **** ***** ***** * * * && a%n2==0)
** * * ** * *** * * * **** * **** * ** **
** ** *** **** * * ** * * *** * ** *** *** *** *****
* * * * * *** ** * * ** ** ** * ** * *****
*** ** * * *****
* * * * *** * ** ** ** * * ** ** %d",gcd,lcd);
** * * ** *** * * *** 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * * * *
int main (){
int i,j,k;
** **** *** ****** *
** *** ** * * ** ** ** ** ****
* ** **
* **** ** *** ****** ** * ** ****
** * * ***** **** *
* ** *** * **** *


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

* * ** * * ** * * * ** i;
** * * * * ***** * result=1;
* * ** *** *** * * * * * *** * **
** *** * ** ***** **** * * * ** ** **** * * && a2%i==0){
** * * ***** * * *** * * ** **** *** *** * * **** * * **** * * * = i;
*** *** * * * * * ** * * * *
*** * * ** * * *****

* * ** * ** * * **** * * result;
}
int Get_LCM(int a1,int a2){

* ** *** * **** * * ** i;
** * **** *** * * ** result=1;
* * * * * ** *** * * * * ** ** *
**** * ** * **** ** * * ** * ** * * * ** * * ***** && i%a2==0){
*** *** * ** *** * ** * * ** * ** ** ** ** ** * * * * **** * *** ** * = i;
* *** * * * * ** * ** *** * ** * * *** **
*** * * * ** ** *** ** *

* * * ** **** * ** ** result;
}


int main(){

** * *** *** * * ***** * * * * * * * ** ** ** ****** *** *

*** ********* ** ** * *** *** * **
** ** ** * ****** *



* ** ** *** * *** ****** * *** ** * %d", GDC, LCM);
** ** * *** ** * 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.9
©2016-2026

Related questions

0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 4.3k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 18.1k views
0 like 0 dislike
21 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 6.9k views
0 like 0 dislike
22 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 7.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users