1 like 1 dislike
9k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiplelowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(ab), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited

edited by | 9k views

36 Answers

0 like 0 dislike
Hidden content!
#include ** *** * * **
//gcd and lcm
int main(void)
{
** **** * * * ** * * * n,m,i,gcd, j,k,lcm;
*** * * * * *** ** ***** * *** * *** * *** &n, &m);
*** *** * *** ** * * i<=n ** * * *** i<=m; i++)
* ** * ** ** * * ** * ** *
*** * **** * ***** * * ** * * * * ** * * *** ** * m%i==0)
* **** ** ** * * * **** * * ***** * * ** ***************** *
* ** *** * **** ***
* ** * * * * ** *** * **** ", gcd);

****** * * * *** ** k>=n && k>=m; k--)
*** **** *** * * ***** *
* * *** ** ** **** * * * ** k%m==0)
***** *** * ** ** *** * ***
**** * ** * *** ** **

** *** ******** * ** * *** ** *** ****


* *** * * * * ******* * ** 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
* ** ** * * ** * **** * a,b,tmp,x,y;
** ** *********** * **** *** %d", &x ,&y);
** ** * ** ***** *** ** *
** * * *** ** ** **** **
*** ** ** ** * * * * {
* ** * ** * * *** * *** * * *** * ******* * ** *
*** **** ** ** ******* * **** ** ** ***** *** * *
** * **** * * ** ** ** **** * * ** * * ** *
** * * ** * * *** * ***
***** **** * *** ** * **** %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
****** * *** ** **** * a,b;
* **** * * * * * gcd,lcm;
* * * * * * **** * * * * %d",&a,&b);

** ***** *** * * * * * * ag=a,bg=b;
** *** * * * **** * ** *
*** * * ** * * * * *** *** * * ***** * **
* *** * **** * * * **** * ** *** temp;
* ** *** * *** * * **** * ** **** ** ** * bg=ag, ag=temp;
* *** *

* **** * * * ** **** i=1,al=a,bl=b;
** * ** ** * ** ** ** * al%bl!=0 ) {
** ** * * ** * *** ***** * *** *** ** * ** ***
** * * ** * ** * ** **** * ** * ** * * * **
* * * ** * * *** **

**** * * ****** ** * * * %d",bg,al);
**** *** * * ***** ** * * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* * * ** ** *** * * ** * * * ***
* ****** *** ***** *** **** * * * * * *** *** ** * * ****** * ** **** * * *** **** ** *****
* * * * ** * * * ****** *** * * *** ******* * * * * * * *** *** ** * * ****** * *** ***** ** * * * * * * **
** ** *** ***** * ** ** * * * ** **** ** **** * * ** * ** * * * * ** ** **** ** ** *** * * ** * *** **
**** ** ** * **** * ** ** * * ** ** * * ** * * * *** * * * ** * * * * ** ****** *** ** * ** ** * ******* * *** * * ** ***
* ** ** * ** * * *** ***** * ** ** * ** ** * *** * *** * * ** * * *** *** * * *** ** * *** * ** * ** * *** ",i);
* * ** * * *** *** * * * ** ** ** * * *** * **** * * * * ** ** * ** * *** **** *****
* *** *** * * * * * ** * * ** ** **** ** ** ** ***** ** * ** * ** * * * * * * * * * * * * * **
* * * * *** *** * **** * * ** ** * ***** *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
***** * * *** ** * ** ** *** ** ** **** * * ***
* *** ** ** ** * * ***** ***** ** *** * * *** * *
**** * * ** * *** *** *** * ** * ** ** ** ** * **
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
*** * * ** ** **** *** * * * * %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
**** ** ** ** * * *** ****** ** ** ** * * *** **** *
*** * * ** * * * * ** * *** ** *** *** ** * * (flagGCD1==0)
** ***** * * * * *** ** **** * * * *
* * *** ** * * * *** ** * ** **** * ** ***** ***** ** * ***** **** *
***** **** * * **** * ** * * ** * * * * * ** * * * ** * (flagGCD2==0)
**** * * ** * ** *** * * * ** * ** ** * *** ** *** * * * ** * * * ** *
** ** * *** ***** * * * ** * *** ***** **** * *** ** * *** **** *** ** *** * ***** **** * * * ** ",i);
* * * *** * *** *** * ** ** **** *** ** * * *** ***** * * **** * *** ** * * **** *** * *** ** *
**** * ****** * * ** *** * * ** * **** * * * * ** ** * ** * *
** * * ** * ** ***** * * * * * *
    }

    //LCM
    for (j=1;j;j++)
    {
* * ** * * * ** * ** * ** * ***
*** ***** ** ** * * * * * * * ** ** * **** * (k=1;k;k++)
* * * *** ** * ** * * **** * **** ** ** * * ** **
**** * ** ** *** ***** ** *** *** * * * * * ** * ** * *** * ******* **
* *** * ** * *** ****** ** *** ** * ** ** ***** **** ** ** * ** **** (flagLCM2==flagLCM1)
** * * ***** * ** **** ** * ***** * ** * * *** ** ** ***** *
* * * *** ** * ****** * * ** * ** * **** ** **** ********** ** ** * ** * ** * * ***** ** ** ** ** *
* * *** ****** *** * *** * * * ** * ******* * * * ****** * **** ** *** *
* * * *** * ** * * * ** * *** * * ** ** * ** * * ** * *
* *** *** ** **** ***** * * ** * ** * **** * **** * * ** * ** **** (flagLCM2>flagLCM1)
* ********* * ** *** * * * ** * * ***** * * * * ** *
** * * * * * ** *** ***** ********* * ** * ***** *** * ** ** * * **
* * * * * ** *** ********* **** * **** ** * * * ***** * *** ****** **
** ******* * * ** ** ***** ** ***** **** ***
**** * * ** ** *** * **** ** ** ** * * * * (flagLCM2==flagLCM1)
* * * * ** * *** ** *** * ** *** *** ** ** *
*** * ** ***** ** * *** *** * ****** * * ** * ** ** * ******* ** * **
* * ** * * *** ** * * *** * * *
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* ** * ** *** * ** **** * * ** *** * ** *
** *** *** **** * * **** ** * * * * * ** **** ** * * *** * * * * ** * ***** **** ** * * * **
* ***** * * * **** ** *** ***** * *** * * *** * *** ** * * ***** * ******** **** ** *** ** ** * * ** ** *** ** * *
* * ** * ****** ** **** ** * * ** ** *** * * * ** * * * * **** * * * ** ** * *** * * *** * *** *
*** * *** ***** ** *** ** ** *** **** ** * ** ** ** ***** ** * ***** ** ****** * * * * * * **** *** *** * * *** * * ** ***
* * *** * * * * ** ** * * ** *** ** * ** * ** * ***** * * ** * * * **** ** *** * * ** * *** *** ** * * * * ** * ** ** ** ***** ** ****
* * ** * *** * ** *** * ** **** * * *** *** * * ** **** *** ** * ** ** * *** * * ** * * * **** * **** *****
** *** * * ** *** * *** * ***** * * * * ** ** * * * ** * ** ******* * * * ** * * ** ** *** * * * ** ****** *** * **
*** ****** * * ** *** * * ** * * * * * * *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
* * ** ** ***** * * * * * ****** * *
** * ** * ** * ******* * * * * ** * **** * *** *
* * * * *** ****** **** ** * * *** *** **
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* **** ** ******* * *** * a,b,smaller,i;

** * * *** ************ * ***** **** * **

** * ****** ** ** *** ** **
** * ** **** * * *** ******** *** * * * ** * * * *
* * ** * * **** * **
* *** * *** *** * ****** * * * ** ** ** * ** * *

** ** *** * * ** *** ** * *** * **** ** ** *
* ** ** ** * * ** **** ** **** ** * * *** * && b%i==0)
***** * ** * * ***** * ** ****** * * * * *** * * *****

*** ** ** *** *** *** ***** * **** *** **** **** *** %d",i,(a/i)*b);

* * * * * * * *** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
* ** ***** * * * * * * i,n1,n2,a,gcd,lcd;
** *** ** * **** *
* ** * ******* * *** * * **** * %d",&n1,&n2);
*** *** ** * * *** ********** ** * || i<=n2; i++)
***** * * * ** * ** * *
*** ** ** ***** ** ** * **** * ******** ** * * * * && n2%i==0)
** **** *** ****** * ***** * ** * * *
* * * *** ** * ** * ** *** * ***** * ** ***** ** ** * * ** * ***
*** *** * * * *** * * ** * ******* * * * *
** ** **** ** * *
* * * * * * ** * * * ** ** * * ** ***** && a>=n2;a--)
    {
* ** * * ** ** * * * * *** *** ** * * * && a%n2==0)
* *** ** * * * ** **** *** *** **** ** ** *
** * * * * *** ** * * **** * * ** * * ** ******* *** * * ** * *
*** *** ** ** * ** **** * ***** * ** ** ** *
* ***** ** *** * * * * *
**** * * ** * * ***** ** * * %d",gcd,lcd);
*** * * ****** * ** * * * 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include * * * * **
int main (){
int i,j,k;
* *** * * * ** *
* **** * * * * *** * ** ** *
* ** ***
** ** *** * * ** * *** **** * *
** * ***** *** * **** ** **
* * *** **** * ***


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

* * * * *** ** * **** * i;
* * *** ** **** result=1;
* ***** *** ** **** * * * * ** * * **** *
* * ****** * * ** ** * *** * **** *** * && a2%i==0){
* * ** ***** *** * ***** * *** * * * * ** *** ** * ***** * ** * *** = i;
* ***** * * ** * *** **** * ***** *
** *** *** * * *******

** * * * * * ******** * result;
}
int Get_LCM(int a1,int a2){

* ** *** **** * * * *** * i;
** ** * * * * result=1;
* * * *** ** * * *** ** * **
** * * **** ** * *** * * **** * *** ** ** ** ** && i%a2==0){
* ** * ** ** * * **** * ***** ** * * * * * * ** ** ** * *** ** * ** ** * ** = i;
* ** ** **** * ****** *** * ** * * *
* ***** ** ** * * * **

* * * *** * ** * **** * ** result;
}


int main(){

* *** ****** *** * * *** * * **** ** ** ** ** *** * **

*** * *** * * * *** * ** * *
*** * ****** ** ** ** ** *



** * * * *** ** * ***** * %d", GDC, LCM);
* **** * * ***** ** *** 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.31
©2016-2026

Related questions

0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 3.7k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 15.4k views
0 like 0 dislike
21 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 6.1k views
0 like 0 dislike
22 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 6.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users