Midterm Question 3

1 like 1 dislike
9k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiple, lowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(a, b), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited
edited by | 9k views

36 Answers

0 like 0 dislike 
Hidden content!
#include *       **   
//gcd and lcm
int main(void)
{
* ** * *    *****     * ** *   n,m,i,gcd, j,k,lcm;
***  * * *** *** *   **  * * ***** **  ****  ** &n, &m);
 * *    * *   * * *  **  *  * *    * i<=n ***  ****  i<=m; i++)
 **  * * **   ** * * **  *****
* **  * *  ** ****  **  * ** ***  *   * ** * **  *  **  *** ** * ** ** * m%i==0)
 * ***  *  **** ** **  * ** * **   **  ******    ** *  *   **     * * * **  *   
  ** *    **     ***   *   ** *
**  **   *  **** *   **** *  *  ****   *  ", gcd);

 ****  * ** *  ****  ******* * * k>=n && k>=m; k--)
* * *    **  ****     ** * ** 
** ** ** * ** *  *  * * * * *      *** ****** k%m==0)
*  * * *  ** *     ** * * ***** 
*   **  * * ** *  *     *

 *********  * * *****  * *  *  * ***    * ***   *  *


***** * ******* *** ****  *    * 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
*** *** * * *** **** *** ***** ** * ** a,b,tmp,x,y;
* **  ***  **   * *  * **  *  *     *    %d", &x ,&y);
**   ***  ***  ** * * ** *  
   **   *  * **  ** **   *    *** **
 **  *   *    ** *  **  *  * * ** *   {
******  *   * * *  * *   *****     *  **** **   **  *  *** 
* ** ***  ***** * * ****  ***   *****  * *  *** *** 
* ***   **   *   ***  ****** *   **  * * **** * ****  * *    ** 
  *     * *   ****  ***   * **  * 
**     * ****** *  *  * *    * *       %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
**  **  *****      **  ** a,b;
*   **       * ** * *** *  gcd,lcm;
*** ****   *  **   ** * * **     *     %d",&a,&b);

*** **  **** **   **** ag=a,bg=b;
 **** *    **   *   *   *  * **** * *    *
 * **    **       * **   **  * *       *         *** * ** *
**    *    *   ** *  * *** * ***   *  ***  *  *    ***  **   temp;
* ***  **  **    *        *  ******   *  *  ** ****   **  * bg=ag, ag=temp;
  **     *   ****  *  ** *

**   *  ****** ******  *    i=1,al=a,bl=b;
  ** *** *   ***   ** * ** *** al%bl!=0 ) {
*  *****  ***  ***     ** * *** *  **   *   *  * * ****
* *   *      ***   ** **  * *   **** ***   *** 
* ***  *  * **     ***  

** *   ** ***     * ** * ** **  * * *   ** %d",bg,al);
 ******* * *  ** ** ****    0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
*    *   * * *   *       * *      ** ** ****  
* ****  **     *** *  **    **   ***    ** **** *     ***  *  *    * **   *   ******   * **   * * * 
 *** ** * *** *** **  * **  * * ****** *** * ****   **  * ** **  *  **   *****   ** ** ** *   *  *  **   * * **** ***** **   ****  *  *  *****  * * *  * ***   
 *** *** ** **  *** ** *        * ***   * *   * *     *  *  *** **** *  *** * *  *  **       **  * ** **  **  *   *  *  *  ***  ** *  
   * *   * *** *** *  * *******      * * ** ** **  * *****  **  **  * * **   *  * *     * * *   **       *  * **     ** * * * **  **  *    ******    * * * * * * *  * *
 *  ** ** * **  * ** ***     ***** *** * * **    ***   ** * *** ** ** ** *** ***** *    ** **     *** ** **   ** ** **** *   ***  *  ****    ",i);
   **** *  *   ***  ** * *    *  * *     **  *  *     * **  * *** * ****     ** *   ** * * ** *  **   * *   *    * * ** **   * **     * ** **
* * ** *** *** * **** **    **    ***  ** **   *   ***** *  * * ** ***    *** * * ** *** * *   * * **    * *** **   ** * ** * 
*    ***** ***   *  * **  * *   ***** *** ** * ***** * **   *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
   *  * * * ** * *    **  *** *    ***** ***  ** **    *  **
 * *** * ** ****   *   *  *   *    * *   *  *  ***    * *  *** *   ** 
  *  ** * ** * * *   *  *     **    *   ***** ********* 
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
 * ** *   **  * ** ** ** * ******  %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
**  * **   ******* *   **  * ** *  *** **     *  **      *
**  *    ** *    *    ** *** * **  *** *** **     * (flagGCD1==0)
 *  * ** * *  **  **   ******   **** ***   * ***      *   
** * * *** **     * * *  **  **  * * **  * * * * * * *     **   ** ****** 
** * *  * **  * **     *****     *  ** * ** *   **  * * *     *   *    ** * * (flagGCD2==0)
*  **  ***  ***   * *  *** *  * *  *   **  ****   * *  **   * * * *  ***   *** *    *  
  **      ** *   ** * * ********* **    **  * * * *** *      *   * * **  **** **   ** **  ** ****  *** ** ***  ** * *  *  ",i);
 *** *  ** * *  *     *  ******* **  **** *    *  * ******   *         **** * **  ***** *  **** * **   ****   * *
 * ****  ***   ***    **  *  * *** *   * * **    *   ***    ** *   **  ***  **  * 
   *  * **   ***    **** ** * * *  *  **** *** **  * ** 
    }

    //LCM
    for (j=1;j;j++)
    {
 *    * *  * * *  **    *** * *** ***  * *  **   * ** *** 
   *** *     ** ** * * *  ** * *  *   **  * **** * ** **  * *** (k=1;k;k++)
 * * *   * ***  *     *  **  * *********  ** **
*  **     * **    ****    ** ** **** *   * *   **   ***   * * * **     *   ** **    **  
 ***   *****   ****** * ** * * **** **  * **  *  *** ** * ** **  * *  ** *     **   (flagLCM2==flagLCM1)
*** *   *** * ** * ** **  ** * *** ** ******** *  * **     *   *   * *  *       ***
*  * * *******  *   * *** *   **     *  *** * * **   **  ** **   *  **     * **  **    **    *** ** **** ****    ***** **** * * *   *
** *  ***   ***  * ******   * *       *   *    *      * *** *  *  *  **   *  * *** **** * *  *  ** *   ***** *    *
* *  *   * * * * * * **** * *** *   ** **  * **  ** ***   *  ** * * ** ***  ***
 *   * ****  *  *          *    *   **  ****  ***  * * * ******     ** ** **  * ***  * (flagLCM2>flagLCM1)
 * * ****    *** *** ***   ***    * * *** **   ***   *  **  *   **   * *** *  **  ** 
*       ** *  *  ***         **     *  ****  *** *         *  **  * *   * ***  *    **  * *  *** * * *** *   * * 
* ******* * *  *   *  **** *  *  **   *   *  **  ** ***  * *  ***  *  ***  *       
 *  ** ***    **   ** *  ****  *  **  **** ** *  
     ******   * * *    ** * **** ** *  ** **  * ***** (flagLCM2==flagLCM1)
  ** * **   * * ***  * * * *  **  **   *** **  ** **   * 
 ***   *     *  *  *       ***  *  * * *  * *    * **** *   *  **   ** * **  *  **
 **       **** * **  *  * ***  *  * * * * * *  *  *     **** ***
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
****** **  ** * * * * *    ***** * *** * *     *    
*** *   ***** *  *  * *    ****    * *  ****   * *  ** **  * **  *   * * *** ***** **        **  **   **
* *  ****    ** ***** *  *****  * *   ** * * * *  * ** *     ***** ** * ****** **  *  **  *  *  *  ** * ****  *  **   **** *   ****  * *  *   * ******  *
* *  *  * ***    ***    **  **    *  *********  ***  ***  *** ** * *  * ****  **   *  ** **  **  *  *      ** * ** *  ****    * * *  ** ***   ***
* **** * ** *   **  *   ** *  * * ** *  *      * *** *  *** *** *  * * ******     ***  ***  * ** *         *** *  *****  *** *   *  ** *****      ****     *
     * ** ** ** *     * ** * * ******* * *  *  ***  **** *   *    * **  ******  *   * **  * * *** *           * * **  ****      *  ** *****  *** * * **   *     **   ***** 
* * * ** **  * ** * * **** * ** *  **** ** ** * *  ******    *  ** ** **    ** *** ***  *  * **  ******   *  ** *  ***  **   *       **** *  ** ** *
 *  **    * *    ** ** *** * * *   ******  **  *   *****    *   **** * * *   *  ** ** *   **      **  *  * * * * *    **   * *  **** * * ***  *
 * *  **  ***  * * * * ** * *     **** *  **  *  
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
* **  *  ** *******  *****  *      ** ********* *  * *    
*    **   ****** ***   ** ** *****    ** ******  *** * * **   **      * ***
*     * ** **** * *  *  **  * *** **  * *** *   
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* *** ***  **   * * ** ****  ** a,b,smaller,i;

 *  * * * * *  **   *   *   ****      *   ***** ** *     *** * *   * 

 **** *    * ****** *  *  ***    
*   * *    **  **** **   * *  **   **   * *   *  *  **   *   
*******    ** * ** **  **  * 
 *  * ** ***   * ******* * * ** *   ** **  *** ** * *  **    * *  

** * **** *  ** ***** *    ** * **  **    *    ** ***
** **** ** *****  * *  *     ***  * * *     *  * **   *  && b%i==0)
 ** * **   ** *  ***  *    *    *   ***** * ** **  *   *    *****  *** * * *  *   *    

*  *  * ***** *     * *  * **  ****   ****      ** ** *   **  * ** %d",i,(a/i)*b);

*     *  * ***    *** **** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
       *** **   ** **** *     i,n1,n2,a,gcd,lcd;
*   **  *** ** ***  *   * *
  *   ***  **** *     * ***    * ** ** %d",&n1,&n2);
 ***  * **** ****   *** * *  **   * *****  || i<=n2; i++)
*****  **  ** ** *  * *
 *** ** * ***** *****  *  *  ** *   ****    ** ****      ** ** && n2%i==0)
 ****    *   * * **** *    * * ****  ****    * *  
 *     * ******   **  *   ****** *    ******* **** *  ** * **   *   * *      * 
 * *   * ** *****  *   * * *  *** * *** ***** *  ** *** *
**  * ** * **  ** ***    *
*     **    ** * *** * * *   **   **** * * * && a>=n2;a--)
    {
**  * ** *** * **** * * *  * *  **    * *****  ** *   *     && a%n2==0)
   ** * *** ******  ** *   * **** *  *  **  *    
** *        * ** * *  *    *   ** *    **  ***  * **** *  *  *   *    ***  ***  ** * **     
**** ** ***** * *  ****** *     * *    ** **  **  *
*  *     *   *  ***** **  
*  *  **   **    **    ******* *   **     * %d",gcd,lcd);
 ** *    * **  * * * *** * ** 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * ****   **   *
int main (){
int i,j,k;
*   **  **   *   *  *   *   **
 * *  **  **  ** ***********   *** 
 *  ** ***  *  *
  * ** *   *** ******* ** * * * ** *   *   *  * *   *
* *  * **   * * *    * *  ** 
 * **** *     *    ** 


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

** *    *  *   * *   * * * **  i;
 * ***  *  **** **** ****  * result=1;
 * ****       *** *   **  ***  ** *  *    
 *** ********* *  ** ******** *** *  * * **  *  *** && a2%i==0){
  **     *     ***  ***    ****** * ******  ****** *   ***  *    ***  ***** * *    ** = i;
** ** * ***  ** ** *      * ***  * *      ***  ** *  
       ***  *           

 ***    *  ******   *** * * ** result;
}
int Get_LCM(int a1,int a2){

   ** * * ****    * *  * *  *   i;
 * ** ** *   * *       ***   result=1;
*   *  **  *  *    *  * * *** * *   *     **
 **    * ***   *  **** **   *             * * **  *  *  **  **  && i%a2==0){
*** * ** *    * **  **  * *   *  * * ** **  * * * * *  **  ***  *** *** **  **     = i;
**   ** * * * **  ** ** ** ***** *   * *  ***** **    
 ******** *             *  ***

**  ***   * *    ***     ** *  **** result;
}


int main(){

* *****  ** *  * *    * *  *   *  ** *   **   * * *  ****  ***   **

   *** *  **   **   *  **    *** *
 *****   *     **** **   **** * * *  **  



*      ** ** ****       *   *  * ** ** %d", GDC, LCM);
  ** **   ** *****  ***  * * 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.32
©2016-2026

Related questions

0 like 0 dislike
10 answers
Midterm Question 3 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 3.7k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 15.4k views
0 like 0 dislike
21 answers
Midterm Question 5 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 6.1k views
0 like 0 dislike
22 answers
Midterm Question 4 - Makeup
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited | 6.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users