1 like 1 dislike
8k views

Write a program that asks the user to enter two integers, then calculates and displays their greatest common divisor (GCD) and their Least common multiple (LCM).

寫一個輸入兩個整數 輸出它們的最大公因數程式

Hint: Use Euclidean Algorithm

使用歐幾里得演算法

LCM:

In arithmetic and number theory, the least common multiplelowest common multiple, or smallest common multiple of two integers a and b, usually denoted by LCM(ab), is the smallest positive integer that is divisible by both a and b.

What is the LCM of 4 and 6?

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, ...

and the multiples of 6 are:

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ...

Common multiples of 4 and 6 are simply the numbers that are in both lists:

12, 24, 36, 48, 60, 72, ....

So, from this list of the first few common multiples of the numbers 4 and 6, their least common multiple is 12.

 

Example input: 

12 28

Example output (first number is GCD, second number is LCM):

4 84

 

[Exam] asked in Midterm by (12.1k points)
ID: 32707 - Available when: 2017-11-15 14:10 - Due to: Unlimited

edited by | 8k views

36 Answers

0 like 0 dislike
Hidden content!
#include ** * ** ***
//gcd and lcm
int main(void)
{
* * * ** * *** ***** *** * * n,m,i,gcd, j,k,lcm;
* * * *** *** * * * ** &n, &m);
*** *** * * ***** * * * i<=n *** * * i<=m; i++)
* ** ** ** * * *****
* * ** * ** ****** * * * **** * * * * * * ** ** *** m%i==0)
* * ****** * **** **** ** * * **** ** * * * *** **** ** * * * **** ** *
* * * ***** * **** **
** * * * * * * * *** ", gcd);

* **** *** * * k>=n && k>=m; k--)
* ** ** * * ***** * *** ****
* * * ****** * * * * ** ** * ** ***** k%m==0)
* * * * * * ** *** *
* *** * **

** ** * * ** * **** * ** ** ***** ** *


** * * *** *** *** * ** * 0;

}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
***** * ** *** **** * a,b,tmp,x,y;
* * ********* * *** * * * * %d", &x ,&y);
** * * * ** ******* ** *
* ** *** ** ** ** * ** *
* ** ** * * ** * **** ** {
** * * *** ********** ****** ****** * * *
* * * ** * * **** * * * *** ** *
**** ** * * * * *** * * * ** **** **** * * **
* * ** * * ** ****
** * * * * **** ** * * * ** %d", b, b*(x/b)*(y/b));
}
answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
*** *** * **** * * ** ** *** a,b;
* ** * ** * *** * *** gcd,lcm;
* *** *** * * ******* * * * %d",&a,&b);

* * * * *** * ** ** ag=a,bg=b;
* ** * * **** * *** * ** * *
* ** *** **** * * * ****** ** * * * * ** ***
** * * * * * * ** * * ****** ** * ***** * ** ** * temp;
* * **** * ** ** * * * ** ** *** * ** ***** bg=ag, ag=temp;
** * ** * *** *** ***

* ****** **** *** * * ** i=1,al=a,bl=b;
* ** ** * ** * * * al%bl!=0 ) {
** *** ** ** * * **** ** * * ** * ** * ** * ***
* * *** * * * * * ** * *** * * *** * * * * *
* * *** **** ***

** * * * * ** ** * ** * *** * %d",bg,al);
**** * * *** * * ** * ** * 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* * * * ** * *** *** ** ** * ****** *** * *
* ****** * ****** * ** * * * *** * **** ** * ***** * * * * ** * ** ** ** ** * * ** * * * *
*** *** ** ** * * *** * * * ** * ** * ** * * * *** *** * *** * **** * ** * * * **** ** * * *** * * * * ***** ** * *** **
* ** ** * ** * * ** ** * * * * *** **** ** ** ** **** ***** ** * ** * ** * ******** *** ***** *** ** * * ** **** **
* * ** * *** * *** ** *** ** * * * ** **** * ** ****** ** * ** *** ****** * * *** ** ** * * *** ** * * * *** ****** **
* ** *** * *** * ** * * * ***** **** * * ** *** * * ** * *** ** *** *** * * ******* * ** * *** * *** ****** ***** * * ",i);
** * * * **** * ** **** * **** * * ** * * *** * ***** * * ** *** *** ** **** ** *** * ** **** **** ** * *
**** * * *** ** *** * * * ** ** ***** **** * *** * ** ** ** * *** * * * * * ** * ** * **** ** ** * * * ******** * *
* * ***** * * * *** ** *********** * * ** **** *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
** ** ****** * *** ** ** ******* *
****** ** * ** ** ** * ** ** * * ** * ** * * * *** ** ****
**** **** * * ***** ** * ** *** * ****** ** *
        }

}




}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>\

int main()

{
    int a,b,i,j,k,flagGCD1,flagGCD2,flagLCM1,flagLCM2;
* * ** * * * * ** * * * ** **** * * %d",&a,&b);

    //GCD
    for (i=a;i>0;i--)
    {
* ** * * * *** * * ** * * * ** * ** ** * * *
* * * *** * * ****** * **** **** ***** (flagGCD1==0)
** * ** ** ******* * **** *** *** * *****
* ** *** ** ** ** * * ***** *** *** *** ****** * * ** ** *** **** * * * *
*** ******** * ** * * *** * *** ******** * * ** *** * ** * * * * * (flagGCD2==0)
** ** ** ** ** * **** * **** ** *** * * * * * *** **** * ** *** ***
** * ** ** *** ** ***** * * **** **** * * * **** * * *** ***** * * * * * *** *** * ********* * ",i);
* * * ** ****** ** * * ** * * * **** **** *** ** * *** ** *** * ******** ** * * ** * * *** *
* * *** * *** * *** ** * **** *** * *** * *** * * * *
* *** ** *** **** **** * * * * ***** * ** ***
    }

    //LCM
    for (j=1;j;j++)
    {
** **** * * ** * ** *** *** * ** * ** * *** ** *
**** ** * ******* *** ** ****** ** * * ** * (k=1;k;k++)
**** * * * *** ****** * *** * * ** *
*** * ** * * ** ** * ** * *** * **** ***** *** **** * * * * **** * * ** **
** ** * **** ** * * * **** * * * ****** ** * ** * ** ** * (flagLCM2==flagLCM1)
***** ** * * ** *** ** * *** * **** ** * ****** * ** * *** * *
** **** **** * ********** *** ** * *** ** * * **** ** **** *** ** * ** *** * * *** *** * * *** *** * *** ** *
* ** *** ** * * ** * * * * ** * *** * ** * *** * *** ** * ** *** ***** * * **** * *
* * * * *** ** ****** * * * ** ** ** * * ** ****** * ******* * * * ***
* *** * **** *** * *** ** ** ******* *** ** * ** ** ** (flagLCM2>flagLCM1)
* ** * *** * ** * * * * * ******** * **** * * * ** * * *** * * * * *
** ** *** *** ** * ** ** * ** * * * * ** *** ** * ** * ***** * ** ***** * * **** * *** *
* **** * * * * * ** * ** **** ** * * *** * ** *** * ** ** * *
*** *** *** * ** ** * * ** * * ** * ** * ***
* * ** *** ** ******** * *** **** * ** * * * (flagLCM2==flagLCM1)
* *** ** * *** ** * * * ** *** ****** *** ******
*** ***** ** * ***** * * *** ** * ** ** ** **** * ** * ***** **
*** ** ** *** * * ***** ** * ** ** ** * *** **
    }

    return 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,q=1;
int main()
{
scanf("%d",&a);
scanf("%d",&b);

for(i=a;i>=1;i--)
{
    if(a%i==0)
* * ** ** * * **** * **** * * * ***
*** ** * * * ** ** * * *** * * * **** ** *** *** * * * ***** ** * * *** * * * * **
* ** ** * * * * ******** * *** ** ** ** * *** ** *** * **** ** ** *** * ** ** **** * *** * ** *****
* *** * * *** ** *** * ********** ** **** * * ** ** **** ***** **** * * * ** ** **** * ******** *** * *
* ** * ** * ** ** * * ** * ***** *** * * * ** * * *** * * ** ***** * ** * *** * * ** ***** * * * ** ** ****** * * * * * * *
* * * *** * * **** ** * ** ** ** ** ** * ** ** ** ** * *** ** **** * ** ** **** **** ***** * * ** *** * * * * ***** *****
** ** * * * * * * * * * ***** ** * ***** ** * * * * ** ** ** ***** **** * * * ** * * * * *** * * * ** *
** ******* *** *** * * * * * ** ** ** ** *** ** *** ** ***** * * * * ** *** ** *** * * * * *** *** *** ** *** *** * * * **
**** ***** *** *** ***** ** * * * * **** *
}


for(i=b;;i++)
{
    if(i%b==0&&i%a==0)
* *** ********** * *** * * * ** * **** * ***
* **** * * * * *** * ***** * ** ** *** * * **** * * * *
*** ** ***** ** ** * ** * ** **** * ** * * *
        }

}




}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* ***** ** * * ** a,b,smaller,i;

* * *** ***** * * * * * ** ** *** **** *

** * * * * *** * ** ** * * *
* * ** * * * ** * **** ** * * * * * ** * ****
** * * ** **
** ** * ** * * ************ * * ** * * * ** *

** * ********* * **** ***** ** **** *
* ****** ** * ** * ** * * * * ******* *** && b%i==0)
******** ** * * ****** *** * ********** * * * * *** * **** ** ** *

****** * * ** ** * * * * ** * * * *** * * *** ** %d",i,(a/i)*b);

**** * ***** * * *** 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
** * * * **** ** i,n1,n2,a,gcd,lcd;
* * * **** * ***** **
* * * * ** * *** ** * ** * * * %d",&n1,&n2);
* ** * ** ** * ****** ** * || i<=n2; i++)
** *** * * * * **** *
****** * * ** ** *** ** * * ** **** * *** *** ** && n2%i==0)
* *** ** ** ****** ** *** * *** ** ** * * ** *
* * *** * * ** * *** **** **** ** * ** ** *** * ** * * ** *
** * ** * ******* * * ***** * *** * *
** * * * * * ** * **
* * * ** * ** *** ** ****** ** ** * *** && a>=n2;a--)
    {
***** * * **** * ** * * * * ** *** * && a%n2==0)
* ** * * * * ** *** * *** ** ***** *
* * ***** *** ** ** ** *** ******* ** **** * * **** * ** * *
* * * ** * * *** * * * * * * * * *****
*** * ** * **
*** * * * *** **** ** **** **** * ** %d",gcd,lcd);
******** ***** * ** * 0;
}
answered by (-323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include ** * *
int main (){
int i,j,k;
*** ***** * * * **** ***
** ** **** ** ** * ** * ** ** ***
*** ** * * * **
* ** * ***** ** * * ***** * ** *** *
* ** **** **** * * * * ****
* * ** *** * **


return 0;
}
answered by (90 points)
0 0
prog.c: In function 'main':
prog.c:6:10: error: expected expression before '=' token
 while(i!==0)||(j!==0){
          ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int a,b,GDC,LCM;

int Get_GDC(int a1,int a2){

********** * * * * * * **** i;
** *** * * * * ** result=1;
* ** **** * ** *** * * * * *** * * **
* ** **** ** * * * **** ** * * * ** ** && a2%i==0){
* **** **** * ** ** * ** * * * **** **** ***** ** * ** * * * * = i;
** *** * * * *** * ****** *** * ** * * ********
* * ** * * *

* ** ** *** ** * ** result;
}
int Get_LCM(int a1,int a2){

*** * *** * * * **** ****** i;
* ** * *** * * result=1;
* * * ** ** * * * ** * ** ** * *
* * **** ** ** ** * ** * *** * ** * ** * * * && i%a2==0){
* * *** ** ** * * ** * ***** **** * *** * *** *** ** ** ** ** * *** = i;
** * ** *** ** * * **** ***** *** **
* * ** * *** * * *

*** ** * * ****** * ** result;
}


int main(){

* * * * * * ** ** * * ** * * * * * * ***** * ** *

* ********* * ** *** * *** **
* * * * * * * * * * ** ** * ** *



* *** * **** * ********** * * * %d", GDC, LCM);
** * ** * *** * *** ** ** 0;
}
answered by (-286 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.204
©2016-2025

Related questions

0 like 0 dislike
10 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36752 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 3.4k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.3k views
0 like 0 dislike
21 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36754 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 5.6k views
0 like 0 dislike
22 answers
[Exam] asked Dec 9, 2017 in Midterm by thopd (12.1k points)
ID: 36753 - Available when: 2017-11-15 14:10 - Due to: Unlimited
| 5.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users