[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3.7k views

22 Answers

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Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ** *** ******   ***
#include  * *  *   * ** 

/* run this program using the console pauser or add your own getch, *  *******  *  ***  * or input loop */

int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**   **      ****   **   * 
*** * ** **     **    **

int ** **     char   * {
/*
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     *** **  

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a = a+3;
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  ***  **  **   
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/* run this ***   *  the *** *     or add your own ***** ******  *  *    *  **     or **    *  */

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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
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Hidden content!
* *   *  * * * **
 
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** *  **    *         ** * *    ***   ** *    * *   * ** *   ** ***  ** *          * *
 
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*  = c + *

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*  * *  *

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**  *
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
***  * * ** ***   *** 
* *    * *  ** * *  *

int *** argc, char *   *  {
*    **        char  * **
   *  *   *** *  * char  *  **
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*   *   ** *   
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*  ***  *   *  *  = **   + 3;
***   *   *     *** =  **  + 3;
*       * *   *     * =  *  + 3;
** *  *    **** letterc = * *   + 3;
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  *  **  * *** 
*** *  **   return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   **  ****   **  *** ***
     *   ** * ****   * *

int * * * argc, char *argv[]) {
   *       *** char    
 *  *** * * ** char letteri;
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* *  *  ** * **   *  *    * +3;
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}


INPUT
* * * * * ***** ***   
*  ** ** *** **
OUTPUT
 ****  ******
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* ****  * * *** *  **  *
 ***  **  *  *** * **

int * * *   argc, char  ** ** {
 *           *  char   
***  *        char *  
* * **  * *     char   * *  
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* **   *  **  * char **   * 
 ****** *   **  
** ** ** **  * *   * * ** *  * * * input the   *   to  **    ****   **  
***   * **  *   
*  ***   ***** *  ** **  * *  **  *  *** *** ** * * ** *  ****     * *   *  ** ** * *   *   * * **
** ** *    *** 
  * **  * * * letter = letter + 3;
  * *       **  **   ** =  ***  + 3;
* **  *  ** ***  * *   =   ** * + 3;
  *** **  *  ** *  = ***** + 3;
** *   *  ***  *   * =  *** + 3;
****  ** *     
***  *     * * * **  ****   * * *  letter is **** * *     **  **** * ***  ****  *** * **  **  *
**    *   * *  
** *   *      return 0;
}

INPUT
******  ***    **
  ***  ***** **
  
 ***  **    *  *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ** *    **  

int main(int argc, char *argv[]) {
****   *****       *  * *  * * *   ** * lettera;
***    *  *  **  ***        * letterb;
*  *    ** * *  *   **** * * letterc;
 *   **** *** * **     * ** *  letterd;
      ** **    * * *   * *** lettere;
 **** **     ** **** * *  *
* **** ***  *     ****  * **  *  *   *  ***  %c %c %c ** * *** *** * **   * **** *** *    *** * **  ********* *    * * *  * * 
*** *   *** *   *   **  * **   *  * = lettera + 3;
      * * * * **  *  **** * *** = letterb + 3;
* ***      **   ** **      * * *   = letterc + 3;
 *****  **  ****   **  *  = letterd + 3;
       *  *** ** * *   **** * **** ***   = lettere + 3;
 * **       **    ** ****   **    * ***  * *   ***   *
   ****  *  ** ******  *****  *****  * * * %c %c %c ** *  **  *   ** letterb,  ** **** ******
**   **     *   ***** ***  **
 * ****** **  *** * *   *        0;
}

*
  *
  *   ****  *  *
* **  
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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