[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 7.3k views

22 Answers

0 like 0 dislike 
Hidden content!
*   ***  ****    *

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* *** *      *   return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ** ** *** * *
#include * ** *    ***   *

/* run this program using the console pauser or add your own getch, *  ** **   * *** ** *  or input loop */

int main(int argc, char *argv[]) {
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**  * *** ** * * *   **    **    = a+3;
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**  **  ** *   ***   * **   = b+3;
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***      *   * ** ** *  = c+3;
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****** **  *  **        *  ** = d+3;
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*  *   * ** * ** *** ** ***
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
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int  **   * * char    * *  {
/*
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* ** ** ***********   *******   0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* *   ***  ** ***    
***  * * *** **  * * *   

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}
** * *   *    * *  * * **     **  * **
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * ***   *  ***  
*
*** *   *  **   *   **** 
 
**    ** **     * * ** **  * *      * *      **  **** **** **  *    *     **  

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* =   *  
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*  = d +  *
*
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*
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *  *    **    ** *  
  ***  *   ***  ***

int     *  argc, char *  * * {
 *    * *  **   * char **** 
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*  ** *   * **   = *  * + 3;
* ******    *   ** =  **   + 3;
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*  *    **      *  * = * *   + 3;
  *** *       ** 
  * *** **  **   * * * ******** ****  * **  *** ****   ***   *         *** 
*    ** ****    * 
 * *   * *   return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** ***   *   *  **** * 
  * **  *** * ** ***  

int  * * argc, char *argv[]) {
 **   *  * ****  char **  * 
   *      *    char letteri;
* *   ***  * ***  char  * *  
**     ** * char * ****
*** * *      ***** char  *   
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*** ** *   *  *  * *  **** *   ** *    *** ** *      *   ** * *      * *  ** *  * ** **   * * *  ** *
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* *   *  ** *   * *     +3;
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***** *  *  *    
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}


INPUT
* *  *   * ****  *
*    * ** *** * 
OUTPUT
****** * * *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   * * *      *** 
*     ** ** ** **      **

int **** * argc, char **   * {
  * * * * * char *  
* *  *** *   **** char  *   
 ***  ** ***    * char  ** * 
** *  * **   * *** * char   ***
**   ***   ***** char * *  
 *      *  * 
*  * *  ****   * *    **    *  *  input the ***** to   * * ** **   *    * * **
 ***  *  **  ** 
 **  *    *  *   ** **   ** * * *   *  **  * ****    ** ** * ****  **     ********  *  **  *  *
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    *  *   * * letter = letter + 3;
* * ** *    ***** **  = *** + 3;
* *   * **  ****  =      * + 3;
**** *  **** ***  *** = * *   + 3;
**       ** *  *   = ***  + 3;
  ** * *  * **  *  
**   ** *  ****  *  ** ****   *  *** * * letter is * *  * ****   *   **    *  ***  **     * * *  *
* **  * *  *   
***  ***  * * * return 0;
}

INPUT
* ***** *   * ** **   
*  *    **   
* *   
 * **  *  ******  **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * *****   **** ***

int main(int argc, char *argv[]) {
* *  ** * * **   **  * *  *  lettera;
  *   *  ** *** ******  ***  ** letterb;
* *****  *    ** *   **      **  letterc;
**    ***** ***  * * * *  ****** letterd;
 * ** * * **  ** * *** ****     * lettere;
** ***  ***  ** **  **  
 *** * **   ******   *** *  ** *  %c %c %c ******** *****   *  ** * *  ***    ** * ****    **** *  *  ***       **  
   ******     *  **  *   ***  ** = lettera + 3;
*   *  *  *  ****  *  * *  ** **  = letterb + 3;
 *  **     * **** *** *** *** *   * = letterc + 3;
***     *  *  * ** ** **  * * *  = letterd + 3;
* *  ** * *    * *   *** *   *   * *  = lettere + 3;
****    *  ** ******    *** ** *** *  ** *    *** *** 
     *  ****** ***  **** **   * * ** %c %c %c      *   ** * letterb,  * *  * * *  * *** *** 
 *  ** ***  ***  * *   *  **  
   * ****    ***      **  **  0;
}

  ** **
* ** *
 ***     * 
   *** 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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