[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3.7k views

22 Answers

0 like 0 dislike 
Hidden content!
** **   *      *

int  ** argc, char    * * {
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*     *  **** int number;
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  * **  * * ** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ***  * * *  **
#include     *** *  *

/* run this program using the console pauser or add your own getch,  * *******   * ***   or input loop */

int main(int argc, char *argv[]) {
* *        * *  *  * *  * ***  * a;
*   ******* ***** **** **** *  b;
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   ***  *   **   *  * * **       d;
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*** *  *****    * **  *  ***   *** the words you want to   **** **
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*  *      *   *   *  * * *   = getchar();
**  * *     *** *    ** = a+3;
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**  **   * *    *** **   = getchar();
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** ** ***  * ** **  * *  *** = c+3;
** * * *  **     * *** ** * *  *
** * **  ***  * **  ** *** = getchar();
*    * *  ** *****  * *    = d+3;
**** **  ***  * **    * *   *   
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*  * *    **  ** * ***  *** * ** ** ** *   ** *  * ** &a, &b, &c, &d, ** **   
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* *  * **  *    **   * 
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 ***** ****  * * ** *    *** * 
**     * ***   ****  *   *** **   0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
***  *      * ******   
*  **   *  ***  ****

int   **** * *  char     *** {
/*
 **  * * * * */

 *    * * * *

***  * ** ** ****    **** ***  *   * * *  *   *     * **   *    * 
a = a+3;
b = *  
c =  
d = d+3;
e = ** *

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**    *  * ** * *  * *  
  * *   *    *  *  * *   *   *  0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 ***   * ** * * * *  *
* * * * * ****  * *** 

/* run this **    ** the  *     ** or add your own   * *   **    ***    * * *** or  *     */

int   * *   **  char * *** {
****     *  * *  int num,  *****
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*   * * *    * * * * ** = ** *  * *
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}
    *  *   * * *    *  *         *  **  
  * ** *     *   * * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  * *  ** **  *  *** *
*
*   ******  * 

          * ** *   **       * * *            *  *      * ** * ** ** *   *  *      **  *

   *** *   * *  ******  

***     *   *  

    *   * ** *

***    ***      *  ** *  ****      **  * **** * *  **       * *    ** 
*
** = * * 
*
**    b +  

 *  = c + *

*** = d + **
 
 **    * 
 
 * ** **  **  *  *  * *  *  *  * *   *    * 
*
   *  
*
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*   * * *** * * **  *** ** 
 ***  * ***** *  *** ** *  

int * **  argc, char *  * * {
***   * * *   * char * * *  
* *    *  ****** char **   * 
 *   **   *  char *  *  
***   ***   ** ** char    **  *
*   *        * ** char * *** 
* *    ***  
** * ** *** *  * *  * * *  **  input the letter to    ** **  *
  * *   **    
* ** *** * * *    *  ***  *** ***     *****     *  **** ***   *  **    ***  *****  ** *  ***   **  *  **   
   **   ***  *  ** * = **   * + 3;
 ** ***  *   **  **   = * **  + 3;
  ***  ****   * ** =  * ** + 3;
****** *   * **  letterc = *   + 3;
   *** * *   **  * * *  = * * + 3;
 *   * *   * **  
  * *  *    *      * * *       *****  ***     ** **   **  *     *  *     *** 
 * *  * *  ****   
   ****  * ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*    * * * ***   *
 ***  *** **      *

int * * *  argc, char *argv[]) {
******       * char   **   *
 * * *  * ** * *   char letteri;
  *       * **    char  **  * 
*  ** ***** char ***  **
* *** *     *   char   **
*** * *   *** 
 *  *  *     *     * *   *  *  *** input the letter to encode: * *     * 
** * ** *  ** ** 
**    ** **  *  *  ** * * * ******* ** ***    *     ** *  * *** **      *  *  *** **       **********       *** **
* *  *  *    * ** *  ** +3;
*** ***  **   * ******  +3;
 **** ** *  * ** *  *** * +3;
  ** *   * **  *     ***** +3;
**     * **   * **     *  +3;
**** * ** * * 
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* *  *   **** * * *   **  ***   ***  *     **  *  *  *** *    *  **     **
* **   *  ** * 
*  ***** * ** return 0;
}


INPUT
  *    *  *    *
*  ** *****
OUTPUT
**** *   * *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   * ** *  *** *  ***
* ***  **   * **** **** 

int  **  ** argc, char   * * {
  ***  *  **** char ** 
**  ** ****    char ***** *
    ** **   * ** *  char    *
 *   ** *  * ****  char ***** *
 **     * * *    char  * *  
 *    *  **  ** 
*  *  *  *   *  ***  *    ** input the  * to     **  **    *   **
* ***** *   *** * 
 * *     * **  *** **      ****  **** **   ** ** ***     **  * *    ** *  *  *** * **  * *  **   *
     *     *  
 ** * ** * letter = letter + 3;
*      * * **   **  * = ***  ** + 3;
* **     ****    * * * = *     + 3;
*    *** * * * **   *** = * *** + 3;
      * ** ** * ***  = * **  + 3;
****      *   *** 
***    *   *   **** ** *  ******  letter is    *   * *** * * *  **   *   ** *   **     ****
*    ***    *     
 * ** * * ***  return 0;
}

INPUT
   * ***  * *** *
*  * **   
  *
   * ***  * * *****
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *** *** *  * **

int main(int argc, char *argv[]) {
 ****  ** ** * *      * *  lettera;
* ****** *  * * *** * *  *   ** letterb;
* ** * * ***** *  *** *  * letterc;
**  * *  *   ***** * * * * *  letterd;
 * * *  ****  *  **  **  **** *  lettere;
   *** **   * ** *** **      ** 
 * * * * * ** *  *  **  **  * * **    *   %c %c %c ** **        ***       * *  *  * *** *  ***     *  ***  * ****     ** 
   *       * *** *     ** ** ***    = lettera + 3;
 *  *  * *   *** * **   * * *** = letterb + 3;
* * *** *   ** **    **    *     *  * = letterc + 3;
** ** ** **   *  ****     **    = letterd + 3;
*****  *   * *  * ** **  *    ****  = lettere + 3;
    **** ***** **  * *   **   **  **** * *  * * ** **   *
 *  *    ***   *   * * *   **   * *** *   %c %c %c ** **     *  **   ** letterb, * **    * * **** 
*  * ** * ** *     ** 
  ***** ** *    * ***** *   *   * 0;
}

*     
*****  
 *   **** * * *  
**  
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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