[Exercise 03] Caesar Cipher Decoder

Question

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

Answer 1

Hidden content!
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
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***   *   *      * * *****   d;
* * *   * * * **    * ***     * e;

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**  *****  *   *    **  * **  ***
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*   * *** * *** **  *  *  *** *  *
**  *** * *  * *       **   *** 

 * **    ***** *  * *  ** *  * *  *        *** *    ****   **
*   *  *      * **     *  * *  0;
}

Comments

Case 0: Correct output
Case 1: Wrong output

Answer 2

Hidden content!
#include ** ** ***  *
int main(int argc, char *argv[]) {


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}

Comments

prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'

---

Case 0: Correct output
Case 1: Wrong output

Answer 3

Hidden content!
int main(int argc, char *argv[]) {


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* ***  * **   ** **  *** * *** * b;
   ***  *  **      char c;
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* ***  *   
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**      * * *  * *****  ** *
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** ***   *** * ** * ******   ******* ******* ***   
**           *** **      * **
 *     ******* **   *  0;
}

Comments

prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'

Answer 4

Hidden content!
***  ** * *  * *****

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Comments

Case 0: Correct output
Case 1: Wrong output

Answer 5

Hidden content!
*** *    **** **      

*   *     *      *  * {

**   ****
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*  =  ******
** =    *
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e =   *
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*  = * * 
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Comments

Case 0: Correct output
Case 1: Wrong output

Answer 6

Hidden content!
#include   ** *  *****
#include **  ** * *****

int main(int argc, char *argv[]) {
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}


INPUT
  *    ** *    ** ** 
**      **  * *
OUTPUT
***     *   **

Comments

prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'

Answer 7

Hidden content!
**  * * ** ****   **

int      argc, char * ** {


* *   * *  ** char a;
** *** ** ******   *  *   **  * ****  * *  char b;
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 ** *   **  * *   * *  the  **   how??
** ***    *  ** * 
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* * * *    * * * 
* **** *   **   *     ** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output

Answer 8

Hidden content!
#include *  ** *   **   

int main(int argc, char *argv[])
{
 * **  **    letterj;
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**  *  ***  *  *  *    * *  * = letterm +3;
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}

Comments

Case 0: Wrong output
Case 1: Wrong output

Answer 9

Hidden content!
*     ***  ** *   *  ****

 *    *   *     *   * {

       * **
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i = * * ** *
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e = * *
* =  **
* =  
*  = ** 

* *  *  *
* * *** 
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*  *  * *
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*  *** * ** *   **** * *  *  * *
*

Comments

prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.

---

prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~

---

prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~

---

prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^

---

Case 0: Correct output
Case 1: Wrong output

Answer 10

Hidden content!
#include ****  *  *   * 
#include *   *** ** ***    

int main(int argc, char *argv[]) {
** ** * * ***  *** * ****  * letterj;
 * * ** * *** **  *  ** letteri;
** *  **    *  *     *         * letterm;
* **     *** *** **  **   * * *** lettere;
*  **        *  ** ***  **    * * lettern;
*  * **** * * ***     *** 
****** ** ****** * *        **  * *    * * * ** input the letter to encode: *  *    
* ** * ** ** **** ** *  *  **  ** ***    * ** ** **   *  ** **********  *  ***   **  *   *    *  *  **       *  *  * *  ***** *  *
* ***  *    *  *  *   *** 
* * *     * * *   letterj = letterj +3;
  ***** *  * *    * * * *  ***    = letteri +3;
 *** *       ******** *********   = letterm +3;
***   **** **  * * *** * *  *     *  = lettere +3;
 * ****  *   ** *  ** ** *  ** = lettern +3;
***  **   * * *         *  *** 
  ** *  *     **** *  * *   **    **   *      ***  ***** *** ** **  *   lettere, lettern);
**  *   *  ** *   *  **
 *** * * ***   ****  * ** *** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output