[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.6k views

22 Answers

0 like 0 dislike 
Hidden content!
   ** ** **  *** * * *

int *   * argc, char     {
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*  *  *    *** 
        ******   return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**** * * *** **********

   ***** *** *     **  {

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* = *** * **
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** = **

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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *****  **  ***
#include *** ***  * *   **

/* run this program using the console pauser or add your own getch,  * *  * *   *******     or input loop */

int main(int argc, char *argv[]) {
 ** ***     **    *** *  *** a;
     *   *      ***  *      b;
 *  **** * * **  ********* c;
   * * *   * ** * * * * **  * *      d;
***   **     *       *** *  *  e;
*****  ***  **    ** * *   * 
** * *  *    * *  *   ***    **** * **** ** the words you want to *  ****    *  * **
**  *  *  * **  ***   ***      *
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** **  *    * ** ** * * *   **   = a+3;
     *** * *** **    *   **  ***   
** ** * *    ***   *   ***  * * = getchar();
 *  *  *   *****  * *  *    = b+3;
 *** *  *** *     *    *   * *   * *
* ***  * **** *  * ****  ** = getchar();
*  * **   **** *  **     = c+3;
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** **    ******** * *    = d+3;
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     **        * * **   * ****** = e+3;
* *  *       ** * ****  * * ** * * **
  *****   *** * *****  *   **  ***       **   ****  **  ***  
 * *  *  * *   *   ** ** * ***   **  *** ** *   * * &a, &b, &c, &d,   ***    * *
* **** **  *****   *****    *
  * ***  ** * ***     * *       *  the message how??
** *  *** *** ** * *   * *   
***   *   * ***  ** *   **              **  *    a, b, c, d, e);
*   *  ** * * * ***  ** **
** *    *   * *   * ****  *  ** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ** ** * * * *** * *
* *   ***     * *  ** 

int  *   ** char *   * {
/*
   ** *****  */

*  *  **    *

 *     * *     **** *    *  * *    *       ** *        ***** * 
a = a+3;
b =  **
c = **
d = d+3;
e =   

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**** *** *  ***  
** ** *       ****   * ** * * * 

 **   * **   *  ***   *
* * **      *    * ****  * * *     0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**  *    *  *   ***  ** 
   *   * ** ** **** 

/* run this ***  * * the **  **   * or add your own  *  ***  ** * ** ** ***   or   *   ** */

int * *   *** char     {
*  ***** * ** **    int num, * ***
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{
* *   **         = *   * *  
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 *** **   * **  * ***  
}
   * ** ** * ** ** * * *****    **   **
* ****  *    ***     **  0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  **    *  * * ** *
*
  * * ** *** **  ** ******* 
*
*   *   * * *   * * *     * * * ** ***  *   *  * *  ** * **  *** ** *  *       
 
*   ** *  *  *    *   * *
*
      * *   

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* * *  **   *    *  * * *  * * * * * ****     *  *   *  ***    * **
*
 *  =   *  

*  b + *

   = c + * 

* = d +  
*
**     
*
** **     ****** *  *** ****  *  * *  
*
 * *   *
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
    **     * *** *
   * **  ** **   *  *****

int   **   argc, char *  ***** {
** **    ** * **  char ** *  
   ****     ** char ** 
*  ** *   *** char  ** **
 ** * *    **   char * **
* **** * * *  char   ***
* ****   * *  *  
** **** *     *   * *****  **  *  input the letter to **  ***  *** 
 **  *  * *  *   *  
* **  * * **** *** * * **** *  *  *   **  *  *    ** *    *  *  ****** ** ** ***  ***  *** * ****
***    * *   **   =  *** + 3;
***           *      = *   * + 3;
**** *  *****  * ** =   **** + 3;
 * * *      **   letterc = *  * *  + 3;
****  *     *  * * = *   * + 3;
* *  **   ***  
 *      **   **       ***     *  ***  *   ***** * *** * * *  *
 * * *  *  ** 
  ** *  ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
****    * ** *    
 * *** **     ****** ***

int * * ** argc, char *argv[]) {
** * * **   *   * ** char *   * 
* ** ***  ** *** char letteri;
*  *  * * * *    char  ** 
**   *  * ***   char * *  
   *  * *   * **** char ** * **
** ** *  ** 
  *   * **     * * *          input the letter to encode:  ** *   *   *** **
* * * *    *   *  
** * ***  ** **   **** *  *** * *   * *** *  *  **  *  ***   *   *  ***  * *      **       *   **  
**    *  **    * *  **   *  +3;
* **    *  *   *   * ***  *** +3;
  * *  **   * **  **       +3;
  *  *  *** *****   ** +3;
 *** ** ******  * **   * +3;
  ***  *   * 
*        *   * 
 *  ** **    ****** * ****  *  *  * ** * *  *** *   *   ** **   * *  **
  ****   * *** 
 **** *  * ** return 0;
}


INPUT
*        **** *  **
***   **  ***
OUTPUT
***  * *   *  *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
  ***   * *  *  *    ** 
     **   *    *   ***

int **** * argc, char       {
* **   *    ** char  ***
 * ***  * ***  *  char    **
*       ** **  char  *  
  *****   *  char *  
 *  *  **  * *   * char  *** **
 *     ***   
 *    * ** *  * ** *   *   ** input the *   * to * * ****** * *  ** ***
   * *   ***** * * 
**  *****  ** ***    *   **** ** * **** * *  *** **  **  * ** *  *    * *** ** * *  **  *** ** *  *    *****  
    ***   **       
  **** **  * * letter = letter + 3;
**   *    ** *      ** =  *   ** + 3;
* * *   ** *** **  = **  ** + 3;
**** *   ****  * ** * = ** *** + 3;
   ***    *   * **  = ***  + 3;
*   **  *  ***** 
  *   **   ** *    *****     ***     * letter is ** * * *   *****      *  *   *   * * *    
** ***   *  *  
    ** * ** *   return 0;
}

INPUT
* *  * *  *  *
 *  * ****** * *
 *** 
 **** *  *  ****
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *** **   * ** *   

int main(int argc, char *argv[]) {
***  **  * ****** *  * *   *  lettera;
  * *** * ** * * *** ** ** letterb;
** *  * ******** *  ** * **** letterc;
*  ***** *   ** **  * *** ** letterd;
**   *  ***   *   * ***  * **  lettere;
 *   ***   ** **   ***  *
*   ****** ***    **** * *  *****  * %c %c %c  *     *** ****       **   * **  * **  *  * **  **  *  *      ***     * 
  **  *  *  **  * *    * **** = lettera + 3;
      *  ** **** * * ***** *  *  = letterb + 3;
**     * *  * * *        **     *  = letterc + 3;
 * ***  ***    * * * ** *** * = letterd + 3;
*   *  * ** **  **   * ***** * = lettere + 3;
* * **   *   ** * *  **  * *  * **   ** ** ****  
***  ** * *  **  ** **      * ****     * %c %c %c   ** *** *    letterb,     * *   * *    *
  *  ****** * * **  ***   **
* * * ***  *    *   **   ** *** 0;
}

* * *
 * ***
   **** ****   
  *   
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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