[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 9.4k views

22 Answers

0 like 0 dislike 
Hidden content!
  **  *** * **  * ***

int  * *  argc, char   *  *  {
*** ** * * ***   * *  **   *  */

** ** ***   *    ** int number;
** *  * * *    char a;
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***  **  *  *   *** **      * ** *  * **     **  * *  ***
*   *  * *****  
     *  ***** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * *   *   * ****   * 
*
*  *  * **   * * ** {

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*  * * ** **
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* *   * **      **   
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include    **  *  *   
#include      * *  *   *

/* run this program using the console pauser or add your own getch, * ** **     **** **** or input loop */

int main(int argc, char *argv[]) {
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**    * ****  *      * * *   b;
** * ***  ** **  **** **  ** c;
* **  * *   ****  ****** * *** ** d;
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**  * **** **  * * * * * * ** * * = getchar();
      **    **********  *   = a+3;
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**  * *  * * *   **** * *    = getchar();
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*  * **  *** ** ***  *   *****  *** * 
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 ****** ** ** ** **   *    = c+3;
   ***** ***    *  * *** **  
* * * ***  ****  *** *  **  = getchar();
 * * ** ** *   * * **   = d+3;
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   ****** *  *  * * *** *** = getchar();
 ********** * * ***      **** * = e+3;
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* *       *   **  *  * * * * * *******       *      *****
****  ** ****** **     * **  **  ** * ***  **  ****   * &a, &b, &c, &d,  * * ** *
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*     * ***  * ***  ** 
**  ** ***** *  * ***  ***  ** *   * * *     * **  a, b, c, d, e);
  **** *     * * **      ** *
   * **   * *  * * ****     **   0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
***   **  * ** * ** 
* *  * ** ***** *  ***   * 

int    *  **  char *  *  {
/*
* *   *** ** */

 **  *  *** * 

****   ****   *  * * *    *     **  *    **   * * * *   * **  
a = a+3;
b =  
c =  
d = d+3;
e = ** 

*  ** the ** *  * 
****** *   ** * * 
  *** *******  *    *** *   *  ** * * 

**** *** **** *   
**   ****     ***       * * * **** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 ** * *    ******* *
  *** ****   * **      

/* run this **  *   the *  *   * or add your own **  *    ****** * ** ** *       or   **  */

int     *     *  char      {
*  *     * * **  int num, ** * 
*  * *     ** *  * *   *
** * ** **   * 
**  *  * **    ***   * ** * *  ****  * **
**     * ** * *   for     = **  *      * 
{
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***    * *  *    ** if * **  * **   * *  
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****  * *   *** **   * * **
}
   *  *   *  ***   ***  *  * * ** * *** ****
** *  *     *  *   ** * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**** *  * ********* **
*
 * *      **  **** * *  

 *      * ** *    ***  ***  * **  **   ** *    * * * *   ****  **   **      

* *    *    *   ***  * * ** 

*        ** * **

***    *      * 

** *   *  *  ** *   * **   **  * * ** * ** *    ****       *   *   **
 
  * =    

*** * b +  *

   = c +  

* = d + **
 
**     *

  **    **  ** * **   * **     *  *  *   **  **
 
*  **  *
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 **        *    *
    ***  * *  * **   * **

int  ****  argc, char **** * {
 ***   *    *** * char *  * 
**  **     ** char  * * 
***  *    *   *  char * **  
** *    *      * char *******
 *  * **  ***   * * char * ***
   * ****  * ***   
***       * *    **  ** **    input the letter to  ***  **  **  
**    ***    * *  
**  **  * *   * ** *  *** *   ** ***** *******    * ** **   **  **   * ** *   ****   **     **    *  ** 
** * ** **  * *    * * =  * *  + 3;
* **     * **  ** = *  *   + 3;
**    ***   * *     = *   + 3;
***  ****  ** * * letterc =  **  + 3;
   ***** * *   *  ** = *  * + 3;
* * *  **     
    *   ** *    ***** *   *  *   **  *  **    **  * *  **  ** *        * 
 * * *   *****   
*    *  ****** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ***** **  *****  **
***   *    * * **  * 

int      argc, char *argv[]) {
 *  * * **  char   * **
* *** *   ** * char letteri;
*        * ** char   *** 
* *  *** * *   * char *** * 
***** **   * *** char      
   *   *  *  *  
  **   ****  *  ***** * * input the letter to encode: **  ** *** **  ***
*      * ** * *  
  *      *** ***   ******** * ******  *      **  **   ***     *  *  *  ** **   **  *   ***    * ****   *  **  * *
* **** ** * ***   *  ***** *  +3;
 * **   * ** *  ***   *  ** +3;
  ***    *   **     **     +3;
* **  * *  *  ** ***   ***** ** +3;
** *  *    *** * ** * ***  * +3;
* * **** * 
* *** ****   
* * **   ***  * ** *** **** **   * ***   **  *    ** * *   *
  **  *****  
 ** *    *    return 0;
}


INPUT
  * * ******   ** **  
 *** **** *
OUTPUT
 **** *    **   *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *  ** * ***** *  *     
  ***  *   ***  **  *

int    ** argc, char  **   {
 **    * **  * char ** ***
* *    * ***** * char **  *
* **  *  *   ***  char    * * 
*  * *     *** char * **
*      *   * char *** 
* **  *  *** *   
* * ** ** *  *  ** * *****  ** input the  *   to ***   *  ****   ***  * 
****  * *   * 
* ***    *      *   *******   **** *  ** ***** * ** * * **     * * **     *  **   ** * **    ***  ** **  *
*** **      * 
** *** *   *  *  letter = letter + 3;
** **   ***    *  * = ***   + 3;
*   ***  *  ***   =    * + 3;
** **    **  * *    *   = *** + 3;
 * *  *   * **          =  *** + 3;
* *       * ** 
****   ** *      *   *  **  * *  * letter is **** ******    * **** ** *   * ****  ****  * * *
* * * ** **      *  
*****   *   return 0;
}

INPUT
 *   * *  *      * *
* ******  **   
*   
*** *  * ***  **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *** *   ***  

int main(int argc, char *argv[]) {
****** ** *  ** ** *      lettera;
 ** * ** *    **    *** *   **  letterb;
* *     ****  ** * **** **  ***  letterc;
 *        * *   ** ***  ***  ** *  letterd;
   ***     *   *****  *   **    **** lettere;
* **  **  *** ***  *** ****** 
*** *    *   * *  **  * * ** *  * * * ** **  %c %c %c  *  *    * ** * ** ** * ****  ***   ***  *  ***      **** * **** ***  **  
** * *      *  *** *   * *  = lettera + 3;
**** ***   *****  ** **   **    = letterb + 3;
 ** *       ***** ***  * **    = letterc + 3;
*    **** ******* *  *  **  *  = letterd + 3;
  ** *  ***     * * *  ****  **  = lettere + 3;
***  **   *  *    *** *** * * *     * *    * * *  
**** *  *  ** **    * ** ******   * * * *   * %c %c %c  * *    *    *  letterb,      *  **   *    *
  ** *   **   * *****  *  
   *   **  ** ***    ***  *    0;
}

*   *
*** *
** ** *  ***
 * **
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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