[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3.7k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   **  * * * *  
#include ** ***  ** ** ****

/* run this program using the console pauser or add your own getch,   *** *    * **  * ** or input loop */

int main(int argc, char *argv[]) {
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*    *** ** ** *** *****  ****   b;
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 *    **** ** ***** * ***
* ** *  **  * * *   *  *  ** *** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** * *  ***  ***  * **
*** ***   *      * ****  *   

int ** ***  ** char    *** {
/*
*     *  * */

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a = a+3;
b = *
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*   **  *   * *
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 **  * *  *  *******  *  *
**** *     ***** * *** *

/* run this  **** *  * the *  *   **  or add your own   **     *** **  ** *   *  * * or  *    * */

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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  ** *  **** *   * 

*   **   * ** ******** 

***   *  *  * *  * **   * * ** *         **  *  *     * *    ***  *    ** *  *  **   
 
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
****     *  * **   * * * **
**** *          * ** ** 

int *  ** * argc, char    * * {
*  ***  * *** char ** 
 ******  * *** char **  
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**** *     **** 
  *  *   **  *** * ** **  input the letter to *    ** **  * 
** *** * *       
*   * * * **    * *** *     **** *** *   **   *  *   ****  *** *  * * ****       *   * *   ****  **    *
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   ***  * *   * *   * = * *  + 3;
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   **  *  *   letterc = * ** + 3;
 * * *   ** *   *  =  * * + 3;
****    *  *  
**  **  *   * *  * *** ****  *    * ****  * ** ***    *   *   * **  ** ***
*    * * ****  * 
  *  *     ** **  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 **    **** *  ** 
*  **    * ***      **  

int   ** argc, char *argv[]) {
* *  *  *****   char    *
* * **  * *    ** char letteri;
 *  *  ** *    char *  *  
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** *      *  *     char    * * 
 *** *       ** 
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**   *     ***  
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**   *    *   ** 
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* ** **** * 
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}


INPUT
          *  **    
  *  *** ****  
OUTPUT
**   * *       *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**    * *   **   *       
*   *  **    ***      

int  **** argc, char   * * {
** * *  *** char      *
      * *    *   *  char *  *
  *   *  ** *      char  ** 
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* **** * *  ***   
  *   * **  ** ***  **  **   **** ** *  * **  * **   ****  *    ** * * ** *** *******  *    * ** *** *  *
   *  *   *  * * 
***   *      **    letter = letter + 3;
 *  *  * **  **   *  ** =   ** + 3;
*  *    * *  *   * =  *   + 3;
 *   ** ** ***  ** ** = * * + 3;
 *****   *** *    *  = * *  * + 3;
*  ** * * *** *   
** * *  *** *    ***  ***   * *  * letter is *  * ***    **  *         * *  * *  * *   
**  ***  *    * 
* * *   *  **  * return 0;
}

INPUT
  * *  ** *   ** 
 * *  ***
**  * 
    *     ***  ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include **  ** ***   *

int main(int argc, char *argv[]) {
 * ***** * * * ***** *  ** *** *  lettera;
*  * **    ******* *    * * **  ** letterb;
*  * ** *****  * *  *   letterc;
 ** ***  **  ****   *   ** * **   letterd;
**  *  **** * *  * * *  *  * * *** lettere;
*** *  *  *     * * * *  **
*  * ***   ** * **    * * *  ** *  %c %c %c * ** **  *  *** *********  * *  *  * *****   * *   * ** * *   *****    * ***   
 *      *  **  **  * *  *  * = lettera + 3;
 * *   *****  * ***  ****** = letterb + 3;
 **   *  * *** ***   ** *** = letterc + 3;
**** ********** *  *   **  *       = letterd + 3;
****** * * * * **     ** ******** = lettere + 3;
   *    ***    **   *   * ****  ****** *   *  *   ***
  **    ***  * ****  *** *******   %c %c %c *  *  *   ****** letterb,  * *  *   * ***  
     **** *    *** *   ****
*  *  **  * * ***  * *  **** *   * 0;
}

*   *  
 **
*   **      * *
  *  
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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