3 like 0 dislike
6.3k views

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited

edited by | 6.3k views

22 Answers

0 like 0 dislike
Hidden content!
**** * *** *** *****

int *** * argc, char *** {
**** * *** * * * * * ** */

*** * * * * int number;
**** * * char a;
* *** ** *** * ** * * ** b;
* * * * ** * ** *** * * c;
** ** * * *** * * ** d;
**** * * * * **** ** * e;
* * * * * ** * *
* * * * ** ****** ** forgert how to shift word * * * * *
* *** * *** ** *** *** * * ** ** * *** * * *** * ** ** * * **
*** * ** **
* ** * ** * ** the message how??
**** * **
* * ** * ** * * ** **** * * ** * ****** **
* * ** * *
* * ***** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
****** *** *** *** **
*
** ** * * * * {

* * **
* = * *
** **
* = ** **
* = ** ** *
= *

= *
= * *
* = **
* =

** *
*** *
*** *** *
** *
* * **
*
* *** ** * * *
*
100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
#include *** * ** ** *
#include *** ** ** ** ****

/* run this program using the console pauser or add your own getch, ** * ***** * ** or input loop */

int main(int argc, char *argv[]) {
** * *** * ** *** ** * a;
* *** * **** * * ***** b;
**** *** * **** ****** c;
*** ** * ** * * * ** ** d;
* ****** * **** ** e;
* * * ******** *** *** **
** * * *** * * * * * ** * * the words you want to * * ** *
***** * * ** *** * *
****** * *** ****** = getchar();
* * *** *** ** * *** * * = a+3;
* * ** * ** ** **** * ** * * *
*** ** *** * * ** * * = getchar();
*** * ** * * * * * * = b+3;
*** ** ** ** ***
** ** ***** *** ** * **** * = getchar();
*** ***** ***** **** = c+3;
****** * *** * * ** *** ** *
* * * * ****** * * * ** = getchar();
** * ** ** ** * * ** = d+3;
* ** * ****** ** * ***** * *
* * * *** * * * = getchar();
* * * * * ******* ** * = e+3;
* ******* * * * * * * * * ** ****
**** * ** * * ** *** * **** * ** * ** * *** * *** *
* * *** * *** * * ** * * ** ** ** * * * &a, &b, &c, &d, * * *** *
****** ** ** ** **** * *
** **** *** *** * * * ** * the message how??
** ** * ** ** **** * ***
* *** ** *** * * *** * ****** **** * * *** a, b, c, d, e);
* * **** *** * * *
* ** * ***** ** * * * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
1 like 0 dislike
Hidden content!
* *** *** * ***
*** * * * ** **** **** *

int *** ** char * * * * {
/*
* ** ** * ** */

**

* * * *** * ** ** ***** ******* * ** ** ** ** *** * * ** **
a = a+3;
b = **
c = **
d = d+3;
e = **

** * the ***** ** *
** ** ***
*** * * *** ** * ***

** * *****
* * * * * ** * * * * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
*** * *** ***
** **** * * *

/* run this *** * * the * ** ** or add your own * *** * * * * * * *** or *** */

int ** ***** char ***** {
* * * *** int num, * *
* * *** * ****** ** * *
* * * ** ****
** * *** ** *** * * ** ** *
* ** * ***** for ** = ** * * **
{
** ** * ****** = * ***
** *** * ** ** if ** * * *
* *** * * **** = * * *
** *** **** * * * ****
}
** ** * ** * * * * * **** * **
** * * * * * ** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
1 like 0 dislike
Hidden content!
* ** * * *** **

*** *** * ***

* * * * * ** * * ** * * **** * * * * ****** *** * * * * * ** *
*
** * * * * * *

**** *

** ** *

** *** * * * *** * * ** ** * ** * ** *** *

* = *

** b +

* = c + *

* = d + *

* *
*
* ** * *** * * * * * **
*
*

*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
0 0
That's correct.
1 like 0 dislike
Hidden content!
* * *** ** *
** * * ** * *

int * * * argc, char * ** {
** * * * ** char ****
* * * * char * **
** ** * **** * char * ***
* * * * char * ****
** * * char * * **
** * * **
** * * * * **** * ** input the letter to * * *
*** *
** * * ** * ** * *** ****** * * * * *** *** ** ******* * * * *** ** * ** *
* ** * * * * ** = ***** + 3;
* ** * ** * *** * = * ** + 3;
**** ** * * *** = **** + 3;
* * * * letterc = *** + 3;
* * ** ** * * = *** + 3;
*** ** * ***
* * ** * *** ** *** * * * ***** ***** ***** ** * * * ***
* * * *
*** * * * ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
1 like 0 dislike
Hidden content!
* ** **** * *** *
**** * ** * * ****

int *** ** argc, char *argv[]) {
* * * ** char ***
* * char letteri;
* *** * char *** **
* * ** * ** char **** **
**** ** * char * *
* * *** *
*** ***** *** ***** * input the letter to encode: * * ** ***
** *** * * **
** ** ** * ** * * ** ** **** ** * ** **** ** * **** ** ** * * * *
******* ** ** ** * *** +3;
* * *** * *** * +3;
* * * * * ** +3;
* * ** * * *** * * * ** * +3;
*** * * **** * * +3;
* * ** * *
* * * ** * * *
** **** ** * * ** ****** * * **** * ** ** * *
** * * * *
* * * *** return 0;
}


INPUT
***** *** **** *
*** *** *
OUTPUT
*** ** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
* * **** ***
* * ** * **

int * argc, char **** {
* *** * ** char * *
** * * char *
* ** ** *** char *
*** * ** ** * char * ***
** * * * * char
**** ** *
***** * * * * * input the * to ** * * ** * * * * *
***** * *
* ** ** * ** * * ** * ** ** * * * *** * * * ** ****** ** * * * * * * *
* ** ** * ** *
* * * * * * letter = letter + 3;
* * ** *** * ** * = *** + 3;
*** * * * *** * ** = *** + 3;
* **** = * + 3;
** ** * ** = * + 3;
* * *
* * * ** * ** ** * * * * ** * * letter is ** *** **** **** ** * ** ********
* ** *** ** *
** *** * * * * return 0;
}

INPUT
** *** *
* ** *
*
** ** * **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
#include * **** * ***

int main(int argc, char *argv[]) {
* ** ** *** *** ** ***** * lettera;
* * * * **** * letterb;
* * * * *** * * *** ** letterc;
***** * ***** * ** * *** letterd;
* *** * ** * * **** lettere;
** * *** * **** ****
* **** **** ** *** * * * ** * * * * %c %c %c *** * * * * * * * ** ******* * ** ***** * * * * * *
** * ** * * * *** = lettera + 3;
**** ** **** * * * * **** = letterb + 3;
** * * ** ** *** *** ** = letterc + 3;
* ** *** * ** *** = letterd + 3;
* ** *** * ***** ** * * * * ** = lettere + 3;
* ** ** * ** * * * *** * * ** ***
*** * ** * ** ** * * * ** * ** %c %c %c * * * ***** letterb, ** ** ** * ***
* ** * * *** ** ** * *
* * ** * ** ** *** ****** 0;
}

* **
****
* ** ** * **
*
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.111.69
©2016-2025

Related questions

0 like 0 dislike
2 answers
[Normal] Essay (Open question) - asked Dec 12, 2017 in Chapter 2: Syntax structure of the C language by 許哲瑋 (449 points)
ID: 37081 - Available when: Unlimited - Due to: Unlimited
| 958 views
12,783 questions
183,442 answers
172,219 comments
4,824 users