[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 4.8k views

22 Answers

0 like 0 dislike 
Hidden content!
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**     **  return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  * * ***  **
#include  ***     * **  **  ** 

/* run this program using the console pauser or add your own getch,  * *** *  **** *  or input loop */

int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** *  *****      *  **
* ***  ***  **    *  **

int **  **  *** char ***  {
/*
*   ****** */

**   **

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a = a+3;
b =  * 
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*** ******** * **** ** *  *  *   *  * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 ** *   * ****** 
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/* run this ***       ** the ***  * * * or add your own     *  * **** * *   *  or * ** */

int    * * * * char    * * {
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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ** * ** *   * ***  *** *

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*
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*  = d +  *
 
   *   

***   ** ** *   *** *   ***  *  ** *** *** **   
 
**  *

*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* **   ** * *  ** *
*  ** ****   *** ***  * 

int **  * argc, char  *     {
* * **   ***   char  * ** *
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*  **** *  **  letterc =  **   + 3;
* *  *  * *   *  ** =  **  + 3;
** * * *      * 
    ***  * * * *    ***    **  ** * ***   *** *****  **    * *   **** 
* *   *    ** 
  *    **  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * *    ****  * * *  *** 
* *    *   *     * ** 

int      *  argc, char *argv[]) {
 *      * * ** char **  *
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  *  ** ***  * char *** 
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* * ** * ** *  ***  *  +3;
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* *   *  ***   return 0;
}


INPUT
* **       * ** **
  *   *  * ***
OUTPUT
***  *   *  **** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 ** *** **    ***   *** 
** * *     * ** ** **    

int   *  argc, char  *   {
**  ***** **      char    
 *        * *  *** char * **  
 **   *   char * **
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*    *    * **   char       
*  **  * **   
*** *   *  *   **  * ** *     input the   ***  to  * **         ** **
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***  **    ** * *  ** ***  *     * **   **   *   ***** * * ** *   ** ***   *  * ** * * ** *** **       **** * **   
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**  *   ** * letter = letter + 3;
* **  **  *  * **  = ****  + 3;
*  *  *    *     = ** *** + 3;
  ***  **  * *  =  * *  + 3;
 *    *   **    *  **   =  * * + 3;
 *   *    ** **   
* *    * ** *   ***       *****    letter is *   *****  * *             *  *  **      **  
    ****  *  *    
 **   *  *   return 0;
}

INPUT
** ***** ****  
  ** **  **  
* 
*  * *****   *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ** *    *** * 

int main(int argc, char *argv[]) {
* *** ***   * *** * ***  ** * lettera;
  *** **  **  ***  **   ** * letterb;
* * *** *   **** **  *     ***  letterc;
     **  *   *  * *  *    *** *  letterd;
*** * *  **    *** ** *  ***   * lettere;
** **    ***  * **  * 
  ** *  **     ***** **  *  * *  **  %c %c %c    * *    * **   **    * ***  *       *** *** ***   * ***   ** ***** * 
*  ******  * * **       ** * *** **   = lettera + 3;
 *   * ** *  ******  **  * **  *   = letterb + 3;
**  ****** * *  *** * * * ***  = letterc + 3;
 *  *  *** *** *  ****  *   ** = letterd + 3;
*  *   *   **** * *  **** ** * **  * = lettere + 3;
** * **    *   ** **    **  ****    **** ****  
   **** * ***    **   ** **  ***** ***** %c %c %c *   * ***  **  * letterb, * * * ***** **  *
 ** ** ****     *** *   *** 
*   ****** ** **  * *** ** * 0;
}

*** *
  *  *
*    ** *   
**    **
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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