[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3.7k views

22 Answers

0 like 0 dislike 
Hidden content!
  **   *        * *    *

int    * argc, char  *    {
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include      ***  * *  
#include      **  * ** **

/* run this program using the console pauser or add your own getch,     *   * *  *****    or input loop */

int main(int argc, char *argv[]) {
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**     *   ** ***** * *  *** c;
*    *  **      * ****  *** ** d;
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****    * ******** ****** = getchar();
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*    **** **** **  * *****  = c+3;
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*** ****   * **  *** * * * = e+3;
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*** * ***    *    *  * *  * 
   **  ****** ***** ** ** ***   0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ** *  *  * * * * *
* ** *  ***  *  *  *** 

int **** * **** char *  * * {
/*
*   *   **  * */

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a = a+3;
b =  * *
c =    
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 * *  ****   **  
  * *   * ***  * *   * 

/* run this  *    ** the *   *    * or add your own *      * **** *    ****  or * *   *   */

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}
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*     *      *  0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**   **** *** **   
*
      * **  * *** **  
*
   *  * *     ***      *  * * *    *** *  *     * * **    *  *   *  ** *   ***  *  
 
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* *  * **    * *

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* = *    *

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*** = c +  

*  = d +   
*
** *  *  

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*
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 **  *  *** * * ** ** ***
*** **   ** **** **   **

int  **     argc, char *   ** {
*    *    *  *   char ** * 
* * **** *  **  char   **
    **  ***    char **  * 
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** *****     ***   char **   **
*  * * *** **  
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  * ****   ** 
*** **  *****     *   *  ** * ****  * * ******  **** **  * *    *  **  *  * *** ***  * ** **  * 
**** *  *  **  * **   *** ** = ** + 3;
  ** * * **   *     * * = *    + 3;
  * *         **  ** * * = ** ** + 3;
   *  *    *  **** letterc = **** + 3;
    *       * *** ****** =   *  + 3;
* *    **     
 * *  * **   * *     ****  *      *  * ******  * * *  *  *** *  *** **   *  *
 *        *  
 ****    * *  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *  *****   * * *   **
* ** ** **  *  ** *  * **

int *   argc, char *argv[]) {
 **             char ** ** 
**  *  *** **  char letteri;
    ** *****   char **    *
 * * * *   ***  ** char  ** *** 
    *  ****** char ** 
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* * * * *** *  * *****  * * ** input the letter to encode: *  * * ** *
    *  *  ** **  
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** *    * * *  * *  **** * +3;
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* *  *** * * **  * *  **    +3;
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***     ** ** 
* ****  * *  * return 0;
}


INPUT
** * *** *    ** 
* **** ** **
OUTPUT
* *** *  *   * *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
  *  * * ** ****** * 
*   ** *   *   ***  ** *****

int * ***  argc, char *       {
  *  *** **  *** char ***  
 **   ***   *       char ***  * 
 * **  **  * * *   char   ***
 * *    ****    char *  **  
*** ****    *** char *** 
    * **      *    
     ** * ***  *  **** * ** ** * input the   * to  *   **  ** ** *  *  
 *** * * **  * 
*   ****  *  *****   *  * **      *  * ** ** * ** * *** *  *  ***    *  *     **    *  *       *******  
* *  *   *  ** 
 ****   ** * * * letter = letter + 3;
*** *         *       = ** * + 3;
*  *     **** * ** *** =   **** + 3;
*         *  *    = * ** + 3;
 *    *  *****  *** * =  ***** + 3;
* ***   ****  
 *  ** * **   ***       * * *    letter is  *  *** ** * **  **    *  *** *** **       *  ** *
   ** ***  **** *** 
  ***     **  * return 0;
}

INPUT
*     *  *** *  
** * ** *** * *
   *  
  *   * ***   * **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ***  ** ** * 

int main(int argc, char *argv[]) {
  * * ******     * * *  ** ** lettera;
*     *  ** ***    * **  **** letterb;
 **  ***    ******* *   **   **  letterc;
* ** *  *****  * *  ***      * letterd;
  **  ** *** **    * *     lettere;
   * * * ******  * *   *
*    *********** ***  *  ********     ** %c %c %c  **  *  **   * **     ** ****       *   **       ******** *     * ****  
 ***** ******   ** **  * * **   * = lettera + 3;
**  * * **  * *     ** **   ** = letterb + 3;
       ** ** **   ** ***  *** = letterc + 3;
 ****     * ** * **** **  ** ** = letterd + 3;
 * *  *  *   *  **** * ** *   = lettere + 3;
****** ***  ** *   *** ****   ***  *** ***  ***  **  **
* **    *  ** *  *  ** **   *** *  *   *** %c %c %c     * * *   ****** letterb, *   *      ** **
*   *   * ** * ***********   ** *
** ****  **   *  *   * *  0;
}

 *   
  **
 ******   **     
***** *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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