3 like 0 dislike
8.6k views

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited

edited by | 8.6k views

22 Answers

0 like 0 dislike
Hidden content!
** * * ** **

int * * argc, char * * {
* * ** * ** * * *** */

*** ** * ** * int number;
** * ****** char a;
** *** * *** * * * ** * b;
**** *** * **** c;
** ***** * * **** * **** d;
* *** *** ******* **** ** e;
** ** ** * **** * * **
* ** ** * * * forgert how to shift word ** * * *
* ** * * * * * * * ** ** ** * ** *** *** * ** *** *
*** * ** **
**** ** *** * *** the message how??
** *
** * * ** * ** ** ******** ** **** ** * * * *
**** *
**** * * * * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
**** *** *

* * ** * * ** {

* * * **
= ***
* ****
* = ******
= * *
= * *

= **
* = ****
* = *
= *

***** *
*** **
***
*** * *
* * *
*
** ** * * * *
*
100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
#include * * ** **
#include *** * ** *** ***

/* run this program using the console pauser or add your own getch, ** * * * ***** or input loop */

int main(int argc, char *argv[]) {
* * * *** * **** * ** a;
* ** *** * ** * ** b;
**** * *** ** ** * * **** c;
* * **** * *** * * * * * * * d;
* ** * * * **** * ** * e;
**** **
*** * * * * ** ** ** * * * the words you want to **** *** * *
** ** * ***** * *** **
*** * * ** ** *** * = getchar();
* *** ***** * ** ** ** = a+3;
* * *** * **** * **
* * *** * * ** **** ** = getchar();
** * * ** ** * * * = b+3;
*** * * * * * *** * * * **
* ** ** * * * ** * = getchar();
** *** ** * * ** * ** = c+3;
** * * *** ** * * * *** **** *
* * * *** ****** * * * = getchar();
** * * * ** *** * = d+3;
**** *** * ** * * **
* *** * * * * * *** = getchar();
* ****** * ** *** = e+3;
*** * * ** **** * * *
* ********** ** * ** * ** ** * * **** * * ***** ****
**** ******** * ** **** * ** * * &a, &b, &c, &d, ** ***
** ** ** * * *** *
** ** ** * *** **** ***** the message how??
* ** * * ** **** ***
* * * * ***** * *** * * ** *** **** ** * a, b, c, d, e);
** ** * * ** **
**** * ** ** ** *** ** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
1 like 0 dislike
Hidden content!
* *** **** *
*** * * * **** *

int ****** *** char * * {
/*
* * * */

* * **

* * ** *** ***** **** *** ** * * ** *** *** ********
a = a+3;
b = **
c = *
d = d+3;
e = *

* ** the * * * *
** * ** * * ***
** *** * ** ******* ** ** * *

* * * * ** * * *
* * * ** *** **** *** * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
* ** ******** *
* * * * * ** *

/* run this ** * * * the ** ** or add your own **** **** *** ** ***** or ** * */

int char ** * {
* ** * ** *** int num, * * *
** * ** * * * * **
*** * ** * **
* * * * * * ***** * * ****** ** *
* * * ** * * for * = ** * ** * **
{
** * *** ** ** ** * = * ** *
** * * * * *** if ** * * **
** ** ** * **** = ************
***** * * ** **** * **
}
* ** * * ***** ** * ** * ** * *
* * * * ** ** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
1 like 0 dislike
Hidden content!
* ****** * **** *

* * ** * **** ***

* * * * **** * **** * * * ** ** * * **** * * * **** * * * *

**** * * * * * **
*
* * *

** * * *
*
** **** * ** * *** *** ** * ** * **** *** * * * ** ***
*
= *

** * b + **

** = c +

= d + *



*** * ** * *** * * * * * *

**** ** *

100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
0 0
That's correct.
1 like 0 dislike
Hidden content!
** ** * * ** **
* **** *** * *** *

int **** argc, char * * * {
* ** ** ** ** char * ***
****** ** * char * *
* * *** *** * char *** *
**** ** ** char *** *
* * *** char **** *
* ** **
* **** ** * * ** * * ** input the letter to *** **
* ** ** *****
** ** *** *** * *** * * *** **** *** ** * * ** ** *** * ** * ** * **
* * ** **** * = * + 3;
* ** *** * *** *** = *** + 3;
** ** * ** = *** + 3;
*** *** letterc = * * + 3;
* ** * ** * * = *** ** + 3;
* ** **
** *** ** * *** * ** * *** *** * * * ** * *** * ****
** * ***
* * * *** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
1 like 0 dislike
Hidden content!
** ** * ** * * **
***** * **** ** * * *

int ** * argc, char *argv[]) {
* ***** *** * char
***** * * * char letteri;
* * * * * char * *
* * ** * * char * **
** *** * * char ** *
** * *** * *
* ** * ** * **** * * ** input the letter to encode: * **** * *
* *** * *
* * * * **** * * ******* * * * * * * * ** ** ** * ** *** ** ** * ** * ** *** *
**** * *** * ***** * +3;
* * * * * * **** * ** +3;
* *** * * ** ** +3;
******* ** *** * * * +3;
* * * * ** * * *** +3;
* ***
* ** * * * * *
* *** * ** * * * * ***** * ** **** * *** ** ** ***
*** ** *****
* * ** **** return 0;
}


INPUT
** **
* * * * **
OUTPUT
* * * * ** *** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
*** ** ** * * * *
* * * * ** * * *

int * argc, char ****** {
* *** ** char ***
** * ** char *
*** * * * char ** ***
*** ** char **
*** ** * ** char * **
** * * * * **
* *** * * * ** * * * input the *** to * * * * *
** * ***
*** * *** * **** * * *** * **** **** * *** * *** * ***** **** * * *** *
** ** * * *
* * * * ** letter = letter + 3;
** ****** * = * + 3;
* * ** = * + 3;
** ** * ** * ** = * * + 3;
* * ** * * = *** + 3;
* * * *
* * * ** * * ** ** ** ** letter is * ** ** ** ** *** * *** ** * **
** *** *** * * *
* ** ** ** * return 0;
}

INPUT
** **** * ** **
* ***** ***
****
* *** * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
#include * * * *

int main(int argc, char *argv[]) {
* * **** * * * * * * * lettera;
* * ** *** * ** * * letterb;
** ***** ****** * *** ** * letterc;
* * ** * *** ** ** letterd;
* * *** ** * ** ** ** * lettere;
* ****** * ** * *
** * * *** ** * * *** *** %c %c %c *** * * ** * * ** * * ** * * * * * *** *** *** * *
* * *** * * ** * *** **** = lettera + 3;
* * **** * * * **** * * ** = letterb + 3;
** * ****** * * **** *** * = letterc + 3;
* ** ** * *** * ** * *** * * = letterd + 3;
** * * *** ** ** * ** * = lettere + 3;
* **** * * * * * * * * * * * ******* *
* * *** *** * * ** * * * * %c %c %c *** * * * * letterb, * * * **
* **** *** * * ***
** * ** ** *** ** ** ** * ** 0;
}

* * *
* ****
* * * ** ** **
** *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.31
©2016-2026

Related questions

0 like 0 dislike
2 answers
[Normal] Essay (Open question) - asked Dec 12, 2017 in Chapter 2: Syntax structure of the C language by 許哲瑋 (449 points)
ID: 37081 - Available when: Unlimited - Due to: Unlimited
| 1.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users