[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 10k views

22 Answers

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Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***  *  *    ** * * *  *

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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   *** *****  
#include ******* *  ** **** 

/* run this program using the console pauser or add your own getch,  * * *  ***   ** * or input loop */

int main(int argc, char *argv[]) {
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** *   ** *  ****  * *** **  *** *  b;
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** * * * *****  *** **       * = d+3;
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  *** **        **  *** *  
** * **   *   * *    * * **** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *         **   *  ***  *
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int *      **  char   ** {
/*
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*      ***  *

***    **  *     *  *   ** **** **   *   *   **    **  *   *   **  ****
a = a+3;
b =  *
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** * ** * * * *  *  **
*  * ***    * ** * *****        * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  *   ******   ***
 * ** **    ****  * ***   

/* run this * **       the ** * *  * or add your own     *    *   **   ****  * ** **  or ***      */

int  * * * *    char * * ** {
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}
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*** *     **  ***  ** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** **   ** * *  *** *  
 
**      ** * **  ***  
 
**   * *   **** * ***   **  * *      ** * *    *  ****** ** *   ***       *  **    *

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*   * *** **    *   **  *** **    *  ** * *  *****    *       *  
 
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** * b +  *

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*
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*
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*
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*
**
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**   *  *     * * ** ***
*****   *** ***  ** 

int * **  argc, char  **   {
*   * * *    char *** ***
*  *  *   *  * char ****
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******* **** char  ** *
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*   *      * *   ** *** **   * * input the letter to * ** **  *  *
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**** **     ***  *    = **  ** + 3;
   * *  ***  *    = ***  + 3;
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*   **  * **      letterc = * **  + 3;
  * **   * *    **   =  ** + 3;
*   * * *** 
* *        *       ** *******  *** ** ***  ***      *      **** ** **  **   
*   *  **** ** 
 * *   *  * ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *   *  * * * **   **  *
*** *  *  *  **    ****  

int   *** argc, char *argv[]) {
  * *  * * * char  * *
******   **  * char letteri;
  *     **** *  * char    ** *
 ***      * ***    char   *
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***  * * **  
*  **  ** * **       *  *  input the letter to encode:   ****   **  * ** * *
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* * **  *  * *    *  **  +3;
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**  ***  ** **** 
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* ****   *  ** 
 ***    * **  * return 0;
}


INPUT
* *  ***** *    ** 
****  *        **
OUTPUT
    **   *  ***
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**  * * ****  * * * * 
*  * * ** * *****

int * *****  argc, char    * {
  *  * * **      char  *  
*   ****  *  * * char     ** 
**** *    *      char  ***
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*   *       * 
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*   *      *     
*  **    ****** * ** ** * *** * *     *** **** ***     * *   ** *** *  **  ********    *     *  *  **  * * *  * 
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***  *   ** * letter = letter + 3;
** ****  *        * =  *  * + 3;
   **      *   *    * * * = ***  + 3;
** * *   **** ***  ** =   * + 3;
 * ** * *      * * =    *  + 3;
*    * ** **  *  
   * *  * ***** ****  **   ***   * ** *** letter is  ** ***   *** *  **       *    **        * *    *
*** ** * ** *   
 *  * *** return 0;
}

INPUT
*  *   * *  * ****
 ** *    *   * *
     
*  ***  * * * **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * *  ****** *

int main(int argc, char *argv[]) {
 *    **  *   *  * *** ** **   lettera;
******** ***** **  *   *     letterb;
  **   * * ****  * * * **  letterc;
* **     ** *  ** *   * ** *  * *  letterd;
 * ** *    ****   * ** * lettere;
*** * * ** * ***   ** 
   *** *   *    *   ** ** * * **** ** *  %c %c %c  ***** ****   **    * *** **  **  **  * * ** ** **  *    *  *****  
 * ** *********  *  *     **    * = lettera + 3;
   ***** * *** *  **  *****    **    = letterb + 3;
*  * ***    ** *    *  *   * = letterc + 3;
 ****     **  *    ** *    = letterd + 3;
 *** * *  **** * *  ** ** * = lettere + 3;
 ***** *    * **** **   ***   *  * * ****  * ***   
*** * *   *    * * *** ***  **** * %c %c %c ** ***   * *   letterb, ** * *  * **** *
*   ******  *   ***  ****   *
**  * **    ** * *   * *  ** * *  0;
}

***  
  **
    ****   *  * 
 *** 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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