[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.2k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ****      * * * *
#include    *  *   *   * 

/* run this program using the console pauser or add your own getch,  * ** ** **    * or input loop */

int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  *    * * ** *   
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int **    *  * char     *  {
/*
***       **     */

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a = a+3;
b =  * 
c = ** 
d = d+3;
e = **

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* * * ***     **  ** 
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
  ** **    *** *** *   ***
***   ***  ** *   *  

/* run this * *     * * the   ***    * or add your own  *   **  * * *     **   * or **** * * */

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}
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* *****    *    *   0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** * * *  **   * *  *

  *  *   * * ****      ** 
 
*        *   *    *        *    **    *  ** **  * * * * *** **  *  * ** **   

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*   * *   
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*  *
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* * * * * * **   
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int ** *  argc, char *  *** {
* *    * * ** char   * 
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       * **   **  * **** * *  input the letter to  * ***   *   *
*   **     ** *   
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* **   *  * *     ***   * =  * + 3;
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** *  ** *     *  =    * + 3;
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**   **   *  * * *  * =    *  + 3;
 *        *    
* *** *   **  **** *     **  * *** *         *       **** *   **** * **  
* *  *** *******  
*** *      *** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
       *   **  * ** **
*  * * * * *       *

int **    argc, char *argv[]) {
* **  * **  *  char ** **  
*  ** * ** *** char letteri;
 ****** *    **  char * *  *  
** * *  ** char *    *
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***      **  
**   * * ** ***    **       * *  input the letter to encode:  *  ***   *** 
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*** ** * *  ** 
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*  *  ***  **  
****      *  *  return 0;
}


INPUT
*  **  * *  **  * *
*** *****    
OUTPUT
*   *  ** *   ** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**  *  *  ***** ***  *
* * *   *  * ** *****  

int * ***   argc, char *  *  {
    ***  *   *    char    *  
*** * * * **   char **  
*  **         * ** char * *   
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*  ** * *  * *  * char    **
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**** * *  *    * **** * **** *            **  **** ** **  ** ***       * * *    ** ***  *   * *  *   *  
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* *          ** letter = letter + 3;
    ** *    * *** *** = **   ** + 3;
** *  **  ***      * *  =  *** + 3;
 ******* *     *** * =    * * + 3;
* ** *   *    ** * *  = * ** + 3;
 ******  * **** * 
*      **  **** *   * *       * letter is *  * *    **    **    ***   ***  *****  * ****
*  * * ** * * 
 * ** * *  ***   return 0;
}

INPUT
 * ** *  *** ***** 
   ****   **  
   **
*   **   * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include    *  **   *   ***

int main(int argc, char *argv[]) {
  * *** ** *   * * ***  * ** * *  lettera;
  * ******   ****    ***  * letterb;
*** **  ***********  ****     letterc;
*        ***   *    ** **  *   letterd;
 *** *** * *  ** *  * ** ** lettere;
*  *   **** ***** *    **
 * *******  * * **   **    **   * %c %c %c  * ** *  ** * **   **** *  *   *  * **  *    * *     *     **   *  ** 
* ***       ** ** **  * ****      = lettera + 3;
  * ** ***    **   * * ***  = letterb + 3;
* *** * **** * * ******     *  = letterc + 3;
 *  * ***   **    *  ** ***    *   * *  = letterd + 3;
** ***  ***  ***** * *  *  ** *** *  = lettere + 3;
        *    ** ***    **      ****  *  * *** ***     **
         * * ** * **  ******   ** * ***   %c %c %c  * *****  * *** letterb, * *  * **** ** *  * *  
**  ****   *******   **  **
    **** *  *   **    * ****   **  0;
}

*** **
** * *
    **     *
* ****
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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