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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[練習] Coding (C) - 最新提問 分類:Chapter 2: Syntax structure of the C language | 用戶: (5.9k 分)
ID: 26955 - 從幾時開始: 無限制 - 到幾時結束: 無限制

修改於 用戶: | 6.4k 瀏覽

22 個回答

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內容已隱藏
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
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** ***** ** * * * *** ** * **** ** * * * * **
**** ** * *** **** ***** ** 0;
}
100/100 最新回答 用戶: (244 分)
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
#include ** ******* *** *
int main(int argc, char *argv[]) {


** ** ** * * ** char a;
** ** ** * *** * * b;
* ** ******** ***** ** * ** * ** c;
* * * * ** * ** *** ** d;
* *** * **** ** ** e;
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* * ** * ** return 0;
}
100/100 最新回答 用戶: (221 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
int main(int argc, char *argv[]) {


* * ***   char a;
* * **** * * *** * ** * * * b;
** *** * char c;
*** **** *** ** * d;
**** * * * ****** * ** * e;
* ** ** *** **** ***** * **** ****  
    * ***** %c %c %c %c * * * ** * ** * * * * * * **** ** ***
* * *  
    * * ** * * ** ** * * *** * * *** ** * ***** *** ** ** * *
** ** * * ******* * ***
* * *   * ** * * ** ** **
* *** * * ******* * ** *
** ** * * * ** **
*** * * ***** ** *** * *
**** * ** * * ** *** ** *** * *
** ****** * ** * *
* * * * * ** * 0;
}
50/100 最新回答 用戶: (244 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'
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內容已隱藏
**** ** *** * **

*** ** ** ** * * {

** *****
= ** **
* = * *
= **
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* = *** ***

e = *
** = ** *
* =
* = *

* *
****
* * * *
* *
*

** * ** * ** ** *
100/100 最新回答 用戶: (183 分)
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
* * *****

** * * * {

* *
** = * *
= ** **
= * **
= ****
* = * ******

e = *
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****
** * * *
*****
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* ***

* * *** * *** * **
100/100 最新回答
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include *** * **
#include * ** ** ** *

int main(int argc, char *argv[]) {
** * ** * *** * * letterj;
* ** * * ** ** **** * letteri;
* * * ** * ** ** *** *** ** letterm;
**** **** * *** * * lettere;
* *** ** ** * ** lettern;
* ** ** ** ****** * ** *
* * * * * ** * * ** ** * * input the letter to encode: ");  
** * ** * ***** * ** *
******** * ** * ** * ** * * ** *** * &letterj, *** * ** &letterm, ** * * ** *
* * ** ** * * ** * +3;
** *** * * ** ** ** * *** +3;
* **** ** *** * * * * **** * * *** +3;
* * * ** * *** * *** * ** +3;
**** * * ****** * * ** ** +3;
**** ** ** * ** * *** *
* * ***** *** ** ** *
* * *** * * * * ***** * * * * *** * ** * * * lettere, lettern);
* * * * * ***** **
* * * * * * * * * * 0;
}


INPUT
**** ** * * * **
* * *** * *
OUTPUT
* *** ***
100/100 最新回答 用戶: (243 分)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
0 喜歡 0 不喜歡
內容已隱藏
* * * * * *

int * * argc, char * {


** *** * ** char a;
*** * * * ** ** * * * * * ***** * char b;
** * ** * * **** ** *
***** * * * ** *** * ** ** * * * * ** * *
* * *** ****** *
** ** ** ** *** the *** how??
* ** * *
* **** * ** * * * * * ** * a,b);
* * * ** * ****
**** * *** ** ** 0;
}
50/100 最新回答
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * * * **

int main(int argc, char *argv[])
{
* * * * * letterj;
* * ** * ** * * ******* letteri;
** *** ***** * * * ** *** letterm;
*** *** * * * ** * ** ** lettere;
***** ** ** * * ***** lettern;
* * **** *** **
* *** ** *** ** *** * ** *** **** * ** * input the letter to encode: **** *** * *****
*** * * * ** ** * *** ****** ** ** * * * * * *** * ****** ** * * ** ***
*** * * ** **** **** **
***** ****** * *** * * * * * = letterj +3;
* * * **** * * ***** = letteri +3;
* * ** * * * ** * * ** * = letterm +3;
** ** * * ** ** * = lettere +3;
* * **** * ** * ** *** = lettern +3;
* * ** ** **** *** *
*** * * * ** * * * ** * **** * * * ** ** *** * lettere, lettern);
***** **** *** ****

*** ** ** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
* ** * * * **

*** **** * * * ** {

* ** **
* = * **
= * * *
i = * * *
= * **
= * ***
e = **
= * *
* = ***
= * *

* **
* **
* * * *
**** **
* * *

* *** * *** ** * ***** * *
100/100 最新回答 用戶: (283 分)
修改於 用戶:
0 0
prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.
0 0
prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include *** * ** * ** *
#include * ** * * *

int main(int argc, char *argv[]) {
* ** ** *** * ** * * * letterj;
* * * ** * * * *** * letteri;
** ***** * **** *** ** * * letterm;
* * **** ** * * **** lettere;
*** * * *** *** *** ** * ** lettern;
* * * ** * * ** *** *
* *** * * * ** * **** * * * ** input the letter to encode: * *** **  
** * * * * * * * *** *** *** * **** ** * ** * * * *** *** * * * * ** * * * * * ***** ** ** *** ** *
* ** ***** * *** *****
* *** * ** * letterj = letterj +3;
* ** * * ****** ** ** * ** = letteri +3;
***** ** * ** * **** * = letterm +3;
** ***** ** ** * * * * = lettere +3;
* * * * ********* * * * * * = lettern +3;
* ** * * ** ***
**** * **** ** * * ** * ***** * * ** *** *** ** * ******** * **** lettere, lettern);
* *** **** *** ***
* ****** **** ** * ** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
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[正常] 開放式問答 - 最新提問 12月 12, 2017 分類:Chapter 2: Syntax structure of the C language | 用戶: 許哲瑋 (449 分)
ID: 37081 - 從幾時開始: 無限制 - 到幾時結束: 無限制
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