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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[練習] Coding (C) - 最新提問 分類:Chapter 2: Syntax structure of the C language | 用戶: (5.9k 分)
ID: 26955 - 從幾時開始: 無限制 - 到幾時結束: 無限制

修改於 用戶: | 8.6k 瀏覽

22 個回答

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內容已隱藏
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
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* * * * ***** * ** ** * * *** ** * * *** **** * ***
***** **** ** ********* * 0;
}
100/100 最新回答 用戶: (244 分)
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
#include ****** **
int main(int argc, char *argv[]) {


* * * * char a;
* ***** **** *** * * * b;
** ****** ** ****** ** c;
** * * *** *** ** * ** d;
* ****** *** * * * e;
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* ** * * *
* * *** return 0;
}
100/100 最新回答 用戶: (221 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
int main(int argc, char *argv[]) {


*   char a;
* ******** * b;
* ** *** * *** char c;
* **** * *** **** * * * d;
* * * * *** ***** e;
* * *** *** * * * * *** *  
    * * *** %c %c %c %c ****** * * ***** * * ** *** ** ** *
* * *  
    *** * * ** ** * ** * ****** * **** * * * * * * ** * * * *
* * * * * **** *
* **   * ** *** **** ***
**** ** * ** * * * * ** *
** * * * *** ** ** *
***** * **** ** * * *
** * * *** ** * *** * * * **** *** *
* ** * ***** * * ** * *
* ****** **** 0;
}
50/100 最新回答 用戶: (244 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'
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內容已隱藏
** ** * ***

* * ** * {

** * *
= * **
= * * **
* = ** *
= * *
* = ** *

e = *
* = *
= ****
* = * *


***** **
*** * ***
*
****** *

** * * ** * ** **** *
100/100 最新回答 用戶: (183 分)
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
** * * * ** * * * * *

* * * **** * * ** * {

** *
= *
* = ***
* = * *
* = **** *
* = ** * **

e = *
= *
= *
* = * *

* *** **
* ** *
* * *
* **
** ***

**** ** ***** *** ** * *
*
100/100 最新回答
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * ** * *
#include * * * * *

int main(int argc, char *argv[]) {
** ** *** **** * *** **** ** letterj;
*** **** ** * ** ***** ** letteri;
* ***** ** * *** * * * letterm;
* ** * ** ** * ** ** * lettere;
***** ** *** * ** * ** lettern;
** ** ** ** * ** *****
******* **** *** * ** ***** * * input the letter to encode: ");  
*** * ** *** * * ** *
**** ** ** * * *** ** * * * ** *** &letterj, *** ** ** &letterm, * ** *** * * *
* * ** * * ** ** * * * +3;
* ** *** * * * ** ** ** * * +3;
** ********** ** ** ** * * * * ** +3;
*** **** * * ***** **** ** * * ** * +3;
* ******* **** **** * ** +3;
** * *** * * ** *
**** * *** *** ****
* ** * *** * * * **** ** * **** ** *** * * * * ** * * * * lettere, lettern);
* * ** **** ****** ** *
* ** *** * * ** ** 0;
}


INPUT
***** ** ** **
**** * * ****
OUTPUT
*** ** * **** **
100/100 最新回答 用戶: (243 分)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
0 喜歡 0 不喜歡
內容已隱藏
** * * * * * ** *

int **** argc, char * ** ** {


** * * * * char a;
** * ** ** **** **** *** ** * * * char b;
* *** * *** * * * ** * **
**** **** * ** *** * * * * *** * *** **
**** * *** *
* * ****** * the * * how??
* * * * * *
**** * * ** * * ** * * * * a,b);
**** * * * * **
** * ** *** 0;
}
50/100 最新回答
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include ** *** *

int main(int argc, char *argv[])
{
** *** ** * * * letterj;
** * ****** ** * ** * **** * ** letteri;
** * *** **** *** * * ** letterm;
* ** * ** * *** ** * *** lettere;
***** * * ** *** **** ** * lettern;
* * ** * * * **
**** * * ** * ** * ** input the letter to encode: * * **** *
** ** * * ** ** * ** *** * * * * * * ** ** * ** * ******** ***** * ** * ** * * ** * ****
* ** * * * * * * * *
** * *** ** ** * * * * = letterj +3;
* * ** * ** **** = letteri +3;
* * * * * ***** * **** * ** = letterm +3;
** ** * * *** * *** * ** = lettere +3;
***** * * * * * * * * ** **** = lettern +3;
******** ** * * ** *
*** * ** * * *** * ***** * * * ** ** * * ** *** * * ******* * lettere, lettern);
* ** * * * * * ***

** ** *** ** **** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
** * ** ** * **

* *** * * ** * * {

** * * * *
= ***
* = * * *
i = * ***
= **
** = ** ***
e = *
= **
* =
** = **

* ***
*** *
* * **
* ***
* **

** * * * *** * * * * ** * * *
100/100 最新回答 用戶: (283 分)
修改於 用戶:
0 0
prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.
0 0
prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * *** **
#include * * * ** * *

int main(int argc, char *argv[]) {
** **** ** ** * * ** letterj;
* * * * ** *** * ** **** letteri;
** ** ** * *** * ** * ******* * letterm;
** ****** * ** ***** * *** * lettere;
*** * ** *** **** **** * ** lettern;
*** * * ** *** * *
* * ***** * ** ** * ******** * ** input the letter to encode: * **** *  
** ****** ** * ** * * * ****** * * ** * * * ** ** * *** ** * **** * * ** *** * ** * ** * ** * * * * *** * *
** * * *** ** * **
*** * ** letterj = letterj +3;
* * * ** * **** * ** = letteri +3;
* * * *** ** ** *** *** ** = letterm +3;
* * ** ** * ** * ** * * = lettere +3;
** **** * ***** ** * ** = lettern +3;
* * * * ** ****** *** *
**** ** ** * ** * * ** * * * ** ** * * * **** * lettere, lettern);
* * ** ** *
* ** * ** * *** * ****** *** * 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
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[正常] 開放式問答 - 最新提問 12月 12, 2017 分類:Chapter 2: Syntax structure of the C language | 用戶: 許哲瑋 (449 分)
ID: 37081 - 從幾時開始: 無限制 - 到幾時結束: 無限制
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