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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[練習] Coding (C) - 最新提問 分類:Chapter 2: Syntax structure of the C language | 用戶: (5.9k 分)
ID: 26955 - 從幾時開始: 無限制 - 到幾時結束: 無限制

修改於 用戶: | 5.6k 瀏覽

22 個回答

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內容已隱藏
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
* ** *** **** * ***** * b;
* * * * * * * * ** * * c;
* ** ** ****** ** ** * d;
** *** * ** ** ***** * e;

** * * * * * *** ** *** * * ***** * *** * * * * *** *** ** ** * *

** ** ** *** ****** ** ** *
** ** *** * ** * * *****
* ** *** * * *** * * *
* * ** *** * * * * * *
** ** * ** ** *

* * ** * ** ** ** ** *** * * ***
** * *** ** * * *** ** 0;
}
100/100 最新回答 用戶: (244 分)
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
#include * **** ** ** *
int main(int argc, char *argv[]) {


** * ** char a;
* ** ** ** * *** ** * ** * b;
* * ** ** * ** * c;
** ***** ** * d;
* * * * ** *** * * e;
** * ** * * * *** * *** *
*** * * ***** **** * * * * ** * ** * * * *** * *
** * * * ***
* * ** * *** *** the message how??
* * * *
* ** * * **** * * ** * ** * * ***
* * * *
****** ** * return 0;
}
100/100 最新回答 用戶: (221 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
int main(int argc, char *argv[]) {


* ***   char a;
* * * * * * * ** *** * b;
* * * ** char c;
* ** ***** ** * d;
** * * * * ** ** *** * e;
*** * * * * **** * ** * *** * *** * *  
    * * ** %c %c %c %c * * * ******* * ** * * ** * ** ***
* ** **  
    * * ** * *** * ** ** * * *** **** * *** *** *** * *** ** **
*** ** * **** * * ***** * *
* ***   ** * ** * ****** *
*** *** * ** *** *
** * * ** **
** * * *** * ** ** * * ** *
**** *** * * * * ** ** * ** ** * * * * *
* **** *** * *** ** ***
* ** * * ** 0;
}
50/100 最新回答 用戶: (244 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'
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內容已隱藏
** * *** **** *

** * ** * ** {

*** **** *
** = *** **
** = **
= ** **
** = * **
* = * * **

e = * *
* = *
** = *
* = * *

****
** * *
* * *
* * *
*** ***

* * * * ** * ***
*
100/100 最新回答 用戶: (183 分)
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
* *** ** *** ** *

** * * * * * ** * {

* **
* = ** * **
** = * * *
* = * *
= ****
= *

e = *
* = *
* = **
= *

****
** *
**
**** * ***
* ** ** *

** * *** ** * * * * *
*
100/100 最新回答
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include **** ****** *
#include **** * * * ***

int main(int argc, char *argv[]) {
* * ** ** ** ** * * * ** letterj;
*** * * * * ** **** letteri;
** * ** * * * ***** * letterm;
* ** ***** *** * * *** * lettere;
**** * * ** ** * * **** lettern;
** * * ** * ** *** * **
** ** ** * * * * ** * * ***** ** ** input the letter to encode: ");  
* * * ** * * **
****** *** ** * * * * *** ** &letterj, * *** &letterm, *** ** * * ** * * **
** * ** * * ** **** ** * +3;
********** *** ***** * *** * ** ** * ** +3;
* ** * * ** ** * * * +3;
* ** * * * * ** ** *** * * +3;
* *** * * * ** * * * ** * +3;
* * ** *** * ***** **
** * * ****** **** ** *
* * * ** ****** ***** ** * ** * ** ** * * * * * lettere, lettern);
** * * * * ** * * **
*** ** *** * * * * *** ** *** 0;
}


INPUT
* * **** *
** * ** **
OUTPUT
* *** ***** * * * *
100/100 最新回答 用戶: (243 分)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
0 喜歡 0 不喜歡
內容已隱藏
** ** * ** ** *

int *** * argc, char * {


*** ** * ** char a;
* * ** ******* *** * ****** * * char b;
** * * * ** * * ** ***
** * * **** ***** ****** * * * ** * ****
* **** * * *
* * * * ** ** the *** how??
****** * * ** **
*** ** ** * * *** ** a,b);
**** * ** * *
** ** * ***** *** 0;
}
50/100 最新回答
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include ********

int main(int argc, char *argv[])
{
* ** ** * * letterj;
* ** ** * * * ** ** *** letteri;
* * * * **** * * *** *** letterm;
**** * **** ** ** * * * * ** lettere;
* **** ** *** * *** lettern;
*** ******* ****** * *** ***
******** *** * * * *** *** input the letter to encode: **** * *
* * * * *** *** **** * ***** ** ** * * ** * * ** ** *** **** ** * ** *
* ** * * ** ****** *** ** * *
** * * **** ** * * * ** ** ** = letterj +3;
* * * ** * * * * ** *** = letteri +3;
* * ** * * * ** *** = letterm +3;
* *** * *** ******* ** = lettere +3;
**** ***** ** * *** * ** * = lettern +3;
* ***** * ** * ** ** ***
* * * ***** *** * * * * ***** *** * * * ** * ** lettere, lettern);
* * * ******** ** * * *

* *** *** *** ** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
* * * * ** *

* *** * **** * ** {

**** *
* = ***
= * ***
i = *****
* = ** *
= *****
e = * *
= ****
= *
= *

*
****
***** *
** **
*****

* *** * * * * ** ********
100/100 最新回答 用戶: (283 分)
修改於 用戶:
0 0
prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.
0 0
prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * * * ** *
#include * * * * * *** *

int main(int argc, char *argv[]) {
* * ** ** * * * ** *** letterj;
* ** ** * * ** * letteri;
*** * * * * *** * * * * letterm;
***** * ** *** ** *** ** lettere;
** * * ** ** * ** lettern;
* ** * * *** * ** * *
* ****** * **** ** ** ** * * ***** ** * ** input the letter to encode: * **  
******* * **** * *** * * *** ** * **** * * *** * * * * * * * * ** **** *** * ** ** * *** * ** * *
*** * ** *** **** *** * **
** *** * * ** letterj = letterj +3;
* *** ** * ** * ** * *** * * = letteri +3;
***** * * ** ** = letterm +3;
****** *** ** * * ***** = lettere +3;
* ** ** * * * ** *** *** = lettern +3;
********* * * * *
* ***** * * **** * * *** * ****** **** * **** * ** * * lettere, lettern);
* * * * *
** ** ** * * * * * 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
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[正常] 開放式問答 - 最新提問 12月 12, 2017 分類:Chapter 2: Syntax structure of the C language | 用戶: 許哲瑋 (449 分)
ID: 37081 - 從幾時開始: 無限制 - 到幾時結束: 無限制
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