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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[練習] Coding (C) - 最新提問 分類:Chapter 2: Syntax structure of the C language | 用戶: (5.9k 分)
ID: 26955 - 從幾時開始: 無限制 - 到幾時結束: 無限制

修改於 用戶: | 7.3k 瀏覽

22 個回答

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內容已隱藏
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
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** ** * * ** * *** * * ***** *** * ****** *
*** ** * ** * ** * **** 0;
}
100/100 最新回答 用戶: (244 分)
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
#include * ** * ** *
int main(int argc, char *argv[]) {


* * * ** *** char a;
* * * *** * ** ** * * * b;
* *** ** * *** * * c;
** ** * * ** * * *** * d;
*** * **** * * ** **** e;
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}
100/100 最新回答 用戶: (221 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
int main(int argc, char *argv[]) {


* ***   char a;
* *** **** ** ** b;
* *** *** ** char c;
** * * * *** ** ** * *** d;
** * ** *** **** *** e;
*** ** * ** ** * * *** * * * *** *  
    * ** ** %c %c %c %c ** ** * * *** * * ***** *** * * * ** * *
**** *  
    * ** *** ** ********* * * * * *** * * * * * ** * **** **
* * ** * *** ** ** **
* **   * * * *
*** ** * ***** * **
* * * *** * * ** * * *
* ** ****** * * *
** **** *** * ******* ** ******* ****
* * ** ** * *
* ***** ** * ** 0;
}
50/100 最新回答 用戶: (244 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'
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內容已隱藏
*** ***

*** *** * ** ** {

* **
** = * ****
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* = * * **
** = **

e =
* = * *
= *
* =

* * *
** *
***
****
** ** * *

* * ** * * ** * * *
100/100 最新回答 用戶: (183 分)
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
* ** ** ***** *

** ** ** *** {

* * * **
** = ***
* = ***
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= * * *

e = *
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* = **
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** *
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* ** * * ** * ** ****
100/100 最新回答
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include ** * **** *
#include ** *** **

int main(int argc, char *argv[]) {
**** ** *** * **** ** letterj;
**** ** ** *** * * *** letteri;
** * ** * ** * *** ** ** letterm;
* * * * **** ** ***** ** ** lettere;
***** * *** *** * * lettern;
** * * * ** * **** *
* ** ***** * ***** *** * ***** ** input the letter to encode: ");  
***** * * ** *** * ** *
**** ** *** ** *** * ** * * * * * * ** * * &letterj, ** ** ** * &letterm, * *** * * *** *
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** *** ** ** * ** ** * +3;
***** ** * * **** * ** * +3;
** * * *** * * *** * * * ** * +3;
* ** **** **** ** * *
* *** * * ** ** ***** *
* ** *** * * ** * * **** *** ***** * ** ** **** * *** lettere, lettern);
*** * * * * *** *
** * *** ****** * **** ** 0;
}


INPUT
* *** *
*** * ** * *** *
OUTPUT
* **** *** * ** **
100/100 最新回答 用戶: (243 分)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
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內容已隱藏
** ** * * *

int **** argc, char *** {


*** ** *** * char a;
** ** ** **** ** * **** ** ** ***** char b;
* ** * ** ** *** * * * * * **
* *** * * * * ** **** ** * ****
****** *** *
* * ** ** ** the * * how??
** *** ** **
** ** ** * ****** * **** ** a,b);
*** *
* * ***** ***** *** 0;
}
50/100 最新回答
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include ** * ** * *

int main(int argc, char *argv[])
{
* * ***** letterj;
*** * *** **** ** ** **** letteri;
** *** *** * ** ** letterm;
* * *** * ****** lettere;
** * * * * ** ** * *** lettern;
* * * * * * *
****** * *** * * * * * * ** * *** * input the letter to encode: ** * ** *** *
***** * * ** ** ** * ** ** **** * * * * ** ** ** ** * * ****** * * ** ** *** * *
** **** * * **** * * *
** ** ** *** *** *** * = letterj +3;
** ** **** * **** * * ** * * * = letteri +3;
** * * * ** ******** ** = letterm +3;
** ***** * * **** **** **** ** = lettere +3;
* *** ** ** ** ** ** * = lettern +3;
**** ** * * * * ** *
* * ****** * ****** * ** *** * * * *** * ** * *** * lettere, lettern);
*** * ***** * ** * *

* **** * ** *** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
** ** ** ***

** * ** * * * * * {

** ** *
* = *
* = ***
i = *** **
= **
= **
e = ***
= ***
= *
= *

* * *
* *******
* *
******
**** **

* ** * * *** ** ** * *
100/100 最新回答 用戶: (283 分)
修改於 用戶:
0 0
prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.
0 0
prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
#include * * * * *******
#include * * * * ** **

int main(int argc, char *argv[]) {
*** ** * **** * * * letterj;
*** * *** * * ***** ** letteri;
*** **** * ** * * * * * * letterm;
* * *** ** *** **** lettere;
* * * * * * * * lettern;
** **** ** *****
**** * **** * * * *** * * * input the letter to encode: ** *  
* **** * ** * *** ** ***** ** ** * * * *** * * ***** * *** *** ** ** ** * ** * * * * ** *** ** * *************
* ***** *** ** * * * ** * *
* ** * letterj = letterj +3;
* *** ** * * ** * * * = letteri +3;
* * *** ***** * ** = letterm +3;
*** * * * *** * * **** * = lettere +3;
** * ** * *** ** * * = lettern +3;
* * ****** * *** * *
** **** ***** * * * *** * * ** * **** ** * * **** ** ***** lettere, lettern);
* * * * * **
* * * ** * * ** * ** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
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[正常] 開放式問答 - 最新提問 12月 12, 2017 分類:Chapter 2: Syntax structure of the C language | 用戶: 許哲瑋 (449 分)
ID: 37081 - 從幾時開始: 無限制 - 到幾時結束: 無限制
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