[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.8k views

22 Answers

0 like 0 dislike 
Hidden content!
**  * **** *    ******  *

int  *  * argc, char  ** *** {
*** *** ***       *       */

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***   * ** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ****  *   **  
#include **** * *   ***

/* run this program using the console pauser or add your own getch,    ** ****** **** or input loop */

int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  * * **  * *  **  * 
*   ** *** *    ******** 

int  **    *   char **    {
/*
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b =  
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
  ***   *      **  *
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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* ****   *     *  *  * 
 
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*
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* * = d +  

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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*    **    * * *   ****  *
*  *  ***    * ****

int  *  *** argc, char  * *** {
 * *  * **  ** char    
* *    ** ***   * char    * *
***  **  * *  char  *
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*  **   * ** *   = *** ** + 3;
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* ****** * **   letterc =   * *  + 3;
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***  **** * * ** *** * *  *  ****    * ** * * **  *  **    ** **  *  * **       *
      *   *  
** * * * **   return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  ***    *  *  *  *** 
 ** **    **** *  * *  *

int   *   argc, char *argv[]) {
 *  *    *****  char   *** 
******   ** **  * char letteri;
*   *  *  **  * **  char *  ** 
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*** * *  **    char *  *  
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***    *  **    ***  *  * +3;
*  **   **    
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 **     *     
*** *    *   return 0;
}


INPUT
**    * *  ** ***
 **  ** ***
OUTPUT
*  ** *** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
** *  *  * * ****  
 ** *  *  *  *    **  

int ***** argc, char ** *   {
 ** **** ** **** char *** * *
 ** **** *** **  char *  * *
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*  **    *** char   ** *
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* ***      * ** 
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*    ***   **   **  
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* ** **    * 
*   **  ** *** letter = letter + 3;
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***   * *  * *** = ** *  + 3;
  * *   ** * ** *     ** = * * *   + 3;
* ***    * **    * * =  *   + 3;
 **   *   **   
******* *   **** ****  * ** *   **    letter is      * ** * ** * ***    * ***   ****  * *** 
 **       * **** 
     * *  ******  * return 0;
}

INPUT
*** *   * ***  * * 
   * ** * *   ** 
  
***** * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ***   **  * * **

int main(int argc, char *argv[]) {
  ******   * * *  *  **   * lettera;
      **        *    *** *  **** letterb;
*         *** *    *  * *******  letterc;
*** **  **   * * *     * * ****  * letterd;
 *   * * * ***  *** **    **   * * lettere;
 * * *   ** ** *****     
*    **   ***   * * * * * *   **** * **  ***  %c %c %c  **   * * **     *  ** * *          *   **   *   *  **      *    *****  **** 
 ***   ******* * ***   *  *  **  = lettera + 3;
* ***** *** ** *****  * *     = letterb + 3;
 * **  **  ***** **    *  * = letterc + 3;
** * **   * * * **** ** ***  ** = letterd + 3;
      * *   * * *  **** **  * = lettere + 3;
  * *    **    *  * ** *  **** *** *  * *****  **** * *  * ***  *  *
  * **** ** ****   ** *  *       ***** %c %c %c    *    *  ****  letterb, **  **    ***  *   * 
      ****   *   * *   
**   **  *  **  *   * *    ** *  * 0;
}

 *    *
* *   *
***   **       *
 ****  
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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