[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.9k views

22 Answers

0 like 0 dislike 
Hidden content!
* *   *  **    * ****

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*  ** ***** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * **  ** *   **
#include   ** *   *****   

/* run this program using the console pauser or add your own getch, * **  *  **    ** * * *   or input loop */

int main(int argc, char *argv[]) {
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****  * *   * * **** * *   * 
      ****   *  *   ** **  *    0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   ****   ***   * ** 
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int **   * * char  **  {
/*
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b =   *
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*  * *** *  *  ***** 
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
** ** * * *       **  
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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ** * * * ** * **  *****
*
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*  = d +  
 
* *      *
 
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*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** *      **  *  ****
  *  **   * * *   ** *

int * ** ** argc, char     *  {
**  *  *      *** ** char   *  *
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* *  **  * *  **  = **** + 3;
*  *  * * * ** *    *** =  *   + 3;
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     **  * **  letterc = ***   + 3;
****     **  ****  = * **** + 3;
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*   ** *  * **   ** * **    *** * *****         **  ***   **   *    *   ** 
 * * * *  *** * 
  *  **  ****** * return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* ***    * ***********  
   *    ** * *   ***  

int **    argc, char *argv[]) {
*    *    * ***   char  ** 
** * ***  *** ** char letteri;
  ** ***  **  * char    * ***
 * ** * * * * char       **
***   * *    *****  char    **
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*  ** **  *** *   *    * * * ** input the letter to encode: * *****  *** * 
**** *   *   
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** *     *** ** ***  **** +3;
*  * *** ** ** 
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*     ** * ** *  
  * ***  * ** * return 0;
}


INPUT
** ** ** * *   *   
 *** *****  
OUTPUT
  * **** * ** **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   *   * * * *** * ****** *
 **  *    *      * * ***

int *     argc, char  * ** * {
*        * char * ** 
** * *  *  **   char *   * 
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* **     ** **    char    *
* *** * * * char  ** * 
 *   **   * *  
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    *   * *   
           *  *   ****  *** *   * * * * ****  * *  **  *  **  *  **** * ** **** ******* *  ***  **
******    ** *  
  * * * **  * * letter = letter + 3;
** **  ** ****  **   = * * * + 3;
*** *    *****  * *** = *   + 3;
* *   ** ** * *   =  *  + 3;
** * *****   *    **** = * **  + 3;
 **   *  **  **** 
 **  * ** *   *** *    *  **  ** ** letter is ***   * * ******  * **     *   **  * *  * 
**  *  **   *  
 *      ***   return 0;
}

INPUT
*  **  * *  **** *
* * *** ****    
*** *
**  **  * **  ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * *  *** **  *

int main(int argc, char *argv[]) {
  ***    *  ** ** **** ** ** lettera;
** **       *  *    *  *   letterb;
** ** ** ** *  **    *   **** letterc;
***      * ***   **** * ***   * *** letterd;
******* **  *   *    ** *      *** lettere;
  ***** **  ** **** *   * 
 *    ***  **   *** **       **** %c %c %c     *   *  * **   ***  * *     **      **  * ** ** * *  ****  * *    
* *** * *    *  * ***    * * *   * = lettera + 3;
  ******* ** ** *** * ** * *  ***** = letterb + 3;
*  * *  ****** *   *  * **  *  = letterc + 3;
** ***  ****  *    *   **    * = letterd + 3;
 **  *** ** **  *  *******   = lettere + 3;
* *  *    ** ** * *****       **   *** ****  **  *** *
     **  ** ***  **  * ** *  **   *   *** **  %c %c %c *   **  *   * *  * letterb, **   ***  **  *
 *    *          ** *  ** * **
* * *   * *   ******  *   * 0;
}

**   *
  * * 
         * ***
* *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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