[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 6.5k views

22 Answers

0 like 0 dislike 
Hidden content!
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** *** * ****  return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include **       * **  **** 
#include * ****  **** * * *

/* run this program using the console pauser or add your own getch,  *   *        * *** * or input loop */

int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *  *   **   *  *** 
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int  * *   *  char  *   * {
/*
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *    ** ***   *  *   **
* **** *    * ***  *  * *

/* run this *      **  the    * ***  or add your own * * *   * * ***  *  *      * ** or   * *  */

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}
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**       ** *  *  0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**   *  * *    *     *
 
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*
   * *   *  *  *     * **  *      *  *   *  ***   * *  **** *** * *    * **   ** *
 
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** = c +  

** = d + * 
*
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****
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *  **  **  **  * 
 * *    * ** ** * *** 

int    * *   argc, char    * * {
   * ** * * ** char  *** 
* *       *** char  *   *
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* ** *    *  * *  =   *  * + 3;
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**   *  * *  **  * * ** =   * + 3;
     **  *   
*******    * *     *  *  *       *** ** ** *  *   ** *    *  *  * *    ***
  * **   *   
**** * *   ***** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * * *          * ** 
  **  *    *  ****** *  *** 

int  **** argc, char *argv[]) {
*  * **    *    char *** 
***  *  * **  char letteri;
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**      * char   *** *
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  * **  * return 0;
}


INPUT
  ***   *** *** ** *
*** *   **** * 
OUTPUT
  * ** *** **  *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* *  * * *   ** **** 
  ***       *   *   * 

int     *  argc, char  ** * {
****  ***  char    *
*  **     * *  char *  
** * *   *  *** char **** 
   *     *  * *  char * * 
     **  ** *  char  * 
**  * * *  *    
    *      ***  ****  **  * input the     to    * *  ** * *  *  ** 
 ***     **   * 
* * * * * *    *  *  ***  ******* **  ** * * *    ** **** * **   * ****   **  *    *  ***   ****     *
* *     ***** 
 **   *  ** * *  letter = letter + 3;
 ***   * *****   * * =  *   + 3;
*     ****  **  =     + 3;
 **      * **  *  *   =  *** + 3;
* *  *     *  *** = ***   + 3;
***  **  **** 
**  *   * ** *     ***  ****       ***** letter is ** * *   *****   * **  *      *  ** *    *    
**     ** *   
** *   * *** **  return 0;
}

INPUT
* ** * *   * *  *
**  **  * **  
 ****
**** * *****      *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   ***  *** * *

int main(int argc, char *argv[]) {
   ****** *** ***** ** **    lettera;
 *** **   ** *  ** ***** ** *   letterb;
**  *     ****      ***  *** *   letterc;
**  ***  *      * ** ***** ** * ** letterd;
* ***** * ** *  *****   * * * lettere;
** **  * *** ***   * * *    *  * 
*****      *  *     *  * ** * *** * *    %c %c %c * *** *  *   * * *** *  *** *  **    *      * *  ***   *   ** *** ******  
 **    ** * **** ** ** *    ** = lettera + 3;
  ** ***    ****  * **  * *    = letterb + 3;
  *    ** ** *******   ***    = letterc + 3;
 *   *  ** **  *   ** *   ** *  * ** = letterd + 3;
  *  **   ** **  *   * ***  = lettere + 3;
   **   ** * *     **   ****  *     ***  *      ** *
 *  *    *   * * * * * ** ****    *** * * %c %c %c * **  ***   * * letterb, **    * *  **   **
 * * * *** **   *  ****
**     ***    *** * **  ****  ***  0;
}

  ***  
*     **
 *  *  ** **
 ******
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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