[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 4.3k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  *** **   ****
#include * **   * * * *    *

/* run this program using the console pauser or add your own getch,  *  ** **** *  *  ** or input loop */

int main(int argc, char *argv[]) {
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* *    * * ***   *****    *   **  
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *   * *  ***  ** *
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int  ***  ** char * *  {
/*
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
****  * ** ****  * *  *
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/* run this  *** *  **   the  * * *** or add your own  * *  * *  ** ** *   * *** or *    * */

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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  ** * **       * **** *
*
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** = c +   

* * = d +  

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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** * *  *  *  * *     *
 ****    ****   * * * *  

int   **  * argc, char  **   {
 **  *    **   char ** ***
**   *     * ** * char   * **
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**   **   * * char  * *
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*  *   * ** *   ** **   *   input the letter to * *  ** ******
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*   *  **** ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *   *     *   * 
** *     *    * ***  *  

int  * **   argc, char *argv[]) {
    **   **  * * char  *    
       * ** ** * char letteri;
 *  **   *** ** *  char  *  
* * *     *  *  char  *    
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* *****  ** *     
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* **** ** *  **** 
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** * ***   *** ** **  ***   * +3;
*  *   * **     *    ** ** +3;
*      *  * * *** ** ***  +3;
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** **  ***  *  * ** * * **** +3;
* *  *** *     ** 
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 * ***    * *   return 0;
}


INPUT
 ***** *   **    *
*   *** * ***  
OUTPUT
* *  * **  ****
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  *  * * *** **   * **   
 *          ********  **

int    **  argc, char  *   {
*   * **     ** char * **
** *  **   *****  char ** **
 **  *  ** * *  char ***  * 
** ** **  ***  char **  
** * *     *   * char    ** 
  ****  ** * 
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**** ***  **  * * 
* * * *  *** *   **   ****** *     * *****          ** *** ***  * **   *** **** ** **    * * *    ** **     
 *  ** **     * * 
*  ***** *     letter = letter + 3;
** *    * *   *   ***   =   *  *  + 3;
* * **  *    ***   = *   * + 3;
 * *  **  **  **  ** =       + 3;
  * ***  *  * *     = * *  *  + 3;
 *     * * *  * 
    **  ** *     *  ** *   *  * * * * letter is   *     *    * *      * ** * * *  ****     *  *
* **   *    ** 
* * *  *** * * return 0;
}

INPUT
*    *  *** * *
* **  **   * 
** 
   ****   *  * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  *  **    *  * **

int main(int argc, char *argv[]) {
 **   *      **** * * *  **** lettera;
 *  * ** * ** ***** ** ***  ** ***** * letterb;
*   ****    * ****  *  *   letterc;
* *   ***  * **  **  * ***  **  letterd;
   *** * ** **  *    ** * *** *  lettere;
***  *** **  *   *   ** ***
**   *  *    * *  **  ******           * %c %c %c ** * *      *  ** ***   * ** *   **  ** *   **    ***       ** ***  **   
* *  *  **       ** * *  **    = lettera + 3;
***  *  *****  * * *     ****    = letterb + 3;
 * *  ******* * * ****  * ** * *  *   = letterc + 3;
**** **   *  *    *     *  *  *  = letterd + 3;
         *   *  *** ***  *   = lettere + 3;
*    * ** * **  * ***      ******       *    ** *  **      * 
  *   ***   *  ******   * ** ***    *  %c %c %c   ** *      *** letterb, *      * * **    *   
 * **  *** * *   **  *  ***
            ** *** **  **  0;
}

* **
 ****
  ***  ***   *** 
* * **
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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