[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 10k views

22 Answers

0 like 0 dislike 
Hidden content!
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 *** *   ***     return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * *  ** *  * ***
#include  *  * ** 

/* run this program using the console pauser or add your own getch,   *      *    *** **** or input loop */

int main(int argc, char *argv[]) {
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****    ** * *** * *    ** * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  **  *    **  *  *   
****** *  * ** ** * * 

int *** ** *  char *  ** {
/*
**** * *  * */

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a = a+3;
b = * 
c = * *
d = d+3;
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***   *** *** * ***
****  * * *    ** **    *  * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 **  * *   ***  ** *   **
 *** ** * **  *    *** 

/* run this     **   the  ***    ** or add your own  **    * **** * **   * or      */

int **  ** *  char * *  *  {
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*    *  **   **   ***   **  ***
}
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 *       ** * *** * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*    * ** **    

   *  * *   ***** *** *  *
 
** *    *  **      * * * *  * *   ***    ***  **  **  *  ** ***** ** *    *** **
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*  = c +  *

** = d + * 

      *  
*
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  * * *
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  * * *    *   *   *
**   ** *  * ** ** **  *  *

int  * *  argc, char **   *  {
 **   **  *** char  *   *
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*    *   * * **   * ***    *  ** input the letter to ***  ******
** *     *  * **  
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** * ** *  * * *    * * = *  *** + 3;
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*  ****   * *   *  ** = ****  + 3;
******    * *   letterc =  **  * + 3;
*    **  * *** ****  **  * = * * *  + 3;
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* *  ***  * **     ***   *  **  *******  **  *   * ****    *** *  * ***** ****   
* *  *** * * **   
 *   **  * * * return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *  ***  *** *    * *** *  
* **  * *****  **  ***

int **    * argc, char *argv[]) {
*  *       ***  char  ** ** 
**   **  *  **    char letteri;
 ***   ** ****  char ** 
** ** *  *   *   char * **
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*  ** * * *    
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** * **  * *  *   *    ** *****  * ***  ****   ***   **       ******    **    * **** ** *  *  *** *   * *      
** **         **  * * *** * +3;
** ** *  *  * *   *******  * +3;
*   *  *** *** *   *** *  +3;
*   **  *** **     *   ** +3;
* ***  *  *    *  ***    * +3;
** *  **    *  
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 * * ***   ** ** 
****   **  return 0;
}


INPUT
  **** *   ***  
* *   ** ***  * *
OUTPUT
    *       * *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
***  *  * *    ** **  *     
    *    * *   ** **  

int *  **   argc, char         {
* * *         *** *  char     * 
* ***      * *   char  * * *
     **   ****  char  ***
 **     *** ** char ** *
    * **   * * * char * * * 
   **    **   * 
* *** *  **    * * ***  ******** input the  *  to **  ** ** **  ***   
 * * ***** ** * * 
**    *  *     *****  ** * ** **   *** ****  * *   *  * * *      *  ****       ** * *    * *    ** *
 * ***   *  * 
 * *  *   **  letter = letter + 3;
 *** * ***** *     * ** =  * * + 3;
*** *   *** **   = * * ** + 3;
 *  *      **     *** = **** + 3;
 * *  *** **** * *  ** =    *  + 3;
* **         * * * 
** * ***   ** **     *   ****** ***   **   letter is ******  ** *  ** ** ** *    *  **   ****      *   *  *
 *    *   ** ***  
*  **  ****  return 0;
}

INPUT
      ** * **** **
***    **    
 ** * 
 *  **   * *  *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ** * * * **  * ***  

int main(int argc, char *argv[]) {
* * *  **    * * ***** * *** ** lettera;
** ***    **** *** ********** letterb;
  *********  * ** *  ***  * * letterc;
*  ** ****     ** ** **** letterd;
*  *   * *      *  **    **  lettere;
 ** ** * **    * ***** * * *  
  * ****  *  ***  ** ** ********* **  * %c %c %c   *  ***    * *    ** * *  ** ***  **  ***   *** * ***     **** ** *****        * 
 * *  *   **  * *** *  **  *      = lettera + 3;
** * *  **  * ** ** ****  * *   = letterb + 3;
 **   *    * *  *    * *    * *  = letterc + 3;
* ** * **** ***    ***  *        * * = letterd + 3;
*  ***   * *  * **  *  *** ** = lettere + 3;
  ** ****   * ** **  *    **   *  ** *      ***  *    *
   **** * *** *  ******     **  *    **   %c %c %c ** *  ***      ** letterb,        ***  *** *  *
 **   * **   ***  *** *  *
 *   *   * * **        * *  ** 0;
}

 * ** 
* * 
  ***      *    * 
 *  * 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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