3 like 0 dislike
6.3k views

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited

edited by | 6.3k views

22 Answers

0 like 0 dislike
Hidden content!
* *** * *

int * *** argc, char ** *** {
* * ** *** ** * ** */

*** ** int number;
** ** **** char a;
**** *** ** * * * * b;
* * * * * * * * * c;
** ** ** * *** *** ** d;
* ** ** ***** * * **** * * e;
* * * * * * *
*** ** * * * * * forgert how to shift word * * ** ***
* * * **** ** * ******* * ** * ** **** **** *** ****** ** * *** *** * *
* *** **
** * * * * ** the message how??
* * *** *
* * *** ** * *** * ******* * ** * **** ********
*** * * ** *
** ** * * * * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
* * ** *
*
* * ** * * ** * {

* * **
* = * **
* * *
= * *
* = *
* = ** * ***

* = *
* = **
= **
= *

* *
* *** *****
**** *
* * *
* * *
*
** * ** *
*
100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
#include *** * **** *
#include **** ** * *

/* run this program using the console pauser or add your own getch, * * ** * **** ***** or input loop */

int main(int argc, char *argv[]) {
** * ** ***** ** *** *** a;
** * ***** *** **** ** * ** b;
* * * * * **** **** ** * ** ** c;
* *** *** ** * * * d;
** ** *** * * * ** **** * e;
**** ** ** ** ** ** *
* ** * * ** ** * * * ** * * ** * * the words you want to *** * ** *
* * * * * ** ** ***
* ** * * * * * = getchar();
******* ** ** **** ** * = a+3;
* **** ** ** * * * ** *
* ***** * ** = getchar();
* * ** * * ** * * * = b+3;
*** ** * * * *** *****
* ** * **** **** ** = getchar();
** * * * ** * *** * * = c+3;
* **** * *** * ** * * *** **
** * * ** * ** ** ** * = getchar();
**** *** **** = d+3;
*** * ****** * ***** *
* ** * * * **** ** * **** = getchar();
** ** * ** ** * * *** ** = e+3;
*** *** ********** ** * *
**** **** * * ** * *** * * * * * * ** **
** ***** * ** * ***** ** *** * ** ** * **** &a, &b, &c, &d, ** * *
** ******** ******** * *
* **** *** * * ** * the message how??
* ** * * **** * **** *
** ** *** ** *** * * *** *** * * **** * *** a, b, c, d, e);
* ***** ** ** ****
***** * *** * ***** * ** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
1 like 0 dislike
Hidden content!
* *** * *** *** * **
** * * * *

int **** * * ** char ** * {
/*
* ** * * * */

* **

***** * * ** ** *** * *** ** * * ***** * *** *
a = a+3;
b = * *
c = ***
d = d+3;
e =

** ** the *
** * * * * * *
** * * * *** ** * ** * * **

* * ***** * **** *
* * * ******* * *** * ** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
* ** ** *
** * ** ** * * *

/* run this *** * * *** the * ** ** or add your own *** * * ** ** * ** or * * * */

int ** * * ** char * * {
* *** * * * int num, ***
** * ** **
** **
*** * * * *** ** ** * * ***
* ** * ** * * * for = **** * *
{
** ** * * = **
**** * *** if * * *** **
**** * * *** * * = * * ****
****** * * * * ** ** *
}
**** * * * ** ** *** **
** * * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
1 like 0 dislike
Hidden content!
* * * * * ***
*
*** * ***** * * *

** * * ** * * * * *** * * * ** ** * ****** * * * ** * *

** ** ** ** * *

* * *

** * * * * *
*
** * ** * ** **** ** ** * ** ** * * ***
*
= * *

** b + *

= c +

* = d + *

* *
*
* * ** * **** ** *** * **

* ** *

*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
0 0
That's correct.
1 like 0 dislike
Hidden content!
* ** *** ** **** * *
** **** * * **

int * ** argc, char {
* * * * ** char ***
*** ** * * * char * **
* * char *
* * * ** * char *
**** * * ** * char ** *
*** * *
* * * * * *** ** ** input the letter to * * ****** *
* * ** * *
* *** * * ** * * *** * * ** ** ** * ****** * * * * * * *** * * *
* ** *** * ***** = * *** + 3;
* * ** ** * ** = * **** + 3;
** * * = ** * + 3;
* ***** * letterc = * + 3;
*** * * ** * = * * + 3;
** ** *
* ** **** * * * ****** * * ***** ** * * * **
* * * *
* ** * ** *** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
1 like 0 dislike
Hidden content!
** * * ** *** ****
****** **** * *** * * *

int ** *** argc, char *argv[]) {
** * * ** ** * char * *
* **** * ** * char letteri;
* ***** * * * char * *
** * * * ** ** * char ***
***** * ** ** * char * **
*** * ** *
* * ***** * ** * * * *** input the letter to encode: * *** ***
* ** *
* * * * ** * * ** * ** ** * ** * ** *** ** ** *** * * **** *** * *
*** ** * * * * * * * * +3;
** * * * * * * *** ** * +3;
** ** * ** ** *** +3;
*** *** ** * ** * * ***** +3;
* * * * ** ** * * ** * * +3;
* * ** * **
* * * ** *
*** ***** * ***** ** * * * ** ** ** * * * *** **
* ** * * *
* ** *** * * return 0;
}


INPUT
**** **** * *
* *
OUTPUT
** * *** **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
** ** * ** *****
** *** * **

int * * argc, char ** {
* ** ** * char * *
* ** * * ** char ***
* *** * char * **
** * *** * char ****
* *** ****** char ** *
*** ** ** * * *
* ***** **** *** * ** input the * to * * ** * * * *
* *** ** *
* *** ** *** ** * * * * * * **** *** * * ** ** ** *** * **** ** **
* * ******
* *** * * letter = letter + 3;
* **** * * ** = ** * + 3;
* * ** ** *** *** * = * + 3;
* ** ** = *** + 3;
***** * * ******* * * * = * * + 3;
* ** * *
* * * **** * **** *** * letter is * * *** * * * * * ** ** ** * ** * * ***
** * ** ***** *
* * ** ** return 0;
}

INPUT
*** ** ** ****
****** ** **
* * *
* ** * *** * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
#include ** * *******

int main(int argc, char *argv[]) {
** * *** * * * *** *** * lettera;
* ** ** *** * *** * ** ** letterb;
*** * * *** ** *** ** * * letterc;
** ** * * * *** ** * * letterd;
****** * * ***** **** *** lettere;
* * ** ** *** ** ** * *
* ** * * ***** * * **** * **** ** ** ** %c %c %c * * **** *** * * * ** * * * * * ******* ***** **** **
* * **** ** ** * = lettera + 3;
* ** * ** * * ** * * ** = letterb + 3;
* * ** * ** * * * * * ** = letterc + 3;
** ** ****** * **** * ** = letterd + 3;
* *** * ** *** * ** = lettere + 3;
* * * * **** ** * ** ** * *
**** * * * * ** * ***** *** * %c %c %c * * * * * * * letterb, * * *** *****
* * ** **** * **
********* ** * * ***** *** 0;
}

* **

******* **
* **
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.62
©2016-2025

Related questions

0 like 0 dislike
2 answers
[Normal] Essay (Open question) - asked Dec 12, 2017 in Chapter 2: Syntax structure of the C language by 許哲瑋 (449 points)
ID: 37081 - Available when: Unlimited - Due to: Unlimited
| 955 views
12,783 questions
183,442 answers
172,219 comments
4,824 users