[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 4.7k views

22 Answers

0 like 0 dislike 
Hidden content!
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**   **     return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include     ****  **  * 
#include *  **  *** *      

/* run this program using the console pauser or add your own getch, * *   *    *** ****** or input loop */

int main(int argc, char *argv[]) {
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*  * *     *  * * * *  ** * *** d;
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*   ** ****   **  ** * ***  = getchar();
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* ****** *   ** *  ***      = getchar();
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*     *  *     *** *   ** *  ** **   0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**  ** *  *** *   ** 
* ** *      **     *** *

int  *    *  char  * * {
/*
**    * * */

*     * *   

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a = a+3;
b = ** 
c =  *
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*** ** **   *  *   * * * *** **   

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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
***  * ***   * ** ** ** 
**  * *  **** **  *** 

/* run this  *     *    the    * * **** or add your own *    * **   **  *    *     ** or  *  * */

int ****   *  char ***** {
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}
*  * * *     * *  *    **  ***   *   ** 
**       * *** *   *   * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**    *  ***  ***  * **

 ***** * **   ****  * **  
*
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* ** ***     **  *  ** ** *  * ** ** *** * * **  **    *       ***  

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*
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*  = c + 

*  = d +  *
 
*   * * **
*
**  *   ***  ***      * * ** * *       * **  *

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*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* * *  ** *** ** **  
*** **  *** *    * ** * 

int  ** * argc, char **     {
 *  ** * ** ** * char * ** 
  *   *  *** * *  char * * 
 *  *     * * char *   
**   *** **** * ** char ***** 
** *    **** *  char  **  
 *******  *** 
 *  ***  ** ** * **   *    ** *   input the letter to ** **  **  * 
*** **    * ** 
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*  *** * *** *   **   * =  *  + 3;
 ***** *  *** *  **   =   * + 3;
****  *  *  *** *   *  = *** + 3;
*    **  * *    letterc =  * *  + 3;
 *** *   ** * **   *    * = * * ** + 3;
****   * *** 
* ****  *  *    * * *  *** *    **   * ***   *  *     **  *    **     ** 
** ****      *     
 *   *       **   return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*    *  *  ***  * ******
* *   *  **  *  ***    

int  * * * argc, char *argv[]) {
  **** * * ** * char  * ***
  * *  * *  *** char letteri;
*    *   * **     char *  
 ****  *  * *    char * * *
* **      * ** char  *  **
*  *  ** *   *  * * 
    ** * * *** **  * ** *   *** ** input the letter to encode: ******  **  ** 
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*   ***  * ** **    * *  *  **   ***  *  * *  *  *  ******  * * * * * * *   *  ** **     **** *     
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*** * **  * ***  * ** ** +3;
* **  *  *  * ***  **** *  +3;
*  * * ***  * *  *  ** *   +3;
* ** **  ****  
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**  **  * * * ** ** * ***   *** * *  *  * * ******** *     * *  **** *
  *** *  * *** * 
******* ****  * return 0;
}


INPUT
**  * ***   *  **
*** * * * * **
OUTPUT
  * **** * **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   * *        ***** * **
  **  ***   * ** ****    

int   * * argc, char **** * {
* *  *    *  ** char *    
 ** *  *   *   char * ***
 *** *     * ** char * **
*    *  *  **** char  * **
  * *  *  ***  * char ** * 
  **  * *   ****  
**** ***  ****  * * * *   ***  ***  input the   ** to *  *   **  * * * ** 
*  **  *   **   
 *  ** ** *  *   ** ***  **  ** *   ** ** *** * *    ****  * * * * *        *  ** * * * ** ***   
** * *  **  * *   
** ***  **  letter = letter + 3;
  * **  * *** *    =  *    + 3;
 ***    *   *** *       =  * *   + 3;
****    *  * * *   ** =    + 3;
 ****            =  **   + 3;
 * * **   * * ** 
* **     * ***   ****   *  ** * letter is   ** *** ***  **   * * *  **   ** *      
***  * *** * * 
*  ***  **  * ** return 0;
}

INPUT
 **  * **  ****  *
*     * * *****
*** 
 * **   ****  ****
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *  **** *  ***  *

int main(int argc, char *argv[]) {
 ******   * ***  ** ******    lettera;
 **    **        * *  * *****  **  letterb;
  ****  **** *    *  ** **** ***  letterc;
   ***  *   *  *   **     * letterd;
****    ** *** **     * *  **  ** lettere;
**  **    ***    ** ***  *
**     ** **  *  ** **    *  *** ***    %c %c %c      **   ***        **  * ***  ***      * **    *   *   ** *    * * ** * * 
**** ***  **   * * ** *** ****  *  = lettera + 3;
   **  ** **  *  * * **  *** ****** = letterb + 3;
******** *   * *** * ** *** **** = letterc + 3;
   ***    * ** * *  *   ***** = letterd + 3;
    * *   *   **   **  *  * ** * = lettere + 3;
 *       **    * * ****   * **  **    **  *    *   
 * * *  * ****   * **   * *** ****  %c %c %c   * *  *   *   letterb, ***  **    * * * 
** ************** 
*** *    *   * ** ******    0;
}

* **   
 ****
* ******** **  
    
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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