[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.2k views

22 Answers

0 like 0 dislike 
Hidden content!
*** *   **    *  ***** *

int   ** ** argc, char  * ** {
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** * **   *     * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ** * * * ** * **  
#include  **  * ***** **    *

/* run this program using the console pauser or add your own getch, *  * ********    *   *   or input loop */

int main(int argc, char *argv[]) {
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*   * * *  * ** *****     *
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *  * *** ** * ***
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int **** *    char       {
/*
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a = a+3;
b =   
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** *  **** ** *    **
****   *  ***      **  **    *  ** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*     * *** *   ***   **
       *   * * * ****

/* run this  ** *   ** the   **   * *  or add your own   *  * **  * ***  ******   * * or       *** */

int * * ***   *  char ***   {
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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**     * ***   *****
 
   ** *       *     
 
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*** = *   

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** = d +  
 
        **

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*
**  * *

100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**** * **       ** 
**      * **  * ****   *

int  **  argc, char * * ** {
***   *  *   * char  * * *
** ***  *  ** * char  *** *
* ** *  *   *** char *** * *
**** ** ** **  char  *** 
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       * ****** * 
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*****  ****  
**   *** ** *** **     *  **    **  **  ** * *   * * *  * ***** ****  * *** ** **     ***  ****** * **   * 
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     *   *  *  *** = * ** + 3;
** ***    * *** *  * = ** + 3;
*  *** * * *  letterc =  ** + 3;
*  **   *   * *   *  *   = ****  + 3;
*     *** *** 
 * * * ***** *   **     ** * *  * * **      **  *** *     *    ** * ** **   
 ** *   ** **  
**  *   **  *  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* ***    *   * ** ****
  * * **  * * *   * 

int     * argc, char *argv[]) {
** ** * *  ****   char *  ** 
*   **** * ** char letteri;
   ** *   *  *  char    **
* **    **  **     char    
 *  *  **** char *****   
***    **** * **  
* * * ** * ***   **  **  *  **  *  * input the letter to encode:      **   * **    *
* * * **   *** 
   *   * *            * *   *      ****    **     ****  **** ** ****    ** *  *   **** **  **  **** **  * 
**       **   *****   *  +3;
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** * *** * ** * *** * *  * +3;
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***** ** *  
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** * ***  * * * *  
      *     return 0;
}


INPUT
** *  **   *****
 ****  ** *  *
OUTPUT
* **     ******
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  ***  *  ** ******    *
   *  *      *** ***  * 

int ***  * argc, char       {
 *      ***** char *  ***
 ***   * *** * char    *
* * * **       * char *** *
***** *  * *  *  char * * *
* * **  * ***  * char    *
* * ** **      
 * ** *  *       *  *  ** ** * input the * *** to **  *  * *   * *  **   
     * ** * **** * 
 *** *     *  ** ***  *  * **** * *******   * *  * ****  ****  ****** *** *****  **  ***      * * * ** **  *  ****
******** *   * *   * 
*   * * *     letter = letter + 3;
  **  ** ***  * * = * *  + 3;
* *** * *  *  ***   =    * + 3;
 * *    *  *  * *** =  ***  + 3;
  * *  ***  * ***  =  ** + 3;
   ** ***  ******   
* *     * **     * **  * *  ** **** letter is    *** ** ** * ** * **  * *  * **  ***
 * * * * **  
*****  *  *  * *  return 0;
}

INPUT
*  ** **    * * *
***** **   * 
* **
**  ***  **      * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  **   *  *  * *

int main(int argc, char *argv[]) {
*   *** *** *  * *   ** * * ** lettera;
* **   *** * ** *  *  *    * *    letterb;
 ****** * ****   **   **  **  letterc;
***  ****   ********  **  * *   letterd;
  *  ***  *  **  *    *       lettere;
  **** ****** *  * *** * * **
   **  *       *** *  * *** *   *  * * %c %c %c  * ** * *    *       ** **** ***  * **   *** *  ** **********  * ** **** 
       **  *  **  **** * **   = lettera + 3;
* ***  * ** ******* **   * ****  **  *  = letterb + 3;
   **  *  * *** * **   *  *  *  **   = letterc + 3;
* ** * * *  **     **  *** * ** ** = letterd + 3;
* ** **   * ***  **  * * * *    ** *** * = lettere + 3;
* *****  **  * *  **    ****** * **  *        * *     * *  *
**  ** **  *  * **  ***  *   * * *    * %c %c %c  * *** **   **  letterb,  **  *       *
    * *    *   **     *   
**     *   *  ******* *    *    0;
}

***  *
  *  * 
*   *     * **
***     
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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