[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 7.6k views

22 Answers

0 like 0 dislike 
Hidden content!
 * ***  ***   ****    *** *

int   *  argc, char **** {
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     *   ***  *** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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* *    *  ** *   *** {

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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *   ** * * *       *
#include * ***** *     

/* run this program using the console pauser or add your own getch, * ********    *** *** **  or input loop */

int main(int argc, char *argv[]) {
***  *  * **   *** * **** a;
 *   * * *  * **** *** *   **  b;
*   *****   ***   **  **    *  ** c;
 ***   ** *** *   *    * d;
 **  *  * * *  *****  *** ** *    e;
*** * *** * ***  * **  *   
* *  * ** ** **   **    *   ***   *   * *   the words you want to *  **  ****   
* * **** * ****** **   ***  
 * * * **** ** * **  *   ** * = getchar();
       **** ***  **  * ***** *  = a+3;
**** ** ** *   *  * ****  ***      
 * **     *  ** *     * * * * * = getchar();
 ******  ***  **   *** = b+3;
*      ***  *   * ** **     * *    ***   
* ** **    **   **  *   = getchar();
  ***  ***** ** * * ** **** = c+3;
* ****  * * *** **** **   **  ****  
****       ****    **    = getchar();
**  *   *  * ** * * ***** * *  * ** = d+3;
**   ** *   *  * ** *   ***  *  *  * *   **
* *  * * * *    ***    *   = getchar();
       * *** *  **  **  = e+3;
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** * *** * ***   * **  ***** ** ** ***  ***   a, b, c, d, e);
** ***** * *********    
  *    * *    * * *****    0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   * *  *** *   * * * *
*  * ** * *   * * **

int *  ***     char  *   * {
/*
****  ***  **  */

*  * * *     

* *   ***       * ** ******** *  *  *       * ***   *  *** *** *    *   
a = a+3;
b =  *
c =  * 
d = d+3;
e =  **

* *    * the *** **  
***   ** ****     * * **
    **  *  *   ** ****   *  ***  ***

***  **  **** **** ***
 ***** ** ** *  ** *  * **   ** ** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* ****   ** *     **   * * 
** *    **  **     * ***

/* run this  *  *    *  the  *        or add your own *       * *  ** ***  ** ****   or *** * *   */

int **** ** * char  *      {
**  **     *    int num,   ***
****  ** * ** *  ***  **
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**    * *  ** * * ** *****  ** * * ** 
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{
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**  *    * ** * *** * ***** 
}
* *   *    *   *   *** *  ***  ***   **
*  **  *    **      *  0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  ** *   **    ** 
 
 ***       *    **    

    ** *** *   * **  *    * ***  * *  *  ** ***  * **    * **** * * *    *****      *  **   * 

**    * *    *  *     ** *
 
* * **      *

*** *      **  *    
*
* **   ****       *    **   * * **  ** **        *   **  *  ** **       *

*   =     *
*
  * b + **

* * = c + *

 = d +  
*
* *       *
 
*** *    ** *   *** *  * ***  * * ** * * ** * *  ** 
*
  ** *
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* ****   *  ** * *     *  
      ** ******  ** 

int   * argc, char    *   {
 * * *    *** char * **  
* *  *  *   *  * char *  *
**  * *   * * *   char   ** * 
*   **  *   ** char *     *
**  * * * * ***  char ***** 
**      ** *   
**  ****     *  **   * input the letter to *  ******  **
 * *  *  *    ** 
* *   * * * *  * ** *   * ********* * ** *     * **** * *** *   * ** ** * ***** *   * ***  *  * * ** ***  
  ****    * *** * ***  =  *  ** + 3;
   *      ** *   =     + 3;
*   *  **         *** =   * *  + 3;
    * ****  *  * letterc =  * * + 3;
** **   *   *    **   = ** **  + 3;
 ***  *  *    
*** *  *  *    *  ***  *  **     ***      **  * **      * *  ***    * *   *** * *
*  *   ** **   
  **    **   return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *  *    *** * *** **
* *    **  **   * *  

int * **  argc, char *argv[]) {
   * *  ** * **  char  ***
*        *  char letteri;
*  * * *  ** *  char * * 
***   *** ** *  char ** * *
*  *   *  ** *  char ** **
*   *    **  ** 
* ***  ****    ** *  *  * * input the letter to encode:    * *     
***   * * *   * * 
**    **** * *   * *  ** *  *  * **    **   ** *   * **  * *     ***  *** *    * ** *     * *      * **
   ***** * ***  ** ** ** *  +3;
  * *   * ***    **    * +3;
**    **   *** ** *** * **   *  +3;
**  * ** * ** *  *** *   +3;
 * * * *  ** * *  *** ** +3;
  *   *    *    **  
 * *    *  
* *** *         *  ** *  *  ****  *  **  **   *** *  **   
** ** ***   *   ** 
**** *  *  *** return 0;
}


INPUT
*  * * * * **     
* ** * **     *
OUTPUT
** *****  ****  *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   *      * * *         **
** ** *   **     **** ****

int ***   argc, char *** {
      ** **       char * *  * 
 *** *  * * ** * char *   
 *  *  *  **** * char  *  **
 ****  * * **  *  char *****
 ** * **      ** char   *  
  * * * ***  ***  
* ***    * *  ** **   *    *   input the   *   to  *** *  **      **
 **     ** *   * 
 * * *  * ** * ** **  * ****** * *    * **  ***   * * * * *   *   *** **      * * *  ****   *********   
* *** *  * ***** 
* **   *     letter = letter + 3;
*** *     *  *  = ****** + 3;
   *  **  *   ** = ** * + 3;
* **  *** ** **** =   **** + 3;
*  ** *  *   **   *** ** = ***** + 3;
 *  **  ****   * 
 * * **   *   ** *  *  *****   **      *  letter is *   ***  *   *  * *   * * * *  *  *  * *** *  
   *** *   **  ** 
*   *    ** return 0;
}

INPUT
   *  * **     
 * ** *    **
**** 
***  *** ** *  *  *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include    ***  * ****** * 

int main(int argc, char *argv[]) {
***  *    * * **  * *  *  ****  lettera;
 *  * *****     *  **** *** ** *** letterb;
  * * *  *** *  ** *       *  *** letterc;
  *  ** * * *    ***      **   letterd;
***** ** ** *    **      * ** ** ** lettere;
 *  *  * **      *********
*** **     * * * * *    *  * *    * ** %c %c %c   ***   **   **    *  *    **  ****   ***** * *   *    ** ***  **    * *  
**   **   * **    **   ***** * * = lettera + 3;
   * **  *** ** *   * ** ** **   = letterb + 3;
   *** **   ******* **     *    ** *** = letterc + 3;
 **** * ** **  **   *****      * = letterd + 3;
******* *  **** * *** * *   = lettere + 3;
 * *  ** * *  * ** *   ** * * **   **   *** **** ***  
*   ****** **** *  *  **** **     ** *  ** %c %c %c  * * ** * *     *  letterb,   *     *          
 **  ** *  **  ** *   ***
 ** **** * ***  * ***  ***  **  * **** 0;
}

 *  * 
* ***  
** **** *  * 
 **** 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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