[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.8k views

22 Answers

0 like 0 dislike 
Hidden content!
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*** *   * * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   ** *   *    * 
#include  *  * **  ***  ** 

/* run this program using the console pauser or add your own getch,   * **   * * * *   * * or input loop */

int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *   **    *   * ***
**  ** ** * *  ***   *  * 

int **  ** * char **** {
/*
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a = a+3;
b =   
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 * * * **     **   * 
  *  ** *  ** * **   *

/* run this ** *   the * *** * or add your own * *** ********  *** ****  *   or  *** * ** */

int ***  * * ** char         {
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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *     * *   **  *     
 
*  * ***  ***   *  *

*** ***   * * ***    * **   * *  *  * ***  **    * *  *  * ** * * *  *  **  * 

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* *   * *
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**** *  

*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
****** *   ****  * 
 *   *  **  *  * ** 

int * *   argc, char *    {
* *   *   * char ** * *
* ***  ** *  * char  ** *
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*    **    **        char *   *
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**    *    ***    
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***** *    ** * *** =   **** + 3;
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   * *    * ** ** *  =  **  + 3;
  *  **  ** *  letterc = **** + 3;
* *  *     ***  *  * = ** * + 3;
*  ****  *  * 
 *  * * ****  * * ** ***     **  ** *   *** ****  ** *  **    *  * *    *
* *  **   **   
  *** *   * *  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** * ***    *   ****  
 **   *  ****  *** * ****

int *  ** argc, char *argv[]) {
**** *     * *  char  *** 
 *  * * * * * *   *  char letteri;
  *     *  **  * char    ** 
** *     ** * char   **
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****  *   *  ** 
*  ***    *    * * * * **** *  input the letter to encode:  *****  * * * 
**   **   ** * * * 
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**** **** **  * *  *** *     +3;
*** **      * *   *** ****** +3;
****  *** *  ****  
** * **     **   
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 *  ***    * *  
   * **   *** return 0;
}


INPUT
** *** ***** ** ** 
* **** *  *
OUTPUT
**  * *** ** **  *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* * *       *    * 
  ****  ***   **   * 

int ** *** argc, char  *  *  {
 *** * * **   *  char   ** 
* * ** *   * ** char *** *
* * *    *   *** char   *****
*  **** *  ***   char *  **
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    **  *      
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 *  **  ****  *** 
* *  *  ** **  * *   *  *** * *   *   *  * ***    * *    * * *  * *  * **    *  *** **   ***** ** **
 *     ****   * 
*   ***  ***** letter = letter + 3;
 **  **    ***   * =    *** + 3;
***  **   *  *   ***  =  *   + 3;
  ***     * * **   *** = **** + 3;
* *  *   **  *  *  * = *    + 3;
*   ** ***   ** 
*  *         *     **  ****** ***** letter is   **   **** **  * *   *  *  *** *    * ** * *
*****   ***    
* *  *  *      * * return 0;
}

INPUT
  *  *****  *  ***  *
* ** *****  ** 
* * *
   *  **    *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ***  ****   *  ***

int main(int argc, char *argv[]) {
  * *   * *   *  **   * ** * **   lettera;
         ** **        **  letterb;
  **  * *** *   **  * *** *  * letterc;
 ** *      *****  **** *** letterd;
 ****  ******* ***** * ** ** ** lettere;
** *  * * *******     *    
*  ******   ** *** * **   ******* * %c %c %c * * * *    ***   * *****  * *    * * *  * **  *    **** *    *  ****      
 *  **        *  **  *  **   **  * = lettera + 3;
 * ****      *    ** ** ******   = letterb + 3;
*  * **    * **  *  ******    **    *   = letterc + 3;
 * * * *    * **     **   * *  *  * = letterd + 3;
* *  ** *  ****** **** * ***  * = lettere + 3;
* *  *****      *** * *******       * *  **  **  * ***
 * *    ***** *   ** *** ***  *    * * %c %c %c    ** ** * *  *   letterb, * **** * *  **  **
 ***  ** ** *  ** * * **  *   
** *     *  **   *  ** *** **  *  0;
}

*   * 
*** 
* ** *** * ** * *
 * *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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