[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3.7k views

22 Answers

0 like 0 dislike 
Hidden content!
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*  ***      * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ******   **  
#include * * *** **    **   

/* run this program using the console pauser or add your own getch, *** * *     * *    or input loop */

int main(int argc, char *argv[]) {
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* *  *  * * ** *  ** *     = e+3;
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 * ** ** *    * ** **** *  *
*      * ** ** *  *   ****  *  * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* ** *  *** *  **  ** ** 
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int * **   ** char      {
/*
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**    ***

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**   ****  *   * *    **  *      0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
     * *    ***** *  
     ** * *  **       **

/* run this **   *   ** the ****    *  or add your own *    **   ** ** **    **** or **    ** */

int *  * ** char ** **  {
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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   * * ** *** *  *   *
*
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*   **  *  *  *  *** * *   * *  ** *   *  *    *** ** * **  *    *    ** **  **  *    
 
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** = c +  

* = d + * 
*
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*
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* **  *** **** 
**** * **   * **   *

int    *** argc, char   * * {
  * ** *    ***  char **  
 **    *     char   ***
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* **   **      * ** *  ****  * input the letter to *** *  *  *  *
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***     *   ** *  ******** **  ** *   * ** **    **   * *   **  * **** * *** *  ** **  * ***      
****   *** *  *  = * *  + 3;
*   *  * *  * * * * *     =   *   + 3;
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    *  ** * *** letterc =  ** * + 3;
*  **     ****   * ** =   * ** + 3;
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**    * ** * **  * ******* **** ** **   * *    *   * **    *  **  *  
* *      * **** *  
**  ***  ** ***  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *** *  * * * **  *
 ** ***      *  ***    ** *

int * *   argc, char *argv[]) {
  **    ****  * char * * **
    *  **  * char letteri;
*   * * *      * *   char *     *
*    * *  *    *  char   *  
* **    *  *** **  * char ** **
*  *     * 
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* *  *** *  **   * *  * *    +3;
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*    *  ***   *  *    ** **  +3;
  ****  **   
*     * **  
**** *  *  **  *** *** **** ** *    *     * * ***** * *  **    * * * 
**   ** *** * * * 
* *  * *       return 0;
}


INPUT
 *  ***        
********** ** * * 
OUTPUT
    *** *   *   ** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*   * **    **  ****   ** * 
* * *     *  **    **   

int  ***   argc, char      {
 *  ****  *    char ** **
 * **** *  * **** char * * *
** ****** * * **** char *   *  
**  **  * * **  char ***   
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* *    * **   
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*    *  ** ** 
** *   *   * * letter = letter + 3;
     * **   ***  * *     = * **   + 3;
 *  **  * *  ** *  * =   **  + 3;
* ****    * *   * ***  =       + 3;
* *** ***   **     *  * =   ** + 3;
* * *  *     * * 
* **   *  * **  *    ** *    * **** letter is *   * ***     ***  **     * *   **   *    *  
*   *  **    *  
** *  ** ****  * return 0;
}

INPUT
* *** *   ****     
****      *   **
*  *
****     * ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   **         ** 

int main(int argc, char *argv[]) {
 ** **   * **** * **  *  **   lettera;
  *** *    * * *  ****  * *****  letterb;
*** **  ** ** ** * *   *** letterc;
** ***  **  ** *** * **    * **  letterd;
* * *     * *  *    *  *****  lettere;
**  **   *    ***** ** **  * 
 **      * * *  ***    * *     ** *   * %c %c %c  ** **   ** ****    *    *  * * *******  **  **      ***   **     * **  ***   * 
    ** ** *** ***  *    * **  = lettera + 3;
* *   ** * ****** **  *   *** * = letterb + 3;
 **   * *  * * *   * *  * ** *   = letterc + 3;
* * *  *  **   *     ***     * = letterd + 3;
  ***    **   *******  ****   ** * = lettere + 3;
*  ** ***   *  *    * ** * * *** *  **    **  ***  * 
******  *   *     *  * ********* **    *  * %c %c %c    **  **  *** letterb, ** * ** *    * * *
* * *    * ********   * 
 ***  * *  **   *     *  ****    * 0;
}

*   
*   ***
 **  * *    
******
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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