[Exercise 03] Caesar Cipher Decoder

Question

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

Answer 1

Hidden content!
      * ** * **  ** * 

int * argc, char     {
   ***   * *     *  ** */

*  * *     *    int number;
   **      *  *  * char a;
  **   *   * * **  *     * b;
     * ** * ** ** * ***** *    * c;
  *  *  *****    ** *  * **   d;
 * * *  *   *     ***   ***  * e;
  **   * *  *   ***  
   *  *   **    *  * *    forgert how to shift word *  ** *  * *     * *     *    
 *   *   * **   *   **** *        **       ** *  *     *  * ** *       ***   ***  * * *** 
 *  *        * * 
**   * *    ** * the message how??
 * ***   * *    
* **  *  * ***  **      * *  ** * *******    ***   * 
****   * ***  
 ******   ***   return 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output

---

Case 0: Correct output
Case 1: Wrong output

Answer 2

Hidden content!
  *  * * * * *  
 
 **    * *** *  * **  *** * {

 ***  * **  *
  = ** 
 *   *   
  =     *  **
*  = **** 
** = *** *

 * = * 
  =  * 
 =  **
** =  

*** 
* * **  
***  * **
* ** **  *
  * ***** 

* ***   *  *  *     
  

Comments

Case 0: Correct output
Case 1: Wrong output

Answer 3

Hidden content!
#include   * *  ***   * *
#include *   **   *   *  

/* run this program using the console pauser or add your own getch, * * * **   * * ** *     or input loop */

int main(int argc, char *argv[]) {
* ****   ***** *        **    a;
* * *  *    *         ** ***     b;
 *   *  * * *****   * **    ** * c;
  ******  *** ***         d;
***** ** * *  **  * **   *   e;
   ******  **  *** * *   * * *
 * *** ****** * **  *  ***** *  * * **** the words you want to   *   *******
* **    * * *    ********  **  
* *   * * * **  * **** ***** = getchar();
  *** *     ** *** ** * *** * = a+3;
   *  ** ** * *    * ****   **  ** **   *
 *  *** *** ********     *  * = getchar();
 * ***  * * ***  ** **  * * = b+3;
* ***  *    *  * ****    *        ** 
 ***   **  **  *  * * *       = getchar();
**** ***  **** **   *  ** ***      = c+3;
* *    *   *   ****     *  *    * *  
  ** *     * **   ** ***  * = getchar();
****         ** *   *   *    = d+3;
*** * *  ** **  * *  * * *   *  
*   * ** *  * * **  * * ***   = getchar();
 *  *****   ** **   * *   = e+3;
 * *  *  * *   ** **  * **** * *  *
**  *     **   *  * * *******   * **    *    ** ** **** *   *****
** * * *   ***  ****     ** * *****   *  *******  &a, &b, &c, &d,     *** * * 
*  *    * * **** ** * * **   *
   **  *** ** * * ***  *  * ***  the message how??
*** * *** **  *  * * *  * * * 
      * * *****   ** **  ***  **  ****   * * ** ***  a, b, c, d, e);
*      *** ** ** * *** * * **  ** *
 ***      **** ***     ** * *** 0;
}

Comments

Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.

---

This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)

Answer 4

Hidden content!
 **** *  * ****  *  ** 
 *  *    **  ***   * *** 

int  *  *    ** char *   **  {
/*
** ***  **   */

     * *  *

 *   * **      ** ***   *  *  *    * *** *           *** 
a = a+3;
b = ****
c =    
d = d+3;
e =    

*    * the   *        
 * ******* * **** *
   * * * ** * ****  *** * ** **  *  

 * *    ** ** *    **
 * **** **    * ** * * ** *     **** 0;
}

Comments

prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'

---

Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello

---

Case 0: Correct output
Case 1: Wrong output

Answer 5

Hidden content!
** *  ** ** *    * *    
  ** **    *  * ** *  **

/* run this ** **   * * the  *  **  * or add your own  **  ** ** ***   *  * ** or *** * *  */

int   * **  *** char   * * {
 * *****  *    int num, * **  
**   *  *  **** *   **  * ******
 *   *   * **     
******  **   *  **     ** * * **  *  ****  **
* * ** * ***   for *** =  *  *  *  ** ** 
{
 ** *** * * **    * * =   ****  
   *  *  **   if *  ** * ** *  
***  **   *  * *   =  ** ****   
* * *  ** *           ** *    
}
****** * ** *     *      *   *     **   * *
 *  ** * * *** *    ** 0;

Comments

prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~

---

Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.

Answer 6

Hidden content!
***   * *   *****  
*
*   **  **    * * *
 
***     ***  ** *  **   *  * * *     ** ** *   **    *  *  ***  * *        *  *   * *  
 
 * * **   *  *  *   **  

   *      ** * *

* * * * **     
*
   ** **  *      * ***** ** **    **  *** * * *     **  *      * 
*
 * =   *   

*   b +  *

* = c + *

  = d +   
 
**  *   *

***  * *  *  *** ***  * *     * ** **        
 
 **   *
 
 *

Comments

It's correct lol you can't judge me

---

Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.

---

printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?

---

That's correct.

Answer 7

Hidden content!
     *   *** * * ***  **
*  *    ***      

int **  argc, char  *** {
  *    * **  * char   **
** *       *** * char * 
* * * * ***** ** char   **
** ***  * *       char  ** 
 *   *   * ** *** char *** ****
  ****  **** *  
 *  *   * *  ** *** **   ***  input the letter to  ** ***** ***  
  ** *  ** **  
    ** * ***** * ***  ***** *     * * ***   *  ***** *  ** ***  ** *           *   **  ****  **   *
* *  *   *  **  **** * = ***   + 3;
*****     **    *****  = *** ** + 3;
* *  * *  *    ** * * =       + 3;
   ****   *****   *  letterc = *   *  + 3;
****        * ** *  *  ** = ****  * + 3;
* **    *  * *   
***   *   * *  *   ***   *  *   **  * ** *   ** *  * **  **      **  *
   **  *  *  
** ***** *****  * return 0;
}

Comments

-----------Re-judge-----------
Case 0: Wrong output

---

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.

Answer 8

Hidden content!
****   **  *****
*  * * * *  ****  **    * 

int  **    argc, char *argv[]) {
*   *  *  ** **  * char ** **
** ** ***  char letteri;
***             *   char ** * *
***    ** *   char  **  
*    *    * *   char  *  **  
**  *     * * 
 * ** *** **  * **   *** **  input the letter to encode: ***   **    ***
*    ***  *  
**     *  **      *** ***   *** **   **  ****    * ** *  **  **   *   *  ***   * * **** **   *     ****
 *    *  *      * **** *  +3;
* **       * * *   *   **  +3;
*     *   *  *   *   *** +3;
 * * **    ** * * **  ** * +3;
    *  *   * ** *  ** * *** +3;
**   **      ** 
 **   *  * *  
 *  *  * *** * *   * ** *    *     ***** ** **  ** * ** * *   
  **      *  * 
 *  **   *  ***  return 0;
}


INPUT
 ** *** * * *   *
   *** ** **  **
OUTPUT
 *    *    ** **  

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'

Answer 9

Hidden content!
       * **  *    
***** * *  *   ***  **

int *  * argc, char ***  {
* *   *     ** char  **  
     * * **   * * char *  **
* * **   ** * *  char  *** 
** * * *   * *  char **  **
* **   ** * * char *   * 
**      ** *** **** 
**  *   *     * **     * *  input the  ***   to  * *  * ***    **  
***  *  *  *    
 ** **   *** **  *** ** **  * ** *  * ***    * ** *  *       *       ****** ****  **    *   ***   ***
**   *       * 
  ***  ** *   letter = letter + 3;
   ** ** ***** *   ***  =    *** + 3;
*  ** ***   *   * *  **  =    ** + 3;
* **   *****    ** = *** + 3;
 **** * *  *   **  * * =    ** + 3;
 *   * *** ** ** 
* *** *  ** ** * *  *      ***  ** *  * letter is **** *** **      *   *** ***  **    *    **   ***
  ** **   * *** * 
  **   *****  return 0;
}

INPUT
 ****  *  *****
    ***  *   ** **
***  
   *  *   **  **  

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'

Answer 10

Hidden content!
#include  **** **  **  

int main(int argc, char *argv[]) {
 ** * * ****  * *****  *****   * lettera;
   * * ****  ** * *   *** * letterb;
*   **    ***    **   ****    * *   letterc;
 *   *   * **   *  **** * *  ** letterd;
 ** ******   *   * ** ***   lettere;
 **          *   *   *
 ****  * **   **    * * **  *****  ** * %c %c %c ** * * * ***  * *  ** * ***  *    * ****   **        **  * *  ** * 
*    ** **  * * ***   *  **  = lettera + 3;
* ** ****  * *   **  *  *      = letterb + 3;
 ********   *  *   *** * *  * = letterc + 3;
** *  * **  ** * * *    *    *  * = letterd + 3;
 * *   *    **  * * **  **** *****   = lettere + 3;
** * *  * *****    ***** ***   * *    ***   **     *  ** 
  *** ***  ** * * * ** ** * ** ** *  * %c %c %c    * * ***** letterb,   ** *    *   *
** * ****      *   * ** * ** ** 
 ** * *** **   *   *   **  **  0;
}

 * * 
 * 
****       * 
  *
//hello

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'

---

prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'