3 like 0 dislike
4.3k views

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited

edited by | 4.3k views

22 Answers

0 like 0 dislike
Hidden content!
** *** *** * *****

int ** argc, char * {
*** * ** * ** *** */

* * * * int number;
* ** * * * char a;
* * ****** **** * ** ** b;
** ** ******* ** *** ** c;
* ** ** * ****** * *** d;
*** *** * * * * e;
*** ** ** * * * *
*** ** * *** * forgert how to shift word * *** ** *** *
** ** * * ******* *** *** *** * ** ** ** ** * *** * ** ** *
* * ** ** *
** ** ** ** * * the message how??
* ** * **
* * ** * *** * ** ** * * *** *** * ***
** ** * ***
* * * * * * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
* * * * * ** ** *

**** ** * *** * {

* * ***
= **
* * *
* = **
* = * * *
= ***

* = **
= * *
* = *
= *

*
**** *
* ** *
** * *
****

* *** * *
100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
#include * * *** * ** *
#include * *** * * *

/* run this program using the console pauser or add your own getch, * * *** * or input loop */

int main(int argc, char *argv[]) {
***** ** ** ** *** * * a;
* * ** ** * * * * * b;
** * * ** ****** ** * * ** ** c;
** * * * * * **** * * * * * d;
* * * * * ** * *** e;
*** * * * * *** **** ***** *
** ** *** * ** * ** ** * **** the words you want to * **** **
* * * ** * * * *
* * * ** * * ** * * = getchar();
* ****** * * * *** = a+3;
******* * ** * ** * *** *
*** ******** ***** ** * = getchar();
* * * * ** * ***** = b+3;
* ** * ** * * ** *
*** * * * ** ** * * * * * = getchar();
** * ** * * *** ** ** = c+3;
**** * **** ******** ** ** *
* *** * * ** * ** * = getchar();
* *** *** * ** * *** ** * **** = d+3;
* * ** * * * ** ***
** ** ** * ** * *** * * ** = getchar();
* **** * * ***** * * * * = e+3;
* * **** * * ** ** * *
** ** *** * * * ** ********** * * * * *
*** * ** * * ** **** * ***** *** **** &a, &b, &c, &d, * *
* * ** ** ***** * * *
* * ** * * ** **** * * **** ** the message how??
** ** * ** ** * *
* * **** ** * ** * **** ** **** * * a, b, c, d, e);
*** ** ** * * ***** ***
**** ***** * * *** ** *** * * * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
1 like 0 dislike
Hidden content!
**** * * * **
**** *** **** ** * * *

int * ** char * * {
/*
** *** ** */

* *

* * ** ** * ** ** ** * ** *** ** *** * **** **
a = a+3;
b =
c = *
d = d+3;
e = ***

** * the **** * *
** * ** **** ***
* *** * * ** *** *

* * * * * * *** *
* * *** * *** ** **** * * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
* ** * ** * *** **
** ** * ** * *

/* run this * * the ** * ***** or add your own ** * ** * * *** *** or * */

int * * char * *** * {
* **** *** *** int num, ***
***** ** * ***
* *** * *
* ** ** * * * ***** *
**** ** * * for = * * * *
{
** * * *** * **** = ** * *
** **** ** if **** *** *
******* * ** * *** * = ** * *
* * *** * * * * **
}
** **** ** ** * **** *
**** ** * ** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
1 like 0 dislike
Hidden content!
* * ******* *

* ** * ** * ** * *

* ** * * * * * * * ** ** * *** * * *** ****** * **

* * **** * * *** * *

* ** * ** *

* * ** * * * * **

* **** *** * ** * **** *** *** **** ** ** * * * * *

* =

* b + *

= c + *

= d + **

* * *
*
* ** * ** * * ** * * ** * **

** *
*
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
0 0
That's correct.
1 like 0 dislike
Hidden content!
* * ** * * ** * **
* * ******* * ***

int *** argc, char *** {
*** ** * * char * *
* ** * * char **** ***
* * * ** ****** * char * **
*** * * ** * char * *
* *** * * char *
* **** * * * *
* * * * * * * * *** * * input the letter to ** **** * *
** * * * *
*** * * ** ** * ** *** * * * *** ** *** **** * * ** * * * * * * *
* * ***** ** = * * + 3;
**** * *** **** = *** + 3;
*** * * *** = * *** + 3;
** * * * ** * * letterc = *** + 3;
** * * * * *** = ** + 3;
* * * ** *****
** * * * *** ** * * * ** ** ** *** * *** * * * * ** *
* ** * * **
* *** ** * return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
1 like 0 dislike
Hidden content!
** ** * * ** *
* * * *** ***

int * argc, char *argv[]) {
**** * * char * *
* ** * * *** char letteri;
***** * ***** char ** **
* * *** * char ** ** **
*** * * ***** ** char
****** *
** * * * * * ** * input the letter to encode: *** *** * *
** ** * **
* ***** ** ** ** ** ** * ** * ** * * ** ** * * *** ** * *** ** *** **
***** ** *** * ** **** +3;
*** * * ** ******* +3;
** ** ** * ** * ** +3;
***** ** * ** +3;
* * *** * * * * +3;
**** * ** *
** ** ***
**** * * ** *** * * * * * * ** * *** *** * ****** * * **
*** * ** * *
* **** * return 0;
}


INPUT
* *** ** *
* ***** *** *
OUTPUT
* ** * ** ***
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
** * * *** ***
** *

int * ** argc, char * {
*** * ** char *
****** * ** * char * *
* ** **** char
* ** ** * * * char * *
** * * * ** char *
* ** * * **
** *** * * *** *** ** * input the * * to ** * *** * * ***
** * ***
* * * ** * * * * ****** ** * * * * ** *** *** ** ****
* *** *** *** ** *
** * ** *** ** letter = letter + 3;
**** * * *** * ** = * * + 3;
* * * * ** * * * = * + 3;
* ** ** * *** = ** + 3;
*** * * *** = ** ** + 3;
* ** * * **
* ** * * * ** ** * * ** letter is * **** ** * ** * ** ** * **
* * * * ** *
* ** ** *** ** return 0;
}

INPUT
* ** ****** * *
** ** * **
**
* * **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
#include * ** * *** *

int main(int argc, char *argv[]) {
**** * ** * ** *** * * ** * lettera;
********** **** * * ** letterb;
*** *** ** * * **** * *** letterc;
* * ** *** * ***** ** * * *** letterd;
****** * * * ** ***** * lettere;
* * * *** **
** * * *** ** ** * * * ** %c %c %c * ** * * *** ** * * *** * *** *** * ** ** * * ** * **
*** ** * * **** * * * = lettera + 3;
**** ** * * ** *** *********** = letterb + 3;
* * ** *** * * * * * ******* = letterc + 3;
** ** * * * ** *** * ** ** = letterd + 3;
* * * * * *** = lettere + 3;
* ** ** ******* * **** ** ***** * * * ** ***
* * * ** ** * ** ** * * * ** ** %c %c %c * **** * * * letterb, **** * ** * ** * * *
* * ** ** *** ** * ** * *
**** ** * ** ** 0;
}

***
** *
** ** *** *
* *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.111
©2016-2025

Related questions

0 like 0 dislike
2 answers
[Normal] Essay (Open question) - asked Dec 12, 2017 in Chapter 2: Syntax structure of the C language by 許哲瑋 (449 points)
ID: 37081 - Available when: Unlimited - Due to: Unlimited
| 681 views
12,783 questions
183,442 answers
172,219 comments
4,824 users