[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3.7k views

22 Answers

0 like 0 dislike 
Hidden content!
*** *   * * *   * *

int * ***  argc, char *** {
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* *         *  * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   **  ** * * 
#include **  *  *  * * * ***

/* run this program using the console pauser or add your own getch,  * ** *  *  *  * *** or input loop */

int main(int argc, char *argv[]) {
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* *      *** *    *     ** ** c;
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*     * ***** *  ** **      = a+3;
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***** *  ****  **  ** ***     = b+3;
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*  *** ***** **   *   **  = d+3;
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*  ** *******    * **  *  *  * = e+3;
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*  * * ** ***   *  * * ** * 
*  * * *******  * ** * **  ****  0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
****  **** * **  
   ***    ***   *       

int *** **    char  ****  {
/*
*  ** *    */

**   *  **

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a = a+3;
b =  
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d = d+3;
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**  **  *** ** *  
     ** * * *** * * *** 

/* run this    *    * * the  * * ** * or add your own * **   ** * ** ** *  ** or * *    */

int   *   ** char **  * {
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}
*** *    *  ****   *    ****   *    **      ** *
** ** *   * ****    ** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*****    * *   ** *   
*
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*
  **   ****     *  *  ** *  * *    *   * *   *  ** *** * *    **  *      ***    
 
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*   =    

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*  = c + **

** = d + * 
*
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*
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*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
******   *****  * *  *
 ** **  * *  ** * * *     

int * *** argc, char   **** {
*        * * * * char * *   *
 * *** *    char   *
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**        **** * char  * * 
**  *** * *   
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**** *    *  * 
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  *   *    **** *  *   = ****** + 3;
**  *   * ** * *   ** = ****  + 3;
 *  *** *   ** *        =    * + 3;
*  *  *** * **   letterc =  * ** + 3;
 ** ***** **  *       * = * * + 3;
*   *  ***   *  
  **** * *  *    ** **  *** * *  * ***  *****     **   **  ** **    ***  *
 *    ****  *    * 
 ** * *   *   return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* * * * * * * ***
*       * *  **   **  

int *** *  argc, char *argv[]) {
 ***   * ****  *  char   * 
** *    *  ****** char letteri;
 *  *    char   *  
**    ***  **   char   *    
* * * *  *  *  *  char ***  * 
** *  *  *  * 
**   ** *   *  ***  * ***    * ** input the letter to encode:  ******  **   *
* ** * *  * * 
*  *      ** *   *** *  **     ****  *   **   *   **   * ****** ***     *      * *      * ****  * 
* ***   **   *  *  *    +3;
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**    ***  *  **   * * ** ** * **   ** *   * ***** * ***  **  * *
 * ** * ** **  
 * *     **    return 0;
}


INPUT
** *** ** ***** **
    ***  * * ** 
OUTPUT
 *   * **** **   *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   ****   **** *    
  ***      *  *  *   * 

int  **  * argc, char  *** {
 **     **  char ****
 * **  ***    char *******
* * * * **  **   char ***** 
**   **  ** *  * char  * *  
  ****** *    **  char ** **
**   **  *  *  * 
****  * * ** *    *    *** ** **** input the * *   to * *  **** **  *** 
****   *    *    
** *             **  ** *  *      *  ** * ***** ** * **  ** * ***  * **     * *   *  *      **     ***  
 ***    *  * ** * 
 *           *   * letter = letter + 3;
**    **   * **** * =  * ** + 3;
 ***  ** ****  ** ** = *   * + 3;
*   *** * *  ***  *  *   =    * + 3;
   *  * **  ** * * = * ** ** + 3;
  * **  ** * 
***   **    *   *     * **   *    * * letter is *  *** *  *   *  **  *** * *  *  * ** ** *    
 **   **** 
   *  ** *  return 0;
}

INPUT
*****  *     ** 
* * **      *
***** 
  *    **     *  *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include     **   * **

int main(int argc, char *argv[]) {
  **  ***   * *   *  * *** *  * lettera;
 ******  **** *   *     **    letterb;
* * ** ** * **  *  **    ** ** letterc;
 *         *  * * *  *  **** * letterd;
  *** **   *  * ** * *     **  lettere;
    ** *** *   ***  ** * *  *
  *     *** *** *** ** * ** ***** **  *  * ** %c %c %c      *      **   * * **  **** * ** *  ** *  **   ** *  *   * ** 
*** *       *  **** ***** *  *** = lettera + 3;
*   ***    ******** **   ** ** = letterb + 3;
   *  *** *  * * * **    **   * = letterc + 3;
*** *  ** *   **   *   * * * * ***** = letterd + 3;
*    **   *   **  * ***  = lettere + 3;
*****   **       *  ** * *     ** *** * *  **  *
*  *  ** *   *   *   *    ** *  * ****   %c %c %c  ****      *   letterb, * *        *   *
   * * ***  *  **       *** * 
* **  *      ****    * *   0;
}

*  *   
 *    
 *****  **  
* *  
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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