3 like 0 dislike
4.7k views

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited

edited by | 4.7k views

22 Answers

0 like 0 dislike
Hidden content!
* ** * * * *** * **

int * * argc, char * ** {
**** * * *** * ** ** */

* * * ** int number;
* * * * char a;
* * * * **** * * ** * *** b;
***** ** ** *** ** * c;
**** ****** *** * ** d;
*** * * * *** **** e;
* *** *** ** **
**** **** ** ** * forgert how to shift word ** * * **** ****
* * ** * * *** ** * * * * ** *** *** ** ****** ** * *
* * *** * *
** ** ****** ** the message how??
**** ** * **
** *** * ** ** ** * * ** * ** **** *
** * * * *
**** * * * ** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
* * **** * *

* * ** ** * ** ** ** {

** ****
* = * ** *
* * ****
** = ** * *
* = * *** *
** = ***** *

= *
* = *
= **
= **

*** *
* ******
* *
** *** ***
* *

* ** * * *** * *
100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
#include * * *
#include * ** **** * *

/* run this program using the console pauser or add your own getch, * ** **** * * * **** or input loop */

int main(int argc, char *argv[]) {
* ** * * * ** *** * * * * * a;
** * * * * ** **** ** b;
* ** * ** * ******** * * ** c;
*** * ** **** ** * d;
**** ** *** * ** * ** * e;
* * ** * ** *** *
* * * * * ** * * *** * *** the words you want to * ** **
* *** *** ** ** *
* * * * * * *** ** = getchar();
** ** * ** * * *** = a+3;
** ** * ** ** *** *** *
* * * **** * *** * * = getchar();
* * *** * * **** ***** * = b+3;
* * * * * * *** * ** ** * **
*** * ** ** ******* * = getchar();
* * * * ** ** ** * = c+3;
* * * ** **** ** * * *
*** **** * ** * * ** * = getchar();
* ** * **** ** * * ** **** = d+3;
* ******* ** ***** **** * * *****
** ****** * * * * * * * = getchar();
* * **** * * ** = e+3;
* * * ** ** ***** ** *
* ** **** * *** ** ** ** ****** * * ** * ***
*** *** ** * *** * * ** * ** *** **** &a, &b, &c, &d, * * ****
*** ****** ** ***
** *** * ** *** * **** * * the message how??
** * ** * * ***** ** **
* * ***** * * *** * * ***** ** * a, b, c, d, e);
* *** ** * * **** ****
*** ** * *** * ** * * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
1 like 0 dislike
Hidden content!
* * *** * * ***
* * * **

int ** ** char ** * {
/*
* * * */

* ****

* ** *** * *** * ** * * ***** ** **** * * * * ****
a = a+3;
b = *
c = *
d = d+3;
e =

**** the *
*** *** ** * *
*** ** ***** ** * * * *

**** * * * * * ** ****
* * * * ** * ** ****** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
* *** * * ** * ***
** * ****** * *

/* run this ** * the ** ** * or add your own ** ***** * ** * ** **** or * * */

int *** ** * char ** * * {
* ***** ** ** int num, ****
* ** ** ** * * * * **
**** * * ** *
* ** ** * * ** * * * * * *
** ** * * * *** for * = * ***** **** *
{
** * **** ** *** = ****
** ** * ** if ** * * * * ***
** *** **** * * * = * * * **
* ** * * **** * ***** *
}
* * * * *** * **** * * *
**** * ***** * * ** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
1 like 0 dislike
Hidden content!
**** * ** * ****
*
** **** * * * * *** **

* * * * ** ** * * * * ** * * ** **** * ** * * *

*** *** * ** * ***
*
** * *

* * *

* * *** *** ** * ** * * * * ****

= * *

* b + *

** = c +

** = d + **
*
* * *

* *** * * * * * * * ** * * *



*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
0 0
That's correct.
1 like 0 dislike
Hidden content!
* ** * ** *** *
** * ** * *

int ** ** argc, char * {
*** * * char *** *
** * * * * *** char *
** * ** * char * *
* * * * * char ** ***
* * ** char ***
* ** *** * *
**** ** * ** * * * ** input the letter to * ***** * * *
** * ** ****
* * **** * ** * ***** * ** * * ***** ** * ** ****** ** * *** ***** * * ** * * *
* * * * ** * = * + 3;
* ** *** ** *** = * ** + 3;
** * **** * ** = ** ** + 3;
** ** * * letterc = + 3;
** * * *** * = ** *** + 3;
** ***** *
** * *** * ** * ** * ** *** * * * *** *** *** * * ** *** *
** ** **** *
** ** ***** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
1 like 0 dislike
Hidden content!
** * ** ** * ***
* * * * *****

int * * argc, char *argv[]) {
* * * ** char ** *
* * ** * ** char letteri;
* * * * * char *
* *** ** char ** *
*** * * ** ** char *
** * **
* * * * ** *** ** * ** input the letter to encode: ** ** *** *
* * ** *
* * * * * * * *** *** ** *** * * * * ** * *** * * * * ** * * * * * ** *
** * * ** ** ** * ** +3;
** * * * * * ***** * +3;
** *** ** * * *** +3;
** ** * ** * * **** +3;
*** * * ** *** +3;
** **** * * **
** * ****
* * * ** * *** * *** *** ***** *** **** * * *** * * *
* ** * ****
* ** * return 0;
}


INPUT
** ** * * *
***** *
OUTPUT
* ** * *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
* * ***** **
* * * ** **** *****

int **** argc, char ***** {
* ** * * *** char *
* ** ** char * *
******* * * **** char * *
** *** * char * *
*** *** ** * ** char ** **
** * ****
** ** * ** *** ** input the ** to * ***** * *
*** ** * *
**** * ** *** * *** **** * *** **** **** * ** ** * * ** * * *** * * * ***** *
* * *
** ** * letter = letter + 3;
** ** * * **** = *** + 3;
**** * ** ** ** * = ** + 3;
**** * ** * * * = **** * + 3;
**** ***** *** * ** = * + 3;
* * * *
*** ** ** ** * ** ** * * ** letter is *** * * ** ** * ** * ** *** **
* * * * ****
*** * * *** * return 0;
}

INPUT
** *** * * *
* * * **

* ** ****
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
#include * * ** ****

int main(int argc, char *argv[]) {
* ** ** * ** ** * * * * * lettera;
* * ** * * * * * * ** letterb;
*** * ** * * ** ** letterc;
* * **** ** * ** letterd;
* ** ** *** * * * * ** * * lettere;
** * ***** *** ** * ******
* * **** * * ** * * * %c %c %c ** * * ** ** **** * *** ** * ** ** ** * * * * * * * *
* ******* * * * ***** * ** = lettera + 3;
** **** ** * ****** * ** = letterb + 3;
* ***** ** ** ** = letterc + 3;
* ****** ** ** ****** ** = letterd + 3;
* ** * ** ** ***** * = lettere + 3;
** *** ***** ********* ** * * **** ***** *** ** *
* ** * ** * * * **** ***** **** ** %c %c %c * **** * * * letterb, * * * * * **
** * * * *** **** ** **
* ****** ** * ***** 0;
}

** *
*** *
***
* * *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.89
©2016-2025

Related questions

0 like 0 dislike
2 answers
[Normal] Essay (Open question) - asked Dec 12, 2017 in Chapter 2: Syntax structure of the C language by 許哲瑋 (449 points)
ID: 37081 - Available when: Unlimited - Due to: Unlimited
| 735 views
12,783 questions
183,442 answers
172,219 comments
4,824 users