[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.6k views

22 Answers

0 like 0 dislike 
Hidden content!
* ** * ********* *** 

int  *   ** argc, char *  ** {
**   * **  *   *      ** */

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* * * * *  *  return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *****     * ***
#include  **** ** *  * * ** 

/* run this program using the console pauser or add your own getch, * * ** * * * * * * ** ** or input loop */

int main(int argc, char *argv[]) {
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**  * *** ** ** * ** * * = e+3;
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**   ** **** * * *** ****
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**   *  *          *  **
****   *  *   **    * 

int * *    *  char    *  {
/*
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*    *  * *

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a = a+3;
b =    *
c = **
d = d+3;
e = *

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*****  * ****** * *  **  * ** *

*** *  **   * *****
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*      * *  **   ** **
  *  *   **  **  * ** 

/* run this * ***     * the  **     ** or add your own        * ****** ** * ***   or   *  **  */

int  **      *  * char * *  {
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}
*  *     ** * *** ** * *       *   ****** * **
*   * *** *      *  0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* * * * *    ** *    
*
** ***      ** *   ** *

** **      ****  *  * **           * * *  **   ** ********  * *         ** *     
 
* *    *     *  *** *  *   

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** *******  *   * *   ** ****    *     * *  ** *   *    *   * ***  * ******
 
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** * b +  

*  = c + * 

* * = d + *
 
***   * * 

*  * ** ** * **  *  * **  *  *  **    * 
 
  * * *

 *
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   * *     ***  *  *
* *  * **  *  *  ** ** 

int   *   argc, char  **  {
* *   *  *  ******* char  * ***  
  *   *   *** * ** char  *  * 
** *  * **  **   char      
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*  **    *  char  ** *  
* *  ***   **   
* * **   * ***   ***** ** ** * input the letter to  *          
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* **   *  ** ** *  ***    ***     *  * ** ***     ** * **  *   * ** * **  *   ** *    *   *  * **   **   *
   ****  * **   * *** ** =   *   + 3;
 *  * ***   *   *   **** = ***** + 3;
* ** **   ****   = **** ** + 3;
** * ***     *** letterc =    * + 3;
* *** * ******   ** * =  * * * + 3;
* *     *** *    
* ***  *  **   * *   ***   **  *  *  * * **  * *** ** **** **    * **  *  * *
**    *   *   
  * * * * ****  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*    *    ****   *   
  * *  * ****  *  *  * **

int   *  argc, char *argv[]) {
** ** *** * *   char **  
**  *   * *  ** char letteri;
***  **** *** *   char    * 
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* * ***  * * *** char  ** *
* ** ***   *  **  
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* *** *  **   ***   * * * +3;
****   * ***  *  *** *  * +3;
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* ** **** * * *   * *   **    * +3;
**  * *** *** * *  *  **** * +3;
 * ** *      ** *   
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 ** ***   **  * 
 *      * *** return 0;
}


INPUT
       *  **
  * ***   ***   
OUTPUT
 *****   * *** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
** * ** ** * *   *
** **   **** *  * * * 

int  ****    argc, char    **  {
     * * ** * char  *  *
* * *   * ****  char  *   *
* * **    * char  *
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*** **   * char  * 
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**  ***    *  * 
*** * ***       *    ***  **  *  * *  ** *  * * *** ****  *   * *  *      *******   **  * ***   *
*** *     * ** 
*   **  *      * letter = letter + 3;
** *** *  * *    *   ** = * * *  + 3;
  * *** **   *        = *   * + 3;
*** ***  *    *  *** * =  **   + 3;
**  **  *        *  = *     + 3;
** **   ** ***  
**   *    ***  ** * * **** *   *  letter is  ***** **** * *      *    * *    *   *    ** **
   *  *  *** 
**  * *** ** return 0;
}

INPUT
 ** *** ** **  * *
*  * *    * **   *
  *  
 *  *  ***  *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ** *  *   *  

int main(int argc, char *argv[]) {
**  ** ** * ** ** *   ** lettera;
 ******   * *** **  * *   ***  letterb;
* ** ***  ** ******** * * **   letterc;
  * **  **   *** * *  * *** * letterd;
****   ** **** *** ** *   *    lettere;
  * ** * *   * * ***  *** * * 
* * *****  *   ***    * **** * **  *    *   %c %c %c    * *   * * * **   **  **   *****  *       * ****   * * **  * 
* *     ** ****  *** * * * * = lettera + 3;
* **  ** *   ** *** **** * *   = letterb + 3;
*    *** *****  *   **  *  *** *** = letterc + 3;
 *   *        * ** *  ** ** = letterd + 3;
 *     **** * ******   ** **  ****** = lettere + 3;
   * ***   * ****** ****   ***  *   *  **** * * *
*    *  *  ** * **   **  *     *  ** ** * %c %c %c   ***   *  *  letterb,  * *  * ****** ***  
 * **  ** **  *** * *** *
 *** * *** * * * ** **    *    * 0;
}

 *   
  ** **
     **  * * *
**    *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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