[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 10k views

22 Answers

0 like 0 dislike 
Hidden content!
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int ******  argc, char *****  {
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****  *  *   * 
*   *  **  return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  *** *** *** **  ** **

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***   *
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ** * * ** **  *
#include **** * **  ** *

/* run this program using the console pauser or add your own getch,  ******      *     **  or input loop */

int main(int argc, char *argv[]) {
* **  *****     * ****  **  *** *  a;
   ** ***   *  ***    ** **** b;
* ********     * * * ******* * c;
       * ** *  **   ** *    ** d;
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**** **      *  *** ******  * = getchar();
  *** *   * *    ** * *   = a+3;
* *   * * ****   * *** * ***** * 
   ******* **   **  *** * ** * = getchar();
      **       *** *  ** **   = b+3;
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*****  * **  ***   *  ** **  * = getchar();
* ****** ** *  *   **  *** *  = c+3;
*  ** ***   * * * ** ** *  ** 
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*** ***** *** * ** *** * ** **  * *** **
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**  * * ***   ***** *  ** = e+3;
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***   **  *   ** *      **  * * *  ***    * * *  ***  ** ** **
**     *****  *    * ** **** * *   ****  * ****     &a, &b, &c, &d, ***** 
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  ** ** ****** * ***** *  *** 
   * ***    ***  **   *** **** *  *  0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *    *   *** *  * * *
***  *  *  *  *    ***

int     *    * char ***** * {
/*
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* *  *   *  ***  * * *  *  *   *    ** * *    * * *      ***  **** *  
a = a+3;
b = **
c = 
d = d+3;
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*      * ***   *    ***
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* * *     ****      *  
 * ***  * *  ****  **  *  

/* run this * * *   *  the     **  **  or add your own ****  ** * *  * ** ***  or *   **  */

int ** ***    *  char  * * {
      *  *   int num,  * *
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{
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* **      *  *    *   *
}
*  *   * *   *   ** ** *  *   * * ***** * **  
  * * ***         0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
     * ****   ***** **  * *

***** ** **   **   **  * 

      *    *     ***   **** ***    *    ** *  ** *    ** *** *   ***  * *    *
 
*    *  ** * *    * *** *
*
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** =  * * 
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**  b + 

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*  = d +  
 
*      
 
* * *  ***  *  ** *  * * *   *       * **    **  *
 
**   *
 
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 **** *    * ****    *
 ****   *              *

int        argc, char *    *  {
*** **        char  *   
* **    * ***    * char    **
*  *   *  * * * char * ** 
 ** * * ** * *  char   *****
 *     ***  char ** * 
*  *** **  **    *  
*    ** ***   **  * ** *  **    input the letter to *******  *  
** *   *    *     
    *    *  ** *  * ***   *** ***    *  **   ** *    ***   ** * *  * * * *       ***    
 **   ** **   * = **  + 3;
**  **  ** * * *  **    = **    + 3;
      * * **** *   *   = **** + 3;
**** *  *  *  letterc = ** *  + 3;
*** *  *  * *      ** =  ** + 3;
 **  **    ***  
* * **     **    * *  ***   * *  *    * ***   * **    *  **   * *  * ***   
** ***  * **** 
* *  *  *  *   return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
******   * *   ***   
 *** * ***    **  *** 

int          argc, char *argv[]) {
*** *  *  ****  char   *
  *** ** * *   char letteri;
    *      *  * char *   
* ***    **   char   *   
* *** *  *    **   char   ****
  ** **  ** ** 
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 **  * * *  * * 
*  **** * * * **  * *    * * ** *  **  **  *   *   ***** *  * * * * **   **  *    * * *********    *  *  
 *   *   * *    * ** * +3;
**    *     ** ** ** +3;
 *  ** **** **     ** *   * +3;
**    ** *    ** *    *  +3;
  *  *** **  ** * *  *  +3;
 **** ***   *  
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   *   ** *   ***  *  *  *******  ** * ** **     * *   * ** ** * * *  * 
*********   * ** ** 
 * *  *  ** *  * return 0;
}


INPUT
  *    * **** **  *
*     * ******
OUTPUT
** ** ***  *** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *   * **** * * *** 
    *      * **  *   *

int  ** * argc, char  ** *  {
*    * *** * char ****
 *** **   *  **  char *** 
   *  ***** **  char   *  *
       *    *  *  char  **  *
*   * * *    *** char ** ***
  * ***   * ***** 
**  ** ***  *** **** * ** * ** input the *  to ***** *   * *     *   
    * *  ***  * 
   * *     **** *   * *     *      * *   *  **  *** **  **  *   *  * **** ****** *    ** *     ** 
 *         *  * 
*    *     *  letter = letter + 3;
* *   **  * *    *   *** =     + 3;
 **  ***    * *   * *  *  =      + 3;
*  **    **  **  ** ** = ***   + 3;
 *  **   *** *   *  = **  * + 3;
    * **  *  ** 
* **  * * *      **   * ***      * letter is * *  **  *       * *   ** ** **   ** *  *    * *
*  **      **    
*   *    ***   *  return 0;
}

INPUT
*   * *   ** ****  
 *****    **
** *
* * **     * *   **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ** * ** ** *

int main(int argc, char *argv[]) {
******     *   **      **** ***    lettera;
*   * * * **      **  ** * ** letterb;
* *  *** *   * * *** * *  **    letterc;
 * *    * * *   *  *** ** *  *  letterd;
 *   **   **** **  *  ** *   *  lettere;
* **** ** ***  ***** * *    **  
 **  *  * * **   * ** * *  ****    * **  %c %c %c **  *  *    * ******* *  * *** *  * **  *  ** ***     ***   **** **  
*  *  *** *   * **   *  **   * = lettera + 3;
 *   *    **  **  ****  * *   = letterb + 3;
 *** *  *****  * * ** **   ** ** * * = letterc + 3;
*** *** * *  *    ** *****  ** = letterd + 3;
   **     *      ** *   *** *** **  * = lettere + 3;
* *   ****      * * * *     ****** *  ******* *** **  * * 
 * ***  **** **    **** * *  ***      *  * %c %c %c ** **    * *     letterb,   *     ** * 
* ** * **** * * *  * * ****  
 *****   ** *** * ** * **** * *   ** 0;
}

  ***
   *
*   ****   * **
 ** *** 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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