[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 4.7k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * *****  ***** 
#include **  ** *     

/* run this program using the console pauser or add your own getch,  * * **** ***   **  or input loop */

int main(int argc, char *argv[]) {
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* *** ****      ** *      ***   = e+3;
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * ** *  **  *  ****** *
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int * * *    * char *  *  * {
/*
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b =  *
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****   *   ** * *
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
** * ***  *** **** *
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}
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*  ***    ** *   **** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  **    **  **  **  
*
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* = c +  *

* * = d +  
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *    *  ******* *
   *  *  ** **  *  *** *     

int    *  argc, char  *     {
 * * *  *  *  *   char * *   
***    ** *** *   char *   * 
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    ** * * * **    letterc = *   ** + 3;
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     * *    *****  
* ***     *   * ***** **  **      ***        * * *   *  ** **  ** *  * * * *
**  ***  * * **** 
    *       * ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *  * * *    **** **  
*      *    * *    *****

int  * *  argc, char *argv[]) {
*   **  *** char  *    
    **    *   ** char letteri;
*     *** *      * char * *  
* *  ** *** * * char ***  
**** **      * * * char *  *** 
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***** *     **  * 
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*  **   * *****  ** ******   +3;
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** ** **   *   *    * * ***     +3;
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*    *  * ** 
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}


INPUT
 ** **  ******
** *  **  **
OUTPUT
* ****** **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*   *   **   *    * * *  
 ***  **    ***   *  

int  **  * argc, char  * *   {
 * ***     **   char    **
* ** * * * **** char ****
* *  **  **  **    char   ** 
**  * * *   * char    **** 
*****     *** * char *  **
*     ** ** *  ** 
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 *    *  * 
*   * * ** * ***  ***  * ****** *  ** **  **  *  *   *** **  ***    * * ***   *** **  *    *   *  *  *  *
   **  * *** * 
***  *       *   letter = letter + 3;
*** ** **  **  * * * = *** *** + 3;
* *  *  ***   * * * = *   + 3;
  **  *  * **     * = **  * + 3;
  *   * *  * ***  *   =  ****   + 3;
  *  ** *     * * 
* *   **    ***  **  * ** *** ** **   letter is ****   * *    *  **     * **  * *   *     
*  **   **    * 
 *       ** *  return 0;
}

INPUT
 *  ** ***** * 
 * **   ** **  **
* *  
***** ***      *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ** **  ***      

int main(int argc, char *argv[]) {
****    * * **** *    **  *****  lettera;
 *   ***     **   * * ** ** * letterb;
 *  **** ** ** ***   **  * *** letterc;
     *** **** * ***  ** *  ** **** * letterd;
*  * ****  **        * * *  ** *   lettere;
* *  ********* *  *  **** **  
  *     ***   * **  *  **  ** ** *** %c %c %c  ** ** **    *  ****   * *   ** *      ** * *    *  ** **   *** * 
     * **  *** * ***  *  * **  ** = lettera + 3;
***  ** **     *** * *    * **  * = letterb + 3;
*   ***  *  *    *  ** *  * ** * *  = letterc + 3;
**    * *** *  ** *          * **  = letterd + 3;
*  ** * *    *  * *  ** **  ** = lettere + 3;
  **  * ******  * * *   *  ****** **** **** *** * *   ** 
  *    *******  *  * *** ** *    **  *    *** %c %c %c *    *    * *  letterb, *  *   **       *
***** ***** *** * **   *** *
** **** *  * *  ***   ** *  * ** 0;
}

  *
    * 
  **     *   
*  ** 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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