[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 4.3k views

22 Answers

0 like 0 dislike 
Hidden content!
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***           return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include **  **      *  *
#include          *  ** 

/* run this program using the console pauser or add your own getch,      ** *  * ***      or input loop */

int main(int argc, char *argv[]) {
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*** *** ** * *  *  *  *     * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** *   **  **    ****  
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int  **      ** char *  *  {
/*
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b = ** *
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 ***  *  * * * *  ** * *
*  *   * *    *  *  * *****

/* run this   **  *   ** the    ***  *** or add your own  *    *     ** *  * ** *    or ***   * * */

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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   * * **     *  ** **
*
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*
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* * = c + *

** = d +  
 
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
    * * **      *  
***  * * **** *   * *   

int  *** argc, char  *  *  {
 **** **   *      char  * *
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* **** ** * *    char * ***
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**        *  * * 
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*       *  ** *  ** =  * ** + 3;
* * *  *    *   **  = *     + 3;
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     *       ** 
**** *  ** **     ***  ********* **  *  * **** *        **   * *   **     * **
 * * ** *  * 
* ***  *  ***  ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *   ***   *  * 
*** * *      ** *  *   * *  

int *    *  argc, char *argv[]) {
  *   *  ** ** * char *  * *
*  *  * ***   *  char letteri;
 *** **      char     * 
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* * *  ** *  * 
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}


INPUT
    *** ** * * *** 
  *  ***** **
OUTPUT
***    * **   **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
***    ******  ** *
*   *  **      *

int *  **   argc, char *  ** {
*   *    * ** ** char  *** * 
 *  *  * * * *   char    **
**  * ** ** **** char *  **
** ** *    **     char ***    
 * * *  **    *** char ***
* *     ** ** **   
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* * ** *  * * 
 * * ** * ****** *** **  *** *  * *** * *          * **  ****  *  ** * * * ***     ** ***  *** *  ** * *  ** 
 *   ** *    * 
**  **     **  letter = letter + 3;
** * *  *** ** =  * + 3;
** * *  ***         =    **   + 3;
 ** *     * * *  ** *  =      * + 3;
* ** *  *   ***        = *  *  + 3;
  * ***   **   
* *   *** * *   *** ***  *    ** *  letter is  *** ** ***   **  *  *   *  ******  *        
   *     ***      
 ****   *  * *   return 0;
}

INPUT
  * *** * **  *
  *     *** *
****
**     * ***  ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *** * ** **  * * 

int main(int argc, char *argv[]) {
 *** *** *  ***  ***  ****** lettera;
*** *****  **  **    *** * **** * letterb;
  * ****** * * *   *  *  **** letterc;
***  * * *  *     ** **** * letterd;
 **  * **** * **   * *  *** * lettere;
     *  ***** *** *****    ** 
 **  **** **  ****  * *** ** **  * * %c %c %c ***** * *  **** **      * ** *  *  * **     * ** *   *** *  **** ** * 
  * **** *      * ***  ** = lettera + 3;
 * *  **   *   ** *   * *  * ** *    = letterb + 3;
 *** ** *   **    * **  *****    *   = letterc + 3;
** ***  * *   *   *  * *** ** **  = letterd + 3;
**  **** * *    * *   *    ***   * = lettere + 3;
 ** *   *    **** **     * * **  *****   *  *** 
**    * **  ** * *  *  *   * * ***    %c %c %c **     *  letterb,   *    **   * *
 *  * *  *   *  * * * ****
 * ****** *   * **  **   *  ***** * 0;
}

** *
 *  * 
 **  ** * *** * * 
**  *  
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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