[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3.7k views

22 Answers

0 like 0 dislike 
Hidden content!
*  * **   * *     *  * *

int  ** ** argc, char  * ***  {
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * * *  ***** 
#include **  ***** *  * *  

/* run this program using the console pauser or add your own getch,   * ***** *  *   * ** * or input loop */

int main(int argc, char *argv[]) {
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*   *   **  * *** *     **    * = a+3;
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*    * ***     *   ****    **   *  0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *  *   * **** * *****
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int   *** *** char        {
/*
* * * *   */

*   *    * 

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b =    
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*****   **  ****  * *** **  ** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  *    ** **   * *  ** 
**     *  * *  **  ****

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}
** *  **  *   ** *  *   *** *    * **    * **  
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**  *     ** *  * *    * 
*
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*    *  *

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** ** **

*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  *  *** *   * * *  
** *** ** ** *******

int  * *  argc, char ******* {
 *  ** *  * *  char **  * 
* * **   *  **  char *  *** 
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  * *     *  * **    = *  *  + 3;
   *    *  * 
    **  *      **    *  *  * ***   * *****     *   *  *****  * ***     *       *
  *    *** *** 
    **** *  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
     *   ** *** ***** *   *
*  * * ** **** *  *

int   * * argc, char *argv[]) {
* * * ** **  *** char  *   ** 
 *   **   * * ** char letteri;
*** ** ****  ** char  *  * 
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* * * *   * *  * char * ** 
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*  * **  *  
** *   ** * *   return 0;
}


INPUT
    * ***     *
    **  * *  ** 
OUTPUT
** *  ** **   * *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 * *  ***** *  * *** *
**** *      *  *     ***

int  *   argc, char   *     {
* ** *  *  * ** char *  
 ** *   * *    ** char ** *** 
*   **   ** char   *
  *      *  * char  * ** 
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 **   *  *       
*  *   **  ** ****** *****   input the * ***  to   *  *  * ** *  *** 
* **  ***   
   * *   * *** * * *** ** *    * *     **** ******  *     **   * * *     *   ****** *  **  *** 
  *    *   **  * * 
* *   ** *** letter = letter + 3;
** ** *   **    **   **  = * *   + 3;
***   *  * * *    *   = *  + 3;
    **   * *  * **  *  =  ****  + 3;
** *** **  ***    * * = ** * + 3;
   *          *  
**   **   *    ** *   * ***   * *** **  letter is  ****    ** * *****  ***    **** *  *** *   * 
*******  ** *  * 
 *   *  **   **** return 0;
}

INPUT
 *  *****  ** * *
  *     *     **
*** 
*  ** ***  *   *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *  * * * ** ** ** 

int main(int argc, char *argv[]) {
 *    *      ** **   **** *  * lettera;
* ****** ***  *   *  **   *  letterb;
*** ** *  *   *** *      ** *    letterc;
 * *** **   *  *  *  * *** **   letterd;
*    ** *****   ** * **     * lettere;
***     *  **  **** **     * **
      * *  **  ** **   **   **   ***  ***  %c %c %c * **   *    *** *  *    * *     ***   ** * * ** ***  * *   **   
 ** ***   *   *   **** * *       *  = lettera + 3;
  *   **   ***  * ** * ** = letterb + 3;
 *   *  **   * *  *  * **  ***  = letterc + 3;
   **     ** ***    ****  **  * *** = letterd + 3;
 ** ***    * *******  ** = lettere + 3;
  ** * *   *** *    ***  * * ** *** * ****  ** ** *  * *  *
    **   * *   * *  ****** **  *     **** %c %c %c  ***  *   ***** letterb,  ** *  **     *** * 
     ** ***   *  ** *  ***
  **** *    * *   * ***   *    0;
}

    * 
*   
 * *** * * * *
**   
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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