[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.8k views

22 Answers

0 like 0 dislike 
Hidden content!
* *  ******* ** *   *

int ***   *  argc, char *      {
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  * *** ** *  
#include  *  * *  *  ***

/* run this program using the console pauser or add your own getch,  ***   * *    **   **    or input loop */

int main(int argc, char *argv[]) {
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***  ****  *   *  ** ** = e+3;
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* * * ** **  * *   * * ** *
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   **  * ******* *** 
* *****     * *  ** * 

int ***  *    char   *   {
/*
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** *      

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a = a+3;
b =  *
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d = d+3;
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* ***** *** **  *  * *** *  * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *  *   * * * *
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int **** *    char ** ****  {
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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
******     * * *    

*      *** **    *  
*
    *    * *     *  * * *      *   * ** *    * **   **  ** *      ****    ****   * **  *** **  **
 
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*   = c + **

*  = d +  *

**  *    
 
** * *  * *  **    *    *      * * *     *
 
*  *    
*
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ***       *    * *
  *  *    **      *  * *

int ** **   argc, char ***   {
****    * ** char    **
  *   *    ** char ***
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***  *  *  ***  char *  **
***      ** *  * char *   
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* *  **  ** 
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* * * *   ** *  ***  =  **  + 3;
***     *  **  * **** = * ** * + 3;
*** *  ** ** letterc = ** **  + 3;
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* *** ***   
**  **     **    *  ***   ** **      **    *  *    **  *** *  *  *  * 
**  ** *** * *  
 *** *   **  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *  *   *  *  
* ***  **      *  **

int  ***  argc, char *argv[]) {
   * *   *    ***  char ** **
**  ** * * *  char letteri;
    * * *****   char * **
******     *  * * ** char  *    *
*  *     *       char  ***
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****  ** ***  * 
** * *    ** 
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*  * *  *   *  
** ***  *  *  return 0;
}


INPUT
**  * * * * ****  *
**** *       
OUTPUT
 * *     *  *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   **  * *      *  
 ** **   ** **** *  *

int  ** *   argc, char *   *** {
*** ***        * char  ** 
 *   ***  ** * ** char  * *
*  *   * *   char  **** 
  **   *  char  * ****
 * * *  ***   char * ** **
*  ***  *** * 
  **    ** * *         ***    input the *  *  to ****   * *   *     ***
   * *   ** *   
**** **    *    **  * * * ** **    ** * ****     *   **  **** ** *  ** *    ** * *   **   *   *
*  * *  * *   
*** **  *    ** letter = letter + 3;
* *     *** **      = ******* + 3;
 ****  *  *      *   =   *   + 3;
    **    *   ** * = * *  + 3;
** *    ***   *   =  *** + 3;
* *      *  ***  
 *    **    * ***** *    *** ** letter is ** *** ** *    * *  ***   ***  * *  **   *** *
*   * *   ****** 
   *   **** ** return 0;
}

INPUT
* **** * * * * *   
  **  ** **  *
** *
         * ***  *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *  * *   * * ***

int main(int argc, char *argv[]) {
   *  **   **  *** *** * * ** ** lettera;
 *    **  * * *  ** ***   letterb;
** ** * * ***   *  * * *  ** letterc;
 *  * *    *  * *  **    *** **   letterd;
   *  *** ** **   *     *   * lettere;
 * *********   * *   *  *
***    *    ***  *  ***  *  **    %c %c %c ***   * *  ** *    ****   * ** **   *  *****  *  ** **  * ******* *   * ** **  
   *  ** **  *   * ** ** * * *  ** = lettera + 3;
  **** **   ** *** ******* *  *  = letterb + 3;
 *  * **    *   * **   *  ****  *  = letterc + 3;
  ****   **  ** ******* *  * ** = letterd + 3;
**  ***      ******* **** *  = lettere + 3;
***   **  **  ** ***    ** **      ****  *   ** * **  * 
** *  *******  * * *   *** *  **   **  %c %c %c *    *** ** *** *  letterb,  ***  *****  *  **
    ******  *  *   ****  *  **
 * ** *    * **  *  * * * **   0;
}

**  * *
* *  * 
*   **    *** *
    
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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