[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3.7k views

22 Answers

0 like 0 dislike 
Hidden content!
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int *  * argc, char ****   {
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  *** * *  ***  *** 
#include *** * * ******

/* run this program using the console pauser or add your own getch,        * * * *****   * * or input loop */

int main(int argc, char *argv[]) {
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**   * **       ***** ***  ** 
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**** *  *  * **    *** 
***  *  *** * **** *

int  ****     char * ****  {
/*
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*    ***   

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b = **
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**** ***    * ******  *
*  *  * *    * *  ***   *  *** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**     **** **     ***
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}
*  * ** ****    * * * **  * * * *     * 
*** **     **  ***  *  * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
****   ***   **  *  ** 

*       ** * * *** ****
*
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** = c + * 

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*    *  *
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*
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  * *   **  *    *  ***
  *   * *  * ** *  *

int *** argc, char   ** * {
   * **    ** * char   * * *
* * *   *****  char   ***  
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** *** * *   * ** **    = ***  + 3;
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* *  * **** * ** *****  * *** *** ** *   **   * * **  * *      ** *   ***
* *  **** * *   
 *  *** * ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
***      *   *   *  ** ***
* * ** ***  * ** * 

int ** *   argc, char *argv[]) {
* **   *   **  *   char   *  
  * ** ** ******* char letteri;
*  * ***    ** * char * *  *
* * ****     ** * char ** * 
* **    * *   char    ** 
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* *    *     ** ** 
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** ** *    *** *  ******* *** +3;
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** * ** *   * *   ***   *****   **** *    *  *    *      *  * *** *   ** *
*** *  *   * *  *  
*  *  **   *** return 0;
}


INPUT
 * * ** *  ** * 
  *****
OUTPUT
 * **  ** ** ****  *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* * *    ***   
***   * * * ** *   * * 

int ** *  argc, char *      * {
 * * *   * *  * * char    
*** * *  *   *** char  * *  
*  * *  ** *** char *  * 
    *  *****    char *  ** 
**  * **   *     char *  ***
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***** *    * *  * ***  *     **   input the *  * to      * * *   *  *  * *
  ***     * 
******     ****    *  *** ** ** *****  *   * ***       * *  ******* *** * ***   *  * * **** * ** ** * *    *
* ***   *  * * * 
 ****   *   letter = letter + 3;
       * * *    **   * * =  *     + 3;
* ***** * ***  * ** * *   = * * + 3;
******    * **  *** = ** *   + 3;
*    *    ** **  *    =  * *  * + 3;
 ** *  * * **     
 ** *   * *         *** **   *  ***   letter is  *****    ** ** ****      *   ****   * *  *****
 ** **    *  *   
 **    ** *  return 0;
}

INPUT
 **    *** *  * *
  *** ***  * * 
*** 
** * *   ** ****
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ** **  *****   

int main(int argc, char *argv[]) {
** ** ** ** ***** *** *  *    *  lettera;
*****  *** **** ** * **   **  * * letterb;
   * *** ** * **   * * * * * * letterc;
 * * *  * ** * *   *** * *    *  * letterd;
** **** *        ** **  **  lettere;
   *  *   *  ** * *   ***
 ***   * *** *   *  *  ** *   * * *  * * *    %c %c %c  *   *   * * *  *  *     * * ** *  *   *** **  * **    **** * ** ** 
*  * *  *  * *  * ***   ***   * = lettera + 3;
*** *  **    *** ***    *  **  * = letterb + 3;
***  ***    * *   * *  * = letterc + 3;
   *  **  *     **  **  *  ***     = letterd + 3;
*** ***** * * *** * ** * ** ***  *  = lettere + 3;
*** *****   *  *** ******** *  * **  **       *    *** *   * 
*  *  *     *  ***   ** *  * *** ****  %c %c %c   ***  *** letterb,   * * *  *     **  
****   *  *** *   *   *** *
  ******  *      ***  *     * 0;
}

** *
*  **
 * *   * *  *  
* *  * *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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