[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 4.3k views

22 Answers

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Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include        ****** * *
#include *  * * **  *** 

/* run this program using the console pauser or add your own getch,   * *     * ****   or input loop */

int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   * * *  * **** **    
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int ** ** * * char **  *** {
/*
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
** ***   ** * * **  **  
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int *       *  char  **** {
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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ***    * **   * **   **

** ** * *** ** ***  ****
 
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*   **  ** *    * *       *  * *** *   ** *  *****     * * * * 
 
** =  *  
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** = d + **

*       *
*
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  *     **

100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  **   *****  **** *  *
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int  * *** argc, char   {
  ** *   ***   char **   *
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**** *  **** *  * *  =  *  + 3;
** *  * *  *  ***   =   + 3;
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*  ** ***   *  *** 
    *  ***  ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *** * ** *  **  *   * *  
   ** ** *** **        * **

int  *  *  argc, char *argv[]) {
   *     **** char ** **
***   ** * *** char letteri;
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* **  *  **  * ** char **    
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******* **  ***  
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****  *  ** ** 
* * *  *  * *** ***** *  *** ** *    ******  *  **  *     * ****** *  **   *  **      * *  **   * ** *     * 
****  *  *** **  ** * * *  +3;
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** *       * **  **** ***    ***** * ***  * *   ***  *** **    *** *    * *
* *  ** ***  
** * *  **   *  return 0;
}


INPUT
**** *      * *
 ***  * * *** ***
OUTPUT
* ***** * *  ** * **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
    **  ** *   *  ***  *
 **   *  **  *  *** * ***

int *  * argc, char  *   * {
  ****** *     char   *  
* *   * *** *** char  * *
 * * *    **   char   * *
   ****  **** * char    * * 
***  * *    **  char * * 
*  * ** *  *  
 * * * ***  **      *  **  * input the ***   to  ** ** *     *  
* *  **    **   
****         ***  *** * * ***** *  * * ** *     ** * ***** ****   *  *   *  *** *    *   *     * **  ** *  
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   **  * **** letter = letter + 3;
* * **  ** *   ** =  *** + 3;
*    *   ****    *  *   = ***   + 3;
 *   ** *****    * *  =  **   + 3;
*   * *** *     **  =     * + 3;
  *   * **  **  
* ****   * ***    *****  ***    ***  letter is * * **   * * ***   ** ***  * *** * **  ***  **
**      *** *  
 ** **  ****   return 0;
}

INPUT
  ***    ** **
 * ****  **  
 ***
***      * * *** *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * *   ** *   *

int main(int argc, char *argv[]) {
*  **** ** **  *    **    * * * lettera;
 * **   *       **        *  letterb;
** *  ***        * ** *  * *  * *  * * letterc;
   **   ********** ** ** *      letterd;
* ** ** **   *    * *  ***   lettere;
*     * * ******* * ***    *
**  ****   * * * *  * ** **  *  *  **  %c %c %c    ** *    *  **      *****  *  **** * *  *   ** **** *  **  ***   
  *** **        ****   * *   *    = lettera + 3;
***** ******     ******  * *  * = letterb + 3;
     ****  * * *  ** **  *  **   = letterc + 3;
***** ** ** * **  * *  *  *****   = letterd + 3;
***       *  *** ****  **** **  = lettere + 3;
** ****    *  *  *** *** *  * ** *   *** ** ** *** *  * * 
        *   **********  *** *  *  ** %c %c %c  ******    * **   letterb,  *    ** * *** * 
* * ***     *  *  *** *    **   
*    *      ** *    ** **    ***  0;
}

* ***** 
***   
 **   * * *  *
*  **
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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