[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 8.8k views

22 Answers

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Hidden content!
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int  **** *  argc, char **    {
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**    * * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
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Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ***           *
#include ***** * * ***** 

/* run this program using the console pauser or add your own getch, * * * **    *****      or input loop */

int main(int argc, char *argv[]) {
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**    **  * **   ***** **
***  *   *    *  ***    *     ***  0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *    *  **** *  * *
**** * *  *   ** ***

int    *  *** char ** ** {
/*
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*    **  

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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* *  *   *** ***** * 
**  * ** *   * **    * **

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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** *  * ** *     * 

** ** ** *  * *****   ** 
 
* *     *    ** * ** *      *   *      *  **  * *   *** * ****  *  ** ** **   *  *  **  **  **
 
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*** = c + *

*  = d +   
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** *  *  *     *  * 
  ****   **** * *  *   

int ***    argc, char * *  * {
*     **   **   *  char *   
*     **   *   * * char    * *
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** ** ****   *  = *** + 3;
**     *  **   * *** * =    * * + 3;
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* *   **   **   
*     *** *  * * ***   * * ** **  *  *****  *  *  *****     *  * * ** * 
* *     * *     
**     ****    return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  ***        ** ********
* ** *    * ***   ** ****** **

int * *    * argc, char *argv[]) {
* *    *  *   **  char  * *
 ***     **  char letteri;
** * ****    **  char  ***
*       *** * ** char    * 
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* * *  ***    return 0;
}


INPUT
   **   *      ***
   *  * * * **
OUTPUT
 *  **        *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**     * *  *  * *   *  * 
 *  ** *  ** *  **   **

int  *  *  argc, char *      * {
   *    *****  char  *  
  **       **  *  char  ** **
***   * *** char   * *
****   **  **  *  char * *** 
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*  **** ***** 
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  * ***     *   
* *  **  **  *** ****   ***  ***** ****    **    *** * ** **    * * * * * *    * ** *  **** **  
*** ***  ** 
******  ** *  * letter = letter + 3;
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***   *  * ****     ** = * *** + 3;
*  *  *   **  *  **** = **  *  + 3;
** * **    ** * * * =   ** + 3;
*    **   * 
*   *  * ** **     *  * *       *  letter is  ***       **     *      *    *   **  *  *  ***   
*  ****  ***  * 
****           *  return 0;
}

INPUT
  *   * ** ** *
 *  *      
* 
*** ** *   ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  * *  *          *

int main(int argc, char *argv[]) {
* * * **     * **** *   lettera;
* ** ***     * ***** *   ** *  letterb;
* * *    **   *  ***** *    *  letterc;
* **** * **   *   *** * *   letterd;
* * * * ****   *  *  ** * **  *  lettere;
    **  * ** *  *     **** **
**     *** *****  ** **      *   *** *   %c %c %c    ****  ***  **** *      *** **    **  **  **  ** ** *    **       *     * 
**  * ****** **        ***** = lettera + 3;
 *  *****  ****  * ** * ***   *   = letterb + 3;
 * **   **   **  *   ** **  ***** ** = letterc + 3;
  * ** *  ***    * **  ** *   *   = letterd + 3;
*   **    **  *****  * *    = lettere + 3;
* *  **  ** * *      *  **   *  * *  *     *    *  **    ****
********** * ***     *   ***   *  ****  *  ** %c %c %c  **       ***   letterb,    **   ******  * * *
 *   *  **** * ** * ** *  
**** *  ** *** ** *  ****   *  0;
}

* **  *
**** *
* *** ***   *  *  *
 *    
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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