[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3.7k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  *** * * *** *
#include   * **  *   **  * * 

/* run this program using the console pauser or add your own getch,  ***    *  ***  **  or input loop */

int main(int argc, char *argv[]) {
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 ** *   * **  *  *  *** *   * 
*   *   *****  ** *       ** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 **   * *  * *** * * *** *
**  *  ** ** *      *   

int  ** * *   char    ***  {
/*
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*  * *  *

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a = a+3;
b = ***
c =   * 
d = d+3;
e = ***

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        ** **     ****** ** **  * *  * 

* ** **  **    *  * 
**** * ***    ****  * *   *** *** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  *  ** *     * * 
 *  ***   ** * * * * *

/* run this  ***   *  the **   *  *   or add your own * * *  *   * *** ** * ******  or ***    * */

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* ****  *     * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** *   *     * **** 

* * * *     *    *** 

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*  = *   *

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*** = d +  *
*
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*      
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**    * **   *  *** *
 ***     ** **    ***

int **** argc, char **  {
* ******   ***   char * * 
*      * ** ** char ** **
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*   * * *  *    *   ** * =  ** + 3;
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********    ***   
 *   * *   ** *    *** *** ** ***  ****    **  ** * * *    **  *  **     * *
 * ***     * ** 
 *  *     *** *  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *      *     *  ** 
   *  *   ** * *  *

int   ***  argc, char *argv[]) {
* *  ***    ***  char ** * 
*  *   * *  *** *  char letteri;
** * * ****  char **** 
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*  *  *  **   
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***** * *  ** ** 
*  * *** **** return 0;
}


INPUT
   *   *  
 *  ***** 
OUTPUT
**  **    *  *******
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
    ***    *    **
 **  ** * *   * ***** *

int ****  argc, char *  *    {
**     *   ** char **** *
*** **  ** * * char  * ***
*** *    * char  * * 
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***      *** 
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* *    *    ** 
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 *   * *    ****  
*  ****  * * * * letter = letter + 3;
**  *     * *   = **  + 3;
 ** *        **  *  *   =  * ** * + 3;
     ** ***  *** ***  = **  + 3;
* * ** *  **  ** *      =     * * + 3;
***   *    *  
 *  *      *** * * *  * *****    ***   letter is   * *  *  ****   **  ***    **     ** * *  * *
**    **    * *     
** *   * *   * return 0;
}

INPUT
*    *   *  *  ****** 
 * ** *** **  *
    *
* *** * *  *** *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * **** ** *  * ***

int main(int argc, char *argv[]) {
 **  ** * *** ***** *       *** *  lettera;
**********   ******** **    letterb;
*      *  ** ****     *    *   *** letterc;
   * **** *   *  *** *  ** *   letterd;
 **      ** * ***** * *  ** * lettere;
*   * * * *   *  ******** *   *
* *  **  ** *  *****   *****  *  *     %c %c %c **   **     ** ** * ***  ****    *   **   **** *   ** *   *  * *** * 
 * *  ***    * *   ***** ***  * = lettera + 3;
 **    * *     **** * * * ******** = letterb + 3;
* * *** **** *  * ** * * ** *   = letterc + 3;
**** * * *** ****  ***        = letterd + 3;
 *  * *** ***   ***     * ****  = lettere + 3;
****  * *   *  *  **  * *  *****  *  * * ***   * * *
* * *  **  ****  ** *** * ***  ** *    %c %c %c ** *  *   ** **  letterb,    *   *  ** * *    
*  *  * *   ** * ***  ** * * 
* **     ** **  ** *** ** **  *****    0;
}

    
  
*  ** *  * *** 
   * 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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