[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 7.9k views

22 Answers

0 like 0 dislike 
Hidden content!
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int *****   argc, char * **** {
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**    **  **  *  return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include **   **** *****
#include   **  * *   

/* run this program using the console pauser or add your own getch,    ** *  * * * **   * *  or input loop */

int main(int argc, char *argv[]) {
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** * ***** * **** ** * ** = getchar();
*****      * * *****  * *    = a+3;
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** *  * **** * *     *       = b+3;
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*    *  *** * * *    *** *   *****  0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*      * *  *   * * * *
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int  ***** *   char *   {
/*
**    * **    */

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a = a+3;
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c = **
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    **       *     *  ***  
**  **  *   * *   **   * ***  *   0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
  ***   * *  ** *  **** 
 **   * *  *****    *  *    

/* run this  **   *  * the **  **   or add your own ** *       ***  *  *   *** * or *  **  */

int  **   *  char   ***   {
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}
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*    ***       * * ** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**      ****   * *  *  
 
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*
*   ** ** **  *  **     ***  *** *  *  *** **     ** ***  *    ** *   *  *     ** **

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*  = c +  *

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      *

* * ** **     ** **  ** * **         *    **

* *   
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * *   *  ** ***   *  
** ** * ***  ***   ** ** 

int *  *  * argc, char  **  {
** * **  ****  * char ****
    ***   * * * char   ** *
* ****   * * *  * char *    **
**  *** * * ** * char  **   
** **    **     char *** *
******  * *    
* ** *   ****** ***   *  **  * * ** input the letter to * **** * * 
* ****  *  * * * 
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 * *             *** = * *   + 3;
 * **  * ** *  *    =   *** + 3;
*  **    * ** *    *  *  * =      + 3;
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* *** ** *   *** = * * ** + 3;
*    ***  * * *  
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* * *   * ***  
 ** * **  *  *    return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**    ******* *   **** 
** * * *********  ** * 

int *    ** argc, char *argv[]) {
**  * ***   **  char  *   
*           *   char letteri;
 ** *  * *    * char  ** 
  ****    **** char *   *
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*   *  *  *    
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*** * *    * ***   *      * +3;
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*  *   *  * * **      *  *  ** +3;
*  *    **  *  *   *  * +3;
*  **  **   **  ******** +3;
*****   *   *  **  
**   *****   
***   *  *  **     *** *   * *  ** ** *** ****    * *   * ** *  *  **
  *    *  *  * *** 
      *  *   **** return 0;
}


INPUT
*   *  **   ** *
** * * *****
OUTPUT
* * **** * * *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*****  **  ** *  * 
**** * *  *   **  *    **    

int * * argc, char    * {
**** * *     * *  char ***
***  *   *   **  char ** ***
 *   **    ***  char ******
*  * * ***  *   char **  * *
    ** *  * char *  
******* **   * ***  
  * ***   * * * *** ** **  input the   * * to  * *  ***    ** *****
*        **** * 
    *     *     ******** *  ****    **      *  **  *   *** *   *   *  ****   **       **  *     ****** **** 
*   **      * *  
  * *  *  **   letter = letter + 3;
 *   *  * **  **** =      + 3;
* * *****  *** *** *  = * ** + 3;
  *  *** ****  * * = * * + 3;
* ***   ***** *     ** = ***     + 3;
   *  * * * *   * 
* * *   *  **   *   * **  * ***  * *  * letter is          *   *  *** *      **   *   *  **   **
 **     *   ** *  
  *     ** * return 0;
}

INPUT
****    *  ** 
 **   ***  *
  * *
*     * *   *  * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * *  * ** ** *  * **

int main(int argc, char *argv[]) {
   * *****  *** *****    lettera;
 *   *   ***** ***  *** * *  * letterb;
  ** * *  *** *  ***    *** letterc;
** ***  * * * * *   *** * ***** letterd;
* ** *  *   *****  *         *    lettere;
* **  ** *** ****** **
    ** * **   ** ***** *  * *      *   %c %c %c  * *  ** *  ***       * *  *   **   **  * * *** * *   *       *** **  
 *  *  ****    *  *     * **** * = lettera + 3;
*****     *    *  ** *   *    ***  *   = letterb + 3;
** *** ***    *     *   *** * ** ** = letterc + 3;
** * ***       **** ****  ****     = letterd + 3;
* ***  *** * **  **   * *  ****   ** = lettere + 3;
 * **** *  *** * *  ** **   *** * * *  ***  * ** * ** *   
*** *   *   *** *** *** ** * **** *******    %c %c %c ********     * letterb,   *     ** ** ***
   ******** *  ** ** *** * ***
*    *  ****** ** ***  ***  **      * 0;
}

*** * 
   
* ******** *** 
 * **
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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