[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 9.7k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include    **  *****   ** *  
#include *     * * * ** 

/* run this program using the console pauser or add your own getch,  * ***   ** ***  *** or input loop */

int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *  ******** * *
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int *** **** char * *  * {
/*
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* *  * *    

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a = a+3;
b =     
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* *****    **   *   
****  ******* * **** * ***  *   ** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
  *   *     ***     * *
* ****      * **   ** *

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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
***   ****** *   *  
 
** *       ****** * ** 

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*   b + * 

** = c + *

* = d +  
 
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*
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*
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** **  ****      *     
**     * ** ** *  * 

int ** *** argc, char ***  * {
 ** *  * **  char   *   
 **  **   *** * char  *** *
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 **    ** *       * ***** ***  ***** **** *** **  **    ***          *    ** *  ***     *  ***  *
 *** * **  *  * **   = ** * + 3;
** *   *   **  **** *  = **  + 3;
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*** *   *** **   
*  *    ** * *  **  ** * * ** * ***   *  ** *    ** * *** *  * * *     * *
   * ** ** * 
 **  **  *** ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* **** * *** **   *  
****   ******  *  ** 

int * *    argc, char *argv[]) {
** * * *     char * *  *
 *  * * * ***  char letteri;
****  ** * ***** char **  
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****   **   * 
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** *    **   *   ***** ** +3;
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* * *   *  ** 
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*** **  *     *** return 0;
}


INPUT
***** *     ** *
****  ** *****
OUTPUT
**   ******* ** * *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**  * * ***   *****
* *    * ** *  * * *  

int  *** argc, char  * *  {
*  *     **    ** char * *
*  *      *** *** char **
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    ***** **  *  char *  
*** *   *  ***  
***     *  * *** *  *   *** input the * ** to  * * * *   ** * * *  *  
** ****         *  
**   * * * ** * ***  ** ***** ** ****  * * * ****  ***    **  ****  ***** * * *   *     ***     * *  *** 
 * * *   *    
 *** * * **   * letter = letter + 3;
 *** *** *  ** ***   *  * = ****   + 3;
        * ** *  *   *  = ***  + 3;
      * **  *   * *   =  ** + 3;
    *   *    ** *  *** =  *  * + 3;
* * * *  **  **  
 *   *     *      * ** * *    *  letter is * * **  ****  * * ***  ***           **  
****      * 
**   *  * *  return 0;
}

INPUT
        *     *   *
* *** * ** **
 *
* ****   * *   *  *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include **  * **  * *

int main(int argc, char *argv[]) {
** ***    ** **  *   *** * **   lettera;
 ** *  * * **** *  *    ** * **  letterb;
***  *** **  ** **  *       letterc;
  **** *** **** ***** *   * letterd;
**  **  *   * ** *  ** *  ** *    lettere;
 *******  *** * ** *  ** *
 *  * * * *   *   *  *  * *  **** ***  %c %c %c *******    ****  *  * *  ****   **   **    ** **    ***** **  * * *   * ** 
   * * ****  * *** ***  **   *  ** * = lettera + 3;
     * *     ****** ***** * * *   * = letterb + 3;
* * * *  **** *** ** ** * ****** = letterc + 3;
  ** *  * *  *****  **     ** * *  = letterd + 3;
 *   *  ***** ** **  * * *  *    = lettere + 3;
    **** **  *** *    ** ** *   ***   ***  ****** **  
   *  *** **     * * ******* * **    %c %c %c  ** **** **  * letterb,   *  * * *     **  *
  *  *****  ** *   *** **
 **   * *  ** ** *** ****** 0;
}

 *  *  
*   * *
   *  ***  * **
****  *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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