[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5k views

22 Answers

0 like 0 dislike 
Hidden content!
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 * ** * ****  * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ***     * ** *** 
#include *  * **   * **

/* run this program using the console pauser or add your own getch,  * ****   *  *  ** *   or input loop */

int main(int argc, char *argv[]) {
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*** *   * *  * * * **    **  * * * *
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** **  *  *** * **  *****  **** = e+3;
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   * *      ***   ** **
*    * * ** * *  ** **   ** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ** **  *     * **  **** 
** ** *          ** *   

int * ** * **   char ** *    {
/*
*  * **       */

     *   

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a = a+3;
b =  * 
c = * 
d = d+3;
e = **

* *** the   * *    ** 
***  * * **  *****
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** **      *   **  *  **
 * ******* ** * * *  * **  ****** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
  *  * *    *****      
**  *  *  ** ** * *   * **

/* run this *    * * the *  *   * or add your own ****    ** **   ***     ***  or     **  */

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}
** **  *    * **  *  *   * *  *  *    * * *
*     *  *  *  * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
       * **  *   * ***    **
*
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* *   * ** ** *  *  * *  * * **  * *    *   *  * * * *    *   *          **

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* = c + * 

  = d + *
*
   *    * 
 
**   * *  ** ****** *** *  * * * * * ***  * * *

*****
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
     *     ***   *  **
 * **   *   * *  * * *  **

int *   * argc, char ** ** * {
  *     * ***** ** char   *    
    *  *** ** ** *  char * ***
 ***      * * char **    
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*  **       **** char     
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* ***    **  * **     ** *   *  * *       * ** **  ***  ** ** ** * ** ***     * * * ***  * *** ***
 *** *     *   * *** = * **** + 3;
      *    ****  *** * =  ** + 3;
  ****** *  *    *  * =  **  + 3;
 ****** **  * *  letterc = ** * + 3;
* *  **  * * * *** * **   = * *  + 3;
*  * *     * *  
  ** *      * * **  *  *  **   *** * **  *  **     *  *** **  ** * * ***    *
* ** *   *   
** ***** ***     return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** ** *      **
* *  **   *  ** *     

int *    argc, char *argv[]) {
**  *       *   ** char *   * *
*  * *   *  **** char letteri;
  * *     *  ** char   * *
 **  **     **  char   ** 
*      *    *** char ** ** *
 *  **     ***  
 *  * *  *  ****   *     input the letter to encode: * **** *** * *  **
 * ***   * *  
*  *    *    *  * *   * ** ***      ** ** ****** *   **  **** ***  *    *     *  * * *  **  ***** *
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 * *   * * **     *      +3;
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***  ***  * ** *** *  * **    +3;
  *** ** **  *  
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*****        * 
 **    * ** *   return 0;
}


INPUT
**    *****  
*    * ** **   
OUTPUT
*******  **  ** **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
  **    *** ** * * * 
 *    *     * * * *

int  *    argc, char * *  {
**  ** *  * * char    
****   * *   char **  
* *   * *** char  * ** 
   *      ****   char **     
**  **  *  ***   char  *  *
  **      *** ***  
**   * * * ****    *** * *  *   input the    ** to  **  ** **  * ** *
 ** ***    ***  
  * *   * *   **** * *  **  **  * ** *  *    * * *  ** *  * *   * ** ***   *   * * *  **** * ***
** **    * *  
*   *     ** letter = letter + 3;
   **  * * *     * ** =    **  + 3;
 *    **    *  * *  =   * + 3;
*     *   * ** **  *    =   *  + 3;
*** *   *  * *** = *   + 3;
 * ******   * **  
      *  *      **  ***      ** letter is   *     ** ** **   **        *   ** *  *  * 
   *   *   * 
** *    ** *  return 0;
}

INPUT
**  *** * * *
* *   *** **
*** 
    *   * ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   ** *****   *    

int main(int argc, char *argv[]) {
 **  ** * *  * * *  * *  *** lettera;
 *   **  **  **  **        letterb;
****    *****  *  **  *      * * letterc;
  *   ***         * ****    letterd;
* ****** *  ** **** ****  * * lettere;
**     ***  * **    *  *  * **
** **       *   *    *  * *  * *  %c %c %c **   * ****  ** ***  ** *    *****  *         ***       * *   ***   ** * **  * 
 * **  *   * **       *   ***    ** = lettera + 3;
* ***   *   ****  *** ** * ** * ****   = letterb + 3;
* * * ***** *** *  *  * ** *  = letterc + 3;
* ** **  *  *   *    * *****    = letterd + 3;
*   * ** * *     **    *  * ** ***  = lettere + 3;
   * ** *   ***** ** *  *  ******* *       ***
** * ** ***   * ****  *   *    ** ***  **  *   %c %c %c   ** **   * * letterb, **  *  ** * *      *
**  **  *** * * ** ** **   
*** ** * *     *   * *   * * 0;
}

*  ***
** *
 *    ***  * **
* *  
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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