1-11 Exercise 3: Prefix of a string

Question

13.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited Jan 11, 2018 by semicolon | 13.7k views

27 Answers

Page:

Diyiel · Answer 1 · 2018-01-13 00:58:32

Hidden content!
#include *   * ** **   *    
#include *  **       * ****

char prefix(char s1[], char s2[])
 {
 int i;
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{
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}

answered Jan 13, 2018 by Diyiel (-193 points)

Stephen Richards · Answer 2 · 2018-01-13 00:46:20

Hidden content!
#include **  **   **   *
#include  * *   * ** **  **  *

int prefix (char st1[],char st2[]){
*     * **  * **  ** ** len=0, i, cnt=0;
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** ******   **  * ** * *  * 
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 ***  **** **** **   * * ** 
}

int main(void) {
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}

answered Jan 13, 2018 by Stephen Richards (323 points)

ryan · Answer 3 · 2018-01-11 22:07:28

Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
 ** *    *  * *** *   **  ** * ***   * ** *   
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    j=strlen(a);
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}

answered Jan 11, 2018 by ryan (-301 points)

Headshake · Answer 4 · 2018-01-11 21:22:34

Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
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** * **    ****  *   * * *  **  *  0;
}

answered Jan 11, 2018 by Headshake (-281 points)
edited Jan 13, 2018 by Headshake

Sabrina Lin · Answer 5 · 2018-01-11 21:03:22

Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
  *   ***   *  * **    ** *** a[100];

*   *     ********  ** **  *    b[100];

** * * * ** ** *  ******* ** * i = 0;

*  ***  **   *** *** *** prefix = 1;

* *  ***  **      **** ***  *   * *   *  *  a, b);

 ***  * *  ******  ** *    len = strlen(a);

 *****  *   **   * *   *        * = 0; i < len; i++)
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     **  ** **   ***    **  *   
}

answered Jan 11, 2018 by Sabrina Lin (-285 points)
edited Jan 11, 2018 by Sabrina Lin

watty1998871108 · Answer 6 · 2018-01-11 21:00:46

Hidden content!
#include  ** *   *   **** 
#include      **   *** ** 

int main() 
{ 
* **  * *****  ****   * * *    * a[100],b[100]; 
 * *  * ***   *** *   ***** i,j,prefix = 1; 
 **   **     *         * *  * * *   *  * %s",a,b); 
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   * **   ** *  *******    = 0 ; i < len ; i++) 
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**   *  ****** ***  *  *   *** *  **   * *** *  *** * *   

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*  ***      *   ** **  *   ***   * 0; 
}

answered Jan 11, 2018 by watty1998871108 (-127 points)
edited Jan 17, 2018 by watty1998871108

prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'

commented Jan 17, 2018 by The Judge (4.3k points)

prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'

commented Jan 17, 2018 by The Judge (4.3k points)

Sammi0208 · Answer 7 · 2018-01-11 21:00:08

Hidden content!
#include <stdio.h>
#include *     ****** * 
#include  ***  *     **

int main()
{
  * *   *** ** **** * * *   ** **   a[100],b[100];
 ** ***  ** ***** ***   * * **** i,j,prefix = 1;
*** *      * *  *******  ** * ** **** %s",a,b);
  ****  **   * ****** **** * len = strlen(a);
 **     **  ** **** * *   ****    = 0 ; i < len ; i++)
** ** * *  ** ** ** * *
* * ** ****   ** *** *     *    *** *  *****         **  != b[i])
 * * * *       ** ***  *   **    *  **  **   *** **** * ** *
 *      *  ** *     * * **  * ** ** * * *       **     *****  *** * *  *   *****  = 0;
* ** ***     *    **** ** **  *    **** *    *  *  *  ****   *    ** **  *  * * **     * ** *** is not a prefix of %s",a,b);
  ***  **  *  **  *  ** * * *  *   * ****    * **  *      *  *** ***  *
********* *** **  *****  **  ** *  ***  * **** ***

 * ****  *** ** * * * *** * 
**  *****     *     **  **** *      ** == 1)
 ** ***   *  *    **   ****    ****  *      ** ***   ** *  is a prefix of %s",a,b);


 *** * * * *    * *  **** *     0;
}

answered Jan 11, 2018 by Sammi0208 (-255 points)
edited Jan 11, 2018 by Sammi0208

410530022 · Answer 8 · 2018-01-11 20:46:02

Hidden content!
#include *   ** ******
#include  *** *   *  * * **

int prefix(const char *pre, const char *str)
{

 *   *****  * * *** * *   *** * **   *   *  *****  ****
* ********  * *  *     **** *** *    *   ***** *   *  0;
  *  * ****** ** **** * ** * **  **        * ** *  *
  ***  *     *** ** * ******* * **** **  *    *  *   ** ** **   1;
  * *  ****** **  *   *** return 0;


}

int main()
{
** *******     ****   *     **  pre[100],str[100];
* * *** *  * ** **** **
********  ***** *  *** *   **  **  **   ** ***
 * * ****  ** *****   *  *** * **** *
 *  *   *   * **  ****    *  ** *  ** *    ** *** * * **     * *** ***  is a prefix of %s",pre,str);
  **** * *  ******* * * *   
* **** * * * **    **  ***  *     *   *******  * **   * *** * * *    ** is not a prefix of %s",pre,str);
 *****  ******  * *  *** *  *** *** * 0;
}

answered Jan 11, 2018 by 410530022 (-196 points)
edited Jan 11, 2018 by 410530022

LinJingYao · Answer 9 · 2018-01-11 20:28:50

Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 * ***    ***** **  *  *  c;
*  * ** **** ******** ** *** **** * * * * *
****** *       *    ** ** * *     * *** * *  * ** * ****  *  * 0;
 ******* **** * * ** * * * *** 
   * *   ** *  * * * * ***** ** 
** ** * **  * * ** *** ** * **   **   *  *** *    * ** ** ** * *  ***  * *****   **     of a string
  * * ** ** *  **   ***** *  ** ****** *** ** *  ** *** * *        * ********  * ** ** **
 ** *  * ***    *         ** **   *** ** *   *** ** ** *   ***   **** * ** *      ** * ******* ****    *  * * * ** 0;
 **  ***    ****  ****    *  * *   **       * * * * *
**  **  *   **    **       * ****  * **   *** ** *  * 1;
    }
}

int main(){
 *  **   **  * *  * ** *     a[100],b[100];
*   *   **   *  **** * *   * *** ****  *  %s",a,b);
 *  **  *    *** *  **     ***  *     **
   * *** *    ** ***   *   *  *** *** * * **  * ******    **   ** is a prefix of %s",a,b);
 *   **  * ** **   **   
 *** ** **** **  **  * ** * *  * *** ** **  *   *   ***** ***   is not a prefix of %s",a,b);
 *  ****** *******   * **   *  0;
}

answered Jan 11, 2018 by LinJingYao (-498 points)
edited Jan 17, 2018 by LinJingYao

VincentXV · Answer 10 · 2018-01-11 20:05:37

Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* *     ***  *  *  * ** ** * p[100],s[100],a[100]={};
***** * **  *  *    ** *  ** ** * * * t;
*  **   *   * ***  **   **** * *    **   
** ** *****  ** ** **   ****        ***** 
  ***  *** *   *  ******    * * **   ** *  * * %s",p,s);
***  *****   ** **** ** * ** ** 
 ** ***  *  **        **  ******
   *  ** * * ****   * * *  **   ** 
**  **** **   * ****    *** ** *  *** *  *  **  
 **    *   *** *  ***   *   * *    *  ***
*   * **  * ***      ***  ** *    ***  *  **  *      **  **** * is a prefix of %s",p,s);
** *** * ***  *  **    ** *    
 *****  * *  **  ****    *   * 
* *** ***   *  **    **   * *    **   *    **** * ****  *  ***  ** *   is not a prefix of %s",p,s);
 **    **   **     **** *  * 
   ** ** **** *   ***     *   0;
}

answered Jan 11, 2018 by VincentXV (54 points)

1-11 Exercise 3: Prefix of a string

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