1-11 Exercise 3: Prefix of a string

0 like 0 dislike
15.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 15.1k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include  **   *  **   
#include * ** **  **

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
* ***  **  ******* *    *  ***
 
  **   * * * **** *****  ****  *  *** ***       * * *       
***  *** **   **      ** **   * * ** *
*    ** *  ** *    ** ** ***  *     *  * * * * *   **** == s2[i])
  *      **  * **     ***** * ******  * *    ** ** 
***   **  ***  *   ** * * * * *  * *    *  * *   *    ***** *    *   ** *  **    ***   
 * ** * ****** ***   *      **      *** **      ** 
 
   *** * **  *   ***** *   ***  *  *
 
    * **** *  ***   * *    *** * **   == length)
*  ***  * * * ** ***** **  *  **   
*       * ***     **  ** **  *   *  *      * * ** * ***  * * **  *   ** * *** is a prefix of %s",s1,s2);
* **** ** *    * ****     **    *   ** ****
 
    * ** ** * *** *  *       ** * *** *   *
 ****** * *  *  *    * * *    
***  *    ***  * *  ** *** *  *  *** *  *  * *  **  *      *  *  *  ** is not a prefix of %s",s1,s2);
 * ***  * **   *  *  * *     ***  * *
 return 0;
 * **  *    * *  *   ***    * *    ** *
 }

int main(void)
{
* **   * ****  *  *  *  s1[100];
 * * *  **** ******* ** * s2[100];
** *   * *  **     ** ** * i,j;
 *  ****** *****   ** *  * 
     *** *  ***** *  * **** ****** **   ** s1);
 **  *** ******   ** * *  *** *  * **     *  **   ** s2);
***  *  * ***    *** *  *   
*  *  *  *** ***  ****   *   * * ** *  **
   **  **  *  * * *   *
  *** *  * * *  * * ****       0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *** *   * * * * 
#include  **  ***  * *   

int prefix (char st1[],char st2[]){
 *     ****  ** *  *   *  **  len=0, i, cnt=0;
    * *   * **  *****  ** *
    **  * *     *  * **   * ** = (unsigned)strlen(st1);
*     **      **** *****
* **  *** *  **   ** * ** * *  * (i=0;i<len;i++)
**    ***   **** *  ** * 
* *** **  ** * (st1[i]==st2[i]){
  ***  *    ***** **** *******  * ** *   *     *  ** **   *   *** **   **    **      *  * ** 
****   * ** * ** ***  ***** ****  ***** ***** *   *
  ** *  **   * * * *   *  
 ** *** *    ** *****  *   * (cnt == len){
 ******* ** ****  * **  ** *  **  * * ** * ******* 1;
***** *** ** *     ** **  *  
  *     ******     * *     ***
  *  *   * *   **** ** * ** *    0;
  **    * * * *** * *    *  *** 
}

int main(void) {
      ******   ** * ** **   * st1[256];
 * *    **  *   ** * ***    * ** st2[256];
* *****  **  *  **    ** ** *******  ***  ** ***  **      st1);
*       *** ***   * ** ***  * *     ** ***** st2);

  *    ** *  ***   **   ***** (prefix(st1,st2)){
** *       ** *  *** * *   ** ** *   * * **  *  ***  ** *** * * **  is a prefix of %s", st1, st2);
*****     * * * *******  * ** 
    ** *    * ** *   ** * * 
* ****   ***   *** ***   *         * *** * ***** *      *       **  * is not a prefix of %s", st1, st2);

**  **** **  *    ***  ** *  **   0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
 * *     ****  ****   * *  *  *** * ** *****  
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
* **  **  ****   * * * * *   * *  *****  * *** ***  *
* ** ** *   * * ** **** **   * ***     ***   ** *** * * *** **** **     **  * 
 *   **** * *  *   **              ** ** *  * * * ** *  * * *** ** ***   *  * **   * **   
    ****  * * *** *  * *    ** ******     *   *** *** ** ***  ******  *    ** ** ***    *   *  *** *    *    **** *    *    **   ** **  **  ** ****   is not a prefix of %s",a,b);
   * **   *** * *** ****  *    ***** * * **  **  *** ******  ******* *  * **** *  * * **   ** * * * **** *  * * ***       ** ***    ****     **
* **   ***   ** * *     **  *   ***   *  * * * * * **   **   * * ******* *******    * *** * * ** *    ***
*   *   **   ** *** *** *     *    ** ***   * ***** *  * *  * ** * * **   *     *  
 **  *     *  *  ** *  **  *  * * * *  ** *  * ** ******* *  ******* *** *  *   *  *    ******     
*  ** *   *  ** *  *  *  ** * ******  * *   ****  ** *   **** *** *    ** *    *  *  * *****  ****** **   ***    *  * *         *** *     **   * *** * is a prefix of %s",a,b);
 ***   * * **  ********* *  *  ****    *  * *  ** **    **  ***** * *   **** **  * **  *  **  *   * ***  * ** ** *   * ***  *   * *  ****  ** * 
** **  *** *   ** * **   ****  * ***  * **   * * *** * *****   **   *   *   * ** * ***  *      * **  **
 * ** ****** *** *    ***   * * * * ***  *  *  **  *  * *    *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
*** *** *     ********  * *  *   * * *  ** *  * 
     * **** ****   **     *  **  ** **

*** ***   ***    **    * *** *******  ** **  *   * * *****  * * ** 0)
 **    **    **** **  *  * *  * **  ****** ***  ** * * ** *    *** ******* * **
*** * ***  *   ****  **   **  * *  *   *   *** * *   **   ****  * * **     * *** *      **    *** ***    *  * is a prefix of %s",pre,str);
** *   *** *****     *   *  * ** ** * **   *** * ***  *  ** **     * ** *
* *  *** * ******  *  **    ***     **  ** * *    **  *** *
 * ** *    *   *    ** ***** *  * **** **** *** *** ** ***** ***  ** *     
  **  **  * ******* * **  *******  *  *  *  *    * ***** * ***   * * ***  *   * **  *  * * ****   ** * **** **** *** * is not a prefix of %s",pre,str);
 *** **  *  ** *** ***     * *     * ** * ** **    **   ** * *** **** * ** *  ******

*   *** ** ****       *  * * ** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
    *    ***   * **  * ** **   a[100];

*** *    **    ****  ***   b[100];

   * *  * **  *    *    *  *   i = 0;

   * ** **   **     *    prefix = 1;

 *    ** **   *****  ** ***** *   ** a, b);

  *     ***     * * *** ***    * len = strlen(a);

     *  *    *  *** *  *    *   = 0; i < len; i++)
*****  ** *       * ******** 
  *   * *  *  ****** *  **** * *** *  *   *** ******   != b[i])
  ***  *      ** ***    ***** ** * *  ** ***  * **     **** **
*   **** ** * * *   ** * * * **     ** ****** ***** **  *  **    ******* ***** **  = 0;

 *    *** **  **  * *** *  * *    ***  ** *   ** * ** ***  *  ***   *     ***  *  **** * *       ** is not a prefix of %s", a, b);

  * *** *   *  *** ** *     *** **       **  ** ***  ***  ** *   **** *  * *  * * *  
* *     ***** * **     *  *  ** * **  *  **  *   * *** 
* * ** ****  ** **      *
** * **** * ** *   *   *   *     *  == 1)
  **      ***   * * ** * *  
 ** *  *   *  **  ***  *   **** *** * ***  **   ** ** **   ** *    is a prefix of %s", a, b);

    **  ** ** *   **   * ** * *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  **   ****** * 
#include   *** **  *  *    

int main() 
{ 
**** **  *****  **  *  * * a[100],b[100]; 
***    * **** * * *** ** i,j,prefix = 1; 
 *          * * ***    *      * **   * **  %s",a,b); 
 **   **** *     *   **  * *  len = strlen(a); 
  *  * *     *  ***  * ***  ** * = 0 ; i < len ; i++) 
***** ** *   **     **  *  *** 
 *  ** *** * ******** *  ** *  *         *  ****  *  ** **  *  != b[i]) 
* *  ** ***   *  ** ***   ** *  ****** * * ***  ***  
   *   ** *    * *     * *    *    *****   ** *     *  *  *  **   * *   *   ******  ** = 0; 
*   * *     *   **  *  *   ***    *  * *  ** **  ** * *  *  *  **  ***  * **  * *** ******  is not a prefix of %s",a,b); 
  ***** * * *  *****  *** *  * * **  *  *        *  * **  *   ***      *     *******  ** 
      *    * *         *** * ***    *****     ** ***  

 ****   **    **  ****   
   ** ** *  ***  ** ** *   ******* == 1) 
**   * ****     ** **   ** * * **** *  ** *  *  **  ***  ***** ***** is a prefix of %s",a,b); 

 
  * *   ****   ***  **  ****** 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **     *** *****
#include ***  *    * *  *

int main()
{
 * *      *    * * **    a[100],b[100];
** *  *   **   *  **   **   **  i,j,prefix = 1;
** *   * *    **  *  ** *****  * ** *      %s",a,b);
  ** *   * ********  * *   **** len = strlen(a);
* * ** ****** *      *  * *  * * = 0 ; i < len ; i++)
* *   *  ***    ** * * * * *   
 *** ****     *** ** * *** *  *  ** *   ***** **   ***   ** * != b[i])
** * *****  **   ** *** **  *** ****  **********  ******
  *    *   * **  ** *     ****   **   ****** ****** * * **   **  *** **   *  = 0;
  ***** *****     ****** **   * ***   ** *  *  * *   ***     *   *  *      ** *  **  ** is not a prefix of %s",a,b);
*** * **  * * * ** **  *  ****  *** * * * * * * ****** **    *** ******  **  *     
***      ** **   *     * *    *** * **  ***       

* * **   * *   **   ***
** ***  *** ***** *** * *       == 1)
 * **   * ****   ***    *  *****   * * ****      * * * *   is a prefix of %s",a,b);


** ***    * **** *** *      * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * **** * * *
#include  * ** ** **** 

int prefix(const char *pre, const char *str)
{

 ***  * *** * **  ** ** *   *  *** **   * * * * *** ***
* ***  *** **** * ***** *  *     ** *** ** ** **      ** * 0;
*****       ***       * **       * * * *  * ****     
  *   **  *  ***  * ***  ****  * * ** **  ** * ** ** *   * **    1;
**    ** ***  **  * ** ** **   return 0;


}

int main()
{
    * *  **    * *   * **   * pre[100],str[100];
 *     * ** ***  *** *
 ****** * ** *    *  *  **  *****  *    **  * **  *  * 
  * * **  *  * ****    *     *** *** *  *
*** ** *   ** *   ** *   ***  ** ** **          *****  ***** *  **** *** is a prefix of %s",pre,str);
   * *       ******   *****  *** 
 * ** *   *  *  ** **** * **  * *  * * ** * ** ** * *   * *   * * *  *  *** * is not a prefix of %s",pre,str);
 *******  ** *** * **  *   ** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
***  *****     ****  *  *  c;
 * ***     *   ***    *** * * *       ******
 *   * *    *   *    * * *     ****  *  *   * *  0;
   *    *      ** * ***  ******
**    ****  **    * **      *** 
* **  *****   *  *  *  *   *       * * * *** *  ***     * **  *     ** * *** of a string
***    *  **   * *  *   ** **** *   *** *** * * * **   * ** ** *   ** ******   *** **  ****
**     * *   **  ***** * *  *  *  * * ***  * **** ***   **      *  *  *** ** **  *** ***  *   * * *  **   * ** *  *  0;
*  ** *  *  ****** * * * **** *** * * ****** ***   * **
*      * ***  ** * *** *   * *   *** **  ***    **   *   1;
    }
}

int main(){
** *** **     *** * * *** * * *  a[100],b[100];
 ** ***  * *** *  ****   **   *  * * *  *  %s",a,b);
     **   *** ***   **  *** **   **  
* ***** ** *       *     ****   *   * * *  * *  * *  *****    *   ** is a prefix of %s",a,b);
   **    *      *      *  *  *
 *******  **    ******* **** *  *    ** ** **  *  *   *  * ***   * ** **  is not a prefix of %s",a,b);
*  ***    * *****   * *   ** ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*    * ** * ***  * **  *****  ** p[100],s[100],a[100]={};
  *** ** **** **      **  * **  t;
  ****     **** *     *** *    * *   ***  *** 
**   ** ****  ****  *** ***     * * * ***** ** 
**        *      *****  *** ***      %s",p,s);
 *  ***   ***   * **   * *  * 
    * **   *  **  **  **  *    *
**      *  ***  **   * *    *  * 
* ****  *   **      * * *  *** * ** ******** **
   *  *  **** * * * *   *   *  * *
   * **   ***   * **  **** *  ***  *  * * ***      * * **         is a prefix of %s",p,s);
 * * ***   *      ***   
  ***** **** *******  *** ** **
       *      * ** * ***** *  *   *   * ** ****  * **   *  is not a prefix of %s",p,s);
*     ***  *** *      * * ** 
** *  ** ***  **   ***  **  * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 21.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 14.2k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 19.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users