1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include   *    ** **    
#include *   **     

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
  ***   ** **  *  * *** 
 
*    * ***   * *********  *  ****  **  ** ***   ** * *
** *  *  *   *  *  * * ** * *********
 *  **  ** ** * ***** **  * *** * *   **** * *  **    ** **    == s2[i])
 *****    **      *      ***  ***** ***  ** ****
 ***    **   ****     * ****  *******   ** *     *** * *    * * ****    **   **  ****
  *  **   * *  ****    ***   *** **   * **  *   ** *** *
 
   * *  * * *   * *** ** * *   *
 
     *** *  ***  *  * ** *     **   ** * == length)
** * *  **   *   **  ** **  ** 
*  ** **     *  ****** *    * * ******* *  *     **  **** ** ** *  * **** is a prefix of %s",s1,s2);
** **** *  **   *    * *  *   *   **
 
***  *  *** ***** *  *** *    * *
*   *   * *  ** **  *  *  **  ***   *
*  *******  ** ****   ** * **** ****** * *    *    ** ***** ** is not a prefix of %s",s1,s2);
*    ***  * **    *   ** *  *  **   
 return 0;
   *** **  **********   **  *  ****
 }

int main(void)
{
  *  **  * * * *   * *  *      s1[100];
 *  *  *  *****  *  * * * s2[100];
* ****** *****   ***** ** **** i,j;
  *     * * *   * ** ** * **
  *   * * ** ** *  **      **** *  * **   * ** * s1);
    *  * ** * *  *** * *   *  * * * ** ***** **   s2);
****  *** **  ** * *   *   
**  *   *    * * *    ** *  ******  * *
**  **   ***  *    ***  *   ** 
 ** * **    * **    * *  *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   * ******
#include *****  *  * *   *

int prefix (char st1[],char st2[]){
**** * * * * ******  ***    len=0, i, cnt=0;
 ****    * *  ** ** ** *    *  *
 ** * **   *     **** * * ** *  = (unsigned)strlen(st1);
  *    * **  * *    * **** * 
**** *   * ** *** * ******  (i=0;i<len;i++)
** *    **** *  *  ** * 
** **    ** ** *    (st1[i]==st2[i]){
******  *    *** *  ** *** ** ***** * **** ***  ******         ** * * ** * * *** ***
*  *   *** **  *** * ****  * ******  **    ******  ** 
  **  ** **  *   **    *
    *  ****  ** *  ***  ********  (cnt == len){
 * **    * * * * *   ***** * * *   **  ***  *   * **   * ** 1;
   *    **** *  * * * *****  
**** * **   ** * *    *    
*   * ***   * *******  *  * * * 0;
  *******      **** *  * *** 
}

int main(void) {
     **  * **   * **** *  st1[256];
* **  * *** ** **  ****       st2[256];
** ** * * ** *  * *    ** ** *******  * *  ** * *    *  st1);
  ***    ****   **   *  ** ** *** * * ***  **   *  * st2);

*  **  ** *  * * * ** ** (prefix(st1,st2)){
*  **  **  *******      ***** **   * ** *** * *   * ***********      * *** * is a prefix of %s", st1, st2);
*** **  *   **    ** *  * * *
************ * * **** * *     **** 
 * **   *   ***  *   *  **   * * * *    *  **** *  ******* *  *** is not a prefix of %s", st1, st2);

     ****   *      ** **   **** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
     *  ****  *  ***** *  ********* *** *  **  ***** 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
  *   * ** * **    *   * * *  **   * **          * 
 * *     *     *  *  ***  * * ** * **** *  *   ***  * * * * **     ** * *    **  ***   ** 
 *** * **** * *     ** *   ** ** ***   *   ** ******* * *     *  ** *      *      ***  * ****   ** *
   * *** *  ** **   ** ***   **   * * * *   ** *  * * * **** ** **  *** * *  *   *    ** *  * * ** * * ***** ******  ***    ** *   *** ** is not a prefix of %s",a,b);
*** * ** * *  ***    **    *  ***  * *   **** *    * ****   ****   * ***  **    **   **** *  ****  **  *  **    *    * **     ** *   *
* * **  **    * ***** ****  * *   ** * * * **       * *********  * **  ****  *  ****  **  *  ****   ******
  * **  ** ****    *  ** *  *          * *  * ***** *  * ** *   ** *   **  *   * 
 * **** *  * **  **  *        *** ** *   **  ***  ******* ***** *    * * * * **  ** ****    * * *    * * ** ** 
    * *  *   * *** * *  *  *  *  **    * ** * *  * ***  **     **** *****    **  **     *      * *  ****    *** *  ** *  *   ****  ** * * ** ********** *  is a prefix of %s",a,b);
**    *    * *    *  *******  * **  ***  * *** *     ***** **  * ** *   ** * **    * **   * **** *    * *** * ** ******   *  ****  *    *  
 * **   **   *    **  *** * * * *  *  **    * * *   * * **  ** **** *  * *    **    **** *    **   ***  *
  * * * *** *** **** *** **** *  *         *  * 




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
**  * ******* * *     *  *  *     * *   ** ** *   
* *** **  ** *  *  * * * ** ***           ****** 

** ** * * ** *** **** *   ** **   ** * *** * * *  *******   ****    *** * 0)
  ****   **** * ***  ** ** * *  **  *** **** ***** ***  * *  **   ** *  * * * 
  *   * *    ***      ** *   *** **     ** *  * *** ** *     ** *  *  *   * **    *** * **     *** * * ***  * *  *    *   **  is a prefix of %s",pre,str);
 * * *   *  *      *  ** * **  *  * **   ** **   *******     ***  **
  * * *   ** * * *       *  *   *  * ** *  ** **   *  *****   * *
*  *        ** ** *  *  * * ** *** ******     *     * *   *** **  **   *  ***  *
 ** * *    ****   **  ********  *** ***      ***  ** ******* *** *  *** **  *** * * * * *******   ** **   *  is not a prefix of %s",pre,str);
* *   ****  * *  ******  *** ** * **    **        ** **  **  *** *** * ***  * ****  * *  ***

* **  * *    *     *** **   * * * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
*** ** * **  *    * *  a[100];

*   **** * *   ** *   * * ***   b[100];

 ** * ****  ****  ** *  ** i = 0;

 ** **   ** *   ** *      prefix = 1;

    *** * **      *     *** * ****   * **  *     a, b);

**  * ***   ***     ***   *  len = strlen(a);

*** * ***** *      * **     *   ** = 0; i < len; i++)
* * *  ***   * ** * ** **** * **
  ******  * *    ******  **  ***    *    * *** **** *    != b[i])
  * * ** * ***** *    * ** ** *  * *   *  * ****   * *
*  ******* *  ** **    *** *   *   ***  ***    * ** *        *     ** * *** ***  * *  = 0;

* * ** *** *   *** * **  *  ****  * ** *      **  ******** * *** * *********    * ** * is not a prefix of %s", a, b);

** *  *     ******  * **  ***  *** ***    *  ** ****   **    *  ****  **  * ** * ****
 ** ******  **   *     **  *    *  **  **** *  ****  **   * *
 *** ***  ** *  *      * ** 
   * * *** * **   ****   ****     == 1)
   *      *  * *  **** *  *
 ***     *  *** **  *********  ********  * ***   *****  *     is a prefix of %s", a, b);

  ** **  * *   * *****  ** ***
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include      * *     **  
#include     *  ****  

int main() 
{ 
*  ****** *   ***  * * *** a[100],b[100]; 
 *  ***  *  ****   *  *  ******* * i,j,prefix = 1; 
****  * * *       * *   ***    *  **   %s",a,b); 
   ******    ******* *        len = strlen(a); 
** *** **     *  * * ****  = 0 ; i < len ; i++) 
    ** * ** * ** *   ** 
*  ** * * *  * **** ***    ****  *    * **  * ****** *    ***  != b[i]) 
 * *********    *  * ** *  ** * * **  * *  *   *   * *   
*** *     ** *   **    * *****    *  *    * ****   * *   *   *** *** *  *  * = 0; 
*** * ***  * ***   *  *******  *****  ** *  * * *  * *      * * * *  *    ****** *****  is not a prefix of %s",a,b); 
* ***  *** ***  * *  ******  * * *  * ***** *   ******  ***     *     *   *  **     
 * ****  * ***** ****  *  *   **  * ** *** **  * *** * * 

      **   *** ****  *  
* **** **    *   * *  * * *** *     == 1) 
******   *  ** * **  ** **  *   **  *** *        ** ** **  *** is a prefix of %s",a,b); 

 
* *   * *** **** ** * ** ** *   * 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * **      *  **
#include    * **** **

int main()
{
  ** *     *    * *   *    **  ** a[100],b[100];
**    * *  *  * *   *  ****  **  i,j,prefix = 1;
 *        ** * **      *    *   * **  * %s",a,b);
   * * **     *  ** ** **  ****** len = strlen(a);
*** *** * *  ** *  ***** ** * = 0 ; i < len ; i++)
* *   * *      ***   **   **  
 * *  * ***  *  *  ** *** ********* ***    **  * *** * != b[i])
**** * **  *        **** * *** ***** * * ** * *** 
** *** ****  * ** **  *  **** ** * *  * * **** *  ***  * * *****   ***     *** **  **  = 0;
**  *  ******    *   *** *** **** * * ** *  *  ** *  *  ***  ***  *  *        *  **   *   ** is not a prefix of %s",a,b);
 ***   **  *  *  *** **  * * * *******   **** *   *** ** *    *******
 * ** *   *   * *  * **  **   **  *    **  * *  * ***  *

  *** * **       ** * *  ***
* *   * * **** * *    * * *  **   * == 1)
  ** *    **  * *** * **  * *** **** ** ***  *         **    ** * ** ** **  *  is a prefix of %s",a,b);


 ** *   *   * ***  **    **     0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***** *** *  
#include  ** * * ** * *  *

int prefix(const char *pre, const char *str)
{

   *   * **  *  ***   *** ** * * **   ** *     
*  ****   **  *** **** *  * ***  *  * ** * ***  ****  *    0;
* * *  * *    **** *   ***  ***** *       *  * 
***  ***    * *   * *    ** * *   ** * ** * *  * ** * ***** *** 1;
*  * ** **      *  * *   *    return 0;


}

int main()
{
*   *** *** *    * *** ***    pre[100],str[100];
 *     **    **  * * * ** 
* *  *   *****  *  ** * *  *  *  * * ****  ****   *     *** 
* ** **** ** * * * ** * ** *  **   ***   
 ***    *   ***** * ***      *   ** ***  *  *** ** * *   *     ****** * is a prefix of %s",pre,str);
  ** **  **  *****  *****  * 
 *  ****  **** **  * * * *    **** *****   *  ***   *        is not a prefix of %s",pre,str);
* * *****          **   **  * **  0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
   *  ***    ** **    ** *  c;
*    *     ****    **  **  **** *    * *    *
 ** * *        *   *   *** *  ***   * ** ****     **    ***   *    0;
*  **  ** * ******** * *****  
*     ****    **    * *   ** 
* ** ***   * * **    **   *  *****  *     ******  *   ***  * * * *****   ***   of a string
 *** ** * *   ** ** ** ** *  * *       ***** * *  * * *   ********  *****  *********  ** ** ** *
 * * ** * ** **  *** ***** *   ** *   ** ****   ** *  *  **   ** ****  * *  * * **   ** * * ** ***    *  0;
 * **        * *   **** *  * * *    ***  ****  * *  *  *
 * *  *  *  **     ****   *   ***    *  * **   * *****   ***  1;
    }
}

int main(){
   * **   *  *   ***  **  a[100],b[100];
**** * *** * *  *     * ******  ** **     ** %s",a,b);
  * *      * **  ***  * ****  **     **  
** *   *******  *    *** *** *  ** **  * ****   **   ** **    ** is a prefix of %s",a,b);
* *     **   *  ** **    * *
**     ** ** *******  **      * **    **** ***  ******* *** *    **  * * *** is not a prefix of %s",a,b);
  *  * *  *********  **   ****  **  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
**  ***      *** * *    * *** p[100],s[100],a[100]={};
  *  * *  ***   * ** *  *  ** *  t;
 ****** *  * *  *  * * *   **  ****** 
  *  *    **     *       *** *  *    ***
** * * ******** **  *     ****  * * *** * %s",p,s);
****   *** *** *   *     **** *
* * *   **  * **** * * *   * **** *
  ***   *** **** **    ***** ** * * * * 
 *  *** * ** *  *   *  **  * *  *** *** * * ***  
    *  *** *    **  * **  **  *** **** ** 
* *   **  *  ** *   *  ** * ****** *    *  *  ****  * * **    is a prefix of %s",p,s);
   * ***  **   *    ***  ****
  *****      * **** *  *   *** *   *
  ****  **  * **  *     ********  *** **  *      * *** *** is not a prefix of %s",p,s);
**  ** *  * ** *  ***** ****   **
********  **  **** * * *  *     *  0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.32
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 17.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 15.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users