1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include **  **  *** 
#include      **** * ****  **

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
*   **   *  *    *     * *
 
**   **  ***    *******   **** ***  * *  *** ** **  ***
 ** **  *   *** *   ** ** *  *  
   *  **** *      **   ***** * **  * *   ****    ****** * * * == s2[i])
* **** ****  ****** * **** *** ***   *  * ** *  ***  *  
   * * **  *     * *   *  *  *  **   *    *** * **  ** **    ***** **     * *  ** * ** ****  *** 
*  *   *  *  * * * *** **** * ** ** ** *  **  *** *
 
** *     *  * **  * ** * * * * ***
 
     ***     *   **     *  ***   == length)
*       ***   * **      * * *
****** *   *********     * *  *   ** *  **   **  *   ****  ** * *   * *  *  * is a prefix of %s",s1,s2);
 *   * *****    *  *   * * **    ****   *
 
*   *  * **   ***  * *  **  ** *  *  *
 ** ** **     *  * **** * *  *   *  *  
* ** ** * *   **  *  * *  *          ******  *** *** **   ****    ** * * * *  * ** is not a prefix of %s",s1,s2);
**  *  * ***  **     ***  ** *  * 
 return 0;
*** *** ** *  * * *** **  *    *  * * 
 }

int main(void)
{
  ** ******  ******  * * ***  * * *   s1[100];
*   * ***     **   ****   * s2[100];
   * **      * * * ***** *  * **  i,j;
*    ** ****        * *** *  
  ****   * **  *  ***    **** ** *   **** ***  **    s1);
** *   *  * * * *  * * ****** * *** *    * s2);
***  **     *  ** * * ** ***
    ** **     **  * *  **   ** *** ****
***   ***    **    * ** * *
  ***  ** *  **  *  * * **    **   0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ** ** *  *
#include *        *** *

int prefix (char st1[],char st2[]){
  *    *  * *  * *** *   * ***  len=0, i, cnt=0;
*   *    * ***   ***** **
*   * * *  ** ** *  * *      * *  = (unsigned)strlen(st1);
** ** **** ** * * *** 
*** ***   ** *  ****      **    *  (i=0;i<len;i++)
  **  *  ***** *   ** * *   *    * *
 ***** *  *** (st1[i]==st2[i]){
     ** *  * *  ** *   **    * **  *   * *  * ***    ***** *  ****  *        * **** 
 * **   **  ** *** *** ****    * *  *** * ** * ** **  * ***
** *  ***  **** * ****   * *   *
 * ** **  *  ** *  ** *** ****   (cnt == len){
   * ** * **  * *** * *******  *  * * ***  *   **     *    * *    1;
* *  * ** *   * *  ***  * 
*   ** * **  ****  * *    **
***  * * *   *    ** **** **  *** 0;
      **   * * * * *    * * 
}

int main(void) {
   * *    * *       st1[256];
 ***  *        **  * ******** * ** *  st2[256];
 **  * * *   * * **     * * * **   ***  **   *  * **** st1);
*** * * ******* ****    ** *  ** **** ***    **  st2);

 ** ***  * **  *  **     *** (prefix(st1,st2)){
*** **  *** * **   *        *   * *  * * * ***  * ** *** is a prefix of %s", st1, st2);
****   **       * * * *  *   ***  
 ****    ***  * **** * *   * ****  
***      **  ****** *  **  * ***** ****** ** *** **      **    * **   * is not a prefix of %s", st1, st2);

 *   *******  **   **  * * ***   **** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
* *     * *    *    ********* *    ** *   ** * *   
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
   *  *  **  ****** **   *** *       **** **   ***    
 * **  **  ******* **     ** * **  *  **   ** *    *  * * ****   *  ******* **** * *  
* * **      ** **      * *   *  *  *   *****  *     ** * ****** * * **    * *  ****  * *   ***
 **** * * *     **  ***  * *  ***  * **      * ** *** ** **  *    **** *     **   ** * *** **  *****   * * *  * *  ** ** *******  * *   * ** * ** is not a prefix of %s",a,b);
* *********** ** **  ** *   ***  **** *   * ***  ******** *    * *     ***   **   **   *   **** * * **    ** ** **** * * ***    * **    
*      *    * *  * * *  * * *  ****  * * ***** ** *    *****  *** * * *** ** * **** *  *** *    * * *** **  *  
* *  *   **** * * * **** * ** ** *  ****  * *   *** ****       * ***  *****  * * *  
* *  *   ****   * *** ****  *  *  **  * *    * * *** ** *  * *   * * ****   * *** *******  * *** ** * ******
* * * *** ** *   **** *  * ** * ** ******* ***  ***   * *   ** ** * ** *****  *  ****     *    **** *   ** ***  ***   *  ****  ***** ***  *  *  * is a prefix of %s",a,b);
* ** **  ** *** ***   ***      ** ********* *  ***    ** * *****  * ** ******* *    ***  **  ****** ***  *****  ****   * *   *   ** **  * *
 ******** * ** * ** *****  *    ***  **    * * ***  *  *** *  **** ***    ***    **     * **  ** *  ***     **
**** * **   **** * **   *  **     *  * *** * * **  *    




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
** **    *   * *    ** *  *  **  **    ***     ** * * **  
** * * * * ** * *    ***  * ** *  *      *     *** 

*      *   * ***** * *    *     **  ***  * **  *****   **** ** ***** 0)
* ****  *   * **  ** *     * ** **    ** *  *** *** *      *  ******   * ** 
 ** ** *  ***   *   ******  * ***    *   * *** *****   *     ****** *****  * **        * *   * ***  *** ***   **  *   ****  is a prefix of %s",pre,str);
   * *  **      ****    * *   **** ********** **    ** **  *  * *    *   *  
 * ***  * *** **  *    * * **      ** * ****  **  ***   *  * 
* ** *  ** **    *      * * *  * *  ***   * *** ** * ****  **   *****    **  ***  * ** * *  
   *  **  **** *     **  * *****   ******** * ***  **  ****** *******       *   *** *  *  ****  ** **** ********  *  *  * is not a prefix of %s",pre,str);
  * **       *  * ** ***    ** *** * ** **** * * *** ** *   *   *  * * * *** **

* ****  **** **     ****** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
  **      * ******   *    *   *   a[100];

*****  ***   *  * **** *  *****  b[100];

**   *** *     **  **   *** i = 0;

*   *  ***   ****  * *   * *   prefix = 1;

* ***** * *   *  **    *  *****   **** ****** **  a, b);

     *** * *    * * *  ** len = strlen(a);

  ***    *** **  *  *  * * ****  = 0; i < len; i++)
  * *  **   *         * ** 
 *   * * **    *  **      **** ** *   **   *  **** ** != b[i])
   ** ** *  *      * ** ******   ** *    **  **** ** * 
   *  * *  ***  ** *** * **  ** *  **     *  ****  * *     **** * * **  ** * ***    = 0;

** *** **      *    **  ** *****        ***      * ** **  ***          *  *  * * *  ** **    is not a prefix of %s", a, b);

*** ** ****** *** **  ****    ** **   ***   * ** ** *  **  ** * *  **** * *  
*  * ** ** ****   *** **  ** ** ***  *  **   * *  **
**  **** *  *****   ******
**  * * *   * **  * *      * ***  *** == 1)
  **** ** ****** * *   * **  * * 
  * **** * **** ** ****  * ** *  * *******   ** **   * ** ***      ** is a prefix of %s", a, b);

 * **  **  * * *****   *  **
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ***  * * *    
#include    ***** ** * * * * 

int main() 
{ 
***         ***** ***  **    a[100],b[100]; 
*  * * * *  ** ***  ** *   * * i,j,prefix = 1; 
* *  * * * **** ** *  * *  **    **** %s",a,b); 
* **  *   *  ** **  **  **  **** len = strlen(a); 
* *  *  *  *         *  **   ** * = 0 ; i < len ; i++) 
  **  *  *   ** * *****  
** **** *** *    **    * * ***      * ***** * *   **** ** **  != b[i]) 
*  * *    ***   *   **** **   **    **   **   * **   ****** 
 *   * *      *   *** ****      ***  ** * ***  **  *     *  ** *   ****   **  ****    ** ** = 0; 
** ** **     *   ******* * ** ***  ***** ** ** * *** ** * **     **** * ** *    * *     * is not a prefix of %s",a,b); 
   * **   *    * * *** *    * *       * ** *   ** * *  ***   * ** * **  ***    
** ** * ** * **** ** **** *         *  *  **    * *  *  

  *  * *****  * * ***  *     ** 
*  **** **   * ****** *  ***  == 1) 
  **    * * *** **** *** ***    *     *** * *  ** * *  **    ****  is a prefix of %s",a,b); 

 
 ** * ****** ******* * * ****  ***  0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *  * * ****  * *
#include *  *** *** *  

int main()
{
***** ** * * * ****** * ***** a[100],b[100];
**    *    *   * *  * * *  *    i,j,prefix = 1;
*   *     *** ***       *    ** **   %s",a,b);
***    *  **   * *  **** len = strlen(a);
 ** **  **** *  *  * * *  ** * = 0 ; i < len ; i++)
   ** *    * **** * *  *
   *****  ** * *  *      *   ********   ** *  **  *   ** *** *  != b[i])
** **       *** *   * *   **** * *   ******* *   ** *  *
 **   * ***   * *     * *  ***  *** * * *  ******** *** *   * ** *** *   ***    * **  = 0;
  **  ** *** * **  **  *****  ******  *** * * *    *       * ** ** *  * *****  * ** **  *   is not a prefix of %s",a,b);
 ** *    ** **** ***   ***   *  *****   ** * * ***   * ****    *   ** * *  *********  *
 *   *  ** *** *** *   **** * *   ** *  *   ***** 

*      *** ******  *  *  **  
   * ***   **    **   ** *  * *   == 1)
     *  *  ****  * * *     ****  ***   ****  **  *  **** **  *  **  is a prefix of %s",a,b);


  * **     *** * **** **** * * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **      *** ** * *
#include *      ** * * **

int prefix(const char *pre, const char *str)
{

*** *** ***** ****    ** *** * *   ******  *** * *   * *  
    ** *   ***** * *  **   ** ** * *  *     *  ** * *  * * * 0;
* *** *    * * * ******* **** **   ******* * **** 
** *** ** *   * * * ******  *  *  *** *  ** *  *** *  *  1;
 * *   *  * * * ***   *     *  return 0;


}

int main()
{
** * *   ***** *    ****   * **   pre[100],str[100];
   * *** *  * ********
 * * *   **** *  * *  *  ** *   *  **  **     *
  *  **  * *    ** ***  ***    * *  *  *
 ***    ** ******    **    * * *** ***  *******  ******* *** *  **  is a prefix of %s",pre,str);
 *** *    * ****  *********  ** * 
  **** *   * * ***  * *   * *  *   * **** ***   * * * ** *    **    is not a prefix of %s",pre,str);
*****  *   *      * * ** ** * *  0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
**  *** *****   ** *    * *   c;
**       * *** ***  ** * ** *   *** * *******   **  
  ******* ** *    *    * *** **  * *     * * ** * **    * *** 0;
* ** * ***  *    **       *
*** *   ******* *    * ***  ** *
 ****   *   ***  * * *******  * ******* ** ***      ** **    * ***     *   *    of a string
*    ** ****** *  *** *   **  ***  **       ***  * *    * * **    ***     **   *  **** ** ** *
*  *   ** * ** **** *  ****** *    **  * * *   *  *** * *******    ** **** ** * **       *** * * *   * *     **** 0;
* *** * *   ***        **   **   **  * *** *   ** **  *****
****  ** *   ** *    *  **   *   * * ******    ***  *   *    1;
    }
}

int main(){
  * * ** * ******** *** ** *** a[100],b[100];
 *** * * *   ** *** ** *** ***** * * ****     * %s",a,b);
*********  *  ***  **  ** * ** * *** **  ** 
 * * * * ****  * * *** * * **      *** * *  * * *  * **    **    *  is a prefix of %s",a,b);
******  * ***   **    **    ** 
* *    *** *  ** *******  ** * *  ********* ***   *  * **  ** * * * is not a prefix of %s",a,b);
  **   * * *    ****  *** ***** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** ** ***  *       ** ** *  * p[100],s[100],a[100]={};
*     *  * ***** *******    t;
 ***     ** *  *  * *        *  * *   **  *
**   ** *** *     **   * * *** *    ***  
 *** **  *    ** **   *****  ** * **   %s",p,s);
   ** *  **** *   *   * **    ** *
    *   **  * * * ** ****  ** *    *  *
 **   **     *     **    **  * *   *
** *  *** **    * * ***  **  **       * *** 
* **  *  * *  *    * * **   *  ** ** ** *  
 ** * **** ****  *  * * *  **   *  *** *  *** ***  *** *  ***    ***** * is a prefix of %s",p,s);
* **  * *  *    ** * * ***
 **  * ***  *** * * *  ****  **
  *      *   **      ** ****    **  * *  *** *      *   ***  *   *  is not a prefix of %s",p,s);
* *** ** *          **      
* *** *****    * * *  ***** *** 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.201
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 10.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 6.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 9.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users