1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include * *    * * ***
#include  *     *  * *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
*** ** ****       **    * 
 
***   *    *** * * * ***   *****  * *** **** * *  **** 
*** *   * *    ** ***  ** * ** ***  *
* ***** **  *****    *    * *     *  * **** *** ***   == s2[i])
 *  *  * ****  * *    *** *    *** *   ** * *  **  **     **  
  ***  *   * *   ** *  *  *   * * *   **  *    * *   ******   * * * **  ******       
*  *   *  * *    **  * * *     * *** *      * *  *  *
 
 * ***** * ***   ** ***       
 
*** ******* *    *     *****  **   * == length)
* ** **         *  ***  *  **  * * *  *
  **  **** ** ** * * *     *** ***   *     *****   * * *** **** * *  ** is a prefix of %s",s1,s2);
 ****     ***   * ** **   ***** *  
 
* * *  * * ** *****  * ***  ***   *     *
*      * *  ** ***** ** *  *    *
    * * *** * * *** * ***  *  *   * **  *    * *  ***  *  ***    *  *   is not a prefix of %s",s1,s2);
*  * *    ** **  *    **  ****  
 return 0;
 *   * *   * **** * *  *    *     
 }

int main(void)
{
      * ******  ** ** *    *  s1[100];
* *  * *      *** ** *     ** s2[100];
**  *  ** * * *      * * ****  i,j;
   *** * **  ** *  ** *****
**  ***     ** * ** *** *** ****** **** ***** * *   s1);
****  *  * ****** * * * * **   *** *  *       s2);
***    ** *  *  ***    ****  *
* * * *  * **  * * *  ****    *
 * * * *    *** *    *
*   * **     ** *  ******* **  **    0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *       * *** *
#include ** *** *  *   

int prefix (char st1[],char st2[]){
*   *****    * *  ***** len=0, i, cnt=0;
**  ***   * ** *  *   * *
 ***  *     ***** ***  **  ** *** = (unsigned)strlen(st1);
* * **   ***** *       ** ** 
***    * ** **  * * *  *  (i=0;i<len;i++)
**  **  **  *  * *  ** * 
* *    *   * (st1[i]==st2[i]){
 **    **** ***** ***** *   **     * ** ** ** * ** ****  * **    **   *** * * ***  *  *** **
 * * * *******        * * *   *   **** * * *  ** *  *   *** 
*    *    *** *   *    ***  *
    ****      * * *    *****   (cnt == len){
  *   ** *  ** ***** **    ** *** *** *  *** ***** * *  1;
     ****   ** **** ** ** * *  *
***    ** *  ***** *  *  
   ***  ** *** ** **  ** * 0;
  *   *      *  * ****  ** *  * 
}

int main(void) {
  ** * ** * **  ** * ** * * st1[256];
*    ** ** **  * ** ***  *** *** st2[256];
** **  * * **  **  *  ***     ** ** **** *     ** ***   * st1);
 **** *   *     * * * **  *  * * ***   * ****  st2);

* **** *** *  ** * *    * *  (prefix(st1,st2)){
 *  *** *    ** * * **  *    *  * * *   *   ***     * * *****   * ***** is a prefix of %s", st1, st2);
 *  **  ** **     *   *** ***
 *  *  *** *    ***      *****   * 
 * * **    *  * *     * * ***  ****  ***  ** *    *    ** ***** **  *** is not a prefix of %s", st1, st2);

* **    *  * ** *  **** ******   * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
* ** * *  *  *    * *  * * *   **  **  * ** **  
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
 * ** **   ** * ** **      *** ** ** ** * **  *    ****   
 * *     ***** *****      *  *   *   ***    **  *   *  *****   ****   ***    ***  * **
**  * *   *  *     **  * * *   * ***  * *** *  ** ***  * *** ** **  *** **     *   * * * * * ***   
 ** ** *  * * * *** ** ** *** *  * ***  **    *** *** ***  *  ****  **     *     **    *  *  ****** ***    *  ****  *   **  * ***** *      ** is not a prefix of %s",a,b);
**** **  *   ***   * *** **   **   *  *  *** ***  ****** ***   ****   * **  *** *    **** *  ** ** ****  * * **    ** ***   *****  *   *   * *   *
**   * * * ***  *** ***  *       *** *    ** *  *  * * **     * ***    *  * ****  * * *** * * *** *  *    
    * *  **    **** *  *  *   *  ** ******  * *  * **** *****  **  *  * ****   ** * *
****** *     ** **  *** **** * *    *   *     * ***  *  **    ***** *** ** *** ***** **  *  ** **     ** *** 
****   *** **   *   * **  ** * ** * ** ********   *** **  ** *    ***    **   **    ** **   **  ****   * *   *  ***** ** ** * *    * * * *** *  *    *** ****  * is a prefix of %s",a,b);
    * *    **     **  * ** ****** ** ***** **    * **  ** * * ** ******* *   **   * ** ** *  *   **  *** **   *** *** *  ****   *   *  *
 *     *    * * **  *      *   ***** *     *** *** **  *  ** *** *  * ** * * *  ***        ** **   *   *  ***  ** ***
**  *** *  **   * *   **  ***** ******    * ***   




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
** *** * ** * * * ****    * ***** **** * ****  ** **
 ***** **  * *  *       * *  **  * *  **   * 

   ** * *  **   **  *  *    * **** ** * ****      *       ***  *** **** *** 0)
* *  *   **        ****   *       ***  **** * **  **   ** *** *  *  *    
  **** * ** ** * *    *    * **    **  *******   *** *  ***** ****    *** * ***  **** *****  ***  **    *  *  * is a prefix of %s",pre,str);
* * * *    ** **** ***  *** *   * **   *   *    **** ****** ** **    *    *
*****   * *** *     *  *** **  *  *  *** ***    *  * 
* *** ***     *   *   **  ** **  *********** * ******  ** ***      * **  * *    **    
* *   *   ***      * ** * *    ** *   *******   ***  *  * *  **  ** **     * * *  ***    **   ** ***   ***** * **   *       * ***** is not a prefix of %s",pre,str);
* *** * *  ** ***  ***    **    *        ** **  *** *** **     * ****  **   * ** 

* ******    * ***** ***** *** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
** * ***  ********  * ****    *  ** a[100];

  *   ** *   *     *****  *** b[100];

 ***     * ** ***  * *   *   * i = 0;

 *   *  ***  *      * *** * * * *  prefix = 1;

   *** **   **     *        ***** *  ** * *  * a, b);

* *****     * ** **  ***** len = strlen(a);

* * ****** ** ***   *** = 0; i < len; i++)
 * * *   *   ** * ***   
* *  ***  **** * * ** *  * *    ***      * **     *  * * != b[i])
*     *  * * **   ***   * **  *  *   *     ******  ** *** 
*    ***** *   * * **  * ***  * **     ** *  **** * * **  ******  *** *** **  = 0;

 *** ***    *****   * ** *   *  **** ****** *  ** * *     **  ** ** ** ** *    *** **  *  ***  * is not a prefix of %s", a, b);

    *****  *   **    * ***** *   ** * ** * ********** *  * * * **    *  *   *** *   **  *** 
** *  *  ***   *** * ** * * *   * *  * **   ** *
   * *** *   *  * *  *   ***
  *  ****  * *  *  ** **  ** ** * * == 1)
*   *  *  *  * ** ** *       
*  * *******  *****  **  *  ** **    *  ** **    **** *   *  *** **  ** is a prefix of %s", a, b);

 **  **** *   *** **  **  * 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** **** ***   
#include *    * * * 

int main() 
{ 
* ** ***   **    ***  * ***  a[100],b[100]; 
* **  *     * ** *  ****  *** * i,j,prefix = 1; 
 * ** ***  ****  ** *** * * *  *       ** * %s",a,b); 
* ** *  **   *  **  len = strlen(a); 
 **** ** *    *  ***** **  * *  *  = 0 ; i < len ; i++) 
** *** **  *   *   * *   **  
   **     **   *   * * *  * * * ** *   ** * *  *  ****  * * != b[i]) 
  * * ***   ** * ***** * **   *       **  **  *  
**** ***** *  *** ****  *  *  *********** ** *   **  *** *** ** *** ** ** **** *   *     = 0; 
  * ** ** ****** *  * ** ****** * *  * **  ***   **  ** **    **     ***    ** * **  is not a prefix of %s",a,b); 
 **    **  *  ***  ****     * **** * ** **   ** *  * ****  **  *   *    * *   *  *  * 
 *  **    ***   * * * ***** * * *  **   * 

 *******   *    ****    *** * 
*** **  **    ****    * ** *****  ** == 1) 
 ** * ** *  *    **  *  *********** * * *  * ****   **     ** **  ** is a prefix of %s",a,b); 

 
**** * * * ** *  ***   ****   * 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   ***   ***   *
#include  * * * *** ***** 

int main()
{
**** ***   *** **  ** ** ****   a[100],b[100];
 * *   * *****    ** *    **** i,j,prefix = 1;
* **  **  * * **  ** *** * *    **** ****  %s",a,b);
 *   *****    ***     ** * len = strlen(a);
* *   ** * * ** * * *  * * * = 0 ; i < len ; i++)
** ** * * *  ** * ******  *
 * * *  * *   **    ***  *  * ** ***** *** *  *  * * * * *     != b[i])
 **  *    ** * * ****  * * **** *  **  * * **    *  *  * *
* ***  *** * * ****     ******        ** *  ***  *      * * *   *  *** * * *  ** = 0;
  ***  *****   *******   *  * *** *    ** **   * * ** *  ***    *    ***  * **   *** ***    **  is not a prefix of %s",a,b);
*  *** *****    **** * *** * ***  *  * *  * **     *  * *  * ******   *  * ***
 * ** *    **   * *****  *   * *   ** * *     **   *****  

*   ***  *** **  *****
*    **    ** * *   **** * *   * ** == 1)
 * * *    ** *** ***   *** * ** *** * *     **** * * *    *  *****  ** is a prefix of %s",a,b);


**** * * * *   **    ***    **** * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    ** **** ** 
#include ****     * *  

int prefix(const char *pre, const char *str)
{

 **  **  *  ** **  **   *  **  **   *  *  
****  * * *   *            * * ** **  * ** **    *  ** 0;
* ***** *  *****  * *** *  ***     * * *  ** * ** *
  * *  ***  * * ****   ****** ****    *  **   ******* * ** 1;
***   * ** *    ******* return 0;


}

int main()
{
  *  *   ** ** *  ***   ** ** ** pre[100],str[100];
 * * *** *   *   *** *   *
    * * **  ***  *    **  *** *** * **    *    ***
*** *** **    ***  ***   ** **   **** * 
* *  **  *  * *** * *** ******   ** ***** *** **     **          is a prefix of %s",pre,str);
* **  **  * *  *   ***  ***
**   ****  **  ********   * ************  *  *  *    ** * **  * is not a prefix of %s",pre,str);
 * ** **** ****** * **  ** 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
**** ***    ***   **  **** **  c;
**** * *  ***   ****  * ***   * * * * ***  **  ****
    **     ** **  **** **  * * ** *  ** ***  * * **** 0;
**  *     **  **  *   *   
* * ***  *****    *****  
*  **    *  ** ** *** *  * *  *** **   ***      * * ***   ** **  **  * * * *** of a string
 *   * ******    *  ****  *  ****  *  **   *   ****       *     *   ***** *     * ** *  * **** 
*  * * ** **** ****  *   *  **** *     ** *   ***  ** ** *          ** ** * **** *  * **    ****  **** *****  0;
 * **  *   **   *   ** **   * ******* * * * *** * *  *   *
  * *** ** *   ** **  ****** **  * ** **** *  *** * **** ** * 1;
    }
}

int main(){
 *    *  *   * *****    *  a[100],b[100];
 * *** ******** *  * **    **     * * *  *   %s",a,b);
* ** * *  *****  * *   *   *    * * *
    **  * ****    ****** ***  * **    ***  *** ****   **  *  ** **  *** ** is a prefix of %s",a,b);
 *   * ** * ***  ** *  * **  * 
* ***  ***    *** ** * **  *  *** **   * * *    ** *  *** is not a prefix of %s",a,b);
   *  **  * ***  * ***    *  ** ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** ** **** *  * **  **  * ****** p[100],s[100],a[100]={};
*  **  *      **** *  * * t;
* * **** * * * *    *** * *  ** ** * ** 
***** *   *  *** *****   * ***    * *    *  *
 ** ***  *  *** *** *     * * *  *****   %s",p,s);
** *********** *** *  * **** *  *
  **    *   *  *  * * * **  **    
*   * ** ***  ** * * **   *    **** * * *
     * ** *     **   ** ***  ****  ***    *  
** ****** * *    **    **      ** *** *  *** 
 ** **  ** ** **** *  *      **    ***  * *  ** *  *   * ****  *  * is a prefix of %s",p,s);
**  ** ** ** * *  * * *   * 
  * **  *   *   **** ***    *   
 * ********   * * * ** * ***   *  ** * ** * *   *    *  **   *   * * * * is not a prefix of %s",p,s);
*  *    ***** *  * ***  * **
*** * * * **** ** **    * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.32
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 17.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 15.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users