1-11 Exercise 3: Prefix of a string

0 like 0 dislike
10.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 10.9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include  ***** *  **    * 
#include  ***  * *    **

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
******* *     ****     ** *  
 
* **    *   ** ****  **  * *  *  ** ** ** ** *  ** **
*** * ** ****** *    * * *   *
 ****      * **   *** ***** **  *  ** ** *** *  **   * **  *      == s2[i])
*    ** *   **  *******   ***  *   *   * ** ** *  * **  ** **
 ** **    * **** *    * ** *  * *  *** **  *   ** **  ***   *  * *   * * ** ** **
* *  *   * ***  **  *****    ** *    *** **  *  ** 
 
***** *  ** **  * ** *** *** *     *** 
 
   * ** ** ***  *  *   *******  **  * == length)
*    ******  ***     * * * *  * 
     *    **  *  ****  **** ** ***   * ** * *   *** *   ** ***    * **** is a prefix of %s",s1,s2);
 **  **  *** **  **   ** * *** 
 
  *** **  ***     *    ** **** **
 *    *      ** **  ** *     * * ** 
 * *  * * * * ** * *   ** * *    ** ** *   ********   *         *  ***  *  is not a prefix of %s",s1,s2);
   ***    **   ** **   *  * *  * *  
 return 0;
***   ** * *   ****** **   **** * *
 }

int main(void)
{
  ** * *        *    *   * * ** s1[100];
  *** ** *   *  * **   * *  s2[100];
 ** ***   ** **** ***   * * **   i,j;
 * * **    ** * ** *  ** **
* * ** **** **            **  * *  * **     ******  s1);
 * * ****** * ** **  * ** * ** *  * ***   * s2);
 *****   * **   ** *   *  
** **** * *     *** * * *  *  * ***  
    *    **  **   ******* *
 * *** ** *   *  ** **  *    ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *** *   ** * 
#include * **  **  *  

int prefix (char st1[],char st2[]){
  *** **  ****  *   * *   ** * len=0, i, cnt=0;
 **** ********   *   *****
 *    **  **** * **   **** *  * *  = (unsigned)strlen(st1);
*** **  * *  **** ****  ** 
** **** **  * ***     ***** * * (i=0;i<len;i++)
**** ** *****  **      ***  **
  *  *    * ***  (st1[i]==st2[i]){
 *     * * * *  **  ******* * *   * **  *   ** **  **** * *  *    **** ****  **  ***
** **      **** **  ** *  ****  * * *    * 
    **   *  ** *   ***  *
*  ***       ****   *** ***  *   (cnt == len){
*   ***   *   *  * **    *****   *** *** *    *   * ** ***    1;
*  *** * *  ***   *  **    *   
 *  **  * **** ***   **  
  *    ***** *   *  *** *   0;
**    * *  *  *  ** * 
}

int main(void) {
    * **   **  ******** *    st1[256];
** *** **  *  ** * *   * * *   * st2[256];
* ***  *  ****** * *  * **    **   *   * *  *       st1);
**    * ***** *   * * * **     * ***   ** ***** st2);

*** ****    **** * ****  * (prefix(st1,st2)){
  * **       **        * ** ****** ***  *            *  * * *  * * is a prefix of %s", st1, st2);
***  ** *  * *  *   ***  *     
   * ** ***     * *   *  **** **
*  ** *   *  * ***  *   * * * **** **  *  ****  * ** *   **  is not a prefix of %s", st1, st2);

*   **   *   ** **  ** ** *  0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
** *  * ** *  ***   ** ** * ** * **     ** * *   
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
****  * * ***  * *   **  ******* *   ** ** *** **  **
*     **    * ******* **** *  *   *    *  *  * ** **  ***   ** ** ** *    **    *    *   * *** *  *** 
        ** ***  * ****** ****   * **** *****  *     *  *****  ***  ***   *****     *     *****  ** *  * **** 
*******   **** **  *********** *   *  * **  **  ** *** *   *   * *  *** **** ** ***  * * ** **     *  **** ***  ****   ***   * *   *  **   *  ****  * *       is not a prefix of %s",a,b);
  *   ***** * * * *  ** **     ********  ** * ** *     * *      * * *  *   ** * * **** * *   *   *  *     *  * *** *  *  ***  
**   * ***   * * **    **  * ** *   *  *  * *** *  * *   **  *  *   *   *** * *  ***           *******  *** 
***   *   **** *     **   ****   **  ***   *****  * *  ****   * *  * * *   
***    *     * * *  *   *   **       *   ***** ****   *  *  * *  ***            * ***   **  **  * * * **    * *
* * **   *  *  **    *   *** *** * *       **   *  * * *  **** ** ** * * *** *** ****      **        * * *      ***   **   **  * **      **  *** *  *   is a prefix of %s",a,b);
  *  * **   **       * * ****    **   * * * ***  * *  ** ***    ***  * *     **  *** * *  *** *****          *  *  * *** ** **** **** *
******  *   **  **   * *  * ******   *   *  * *** **   * **  *     **   ****   * *  ****  * *  ** *  * * *****  * *   ** 
    **         *  **   * * * *  *  * **  *  *  * ****   **




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
******   **   ** * *** * ** ** * ** ****     * 
**** *****   * ** * * *******  ** *        

*****     *** ***  *   * * * ****   *  *** ** * **  **  * **        * *     0)
****  * *  **    *    *  ** * ** * **  *   *    *   ****     ** *** *          ** 
* * *  * ** * *    *   *  *** * **  ***** * * **  ***   *  ***  *  **    *  **   * *** *  *  * *  ***** ** * *  **  *  * ** *  is a prefix of %s",pre,str);
  * *    *  * * *   **   * ****  *  * * *  ** ** *   **** **  *  *
 *  *** **    ***  *****  *    ** **  **  *  **  *  **    
  *     ***     * **** **  * * *  *  ****  * **  ***  *  * **  * **     **  * *  *** *  * 
 ****     ****   **** *******  ** * * * *     **    **  **  *  ***  ***  *** * * * *  ***   **   * ** ** *   ***** *    **** *** * is not a prefix of %s",pre,str);
  *     * *  *  ** **    **   * *  ****  ***  ** *   *** **   ****** *  *    *   * 

* * **  *******  **    * * * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
 ***** ** ****    ** * *  *  ** a[100];

   ****** * ** **    *      *  b[100];

*******  ****   * **   *  i = 0;

**** **** * * *    * * * *  *  *    prefix = 1;

  ** **  ** *     **** ** **  **  * *    * **        * a, b);

  **** *** *  * * *  ****  len = strlen(a);

  * * *    *    * * **  *** *  = 0; i < len; i++)
    *     *  * *  ***     *   *
* *  ** * *** ***** ******     *** * ****  * *** ** * != b[i])
* * * ****** *  **  *  ** *** ***   * * * ** *  *
* *  *** *   * * ** *    * ****    *  **   * ** * * * ** **  ***** ** *** *  *  **    *  **  = 0;

  * *  *  *   *   *******  * * ****   *        * *  **  *  * ** *****  **  ** * ***       is not a prefix of %s", a, b);

** ** **  * *   ***  *** ***     ** * *   ***   * * *** *    *   ***  *   ** * *  *   
* * *** *  **  *  **  **    ** ***  * ***** * *   
 ****    *** * ** **  * * * 
 * **** *  **   *  * ******     == 1)
****  ** ***  * *** * *   *  
  *  ** * * *    ***  **   *** **  * **  *   ** *        **** * * is a prefix of %s", a, b);

 **** * * *  * ***  * **   
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ***    **  **** 
#include **** * ****  *  * 

int main() 
{ 
 *    *** ***    *  **   * a[100],b[100]; 
 *  *  ** * *  *  * * *   **** i,j,prefix = 1; 
 * * ***** ** ** ***   * * *  ***    **   * %s",a,b); 
 *** * * ***** ***   *  ***  * len = strlen(a); 
   **** ** ****    *** **  **  *   **** = 0 ; i < len ; i++) 
***  *  *  *   *  *  
  ******   *** ** *  ***  *  *  * * **** **  ** **  ** *   != b[i]) 
*  *  * ** *  **** ******* * * *******  *   *** ****** 
*  * *** *******   *  * * * * ** **  *      **  *  **** *  ** *** * *   *    *  *   * = 0; 
      ** * * * ***    *    **   * * *  ****         **    *  * ** *  **  *    ****       ** is not a prefix of %s",a,b); 
   *        ***        *     *** *  ***  **   * **   ** **   *** *** ***  
  **    **   * * ** ** * * **  *  * * * *   *    ** * *    *   

   ** ** * *   * ** *****  * *** 
*   ** ** * ** ** * ** ** * ****** == 1) 
   * *    *     ** ********** * * ** *  **  *  *  * ***   *    ** *   is a prefix of %s",a,b); 

 
**  ****    ****   *  * *  *      0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  ***   *    
#include * *** *   ** 

int main()
{
*   ******* *  ** * ** ** * *   a[100],b[100];
 **   **    ** ***  ****  * i,j,prefix = 1;
 * **  ** ***   **        * ** *   *  ** *  %s",a,b);
  **  **    * *  *** ****  * * len = strlen(a);
* *** *******  ******* *  * *  *** = 0 ; i < len ; i++)
   **  *** *  *       *****
* ***** *    *  ****   *  **  ** * *   ****  ** *****   ** **  != b[i])
*    **  ** *** *  *   *** ***   * **   *** *   * ** *****
** ***    ** **** ******   **  ***  *  *   **    *  **  ** *******     ****  *  * = 0;
 *    **   * *   *** * **  * ** *********      *  **      **   * *  *   *    *  **       *   is not a prefix of %s",a,b);
 *   ** **** ***   ** **   **  ** ** * ** ****  ** ****   *    ****** **** *  *  *   
 *   ***    *  *  ** ** ** * ** *   ** ******* *

  ***** * * * *** * **  *  * 
**  * * * *  *    **  ** * *    * == 1)
  * *   * **   ***  * **   * * ******    ***  * *     * **  *     is a prefix of %s",a,b);


* * * *  * ***** ****     *  *  0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ****  *** **
#include * ** *   *   *

int prefix(const char *pre, const char *str)
{

  ** ** **  **        **   ***** * *    *  *  *** 
** *** * *  ** **  *** *    *   ******   *  * ********  * 0;
 ** * *****   * *  *****   * * *     ** ***  *** *** 
**   ** *  *  ** *****   *    * *    * ** *       ****   1;
 *** ***   *** ***  ** * * *   return 0;


}

int main()
{
  *  ****** ***  * ** **  *  * *  pre[100],str[100];
**   * **   ***    * * 
*   ** *   ****     *****     **  *** **  ***** *   
   **    *****    ** ***   *** *** *  * *
 **    ** ** ** * *    * *    ***   *  *       *  * ******* **  ***    is a prefix of %s",pre,str);
**** ****     ** ****  * **  
  * * * * *** * * *   *    *** *****  *   *      * **** ******  is not a prefix of %s",pre,str);
 *   *      *** *****   *  * *   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
* * **    * ***** *  * ** * *   c;
* **  **     ******  * * *  * *  ****  ***  **  *   
 ******* * *** * **   *   ** * *  ***  *  * *  **  0;
  *  * ***  *   *  ***  **
 * * * *** **   *  ***   **** * *
 **    * ***     **   ** *****   * *  * *    **** *  * *****   *    **    of a string
  * **** *****     *** * **   ****   * * * * *  **  ***   * *  * ** **  *  ***** *****  *** 
  ** ** *    * * *** **  *    *** * ** **    ****   *   **    * *   *  **   ** **    ****    *   *    * * ** * * ** ***  ** 0;
   **  *** *  **        **  ****   *    *****    * *  
*** **   **         * *  * *  ** *** ***  ** * * ******    1;
    }
}

int main(){
* *   *** *  * * ** ** **** * **** a[100],b[100];
* ****      ** *  * **** *  ** *  *   * ** %s",a,b);
*  ***    *  * * *  **  *******
  *** *  *   ****   *   **  * *       *   ** * *  *  *  ***  * is a prefix of %s",a,b);
 *    * **    * *       **  *
** ****** **** ** *    *      *** *** ** *    ** *    * **   *  * *  is not a prefix of %s",a,b);
**  **** *****  ** * * * ***   0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 *** **** *** *     * **  *  ** p[100],s[100],a[100]={};
 *   ****  **** * **   *  *    * t;
     *** ** ***  *** * ***   ** ***    *
**  * * * *  *    **      *   * 
*   *  **     *  * *     *   ***   * %s",p,s);
**   *    **  * **** * *** * *** * *
 *** *** *   *   ****  *  **** *** **
*   * **     *   * *  ** * *   *  **     
 * *  **  *    *    **    ** **    * 
 *****  *    ***  * **  *  *    **      
  **  * * *  *   * *** ***** ***  *** * ** **    ****    ** is a prefix of %s",p,s);
*** * ******* *** *  *  *
 *** * * * * *   **** ***  * * *
*  **   **      * *  *  *   * ********** *  * * *    ** ** *** **   is not a prefix of %s",p,s);
    *** * * * * **    *  **    *
** * * * * * **  * **   *** ** *  0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.32
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 15.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 10.7k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 14.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users