1-11 Exercise 3: Prefix of a string

0 like 0 dislike
10k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 10k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include * **      *
#include *  *  *  * ** *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
** ****   ** **** **   **   * *  
 
* ** * *   * *  **    **   *     ***       **  *
  **  *   *  * * **  **   **    *
 *** ** *  **  *  *      * * *   *      *  *         **** *****  == s2[i])
 **    * * * **   *   **  ** *   **  *** ***** ***   *   
   * **** *** ***   *    ** *  **** * * * ***   **   ***  * * ******  *** ****          *
 **** * ***** ***** *    *  * * **  *   **  **     
 
    *   *** **     * *       **** * 
 
* *  ****   * *** *   ****  *** ** * * * == length)
   **   ** * ***** ** ****      ***** *
    *****  * * ***  *    ** **      **** **   **** *  * * *****   *****   is a prefix of %s",s1,s2);
   **   **     * *  * ** *  **  ** **  
 
  *** *  * ****  *  *         **   
  **    *  ** **  * * * **   
 ***    **        *   **   **   **  * ** * **  **** * ***    **** **** is not a prefix of %s",s1,s2);
***   ** ***   ** *    ******   *  
 return 0;
 *   **  * *  *       *   ******  
 }

int main(void)
{
* * *  **** * * ***** **   s1[100];
**  *     **   * *    * **** ** * s2[100];
 * *   ***  **** **     ** i,j;
* *  * ** *   *  * ****  * *
*** * ***   *** *       *  ***    ****    **     *    s1);
**** **** *  ***   ******* * ** **** *****  ** ***** s2);
 * ***       ** **  **   ***
* **  *   ***  *  ** * ** ** **  *** *
*  **  ** *    *  * * *       *
 ****  * ** *   **   *    *  *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   **** ***       * 
#include   ***       

int prefix (char st1[],char st2[]){
*  * *  * ** *****     ***   **** len=0, i, cnt=0;
***** * * *   ***   ****   ** 
  *** ***   ********** *      = (unsigned)strlen(st1);
**   ** **   **  ** * ***
  * * **   * *** *    * *   (i=0;i<len;i++)
** ** ** *    * *     ** *
     **** (st1[i]==st2[i]){
****   ***      ** * **  **  *  **   *   * *** *** * **** *   *  *** ****  *** **   ***
** ****** *  **  * * *** ** *** * *    *** *  * 
  * *    ** *   * ** * ***
 *  ***    * * ** **   ** **  ** (cnt == len){
   *   **** *   *    ** ***** *****  ** * **  * * * * 1;
   ****  ***** **      **** 
  *  * **  * ** * *    ******
   * ***      * *  *   ** ****** * 0;
 * * * *   *   *** * * * *
}

int main(void) {
 *** ***  *      **  **  * * st1[256];
 *  * * * * ** **    *  ****** st2[256];
 *** *  *****   **** * *****  ****      *  *  * * ***   * st1);
 ** **  *     *** **        ** *  * ** *  st2);

**     *****        * ***  (prefix(st1,st2)){
 * ***** *   * ** ** *  ** *    *  * **   ** *  *** **  *** *** is a prefix of %s", st1, st2);
* *    *  *   *  * **** ** *  *
  ** ** * *  ***  *   ** *** 
 ** ** **    ** *    *  *  * *  *  *  ***  ***  * *** * **    is not a prefix of %s", st1, st2);

 *   *    ** * *  *** **   0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
*  *  ***** * * *  **  * *  ***   **    * *  **  *   
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
 ***** ***  *    **    **** *  *** * *  *  ** * * *    * *
 * **  *  * *   ** **    **  *   *** *  **   * *   *** * *   * ***   * * * *   *   **  
 ***  **  *     * ****    * **    **** ***   ***  ** ***   ******   * **      * * *   * *    * **  *** * 
*** *   *** ****  ** ****  ** * **   * **      **  ****      ** * *  ** * *** ** * * *   * ** *********          **  *  * ** ** **   * ***   * ** ***  * *  is not a prefix of %s",a,b);
  **  ***    * * **  * * ***  * *  **** * *  *****    **       *  * * *** **  * * **  ***  ***   ** *   *        *  *  ** ** ***  ***  ***
*    * *   *    *** *  ***** ** * *** *** ***  * * * ****   *  *     *** * ** ** * * ****    * ** *  * * ** *
 * *  ***   *** * * ** **   ***  ** **  *  * * *  * **  ***     * *  * **   *  *  **
    **  **** *   *** ***   *** *   **** *** *   *** * **     * ** * *** *   **   ** **    * ** 
* ***  *** *** * **    ******* ** *** **  ***   *** ******* **     *  ***** * *  ****** * *  * *    *      ******   *    *   *  * * *    ** * is a prefix of %s",a,b);
 *    ** *  ** *  *** ** *      *  ***** *  * *   **    ***     *  *     *** *** **    *   * *  *  ***   * ** * * * *   ** * ** *  **** 
   * ** ** * **  * * *  **** *     * ** * **   **  ** * ****  ** * ***   ***  ***  ** ** *  *** *  *
  *   ****       ** ***  *   ***  ***** *  ***** ** 




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
 ***** * * *** **      * *  * **** *   **** 
******     **  *  ***  ** *** ***** ** **

** ** *** ** *   * *   ****** *    *** *** ********   ** ** * **   0)
*  *   *****   **** ***    *** ** ** *  * **  *    *    * * **  * 
 * * *  **  * *    *    * ***      ****** *   *** ** * * * **** ** * ******** *** * *   **      ***  ** *** *    *   is a prefix of %s",pre,str);
**** ***** * * * ****** **   * *** ** **  * *  **   *  * ** **** *  
  *  *  *   ***  **    *    ** ** * **    * * * **  * **
*  *     ****  *****  ** ****  * **  * * *** ** ** *****  **     *
* *   ** * *  *      *  ***   * *** ** *** **  *   ** * **** ** * *****   **  * *  *   **    *** *   ***** *****    ** **   ** is not a prefix of %s",pre,str);
 *  * * **    ***  ***   **    **** *  * * *    **  *  *****  * * **    ** ** *  ** *  

** *  * ****   *     ***    * *  ** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
* ***   * *******   * *****   *  a[100];

*  *  *   * * ***  *   *  *  * * b[100];

  ***  *  ***  * **  ** *    i = 0;

   * *  *** ** *    *** * * prefix = 1;

   * * ***   * *  *** **   *   * ** **      * **   *  a, b);

 ** **  ******    ****    * ** *    len = strlen(a);

* **    * *   *     *******  ** = 0; i < len; i++)
**   ** * **   *  *    *     *  
     **   *** ***     **** ********  * ***   **   **  != b[i])
**** * * **********  * * ***  * *  ** **** ***     ***
 * *  * * ***  * *    *     ***   ** **   *  * *******    * *  *  * * ** *** **     = 0;

*****  ********  *  ** **  **  ** **    * *** * ***** **  **** *     *  *  ***    *  *     *  *    *  *  is not a prefix of %s", a, b);

*     * *   ** **    ** **   **  ** * ***  ***   *** **    *    *** *  *  * ***    *   *  *
* *   ** ***    **  ***   ** *   * *  *    * **  *  *** ***
  ** **    *   * **   * * * 
       * *  *  **   ** **   *  **    * == 1)
  *   * * ******    ***
* * * * *** *    ***  * **********  ** *   ** **  ** ***         is a prefix of %s", a, b);

*** *** *     *    * **   
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   *  ****  * 
#include   *   ** * *   

int main() 
{ 
* ***** * *  * *****  * *  *  * a[100],b[100]; 
*     * **** ** *   *   *   i,j,prefix = 1; 
 * *    *  * * *  * * **  ***  *** * *  * %s",a,b); 
* *   * *** *       *  *   * * len = strlen(a); 
******** **  *  *  * *     *  = 0 ; i < len ; i++) 
*    * **** *    * * ** * * *  
***** ** **** *  *** *   ** * *  * * *    **** ***    ** *  != b[i]) 
*** * * * * *** ****  * *******  **** * *   ***   ***  
 ** * *   *  * *   *   ***     ***  * * **** *  * * **** *** *  * ** *  ***  ** ********  = 0; 
* ******  *  ***     *  * *  ******   *  *  * ***   *   **   ****      ***   * * *** * is not a prefix of %s",a,b); 
* ******* *   * **  * **  ** **** * * **** *  *      *  * *   * **** ** *   * 
  *  * **    **  * *  *  * ****** * ****       *       *  * 

 ***    **  ** ** *   * * * 
** * *    *   ** * **   ** *  == 1) 
** **   **   ****** * ***  * *** * ** *  ****** * ** **   ** *  is a prefix of %s",a,b); 

 
*    *  *****  **  * * ** *   *  0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ** ** * * *** *  *
#include  ** *  **  * ***

int main()
{
 ** ** * **  *    **     * * a[100],b[100];
*  *  ** * * * ** **** * i,j,prefix = 1;
 ***  *****  *    ****   * *** *   * *** %s",a,b);
*****   *  *  ** ***    ******  len = strlen(a);
  * ***   * *  *  *   * *  * *   = 0 ; i < len ; i++)
 **** **   *******     * * 
*    *** *  *  * * *  ********* **** *    *  ****   * *     != b[i])
   *  * *  *    *** ** ***   * * * ** ***  * **** ****  * 
  * ****    **  **     **  **** * *** ***  * *  * * *** *** **** *** * *   * *  *****     = 0;
* * **  * *  *****  *** ** ** *   * ** ** **** *  ***    *   ***  *  **  **   **    **   ** *   is not a prefix of %s",a,b);
* *   ****   *    * *  **  ****  * * ** ***  *   ***** *  ***    * ***    * * ** *
 **  *      * **  *  * *  **  *  *      * ** * **** **

 ***     ******* ** ***
**    *     *****   *   **** * * == 1)
**  ** ** *  *****  *    **  **  **   ** * **** *** ****** ****          is a prefix of %s",a,b);


  *  *  *  * **  * * *** *   0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *    **     ****
#include   *  * *  ****

int prefix(const char *pre, const char *str)
{

* *      *  *    * ***   **  *  * ** *  *  **    * 
** **  *  * ** **   *     * **       * * ***** *   * ** 0;
 *********     * ** *  *  * * **     * * *  *  *  *
** *  ** *   ** **    ***** *   *   *   ** * ***** *  1;
 *  *  *** **  * *** * ****** return 0;


}

int main()
{
***   ****** ** ***  *****  pre[100],str[100];
*** *  * *  ***   ** *
 * *  ****  *    * * *  ***    * **    *    *  *  *
** *  ** *  * ******* * **     * **    * **
  ** ****** *  * * *  *** * **  ** * **    **  *** **   *** * *** **  * is a prefix of %s",pre,str);
** *  * *** ** * * *  * *  ***** 
**  * ****   ***** * *   ***   ** * *      * * **  *** * ** *  *    * * is not a prefix of %s",pre,str);
**   * **   * *** **   ** *** ** * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
* *     *  *   *   *  **  **  c;
  **** **  ***  * * *  *** *  *  **   *     *  **  
**   *** * *  *       *  **  * * ****** ** ***  *** ** * *** * * * * 0;
*   **  *** ***  * **  * *  **
**     *** *      **   ******    *****
** *** *****  *******  ** * ** *   *  ***   *   * *** *  *  *  *  *   * *** **** of a string
 * ***  **  **    *  * *    * *  * ** * **   ** * * * *  * * ** ****    ***    * *  **   *  
**** ***** **  *  **   ** * ******    * ** *  ***   * * * *** ***  **  *  **  ***       *** ***  *  * ** *   *      0;
     *    ** ***  **  ****  *    ****** ** * * * *  * **
 **  ***    **  **  ** * * ***    * * *    **     ***  1;
    }
}

int main(){
 * ** ***** *     * *   *  *** a[100],b[100];
* **** ****** *** ** **** ****** * **     %s",a,b);
** ** **   ***  *** **** *  * ** * ***  **
 * ** **** *        *******   * *** **    * * *    ** ** **   **  is a prefix of %s",a,b);
  ***  * ** *   *     * ***
  * ** **   ** *****  *** * *********     ** *   *  ***  ** ***   * is not a prefix of %s",a,b);
 **    ****   *  * * *  ** ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 *** *   *  * * *  **  *** * ** ** p[100],s[100],a[100]={};
* *** ** *   * **  ***********  t;
 ****** *   ***  **** ** *   *   * * 
**** **  * * ** ****** **    **   *   ****
 **** * **   **   *   *    * * * **  * %s",p,s);
*     ** * *****  *** *     ** ** ***  
  ** *     **      ** **** * * * *****
  *     ** ** *  *** ***    * ** ** ** 
**   **  ***   *   *    ** *   **    * *   *
 *****  ** * ****       * * ** * ** *  *** 
*  ** ** *****    **    * *   ** **  * **   ** **  *** **** ** ***  * is a prefix of %s",p,s);
**   * *  **      *****   
*** ********  *****     * **     **
 *   ****  *  *   *   *   **   *  *   *** ***  * * *  * ***** * ** is not a prefix of %s",p,s);
 ***  **      ** **  *   ****
   ** * * * ** ******* **  *  * *  0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.52
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 14.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 10.2k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 13.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users