1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.1k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include ** * *   * *   
#include  ** * ***    

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
  *    * ** *   *   **** *  *
 
* * * **   ** ** ** * *** **** **** * *   ** ****      
* **  *  * ********   *   *     *  
* ****   ** *** *       **** ***     ****  **   *****  *** **   == s2[i])
*  ******  ***   *   ** * *******      ***  * ***** * 
  ***   * * **** *  ** ***     **     ** *    *  ** **   ** *  * ** * *   ** ***  ***   
  ** *          * ** *          **     ******* ** *****
 
 ** **  *  *  *  ****    ****   *** * * 
 
** *  ** *   **   ***    * * *  * ** ***    * == length)
** ***  * *  * ***  **  ***  *   *  *
*******  * **  *  *   **   * * * * *   * ** ******* * ***   **  is a prefix of %s",s1,s2);
* ** **    * *  *     ** *****  *
 
 ** **  * ** *     **     *   **   *  * *
*** * * * *  *     *   *   *    
*  *   **  **** *** *** * *  *  ******  **    **   ** * ****    **  is not a prefix of %s",s1,s2);
*  * * * * ** ** ****  ** *****     *
 return 0;
  * *   *  * * * *  **  * *** *  *****
 }

int main(void)
{
    *****  *  **** *** *** *  s1[100];
*    *    **    * **** *** * s2[100];
****** ******   *  *  * ** i,j;
 *** *      **  *  **   ****
 *  ****   *  *   * *   ***    ** * s1);
  *   * * * ***** ** *     ********* *   * *** *   s2);
* * *   ****  ***  *** *  * *
   **** ** *** *  *   *    *** **** 
      *  *      ****** *** *  *
*   * **   **  *      * * *    0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * * * * ** ****   
#include ** * **   * * *  * **

int prefix (char st1[],char st2[]){
*** * *  **    **** *    *    ** len=0, i, cnt=0;
 *****  **          *
* ***   **** *****   * * **  *   = (unsigned)strlen(st1);
**   *  *** ** *   * ***
 * ***** ** *  *****     **  (i=0;i<len;i++)
 * **  *** ** ** **** * * * 
  * * * *   *  * (st1[i]==st2[i]){
**  *****        ** * * ***** *    * *** **   *****         *  *** *  ** ****** *  *
*** ***    ***   * *  ********** **  ** * *  *       *    
 *  *  **  * *   *** ******
 *   *  *** *** * **  ****  *   **  (cnt == len){
* * ** **   ** * ** ** *  ***  * ** *   ****    ** * ****  ** * 1;
*   * *** ***  *  **  **  **
  ** *   ** *  **** *** * 
 * *    *** *** *    ***    * * *  * 0;
   * *   * ***  * ****** 
}

int main(void) {
***  ** **  ***  *****  *  * * * st1[256];
   *  **   * * ** ****  **  * st2[256];
* **   *****  **  ** *    ***  * * ***** *  ***   ***   st1);
* **** *    *  *     * * ********   **  *  *  ** st2);

*   ** **** ***  *  ****   *   (prefix(st1,st2)){
   * * ***   *** *  ***  ***   **   **** *** * **    *********** ** ** ***     is a prefix of %s", st1, st2);
*    **   ***** * *** ***  
***      *       *  *    *
 *** ****** * ****  **  ** * *  *    *   * *  *** ****  * *   * *      is not a prefix of %s", st1, st2);

 **** *   ** * * ** *   *  **  0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
   ** ****   ****   ** ** *    * ** * **  ** * 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
  *  *         ******  **   *  ** *****  ***  *** *
 * **     **      ***  *** ****  *  *  *     **** ** * *  *   *  *  ***  * * *  *** * ** *
  *****  * **   * * * * **  **  * **** ** *   **  **   ***** *      **** *  *    *   **  *  *
 *  * **  ** * * ** *   ***   *   * **  ****  *** **  ************* * *****     ***    ***    *   ** * *      *  **  ****  *  *** **     *  is not a prefix of %s",a,b);
**** *****  **   *    *    *      *  *  * * **  * ***  * ***  *****    * *  * **  ** ** ** **    ******** **  *   * ***  ***  * ******   ** * ****  * ****
   ***** *  ** *   *  ****    * ***** *   ***    *  *   *  **  *  *  ***  * * **   *   ****** ** * ** * *  
   * *** *    **  * ****  ***  ** *******  ***  *  ** ***  *      **   * ** ** *  
   * ** * * **** *  ******   *** *  ** *    *****  * *****      ** **  ** * *  * * *   ** ** * ****  * *****
  *   *   * **  * * ** ***        * ** ****  *  **  *   *  ** * ******    * * *  *      *    *****  *      *   * *  *   *  * * *** ******* *   *    *  ** is a prefix of %s",a,b);
    ** *  ** * * *  * ** * ***** ** **   * *    * * **** ** ***** *** **  ******     **  **  ** *** ***  *  *  *** *** ***   ***** * **
** ** ** *   * * **   *  * *  **   ******** ****  **  *  **  *  * ***** *      * * * * **     ****     * * *  ***
*  *** *    ** * *   *    *          **   ***  ** *  




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
****    *  ** *  * *   *   *  **     **   **   
*  ****** * *** * * *  ****   *  ** **     * *

 ***  ** ***** ** *** * **** *  * ** * * *   *  ** ** * * ** ***   ** ** *     0)
  *** **     * *    ***  *  *  *   * **  *  ***  * **    *** * * ** *  *   ** ** *   
*   *******   ** *****  *  * ***  * * *** *     **** * *  * **    ** **** * * *  * * ** *   ** *   ** ** * is a prefix of %s",pre,str);
    * ** ***   *    *    * *** *   *  * ****   ****** **  ******* * *  **  
** ********* ***  ** ********  *  ***   *   *   *     ** ** 
***  *      ***** ** **     *  *  ***  *** ** ** **  *    * **** ***   
 *         *  * *  * *** *****  * ****  * ** ** * ****   ** *** * **  *** *** * **  *    *****  *** *   *********  * **  * * is not a prefix of %s",pre,str);
    *** ***   **   *  *** **      ******  * * *  * ** * ***    **  * ** **  * **** *

 * * *   *  *  *  * * ****   0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
** *  **   **  * **     *  *  *  a[100];

**   *  * *  * *  * ** *  * b[100];

* ** * ** ****** * **   * ** **  i = 0;

* * * * **  *  * *** prefix = 1;

*  **** ***  ****  *  ***   * * *  **  ** * * a, b);

    * * ***** **   * **    *   * len = strlen(a);

* *   *    **  **     **   = 0; i < len; i++)
  * **    ** **   * ***  
  *** ***     * **  *   ** *  * ****** ** *** ** * **  *** != b[i])
   * * **  *  * * ***** * ** *** * * * *     *  ** *
*  * *    ** * * * ** *** * * *  ****  *     ****  *   *   ** * ** *      *** **  = 0;

* **   ** * **** **** * ***  **** *         * ** *   ******  ***    * * * *  *  * * ** **   * * * **    *  is not a prefix of %s", a, b);

  ***     * *  * * *** **    * *    ** ** ***   ** ********  *   *   *  *******
 **  *       *  * * ***** *      **   ****  *   * * * *
 ***** *   * ****** *  ** *
 **  *  ***   **   *      ***** *  * == 1)
* *  *** ****  *****   *  
  **  * *****   *    **  ** *      * * ****    **  * **   **  *  *** is a prefix of %s", a, b);

 * * * **    ******  *  * ****
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * **  *        *   * 
#include    * * * ** ** * * 

int main() 
{ 
**  **     * * ** * ***  * *  **  a[100],b[100]; 
   ** * **  ** * *** * * *   i,j,prefix = 1; 
* * ***  ****  *****      *  ** *** ** %s",a,b); 
*   * ** ** **   *** * * len = strlen(a); 
   * ***  * ***** *   ***  ** * = 0 ; i < len ; i++) 
   *    ** * *   *    * * *   
* **** * ***** *** ***   ** *** *** ***** * **** * *    * *  != b[i]) 
 **   * ***    *    **** **         ** **  * **    
* *** ** *  *  *****  * * **   ** *   ***** ***** *** **    ****** * **   = 0; 
  **  **   * * ***  ***  * *  *  ** **  *** **     **   *  *** **    ***  *** * *****  **   *   is not a prefix of %s",a,b); 
** *  ** *    *   ************ *  **  **  ***       ***  * * * *     * *  * * ** *  ** *  
*    *   * * * ** **  ** ** ***  * *** * *    * ***  ***  

**** * **  ***** * ****  ** 
***  ** *   *    * * **   ** *  *** ** == 1) 
*    *  * *  **    * * * *   ***** * *    *  ***  * * * *  *  *     * is a prefix of %s",a,b); 

 
 *    * * *  ******   *  *** **  *  0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ** ***   **** **
#include  *** **   * ** *  * 

int main()
{
***  ***         ** ****** * a[100],b[100];
 ***  * * *  *          **  * i,j,prefix = 1;
 **    *    *   **  *    ** *   * * *   ** %s",a,b);
 * *  ***   * *****  *    *  *** ** len = strlen(a);
 * * ** *   *  **   *  *     = 0 ; i < len ; i++)
 *     ** ** ** ***** * * ****
  *   * **    **   * * *  *  *   * ** * * **  *  **  **  != b[i])
**    *   *  *** *  ** ** **   ** **    *    *  *******
****  *    *** *** ** * ****    *  **  *  **   *  *  **  ****  **  *  *** *   ****** = 0;
*  *** **  * *** * * * *  ** * *  *  ** *   * ** ***** * * ** *   * *** *  **  *** **     * *   is not a prefix of %s",a,b);
 * *****  **   **  *   *  *    **  * **   ** ** *** **   **  *  ***       * ** *  
*  *******  *** **      ** ***    *** **   *** * ***   

* * ** *** *** ** ** * ***
**  *     **       * ****  * * == 1)
  * *   ** ******* * *  * **** ** * * ** * * * **  * *      is a prefix of %s",a,b);


   *  * ***  ** **  **    * *  0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  **    ** * 
#include  * * ** **** * **

int prefix(const char *pre, const char *str)
{

 * *   * * *  **  * **  *  **   *******  * * 
** **** ***   * ******   *** ***   *    *  * *** ** ** * *   * 0;
* **   *  ** *   *** *  * * * * ** ** * *  ****
  ****  ** *   * *  **     * *    *        *   * * * * ****   * * 1;
***      * *  ***  **** **      * * return 0;


}

int main()
{
******  *  ***   **  ****  pre[100],str[100];
   ** **   * ** *** ******* 
** **** ***  **   ** * * *****   **  *   * * *
*  **  ***      *  *   *  **   * * 
     *  **     **  **    * ****     *** ***  ***  ** ** *  **  *     *  *  is a prefix of %s",pre,str);
* ** ***  **  **** ** *   ** 
  * * ***    * ***      *  *** **   ********* * ** * ***  **   ** is not a prefix of %s",pre,str);
*   *** *   * * * *      **  *    0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
* **  * *   **  * *    ***  **  c;
 * *    ** * ***     *      *** * ** *  *** ** *   
*** * * ******    **   * *  *   *** * ***  ****** 0;
* ** ** *   * **  *    * 
  * * *  ***  ** ***** *** *
 * * *  * * * ** *** ***  * * *   ***  ****   *  ***    ** ***      * * ** of a string
  **  ***  *  * ******     *   * ********  * ** * * **      *  *    *  ** ** *   
 *  *  * **    *  **   ** *  * *   * * *** *   *******  **   * ** **   *  **** **   *** *** * * *   ** * *   0;
* * *   *  **  * *   *  *  ** * * **  *********  ** 
 * * ** *        * * *** ** *  *  * ***   ***      **   1;
    }
}

int main(){
 ** *  *     *  ***    a[100],b[100];
     * * *   *   ** ** ***** ****   * %s",a,b);
 *** * *  * *   * * *  * *** * ** *
*       ** **** * * ****   *****  ** *     * *    *  * * ***** * ***** is a prefix of %s",a,b);
**      * ***** * **    * * *****    
**   * *    * *******  *** **     * * ** * *** * * * **  **    **** **** *    is not a prefix of %s",a,b);
*    *  ******  * *    ***     0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*    **   * * ******* ***  ** *    * p[100],s[100],a[100]={};
*  *  ***  ****  * **  ** **  ** t;
 * ** *   ** * ** **** *  **  *  **  *  *   * 
 *  **    * ** * *  *   *  ***   ** *** *  * *  
 *  ** ***  *   * *   * ** **  *  *     **  %s",p,s);
*     *** **  **** ** *  *** ** * *
 * ****  * * ****    *  ** **     * ***   *
*               * ** * *    ** ** **   
**   *   *****   **** *   ***  ****  ***** ****
     * *  *** ****** **    *** * * *   * 
 **    ****** ****  *  ***     *    *  * * ***  ***** ** ** **  **  *** ** is a prefix of %s",p,s);
*** ******* *  *  * * **  
*   * **    * **** ** ***
**     * *  * ** * **   * *****  **  ** *  *    *     * ** **** ** is not a prefix of %s",p,s);
*** ** * * **   **   *   *
 **      ** *  ** * ** *  *     0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.32
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 17.2k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.4k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 15.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users