1-11 Exercise 3: Prefix of a string

0 like 0 dislike
7.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 7.5k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include   * **       **
#include * * *    * **  * 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
*     * ** ***  *  **  **
 
*   * * * *   ** *  ** * * **  *    **  ****  ** *****
   *   * **  **   *  * *   * *  *  *
**     *   * *  **  **** *** ** ***  *     *** ** * == s2[i])
 * ** *** **    *  **** *   *    **** *       **   * ** *
    *  *   *    * * *      *** *     ** *  *  *** *******  *** * * * ** **    ** ***  
   ******  *  *** *    *****  *  ** * * * **    * **   *** 
 
 **  *    *   **  ****   * *** ** 
 
* * * ***  * *  * *    * ***** * == length)
**    ***  ******* *  *** *  ***   *
*   ** *   *****  * **  * **    *  **   * *****  *********  *** *   * **   **   is a prefix of %s",s1,s2);
*  ** ** **  ** * ** * *    *  *  **
 
 * ****** ***  ***  *  ***  ***   ** * 
    * *    *******  * *     ** ***
***   **  * * *******  *****  ***    *   * ** **     ** * **   *****   is not a prefix of %s",s1,s2);
**  * *** **        * *     *     ** 
 return 0;
**** *  * **** *         * * **** 
 }

int main(void)
{
* * * ** **  * **   * s1[100];
 *   ** *** * * ******** **    * s2[100];
  ***  *  *   * **** ******** *  i,j;
   *  * * *** **** * *** *  *
  *  ** *  * **  **** * *   ***  *    **     s1);
*       **  ***     ****    ** *   **** s2);
 * *******    * *** ** * ** ** 
   *   ****  ***  **   ******
** * *   *  *  *  *   ** *** 
     ***** ** ******     *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *  ** ** ** 
#include  *  * * *     *   

int prefix (char st1[],char st2[]){
    ******* *****  ** ****   len=0, i, cnt=0;
     ******** *   **   *** 
* *  *  *****  **  **** ** = (unsigned)strlen(st1);
 ***** ***    *  * *     *  
 * ** * *     * *** ****  ** (i=0;i<len;i++)
  *** *  * **    ** ***  *
 *  * ** *    ** (st1[i]==st2[i]){
    * * * *   ** ** *** * * **  *    *    *******   ***  **    *  *    *  ** **  *
* ****  * ** *  ** **   *   ***** * **  ** *  * *** 
*    **** *** * * * * ***
* *****   *** *   * *  **** *  (cnt == len){
   **** *   * *** * *  **  * **    ***** *   *    *  *   * *   1;
*  ***** **    *  * **    * 
* ** ** ***  * ****   ** *
*  * ** * *   **  ***  *  *** 0;
     *   * *  **    ***  
}

int main(void) {
    ** ** ***** ***   **** *   st1[256];
* **   *****  *      **** st2[256];
*     *   * * *   ******  *** *** **  *****   * ** ***  st1);
 ** * * ****  *** **     *   *      * **** *    * st2);

 *  * *   ****  *       *  * (prefix(st1,st2)){
*** *     ** *  *** *    * ****   **     ***** *  *    **      is a prefix of %s", st1, st2);
**    ** *** ****** ** * ** * **
**  *** ***   *  *  ***    *  * * *  
 **  *****   * **  *  **** * ***   ** ***  * *  ******  *   *  is not a prefix of %s", st1, st2);

**  **** * *  * * *******   *  *   * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
*  *** ***  * *     * **  *  **  ***    *  * *  *** 
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
  *   **** *  ** ** *  *** *    * *  *  *    **   ****  
 ***  ***  *  *  ** **  *** **   *   *  * ***     **** ***   *** *  ** *** *** *****
*   * *  **     *  * *  ***** * * *    *  *  *** *  ** *   **** ** *  **  ** **          * *** *  *   * 
** *  ** * * * * ****    * * ** *   * * *  *     * * * **    *** *****     * * *  * **  * *  * ** *     ***  ** *  **   **    *  * *   * *  ** is not a prefix of %s",a,b);
 * *    *   *** * *  ****** ***    **** * * *    ** ** * **   *  * ***   * ***** ***** *  *   *  **  ** **  *  *****    *       *** * *  ** ***   
 ** *******  * **  **  **** * ** *  ** * ***   *    **** ***** ******** *    ** *  *******    *  **** 
 *     ***   ** * *     * **** **  * **  *   ** **  ****** * *** ** *** *   * ****
 * * *  * ** ****  ** * ** * *  * ** * ***   **     **      * *  ***   ** *  *           *  ******* ** * **   
 ***   * *    **  **** ** ** * *   * ** **  ** * *  ******* *** ***  **  * *****       *  **  ****** *  * * *     *  **          *    * **    * is a prefix of %s",a,b);
*  ***     **     *     * *      ***  * **  *      *  * * *  * ** *    *       ** *** *  **      *****   * * *  **  **  **** *      *
 * *   *  * *   *   **  *  * ****  * * ** *       *     ** *  **      ***  **  **   *  *   * **  * * * 
 *   *  *     *****  **    * *  **    ** *   * ** **  *




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
* *  * *** * ** ***     **   ****   ** ** * * **
 ** * * *  ****  * * ***     *      ** **   **

    * ** ** ** *** * * * **    **** * *  *   *  ** ****   ***  *  *** *** 0)
 *  *  *     ** * *** *****   *   *    *** **   *  * *  ******   *  
**   * **   * *   **** ** *           ** **     *   **   *  * * ** **     * *** **  *    ** **   * **  * *  * is a prefix of %s",pre,str);
* ***      **  *   * ** *  *  * * ** ******  *** **  ** * *   *  *       *  *
**   * *  ******     * *  ** * * * **** ** * * *     ** 
* * * ** * *  **  *   *   ** ** * **  **** **     *  *     **   **  *   *** * *  *   
 *  ***  * * ** ******* ***   *  ** **   ********  ******   *    *** * ***  *  *  * *** ** ****  ***** ****** **   ***  * is not a prefix of %s",pre,str);
 *      **** * *    **  **  * **  ***  *** * *  **   ***** *** ** * ******* ** ** **

**  *  ***   **   * ** *  **   *  * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
   *    *  *   ***************   a[100];

*  *  **  ***  *  ***  *  **  b[100];

 *   ****    * * ** **   * i = 0;

     * *  *****  *    * * * prefix = 1;

  *** ***  *  ** * *  *  **     * *    * * ***  *   *   a, b);

***** *****   ** *** * len = strlen(a);

  **  * *  ***   ****   *  * * * * = 0; i < len; i++)
 *   ****      * ** *  *  *    *
** *  * *** * *****  *  *** **  ***  * ** * ****  **    * ***  != b[i])
*** ** **  **   *  **   ***  * ** ** * *      ***  ** 
      *****  **    ****  ** * ** ****    *    * *** *  * **      **   * ***** = 0;

** ***  *  ***   *   * *** *     ***    ***   * * * * *** ***  * *        * *   **   **   * *   * is not a prefix of %s", a, b);

 * *****  *  *** ** * * ** *  * ** *  * ***  * *  ***   ****   * ***** *   * 
  *  *** *** ** * *    **   **   *****   * *  *  *
     *  **  * *  **  * **  *
**   **   **  *  *** * ******    * * == 1)
 ****    * ***   * ***  *    
 * ** *    ****  *** * *  ****    *  *  ******* *    ***  * is a prefix of %s", a, b);

*    *  **** *  **   *    ** 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ****   **   **** 
#include         *  **  

int main() 
{ 
***** * *********   **     * * a[100],b[100]; 
** *  *** **** **** *  **    i,j,prefix = 1; 
     * *  ** ** *  **** *** * *  * *  %s",a,b); 
   *  *****  *** **     *  * *  len = strlen(a); 
  ** ** *   *     ****  **   *   = 0 ; i < len ; i++) 
   * **** ****    *** ***  
***   *****  * * ** *   *  * * *** *    * *      *      * * != b[i]) 
***  *  **   *** * *    *   *   **   *** ** **   *** ** * 
  * **** *  * *    *  * *   *  * *  *          ****  ****** **** * * *** ** * *  *  = 0; 
*    ****            * *     * **** *   **** **  **  * *  * ****   ** * *****  *** *** ****** * *  *** *  is not a prefix of %s",a,b); 
***   * **  * ***      *    ** *** **** ****  * *   **** *    ** ** *  **  *  **  * * 
 * ****  **  **  **  ***   ** ***   *   * ** *  *******   

* * ***  *  *** *      * *    
*** ** *     *     ** ** ***** == 1) 
 ** *   ***    ** *     ** *   *** ** * ***   ****   **  ** * * is a prefix of %s",a,b); 

 
**   * ***** * * * **    **** **  0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  *** *   ****   
#include *** * * ******   ** 

int main()
{
* ** **   *   * * ** *  * a[100],b[100];
 ** * * *   * * ** **   * ** i,j,prefix = 1;
 *    *  *****  * *   ***  * *     **   %s",a,b);
*  *  *   **    *******  ****** ** len = strlen(a);
*** *   * *****  * ******    *   *  = 0 ; i < len ; i++)
 *  **  ***  *      *  * * 
  *   *          *** **  *     * **  ** *   * *              != b[i])
*** **    ****  * *** * * ******  ** * ****  **     
**  ** **  *  *     * *  *  *  * *  ****   *    *   * **   *   *****   ** *   **** = 0;
** ** ****  **  * **    * ******   * *** ****  *    ** * *  *    * ** * **       ** ***    is not a prefix of %s",a,b);
*  **  **** ****  ** * * * ** * ** **  *       * ******  * **    * * *  *  ***  
**** *** * * ***       ******      **   *  *   *    * *

***   ****  ** * ** *  *  **  
 *** ****** *  **    *    ***   ** == 1)
*  ** *  ** *   ** ** *** *** *  *** ** *** * * **    **** * * **** ** is a prefix of %s",a,b);


 *****  ***   *********** * *  **  0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** ** ****  * *
#include      ** * * * 

int prefix(const char *pre, const char *str)
{

** * *  ** ** *** **  *  **   * * ** ** *  **   * *
 ** * **** ** **  *** *  *   ** *   ** ***    * **  *  0;
 ** *  ** ***   * * **  * **** ***  * *   **
**    *** ********   ***  *   *  ****  * **    *      *** 1;
  **  *    ***  *   **   * *    return 0;


}

int main()
{
  *** ***  *** ** *  *    pre[100],str[100];
 ** *** ***      *** ***
 * *   * ** ***   *  * ***  ** * **** *   *  ** 
 ** *** * ******   *    **      ***
* **  *  ***     **** ***  ****  **** *  **** **  ** ** * *  *      ***   * * is a prefix of %s",pre,str);
***  * *****    *  *** ******   
*       *    **    **** * ***  ***  **  **  **     *  ** ** is not a prefix of %s",pre,str);
   *      **  ****** *    0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
* *  *    ** * ** **   *** *  c;
*      *** * *  *** ***** * * *** * **    ***
*     ****   *    * ** **** **    * **  **   ** * ** **  * ** 0;
* * **  ***** * * **** *** *
 *   * ** *******  ** **   
*****  ** ****  **  ****       *       *  **** *   **** * * *   **  **  *** * of a string
 *  ** * **   *   **   *  *    **  ** *   **   ** ****  ** *  *  * **** ** * *   *** * ** * **
**  * *  *   **  ** *  *  *   **     *  ********   * * *    *  *   ** **   ** * *  ****    *     ** * * **   * 0;
****** * * * *** *     ** * ** ** * *   **   * * 
* ***** ** *   **** ******* * * **  *   *** * **     ** **  1;
    }
}

int main(){
 *  ***  ** *  ****   *       a[100],b[100];
 * * **** * ** ***    *  *  **      * %s",a,b);
 *   ** **  * *   ****       ** * *  
 *******   *   *** * *** ** **   *   *** ********   *****   ***  is a prefix of %s",a,b);
*    ***     *** *    ** *
**   *  * *** ** * ** *  * *  ** *     ** * **    ***    ** * * is not a prefix of %s",a,b);
** ***  *   * *  *  ***** ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
  *  ** *  * * * * ***   * p[100],s[100],a[100]={};
 * *   **  ****** *  * *   * t;
  **     ***** ** *   *   *     *   *   ** 
**  * **  *   ** ***  * *     **    * *
**   *  * * * *     *** *  ******  %s",p,s);
*  * ****    *  * ** *****  *      
*   **       *    * * *** * * ** ** **
*********  ** *  ** **  ** *      ** * 
 *  * **   * **   ** ** * ****** *  * ***  
 * **  **      *** * *** * *     ******  
**   * **  ** *  * *   **** **  * **** ****  * ** **** ***  ***  is a prefix of %s",p,s);
****  ** ****  *  ***** * * 
**** ** ** *  * * ***    * ** *  
 *** * * **  **    **  * **      *** * *  * * ****  *  * *     * is not a prefix of %s",p,s);
*** **   * * ***  ***  ****  * 
    * *** ***  * * ****  * * *   0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.95
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 11k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 7.2k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 10k views
12,783 questions
183,442 answers
172,219 comments
4,824 users