1-11 Exercise 3: Prefix of a string

0 like 0 dislike
10.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 10.8k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include **  **  * **  
#include    * * ********** *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
** **** ***   ****    * 
 
 **  * * *  * **  *  **  *  * *  ****   * ***  ** *** *
* *  *    *   *** *  *** ** ***   *
* ***    ** * * *    * ** *** *   *      *****  * *    *** == s2[i])
   **** *    *   *  *   * **   *  **  * *   ***** *    
********     * **   ****** **** **       ** ** ** ** **   * ** ** *** ***    * * ***  **   **
*  *** ** ***  **  *   * **    **   ** ***** ** **
 
* ***   *** * ******* ***    * *  
 
   ** ** *** *   ********  *   ** *** * == length)
  *** ***   ** *****  * ** ** *** *
*  ***  **  ***   *   *   *   **   ** *    ***     * *    **  ** **** ***** is a prefix of %s",s1,s2);
      ** **  **   * *  * * *  **   **   **
 
* **   *   *  * **   * * ***  *  *
** ** * *   * *** *     ***** ** **** 
    *      ***  * **  ***      * **     * *  *  *  *   ***  * * ** ** *  * is not a prefix of %s",s1,s2);
*  **  **  * ** * *  ***** *   * *
 return 0;
*    **  * ** ****  *  ** ** **  *    
 }

int main(void)
{
**   ** *   * ** * * * * *     s1[100];
    ******   **  * * *** **  ** s2[100];
*   ***** * ** *  **      ** i,j;
* * * * ***** *    *  ** *  
     *****     **   *  *      ** ** **  *  ** s1);
   *       ***  *   * * * * * ** * * **  *  * * s2);
 **   * * ****** **  ** **  **
* * *** *******  * *  * *    **** *  ** 
***  *****  ***  * *
 **   * *****   *  ***** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * **** *****   **
#include  *** *  *****

int prefix (char st1[],char st2[]){
 *    * ***** *  * **** len=0, i, cnt=0;
   * *   ****      ****
  ** **    ** **  *** **    *** * = (unsigned)strlen(st1);
***       *** *  *   * *
   *  * *     **    ** *** **   (i=0;i<len;i++)
**   * **  *   ****  ****
**  *** **     * (st1[i]==st2[i]){
    * * **  **   ***  *   **   ***  **** * *    *** ** **** * ***** *** **
*  ** *   ***    *  *  *  * ** **         *  * * ***   ***  ****
 ** * *     *   ** ** * *    
  *** ** * **   ****** **** ** (cnt == len){
**** *  *** * ***  *  *  *   ** **   * ***       ** * 1;
  *   * *** *  * ** * *** **** ** 
     * **    * * ** *
  *   * *** *   * ** **  * * 0;
  *  ** *  * *   * *   * * 
}

int main(void) {
 **   ***   *  *  *   *    st1[256];
**  *   * ** *  *** **    *   st2[256];
* **         ****  * * *** * *  * ***   **  **** st1);
   ***  *   ** *   * * *         ***  **  * ****** st2);

********  ** *  * * * **  *   * ** (prefix(st1,st2)){
** ** ****    *  * * *** **  ** * *   * * *** *    *   **  **** is a prefix of %s", st1, st2);
** **  * * *****   *  *   
* *** * *** ****    ****    *   **  
 *  ***     *  * *    **   * *     ***      *** *  ******    **   is not a prefix of %s", st1, st2);

  **  ******* ** ** *** ***  *  ** * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
*  *  * ***  * *  *  *   ** **  * * * *  ****    
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
 ** ** * ** ** * ***  *  * **  ** **  * ** ** ***
  *  *  ***   * *    *** *   * **  *    * ** ** **** **  * *    ******* * * * * * ***  *    
** *   *  * * ** * *** **** **  *  **    **  **   * ** * *** ***  ******* * *** **       ***  *** **      ** *** 
      * *   *  *  *** **  ***  ***    ***  ***  * **    * **** *  * *    ***    * ** **   *  *  ***  ** *****  *** * * *** *  **********  ***      **** ***** is not a prefix of %s",a,b);
*** ** **  *     *  * **  ** **    ***** *  *   * ****  ******  ** *   *  ** * **  **** * ***    * * ** ***** **  *       ** **   * ***** *  *
  ** ** **     **** **  * *   *   *   * **      ** **  * ** **    *  ***       *  * * *     ** *   * *   *  **  
     ** *   ***  ****  * **  * *   **       *     **  * ** *** * * *    
 ** *   ******  * * * *  * * *  *** ** ** ****** ** * * **** ** *   * **  ****   *** ** * **   *    
**    ***   *   **** * *       * *** ** ** * **** ***  *  *  * *   *    *  * *******    * * **    *      *  *** ****   *   ***  *    **  *** * is a prefix of %s",a,b);
*** *  * *   ** **  *   *** **     ***  *     ******     ***** ** * ***     *  * **  *** ***  ** *  * **    *** ***     * * * *  * ** 
******  * *  * * *  **   ** * *  * * **** ****************  ** *   ** ** *** ** *  * ***** * **      * * ****  ** 
* * *    *  *    * *  ****   * *    ******  *  * **  ** 




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
*** ***    * * ***    *****   *     * *       ** *
   **   *** *     * *  *  * ***   **  * *   *  * 

 * **** ***   * *  * **** * ** ** * ***  ** *  ****** ****   * **    * * * *****  0)
 *** *  ** *** ** **** * *** * *    * *   ***   ***  *   * * **    *****       * 
** ** **    * *       ** *  * * **  *    ***  * *  *  *       *****     ** *  * ** **  ***   ******     * **** **** is a prefix of %s",pre,str);
* * ****   * ******     *  * ** *  *  ** ** *   ***     **** ** **    ***
 **   *   *   **     **** * ** * *  *  ***** **  * ******
*   ****** *   * *** ***** ** * * * * * ****  *    * **  ** * * ** 
 ***** * *    *  * ***   ** ** ***  *     * *  *  ****    *******   **  *    ***** **    *******   * * * **  *    is not a prefix of %s",pre,str);
  **     **  ** *     **  * ***   *  *** ** ******* *** *******   *    ***   

* ****   *   *****  *** * ****** *  * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
**  ***  *  ***  **     a[100];

 ** * * *   ***  *    * ***** * b[100];

*  ** *  *   **  *   * *    i = 0;

****  ** **  **       * **** prefix = 1;

*  *    ***     * **** *****  * *** **  *  a, b);

    * ***    *****   ** *  * len = strlen(a);

** ***  ***    **   * ** *   **** = 0; i < len; i++)
   ** ***   ****  **  * *****
  *    *** ** *  ***  *     **   * **** ** * ** * * ** * ****  != b[i])
**  * *****   * *  * *    **   *** *  **** *  *
  *** ** ** ** * * * **  ***** **    ** **  ** *  * ** *    * *** *  ***    ***** *  ** ** **** = 0;

     **   **    ***  *  **   ***** *    * *  *  * *****    * *  ** **** * * **   *   ** ** ** *** is not a prefix of %s", a, b);

      **     ** ***** * **    * **  ** ***   ** **** **     *  *  * * * * ** *  ** * ***** *   * 
***  * **   *  *  *** ** * *  * * ** **  * * * *     * * ***
    *** ** **  ***    *   
* **   * **   ** *       **   == 1)
 * * *   *     ****      ***   *
*** *     **      * *  **  *   **   *              **     *  * *  *   is a prefix of %s", a, b);

*  **  *  *  *  *** * * *** 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *   * **   *  
#include  **** ** *  **** 

int main() 
{ 
 ** *  * * * **  * ** * * * *  a[100],b[100]; 
* **** ** * * ***  ***  * ***** i,j,prefix = 1; 
* * **  **  * ** **  ***** **   * ** %s",a,b); 
** ** * *  * * ** ** * ***  ***  len = strlen(a); 
    *****    *   *** ***  *    = 0 ; i < len ; i++) 
***      *        *     * * 
 * ** *** *** **  **  ****   *   *  **     **   *  ***  *** != b[i]) 
*  ****   *  **  ** *   *  **   *  ** **** ** ***  *  
** * **  **      *   **    ** * *  *   **             * * *****      * ** * *  **  = 0; 
    * *  *** **  *** **     * ** ***  *  *   * * * *** *** ** *****     * ** *** * * * **  is not a prefix of %s",a,b); 
 * **   ** *  *  * ** * ** * *  *** **** ** ** ** **   * *   *  * **          ****   ******  
***   * ***  **** ***       **  ********** *   **     

** *   *********  **  * *     
 * ***  ** *** ***** * ** * ***** *  == 1) 
 * ** ***  *** * *  * *** *   * * * **  **  *  *  is a prefix of %s",a,b); 

 
***   * *   *   ** *     ******** 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ** * ** * *   ***  ** 
#include ***  *****   

int main()
{
*   **  * *   **  *** * * **      a[100],b[100];
     *** **   *  ***   ***** **  i,j,prefix = 1;
*   * ***  * *** *** ** *  * *  *    %s",a,b);
  *   * *  *  *  **   ***   ** ** len = strlen(a);
 * * ***  *** *   * **    **  = 0 ; i < len ; i++)
  **  ** * * *    ** ** 
  * **   *  *  *  **  * ** ***  ** *    * * ** **  *  ** != b[i])
     ** *   *  *    ******   *  **   *    ****  ** *****
*** * *** *  *** ** *  **** ***  *  ****  ********* *** * * * ****   *  * * *    ****** ** = 0;
*  ** * ***** * *  *  ***  * ***  ***   ****  **  * * **  **** *  **   * ***  *   *   * * *   is not a prefix of %s",a,b);
* ****   *** *    *   *****  ***** *   *  **    * * ***   * **  *   * **   ****      **
 **  * * ***   * **     ** *    *  *   **   **  ** * *   **  

  ***  ***   ****  *       ****
 ** **     * *  *** * *  == 1)
*  *    *** *    ** *  **** ** *** * *  *   **** ****** * * ***  *  **   *  is a prefix of %s",a,b);


  ***      ******** **  *  * ** *   0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** ** **     *
#include *** *  *   ** *

int prefix(const char *pre, const char *str)
{

 *      **  *** * **    * ******* *  * * * *   ** *   
** *  ***   * **  ***    **  * *   *    *  * *   *     *   0;
 **** * *   *   ****** ** *********  *  ****   *** 
  *** * *  * ***   *  * *  ***  *     ** ** ****  **  * * 1;
    *   *  ***  *  ****  *  **  return 0;


}

int main()
{
  **** * **  *    ****  pre[100],str[100];
**    ******* *    **   * *
* **  * *  *     ****      *    ** ** *    **  ***
*** ** * ** *** *  **  ***** **   **
 *   *   ***** ***** *   *    * * ** *  * ***   **  * *  *****  is a prefix of %s",pre,str);
***  * ** **   ***** *  * *  *
* ***    *     ****     *   *      ** ** ***  * * * ** ** *  ****** is not a prefix of %s",pre,str);
* *****  * ** ***** * *   **  * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 *    * *  *** *******     c;
* ***   *   *  ***          *   ****  *** ***
* *  *   **** ** **      ******* * * *    *  ** * * ** 0;
*  **  *   *   ****     * *  
 *** ****  ******* *   * **
  *  * * **** ** *  *   ***    * * * ** *  **    * * * ****   *** ** **  *   ****   of a string
* *  ******  *****  **  *  * *    ** *** *  **** * *      **   ** * **    **  **     ****     
 **  **   **   *  **** **   *  * * * * * *  ***  ***  ***  *** ***      ***** ****  **  ***  *** * *  *     ***  0;
**   *** *  **  * **    *******   *  ****      * * 
 * **      ** * ** * ***  ****    **    **** *   1;
    }
}

int main(){
 * **   *  *  * **   * *   a[100],b[100];
 * * ***   **  ****  *  * **   *  *   *  *  %s",a,b);
   * **     ******    ** ** *   **    
* ** ** * ***      * ******  *****  *** ***   *    *  ****  * *     is a prefix of %s",a,b);
  *   ** *   *  *  * *  ** * *  
  * **            ****    *  * **** ** ***  *     * *   ***** *    *** is not a prefix of %s",a,b);
* *  *** * * *     ** **   *  * * *  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*   *    **** *  ****  * * *   *  p[100],s[100],a[100]={};
**  *  * *  *********  *   *  ****  t;
 * **   *** ** ** *  **        *****  * ** 
    **  * *** * *** * * **  ** *  ** * 
** * *****   ** **  ** * * * *** ***   %s",p,s);
* *  ** ** **   ***** ** ******  **
*    **  ***  *  *       **   * * 
*  * ** *****  **  **   *  ** **   ***
  ** * *   **  *  * *   ** *****   * * * **
**  **   ****  *  *  * * * **   *  ***
***  *  **   *  *  ******* ** ***** ***** *   *  *   *** ** * *    * * is a prefix of %s",p,s);
*  ** ** *  ****** *  **
 *** * ** *    ****    * * * *
*** * *******  * ** *  * * ***  ********* *  **** *   **** * **     is not a prefix of %s",p,s);
 * *  * *    ****  * * **** *
 ***   ***  *** *    * *   *  0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.120.164
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 15.7k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 10.7k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 14.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users