0 like 0 dislike
15.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited

edited by | 15.1k views
0 0
12345

27 Answers

0 like 0 dislike
Hidden content!
#include ** *** ** * *
#include * ** * ** *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
** * * * * *** * *
 
***** ** *** ** * *** * * ** ** * *** * * *
**** ** * * * **** * ** **
** * * * **** * ******** * *** ** *** **** == s2[i])
** * ****** ** * * ** ** * * * * ** * * *****
* ** *** ***** *** * *** * ** **** ****** ******* * * * * *** ** *
* * * **** ***** * * * * * * ** *** ** ** ***** **
 
* * * ** ** *** * *
 
* * * * **** * * * *** ** == length)
** ** *** ** * ** ** ***** *
* * ***** * * ** *** * ** * * * ** ** **** ** *** ** * ** * * is a prefix of %s",s1,s2);
* ** * * ** * * ** * * **** *
 
* ** * * * *** * *** ** * * *
* ** * * ** ** **** *
** * ** ***** * ***** ** ** *** * **** * * ** * * * * * * * is not a prefix of %s",s1,s2);
* * ** * * * ** * *** * **
 return 0;
* * * * * * ** * * **** *
 }

int main(void)
{
**** * * * * * **** s1[100];
** * *** *** ****** * * s2[100];
** * ** * * * * * i,j;
*** ** *** * **
* ** ** * ** ** * **** **** ** s1);
** ***** * * ** ** ** ** * * * * s2);
** ** * ** * *** * *****
*** * *** ** ** *****
* * *** * ** * * * * *
* * **** * ** *** ** * *** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include * * ***** **
#include ***** *

int prefix (char st1[],char st2[]){
** ****** ** * * * len=0, i, cnt=0;
* * *** * ** **** *
* **** ** ******** *** = (unsigned)strlen(st1);
**** *** * * * ** ***
* * * ** * *** ** (i=0;i<len;i++)
** * * * * * * * *
* **** *** (st1[i]==st2[i]){
** * * ** * ** * ** * ** * ** ** * ** * * * * * ** * * ** ** * *
** * ** * ** * ** * * *** * **** **
* * * ** *** *** * * *
* *** * ** **** (cnt == len){
* * * * * ** ** ***** ** * ** * ** * * * ** ** 1;
** ** * *** * *** *
** * * * ** ***
** ** * ** * *** 0;
* ** ** ** * * * * ** ***
}

int main(void) {
** * * * *** ** * st1[256];
**** * ***** * *** ****** st2[256];
** * ** * * ** ** ** * ****** *** * st1);
* * * ** ** * * * ** ****** * * st2);

********* ** ** ** * * (prefix(st1,st2)){
* * **** * * ** ** * * * ** * *** ** * is a prefix of %s", st1, st2);
* *** ***** * * ****
* ** ** **** *** *** * * * *
* *** ** ** * * * ** * * ** * * * ** * * * is not a prefix of %s", st1, st2);

** ********** * *** ** * * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
** *** * * ** * * * * *** *** *** **
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
*** *** * * * ****** * * ** ** **** **
* *** * * ** * * * *** ** **** * * *** ** * ***** **** * ** * * *
* ** * ** *** ** ** * ** * * ** *** * *** * ** *** *** * * * * * * ***
* ** *** * *** * * * *** *** *** ** *** *** * * ** ** ** ** * * ******* * ** ** ** ** ** ** ** * * * ** *** * * * * * *** ** is not a prefix of %s",a,b);
** ** ** ******** ** ** * * *** * * ** * *** * * ******** * *** * * * * * *** * * * ** * * *** * **
* **** *** * ** * * * ***** * ** **** * ** ** * ** * ** * * * **** *** *** * *
* * ** * *** * * ** * * * * * ** * ** * * * *** ******
* * ** * * * ***** *** * **** ** * * * **** * * * * * ** *** *** ********** *** *
* *** ** ** ** ** * ***** * * * *** *** *** *** * ** * * * * * * * * * * **** ** ** * * * * *** * ** *** ***** is a prefix of %s",a,b);
** * *** * *** * ** * *** * * * * ** * * **** * **** * * ** * * ** * ***** * ** * * * * *** *** * ** *****
*** ** * ** * * *** * ** * * * ** * * * *** * ****** **** * ** ** *** ** ** * **** *** ****
** **** * * * ** **** ** * ** ** * * ** **




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
* * * ** * * * ******* * * *** ** * *** ** *
** ****** * ** * ** * *** *** * * *

* * * ** * **** ** * * * *** * *** * * *** **** ** *** * 0)
** *** *** *** * * * ** *** ** ** *** * * **** ** **** * * * *
* * **** * ** * * * **** * * *** * * * ***** * *** * ** **** * * * * * * * ** ** is a prefix of %s",pre,str);
**** ****** * ***** *** ** *** ** ***** **** *** * * * *
*** * ******* ** * * * **** * * * *** * ******* *
* * * ** *** **** * *** ** ***** ** *** * **** * * * * ** *** *** ******* *
*** * * ** ** * *** ** * * * * *** * * ****** **** *** * *** ***** ******* ** **** * ** * ** ** * is not a prefix of %s",pre,str);
* * * **** ** * *** **** *** ** * *** *** ****** ** *

* * ***** ** * * **** ** *** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
* * * * * ** * * ** *** ** a[100];

* *** ** * ** ** * ** * * b[100];

* *** ** ** ** * i = 0;

* ** * * *** *** * prefix = 1;

*** * ** ******* ** ** *** *** ** **** a, b);

*** * **** * **** ** **** ** len = strlen(a);

****** ** * * * * *** = 0; i < len; i++)
* * * * ****** ****
**** * * *** * * ****** ** ***** **** * * ** *** != b[i])
** ** * * * **** ** ** ** * * * ***** **
** * * ** * *** ** ** ** * * * * * * * * * * * * ** *** * * ** ** = 0;

** * * ** * ** **** * * *** *** ** *** ** ** ** * **** * * * * * * * * ** * is not a prefix of %s", a, b);

* * * *** **** *** *** ** * *** *** ** **** ** * ** * ******
***** *** ** ** * *** ** * ** *** ** *** *** *
* ** * * ***** *** ** *
* **** * ***** *** * * ** * == 1)
** ** * * ** * *** *
* * * ******* * * *** ** ** **** * ** ** *** * * * * is a prefix of %s", a, b);

* * ** * **** * ****
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include * * * * **
#include **** * ** ****

int main()
{
** * ** * * *** ** * * ** * a[100],b[100];
** * * * ** *** * * i,j,prefix = 1;
* *** ** * ** * * ** **** * %s",a,b);
*** ** ** ** * *** * * *** len = strlen(a);
**** * ***** ** ** * = 0 ; i < len ; i++)
***** * *** *******
* * *** ** * **** ** ** * * * * * **** ** != b[i])
** * ** * **** * * * * *
*** * *** ** * * ****** **** ** * * *** * *** *** ** * **** ****** = 0;
* * * * * * **** ** * *** * * ** * * * ** * * * * * *** * * * **** is not a prefix of %s",a,b);
* * * * ******** **** ***** *** ** * ** * ** *** * * ** ** ** * ***
** ** * * ** ** ** *** *** ** **** ** * *

* * *** *** ** ** * **
* *** ****** * * ** ** * * == 1)
* * *** * * ** ** * * ** **** ** * *** **** ** * ** is a prefix of %s",a,b);

 
*** ** * **** * *** **** ** 0;
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * ****
#include ** ** *** * *

int main()
{
** * ** * * ** * ***** * a[100],b[100];
* * * * * *** * i,j,prefix = 1;
* ***** * * *** * **** *** %s",a,b);
**** ** *** * * * * ** len = strlen(a);
***** **** ** * * * * *** ** = 0 ; i < len ; i++)
** **** ** * * * * ** * *
*** ** ** * *** ** * * *** ** ** * * * ** != b[i])
**** ** ** ** ** ** ** * * * * * *** * **** * ***
****** * * ** * ***** **** * ** **** ** * * ** * * * ** *** * * = 0;
** *** * * **** * ** ** * * * *** * ** * **** *** **** *** *** ** * * ***** is not a prefix of %s",a,b);
*** * *** * ***** * *** * **** * * * ***** ***** * * ******
* * * * *** ** *** ******** * * * * * * ** *

* * * * * * *** *
** * * * * **** ** ** ******* == 1)
* * * **** * *** ***** * * * ** * * * * is a prefix of %s",a,b);


* ** * * ** **** * * ** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include * ******** *
#include **** *** *

int prefix(const char *pre, const char *str)
{

** * * ******** * ***** * *** *** * * * * * **
* * * * ***** *** * * ** ** * *** * ** ******** 0;
**** **** *** *** ******** ** * * * *** * * * ***
** *** * * *** *** ** ** ** * *** * * * * * 1;
* *** **** * * * ** ** * return 0;


}

int main()
{
* * ** ** *** * * * * pre[100],str[100];
* * * * * * *
* ** * * * ** * ** * ** ***** * *
** **** **** ** * ** ** *** * ** * ** **
* **** *** **** *** * * * * * *** ** * * is a prefix of %s",pre,str);
** *** * * * *
* ** * ***** * ** * *** * ** ** * ** ** * * **** ** * is not a prefix of %s",pre,str);
**** * ** * * ** * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
** * ** * * * * ** * * * c;
* * ** ** * ** * * ** * ** *** * * **
** ** * *** ** * *** * ** *** ** * *** ** * *** * 0;
***** ** *** **
*** *** **** * *** * * * ***
* ** * ** * *** * * *** ** ** ** * * **** * * * ** * of a string
** **** ** * ** * * ****** *** *** * * ** ** * * ** * **
* **** ** * *** * ** * * **** * * * **** *** *** * ** *** ** ** * ** **** * *** ** 0;
** * *** * ** ****** ** ** * ** * ** *
**** *** * * * ** * * ** ** *** * **** * 1;
    }
}

int main(){
*** * *** * * * * **** a[100],b[100];
*** ********* * * * * ****** * *** * %s",a,b);
*** ** ** ** *** ** *** ** *
**** ** * * ******* ** ** **** ** ***** * * ** * * is a prefix of %s",a,b);
* ** * * ** *** * **
** ** *** * * **** ** *** * * * * * *** * ** ** *** is not a prefix of %s",a,b);
* ******* ****** * * * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ***** ******** ** * ** p[100],s[100],a[100]={};
* * * * ** ** **** ** * t;
*** ** ** *** * * * * **
** ** * * * ** * ** * **** ** **
* * * * * ** ** * *** * * %s",p,s);
**** * * *** **** ** ** * ***
** * * * **** * * *** ** ****
* ** ** ******** ** *
*** * * **** *** * * * * *** * *** *
*** * ** * ** **** * ** * * **
* ** ** * *** **** ** ** ** **** * * *** **** is a prefix of %s",p,s);
* ** * ** * * * ** ******
***** * ****** * * ***
* * ** * * * * ** * *** * *** * * * * *** * ******** is not a prefix of %s",p,s);
**** * * * *****
***** *** * *********** * * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.65
©2016-2026

Related questions

0 like 0 dislike
57 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited
| 21.7k views
0 like 0 dislike
29 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited
| 14.2k views
0 like 0 dislike
53 answers
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited
| 19.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users