1-11 Exercise 3: Prefix of a string

Question

12.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited Jan 11, 2018 by semicolon | 12.5k views

27 Answers

Page:

Diyiel · Answer 1 · 2018-01-13 00:58:32

Hidden content!
#include   *  **     * * *
#include    ********

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
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{
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}

answered Jan 13, 2018 by Diyiel (-193 points)

Stephen Richards · Answer 2 · 2018-01-13 00:46:20

Hidden content!
#include  **   ***  * **  *  
#include  **  *** *      

int prefix (char st1[],char st2[]){
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***  *** *  ***    * ***  
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*    **    ** *** * ***** ** ** 
}

int main(void) {
*   ** *  * ** * ** * * **    st1[256];
**   ** ****  ** **  ****   st2[256];
* *   *  *    *    * ** ****  * ***  ******  **      st1);
*  **  **** *      *  ****  **  *   ***   ***   st2);

*  *  *  ** ** *    * *      (prefix(st1,st2)){
***   ** ***    *   *****  ** **    ** * * * **  ***  *  *   *   is a prefix of %s", st1, st2);
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*   * * *  * * *    *  *** 0;
}

answered Jan 13, 2018 by Stephen Richards (323 points)

ryan · Answer 3 · 2018-01-11 22:07:28

Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
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}

answered Jan 11, 2018 by ryan (-301 points)

Headshake · Answer 4 · 2018-01-11 21:22:34

Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
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*****   * *  *   *** * * ** 0;
}

answered Jan 11, 2018 by Headshake (-281 points)
edited Jan 13, 2018 by Headshake

Sabrina Lin · Answer 5 · 2018-01-11 21:03:22

Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
**    * *  * * **  *   *  ** a[100];

  ** ***  *  *   * * **     b[100];

*** **    *** *** * *    *  i = 0;

* ****    * ** ** **  ** prefix = 1;

 *  * *    *** *** * * **  * **   * a, b);

** *  *     * * ******   ** len = strlen(a);

** *** * * ** * **  * ** *     * = 0; i < len; i++)
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*      *  ** **  * *
}

answered Jan 11, 2018 by Sabrina Lin (-285 points)
edited Jan 11, 2018 by Sabrina Lin

watty1998871108 · Answer 6 · 2018-01-11 21:00:46

Hidden content!
#include    *  ***  ** 
#include  **  ***    * *   

int main() 
{ 
 ********   * **** *     ***** a[100],b[100]; 
*  ***   * **  * * ****** **  i,j,prefix = 1; 
*** *    **** *   ** *  * ** * *  ** **   %s",a,b); 
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   *   ** * **   ** **  * * ** 0; 
}

answered Jan 11, 2018 by watty1998871108 (-127 points)
edited Jan 17, 2018 by watty1998871108

prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'

commented Jan 17, 2018 by The Judge (4.3k points)

prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'

commented Jan 17, 2018 by The Judge (4.3k points)

Sammi0208 · Answer 7 · 2018-01-11 21:00:08

Hidden content!
#include <stdio.h>
#include *  *** * ***   * 
#include  * **  **** ***** **

int main()
{
*  *      ****** *   *** * *   a[100],b[100];
 ***     *  **   * ** *         ** i,j,prefix = 1;
*   *** *****   * * **** *     **  *  %s",a,b);
*     *****   ***  **  ***** ** len = strlen(a);
*  *****  *         ***     ***** = 0 ; i < len ; i++)
***** **          ** *  *** **  ** 
*  ******** * *  **  ** *******  **      *        *   ** != b[i])
 * *    **  **** **  ***  * *    *    * * **  *   *  * ** *
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* * **    * * * * ** *  * *  **  **** ** **** * *  ** * * *   **  ** ***   * ** * **   *   *  is not a prefix of %s",a,b);
*   *    *   * *  ***** * * * **** ** ***** ****   * *   ***  *********  **   **    *** 
 * ** * **    * **** **  **** * **   * **   * *  *

* *  * ** ** **   *  ** *  
***      ** * *  *    ** **** ** * == 1)
*  * *****  **  * ****  **  ** ** * ** *   * * *   ***** ***  * is a prefix of %s",a,b);


     *********    *  **    *     ** 0;
}

answered Jan 11, 2018 by Sammi0208 (-255 points)
edited Jan 11, 2018 by Sammi0208

410530022 · Answer 8 · 2018-01-11 20:46:02

Hidden content!
#include *  * * ** ** **
#include * * *   ** ** * *

int prefix(const char *pre, const char *str)
{

*** *** **   ** *****  *  * * ***       ******* *   *
  * ****       *  *** **** ** **   ******    * * * **  0;
** * ** ** **  ***   ** **       *      * * * * * 
 ** ** *    ** **    ******    * * *  ****    * **  * * * * 1;
 * *    ** *** ***  ** *      return 0;


}

int main()
{
        **    *  ***   *  * *  * pre[100],str[100];
     *  **   **   **
*      * *   *** * * ** **     *   *         
  **  * *  *   ** *       *******   * *
* ** * * ***        *  *  *  *  **  * ****    * ***    * **   is a prefix of %s",pre,str);
**   *  *** ****      ** ****** *
** * **  * *  *   * ***  *  ***** * *** **  **  **    * ****  ** ****   is not a prefix of %s",pre,str);
 **  ******       ** ** ****    0;
}

answered Jan 11, 2018 by 410530022 (-196 points)
edited Jan 11, 2018 by 410530022

LinJingYao · Answer 9 · 2018-01-11 20:28:50

Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 *****    ** * *******  c;
* * *    **** ** * *  * ** ***   *   *  ****
     **  *  ********* * *****   *** **** * * *** * * 0;
*  * *   *   * *  **  * *  *  *
 **    **   ** *****  * *   *** 
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* ***  **** *  *  *    *  * ***  *    *  ***    * *  ***** *** * ** ** *   *      ***   **  * **  *    *   *  *  0;
 * *  ** *  *  **     ******    *  * **   *   * 
******* * **    ** *   * * *   *   *  ** * * *    * *  **  1;
    }
}

int main(){
**  ***       * ** *** ***  a[100],b[100];
    ****    ***    *     ** * * * ***  %s",a,b);
* ** * **** **    ***     *  *** * ***
 **** *         ** *** * ***** * *  *   *     **  * * * *   * **   is a prefix of %s",a,b);
 *       ** *  * ****   ***
 *  * * **** **** ** *  *** *** * *****  * * **     ** *** ****  ***  * is not a prefix of %s",a,b);
*** ** *    **** ***** **  0;
}

answered Jan 11, 2018 by LinJingYao (-498 points)
edited Jan 17, 2018 by LinJingYao

VincentXV · Answer 10 · 2018-01-11 20:05:37

Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
**   * * ******  **  * ****  p[100],s[100],a[100]={};
  ****     *     *** ** *** t;
* *** **  *   ****  ** **   * *   **
*  * * * *  * ***    *       **   **   ** *   
**      *   ** *   *  * *    **  * *  **** *  %s",p,s);
 ****  *   *****  * *    *******
* * ******* *    ***    *  *********     
***   *   ***     *** * ** *** **  ** 
  *   **    *** * ***  *   * **  ** **    *    **   
*** *  **  ***** *  *** *** ** ** *** **     *
* * *  *** *** ** *    * ******* ****** * *  * * *   ******** * is a prefix of %s",p,s);
  * ** *  *   * *  *     *** 
* *  * *****  ***  ** *   *  
*  *      * **** * * *  ****** * ***** * *  *  ***** ******** * * is not a prefix of %s",p,s);
 **** ** ** **** * *****  * *
 * * ** **    **    * *    ** **  ***** 0;
}

answered Jan 11, 2018 by VincentXV (54 points)

1-11 Exercise 3: Prefix of a string

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