1-11 Exercise 3: Prefix of a string

0 like 0 dislike
10.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 10.9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include ** ***  *** *
#include **  ***** *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
 **   **   *********** ** 
 
* * *   *  *   * **** **   * *****       *  * 
***    ** *  *   *   **     **   **
*****  * ** *** ** *  ** *   *  ** *  *      *  ** *       == s2[i])
*  *** *    **   *    ** * ****    **  ** * ***** * *  *
***  *  * **    *  *   * **   *   * *** **** *     ** * * ********  * * *  *** ***   **** * * *    **
 *  **   * *  *** * **        **** * * * ** *****    * *  
 
   *** **  ***   * *   **    
 
    *         * *** ** * **  * *  *** == length)
*   *** ** *** *  **   ** *   
*     * *     **   *   *  ****  *  ** *  **  * * * *    *    *   ** *** ****  is a prefix of %s",s1,s2);
 * * **  ** *   **   *  ** **    *
 
  **     * **  ** *   ***  *  * * **
*** * *  *   *    *****   * * *  * *  *
***** ****   ******   ** ***  *** ***  *  **  * **  ***   ***  * *  *****  ***  is not a prefix of %s",s1,s2);
 ** *     * ** **       * * ****
 return 0;
*  *   * *  * *     *      * *    
 }

int main(void)
{
 ** ***** ** ****   ******* * *   s1[100];
  * * * **  ***   *   * ***** * s2[100];
*  * **  ****** * ** ** * *   ** i,j;
 *  * ***  *  ** ** **  
* *** **  ** *  * *  *** *  ***   *   ** * *** * s1);
***** * **    * * * *** ***   ** ** **** * * ** s2);
 *** **   * *    **    **   
  ** * ** ** *  * *  *  * *** ****   *
*  ** * **  ** **   ***  *
**  * ****  * * *****   *  0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***  ***  *
#include  *** ** ** *****

int prefix (char st1[],char st2[]){
 * *   * **  **  *   **   * len=0, i, cnt=0;
  **   * * *   *** *    *** **   
 *  ** * ***  *   * *       * = (unsigned)strlen(st1);
**  * ** * ** * *    *** **  
  ****  *****    * *    *   *** * (i=0;i<len;i++)
 **  * *******  **** ***** ** 
 **       ** (st1[i]==st2[i]){
* ****  *  **  *  ***** ****      *  **  *  * * ***** *****     **  * * *****    *   ** **
 *     ** * ** * ***** * *  *  * * ********** *  *    ** * *
  ** *  ** *  ***     * 
* *  *  *  **  * * *   *   *   **  (cnt == len){
* * ** **** **** * ** ******* *       ** ** * *   *   ***  * * ** ***  1;
 ***        *     ***** 
*  ****** * ****** * * * * 
*** * *  **  *** *  **      * * 0;
 * ** **  ***  *  **  * * *
}

int main(void) {
**  * * *  ***  **  **  *   * st1[256];
*  * **   ****   * * *   * ** **** st2[256];
** * *  **** ***    * ***  *   *** **   ******* **** * * st1);
*** ******  *  **   *  * * ** *   **    **    *** ** st2);

*****  * * *   *    **  * (prefix(st1,st2)){
 ** *  *     * *  * *  * *  * ***  ***  ***  * *  ** *   *  * ***  * is a prefix of %s", st1, st2);
 *  **  *    *  *  *  * *
** ***   *   ****  ***  ***
  *    ** ***  * ***    **     *  *  **  *   ****      *** **  ** ** is not a prefix of %s", st1, st2);

 *  *** * ***** *     *  * **  0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
*   * **   *** ******* *** *** * **** *   *   *** *  
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
 ******* * *      ** * * * *  **   **  * * *   *    * * *
***    *** **  *    * ** ***** *  *   **   ***  *      ** * **** ** *  * ** **   
***        *   **  ** *  *  *       ******  * **** ** *  ** ***   ** * * *** *  ***    *****  * ****** **     
  * ** * ***** **** *** *  *****  *  ********  *** ***  **** *  *  *** ** * ***       * * *   * * *  **  **** *  * * * * * * ***  * **     * ** * is not a prefix of %s",a,b);
  ** *  * * *  *   **    *** *  * ***  * **  ***  *  * *    *    *  * ****  ** *   *** * * **    *     *** ******* *  *** * *   ** *    *** *    * *
    ***** *  * * *** ** *   **       *  * ** ** ** *    * ** *    *** *   *     ****  * ***      *** * *  **
  **   **  *   *      * *   * ** * *  *  * ** *    ** * * *      * *** *    *  *  ** *  
*  *****  *  ** **    ***  *** ****  *   * *  * **    *** **    *****  ** * * *  ** **   * *  * *  * ***  ** ** *
*** ***   * * *         * *  **   ** *** **** ** ** *** * * *  ****** *     *   * **** ** **** * *   *   **   *****   *  *  **   ** ***   **** *   is a prefix of %s",a,b);
 * *  *****    ** **  * * * *  * **    **       ***   * **  **** * *** *   *   * ** ** *   ** *  ****          * * ** ** *      * * 
* *   * * * *  * * * ****** * **   **  ****  *    *  **  *** * **  ** *    * **  * ** *** *   *** *  ** * ** ***
 *** ** ***  * ***     **   **    ******  * ***   ****




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
 * ** *   * **** **   * ** *** *  * ****  ** **  *** **
**   *  ** ** ** *** * * *    **  *  * ***** ** *

* *  ****  *  * **  *  ** **** *  *     *  * ** **  **   ****  ***** 0)
** * * * * * **       * **  * *     *   ******* *** * ** ** *  *  ***     **** ** 
*  ** ****** ** ** *   ******  **** ****  *   * ***  *** * * ** **  * *   ** ** * * *   ****     **  *  *  * *** ** *  is a prefix of %s",pre,str);
  ** ***  *  **  *  * ***  * ** *  ***      * *   ****** ***** *    ** *  
********   ***  * ** *** * *  * ***  ** *      *           ***  
 *    **   * **  * *  *** *  *  *  *** ***** **  *  ** *  * ** **   * * ***      * *  * *
 *  ****   ** *   ** *** * * **  *  *  *  **  *** **** * ***** *  **  *  ***  *  *****  ** ***** * * *  **** *****   ***   *  is not a prefix of %s",pre,str);
***   ** * * **  * * ** * * *** **  ** *      ** *     **   *   * **  *** * **  *

     *  * *** ****  **   *  * *** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
*   *  *** ***  *  *  a[100];

  ****** **  ** *  *    * *    b[100];

* ** * ** ** ****      ** ***** i = 0;

   ** *       *  * ** *  **   prefix = 1;

 * * *  * **   **    * ** ***     **  ***  * * *   a, b);

***  *    *     * *   ***** *** len = strlen(a);

  ****** ** *  *** * **  ** ****** = 0; i < len; i++)
**   *    *    **  * *  * *  *  *
 *  ****    **      ** **  ***  **  **** *   ** * ** * * != b[i])
 **** * *****  ** **  **  * *** * **     * * *** *  ***  
********* * ***  ** ****      ***          *** * *** *    * * **  *  **** * *  *** *    = 0;

     ** * ** ** ***** *  *** *** * * **     ***       ****     *****  ****  ****         *   ***  *  is not a prefix of %s", a, b);

* ****  * * **  * ** *  * *  *  * *   * *** * ***** ** ** *   * ***       * **  
* *    *  * *      *  *** * *  *  *      ***** *  * * 
**  *    **   *****  * *
   **     *** ***    * * * * == 1)
     * *  *  *  ** **  * ** **
 * **  ** *  *  ***  *  * **** * **  * **     *** *   ****   ** *** **   is a prefix of %s", a, b);

       ** ******     * * ***
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * * *  *  *   
#include  **  ** ******  

int main() 
{ 
* *  *  ****       ****** *  *** a[100],b[100]; 
**** ** *  * * *    * *  **   i,j,prefix = 1; 
* * ** ******* *** *  *     * *    *  ** %s",a,b); 
* *  *   ****** **    **    *  len = strlen(a); 
*  * **   ** *** *** ***  = 0 ; i < len ; i++) 
*** * *** ** *  *** *   * * 
   ** ****    ** ** * ***  *     * **** *  **** *** ** != b[i]) 
 * * *  *      ***   * **** *   *** ** ** **   *   *  
*** **  ** *   * *  ***  *      ** **   **** ** **  **  * ** * * ****  * ** *  ** *  = 0; 
  *     ** *  *    ***     * *** * *  ***   *  * **** ** * ***   ***  *****  is not a prefix of %s",a,b); 
**   *   * * ****  *** **  **** *  * *    *** ** ***  ****  **   ** *    *     *    **  * 
* * *****  * * **  **  *   *          *    ** *  

    ** * *** **   *** *    *** 
   **  ** *   *   *****  *  **** == 1) 
    *  ** *******   * *  ** *    * ** *    * ** *   **  *  *    is a prefix of %s",a,b); 

 
*  *  *     ****** *** * *   * * 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  **  *   *  * * 
#include  ** *  * ** * **

int main()
{
  *******  * *****  * *   **   a[100],b[100];
**      **      * *  *   **   i,j,prefix = 1;
    *** *  ** ***   *  **  *****  *  %s",a,b);
*    *     ** ** * *** ******  len = strlen(a);
*** * * * *** *    ***  ** *  ** * = 0 ; i < len ; i++)
*      *****   **** *  ***    
**           * ** ****  ** * ***** *  *   ** * *   * **  ******   != b[i])
 *    ** *** *   ****  **  * * * *** * * **  * **
** *** * ** ** * * *** *  **  *  ***** *   **    * *  * * * * ***  ****** ***     = 0;
 **   * *  *  ** *  *  ** ***  *  ***** *  *  ** ******    ****  ** * *    **    **    ****   is not a prefix of %s",a,b);
 *** * **** **** *** ***  * *******   ** **   ** ** ****    * *  *    * * *  *
*  * **  ***   **   ***     **** * *   ****  *** *     *

   * * *** * **  *  *  *****
  * * * **** * ***    ** *****  == 1)
      * ** ****  * ** * * *  * ** *  ***  ***  *** ** *   ********     is a prefix of %s",a,b);


   * * ***** ** **      *    **   0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***** *   *  
#include *   *    *  *  **

int prefix(const char *pre, const char *str)
{

** *     *    ***** * *  ** **      * **  **  * *  ***
 *    *** *  ***   *   * *** * ****  *      *   **  ** * 0;
 *  * * * ***  **  *  ** *  *   *  *  * **********    ** 
** * ***  *  *    *   ** * *  ** *         *    *** ***  *   ** 1;
   *  ***** * *** * ***** * * return 0;


}

int main()
{
 *** *   **  **   ** *  *  * pre[100],str[100];
****   ** *   *    * *  *** 
 ** ** **  *   *   *  ** ** * *   *        ***   * ****
* **  ** * ** **     *  * ***  *       
  *  * * *   ** *    **** **   ** *  *** *** **** *** * * * *  *** * is a prefix of %s",pre,str);
*** ******* *  ****  *  * *  *
* *  ***    * *  *  *   * * *  * **     *   *  ** * * ** * is not a prefix of %s",pre,str);
* *    * ** ****  **      * *   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
****   **     *    ** *  **** c;
*  * *    *  * ***  *   ** * **   ** **   *** ** *** 
 ** *    ** * *  *       **   **     ** ****** * * *  * * 0;
*    *  * * **  *         ** *
      ***** * *  * * *   ** * *
***  * *    ***   *  *   **** * **  *  *    ****  *  ** *** ******  * **      * of a string
 ** *** **     * * ***   *****  * ***    **  ** *  **** * **   *  * ** ** * ** * **   *  
 ** *  ****     ***  *    *** **   ** ***   ** *  ** **** *  ***  ******* **   **** **  ***      *  *  *** * * ** ** 0;
 **** ***    ** * *** *  * * ****    *** ***   *** 
      ** ** ** *    ** *  * *  *******  ***  * * *   1;
    }
}

int main(){
*****     ** ****  *    *  **   a[100],b[100];
* * *    *****  ** *** **  **** *    **  * %s",a,b);
   **   * ***** *** ** * *      *    *   * 
***  *   * *****  * ** *  *  **   ** ** *     ** *  **** *      ***   is a prefix of %s",a,b);
   *  ***   *** * *  **   * 
**** *   **  *  * **   ** *****  ** *   *     **  *  **  ****  *   is not a prefix of %s",a,b);
** **** **  *   *  * ***  *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 ** *  *****  **  ** *  p[100],s[100],a[100]={};
*  ***  ** ** ** * * *** ** t;
* * * * ** ** * *  ***  *  ** *   ** *  * 
*   * ***     * *    ***  * * * ***  ***** 
    **  * * ** ** *    *   * * * * **  ** %s",p,s);
  *   **   ** ***  * *        
***** **  ** ****  * *  * *** ** **
     *      * **          ** * 
   *** * **   * **  *       **  ** *   *  
  * **    * ***** *  ** * **   * *   
 ** *** *** *  ****  * ***** ** * *  * **** ** *** **   **  *      **** is a prefix of %s",p,s);
*******  ** **   * * ****     **
** ***  ***  * * ****   * **
 *  ***  **   * ** *    ****   **   *  **    **  *  *  *  **** * ** is not a prefix of %s",p,s);
 *  *   **** *  *  * * 
* *********   **  *  ** ***   0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.201
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 15.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 10.7k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 14.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users