1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include  * *  ** **  *** *  
#include *    * ***  ****  *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
*   *  * * *** *****  
 
  *** **** *   * *      *** **  * **   ** *****  ** 
 ***   * ******    *   * ** * ****
 * * *     *  ***    ** **  ****** *** * *      *    **    **** == s2[i])
   * *** ***  ** * *****   *   * ** ** **  *** ***   *  *
**       ***  * *  * * * ***   * **********  *** ** *   *  * * *    *  *  ********** *** *
 *   * *  ** ** * *  * *   *  * * ** * ** ***  * **** *
 
 ***  *  ***  ***    * *** ** *  * 
 
 * * * *** **       *  ** ** *  * * *     *** == length)
*    * ****     *****  *  * **
**       **       **  **** **  *****  ****** * **** *  ** ***   ** **  *   is a prefix of %s",s1,s2);
 *  ******  * * **  * ** *   *   ** 
 
*** *  ****  *  **  *       * *** *
*   * ***  *   **     * *   * ** * 
 * **   ***  **  *** *  * * *    * *   *  **  **  * ***** *** *****  ** is not a prefix of %s",s1,s2);
 *   *   * *  * ** *   * *  ** **
 return 0;
 *  *    **** ** * ****   
 }

int main(void)
{
  ** *   *  * **** ***  ** *  s1[100];
*  * *** * *** * ***   * * s2[100];
  * ****   *   *  * *  *    *** i,j;
**     * ***  ** * *  
  **** ***   *   ******    *** *** **** **** ** s1);
   * ***    *   ***  *   **     ***** **  s2);
 ******   *  **** *   *  * *   
 *    *   ** *    ***  **   *  * 
  * *  * *   * * * *** *****  
***        **   *   *** **  **   0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** *    * ****
#include *   * *** ** * 

int prefix (char st1[],char st2[]){
 *****  *** * *  *  *   len=0, i, cnt=0;
  *   **  * **    ***** * *
* **   ******  *   * * ****   = (unsigned)strlen(st1);
 ** **   ** * ***** *** 
*  * *  * * ***   *  ****   * (i=0;i<len;i++)
* *  ** *     * *****    
 ** * *  * **  (st1[i]==st2[i]){
*   ****** *** *** * **      ** ***    * *  * ****** ****      **   ** ***** *
***** *  *   *  **** *  **** *   *** * ** * * ***   * **
  **   *  ** *   ** * ** *  * 
 *   * * ***     ****   * (cnt == len){
*   **   * * ****  *   * * *** **     *  * ** **    *****  **   1;
* *  **  * ***** *  * **   * 
 * *       *  ** ** * *** **** 
 ***** ***  ** ***** * *  * 0;
   * *    * **    *** *** 
}

int main(void) {
* * * * ***   *** ****     *   * st1[256];
   **  ** ****   *******  *** st2[256];
   ***       * ** *********  *  ** *    * *  ***  *   **** st1);
 ** **    *   * *** **  * * ***** *** *      st2);

** ** * * * ***  ** * * *    (prefix(st1,st2)){
** ** ** * **  * * * *     *  ***    *   * *  * **  *  *    **** is a prefix of %s", st1, st2);
***   **   ***   * * ** *   
* *  * ** **** **   * *  **   *  
 ** *   ***      *     *   *  ** * * **  **********  *   is not a prefix of %s", st1, st2);

** **   * * *    **    * ** *  0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
** *     **   **   * ** * ** *   **  ** ***  * *
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
*****  **  * **  *  *     ***   *** *****    **    * *
 *  *** * * ***    ** **  *** ***  * *****    ** *  *  ***     * ** * ***    *  * *** ** **  **   *
**  *  *  *   * ** *  *     * *   ***   *   * * * * ** ** *  ***     ** *  **  * * * *  *******  *
** *** *  **    *****  * * ** *** * ****  ***      ** * **  *   * ***** *** *   * * * *  *** *   *       ***    * **   *** *    ***  * **** is not a prefix of %s",a,b);
   ** * * ***  *  ***   *** **** ** ** *** ** * ** **   *   * **   * * *  * ***** *  *  * ** * ***** *** * **  *     *****  * ****  
 * **   * *  * * * ****  *   **    *** * *    *  *  * *       * * **  * ***  **    *    *  **   * **
   ** **     * **      * ****   ********* **   *      * **   *      * * *          * * *
* ** *   ** *  ********  *  *  *  *      ** *   *  ****  * *   **** **  ** ***** *** *     *******   ****
 * * ** * * * ** *   *  ** ** * **    **  *** *** **  *** *** **  **  ***  * *  *     * * *  **   *   **    *  *  **  *  * * ***   * *****     *  * *    is a prefix of %s",a,b);
*** ***  *  *******   ****   **  *** ** * *  * *  * *  *   **** **   *****    *   * ****     * ***  * *    ******* ****  *   ** ****
 *  * **   **  *   ***    * * **   ***** * ***   ** *  *   **      *****   *  * ****   * *** *** *  *  * * ***    * ** *
  ** * ***  ******  **   * ** ** * **  * ** * **  




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
   *        ***  *   *   *** *  ** **   *  *  *** 
 * * *****  ** ** *  ***   ** ** * ******  * * 

   ****  *** **** *  * ** ****  * *   *  *   *   ***  **   **** *  *  **  0)
****** ***  * * ** ****  **** ** ** ****     ****    ***   *   **   * *
 **   ***   *   ** ** * ****** **  * * * *  *    ******* * *   ** ****** ***      *  * * ******  *    *  **      is a prefix of %s",pre,str);
 *  *   * * *  *****     ** * * **** *  **  ***   **** *  *    *      ** 
**  *** * * **  ** *     *    *** ***    ** *     * ***   
 *    *  * ** *   ***** *    *  *  * *  **** *      *       ******   *   * *  ** ***  *  
 *    **  * * ***    * *  *   *  * *  ** *  ******* ***    **  ***    *   *   ***    * ** *** **  ** ** ****  **** *   ** ***  is not a prefix of %s",pre,str);
*  * **      * **    *  *   ***   ***    * ****  **       *********  *   

** ***    * *****     *   **  ** * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
      **   *  ****  *  *  * *   a[100];

* *      *****   * *  ** * ** b[100];

 ****   ***  *** *      ** *   i = 0;

  *    *   *** ** * ** ** prefix = 1;

 ***  * * *  *     *** **  * * *** *  ** a, b);

*  ** **  *  *  ** * **  **    len = strlen(a);

**   ***      *   **   ** *** *   = 0; i < len; i++)
 * * ****         ***  * * * *
  ***   ** * ** * *    **  *****  **** *  * ** * * *  ** != b[i])
 * *** **   * *    *  * * *** **  ** ** *** **     **
 *** *  * **   * * *    **  * **  ** * ***  * * **** **** *  * **   ** *  *** ** * *   = 0;

*      *  * *** *  * * *     *** *  ** **     ** **  *   *  *** * *   **     * * **   *  ** is not a prefix of %s", a, b);

*   *  ****  **  *** *  * **   * *  ***** ****** *    **        **** *      *****  **
   ***  *  ****  ***   * *** * *   *** *  *  *   * * * *
* **** *   ******* ** * **  * 
 * ****** * * ** *  *    **  == 1)
***    *   ** *  *** *   * 
  **   ****  ***** * * *    ****  *  ************* *    *  *  **   is a prefix of %s", a, b);

  **  **  *   * ** *  * *  **
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  *** **      * 
#include *   *   *  * * * 

int main() 
{ 
** *** * * **** ***  * **   a[100],b[100]; 
*    **  *  ** **   ** *   *  i,j,prefix = 1; 
**   **** *  *   *  *** ***  ***  *       **  %s",a,b); 
   **  * **  **  * ** *   *   len = strlen(a); 
 * ** ******  *     ***   *    = 0 ; i < len ; i++) 
 * *    ****** ***  *  *   * *   
 ** *       * ** * ** ** **  ** *    *******  **  **** ***  *     != b[i]) 
 ** ** ** ** ****  ** *** ***  **** ** **** ******  ** 
 *    *  * *    * * * * ** *  **   *  * *** *** ** **  *  *   ** *  **  *  **** * = 0; 
 ***  *  *  * * *   ** * *  * *  * **** **     * **   * *  *   **  *** * * ******  ****  **  * ***   is not a prefix of %s",a,b); 
*****     **** * ** * *  **  * ** * *  *     *   *  *  ** ** ******* ****      * 
**  **   **    *     *****  ***  * **    * ****** ** 

***   * ***    *  * ** * ** 
*  **** **** *  *** **   *  ** == 1) 
*   ***** ******      *** **     *** *     **   *** * *  **** ** is a prefix of %s",a,b); 

 
 *      * * * *    ** ** *     * 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **  ******     *
#include     **    ** **  **

int main()
{
 ******* *   * ****  *    ***  a[100],b[100];
**  *    **     *  *  ** ***  i,j,prefix = 1;
 *** * * ***   ****       *    * *****  %s",a,b);
  *  ** * * ***     * * len = strlen(a);
 ******  **  *  ***   * **** = 0 ; i < len ; i++)
 ***  *  *** **  *   * * *   **
 ** *** ** ***** *   ** * *  * *  *  *     ***  *  ****  **** != b[i])
  **        *  * *****  *   *   *  * *****   ***** *  
   ** **** ****    *  *  *  *** * *  **   *    *  * * ** *  ** ***  * * *** *****    = 0;
*  **** ** ** *  ***  **  *   *  ***  ***  *** *****  * * **    **   *  * *   ***** ** ** *  is not a prefix of %s",a,b);
**     ** ** * ***** **** * **     ********* *  **  *** ***** **  *  *  * ***** * **  * **
**   ** *** ****** *  ****  *** ** ** *  *   ****  ** **

*   ********* **   * *   * ***  
 *   * ***** **  **  **** *** *    == 1)
 * *    * **** *   * ** ** *****   *     ** *** *  **  **       is a prefix of %s",a,b);


*   **   * ** * *** ** ** ***  0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * * * ******* 
#include ** **  * *** 

int prefix(const char *pre, const char *str)
{

* *    *   **** * *  *   ** ****  * * ****   
 *  ** * **** **  * ** ****  ** *  *  **** ****    * * * 0;
** **   * **   *   ** *** *  ***  ** *   **  ***** 
   * ** **  ***  *   **  * **   *  ** **        * **** * * **** 1;
  *** ** *  *   ** *  ** *  ** *  return 0;


}

int main()
{
 *** * **       ** * *** ** *   pre[100],str[100];
 * ***     ***  * *    
 *** * * * *   *****       ***  *  * * * **        
*    *  **  **    *  *  ***** ** *  *****  
*     *** * *  ***        *** ** ** *****  * **  * * * * ** *  * is a prefix of %s",pre,str);
* * *   *** *** * *   * **  * **   **
** ** ***  *  * ****  ****** ***  ***  **  **   *****   **   *  **** *** * is not a prefix of %s",pre,str);
* * *     **   *  **   ** *   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
  * * ** ***     *   *  *** * c;
  ****  *      **   ** *   *****  * *     ***  * *
*  ** *   * ** * ** * *  ******    ***  * *  * *  * * *  0;
** * **   *   *   * ****
* **   * **   ****  *** **   *
* *  * *  * *   ** * ** *   *  **  * *** **      ****        *   **  ** * of a string
** * *  *  **   ** *  **   **********   *** *** *   *  * **** ****    * ***** * **   *  ** ***
*   * *   **  *   * *  ** ***   *****      * ** *       *** *   *     ** ** *  ** *    *     *** * *  ***  0;
*     * *** *  **** * * *  ** * ** * * *** **    * ** 
* * *  ** ***** ** ***   ***    * **    * ** ***** * 1;
    }
}

int main(){
* ****  * ***  * ****  * *     a[100],b[100];
* *  *   **   ** **** ** **   **  %s",a,b);
** * * ****  **** * **   **  ******* *  ** **
   * **** **  *  *****  * *   ***  **  * * * *   * ** *      *** *  is a prefix of %s",a,b);
*  *  *** * ***   **** * ** * *  
 ***** *** ** **   ****** *   *    *    ****  **  * **    * ***  is not a prefix of %s",a,b);
* *  * * ****  *   * *     0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*****  *****  * *   **   *** ** p[100],s[100],a[100]={};
* ** * *    * *****  * *** *  t;
 ** *        * * *** **  **    *   ***  
*        * ****      *  **** * * *    **
***   * * *** * ** ***  ***   *  *  * *****  * %s",p,s);
*** *  ** * ** * *****   **    * *
 ** **  *  * * **  * **  * ** *   
 *** *   *****   * **  *   ****** * *
  *     *  **  *  *   **  ** *    * *  * *  *  
      *** * ***  *   ***** * **  ** ** * *
  **   *  * ******   *  *** **  ** **** * *  *   **  is a prefix of %s",p,s);
  *** *** ****  * **     **
****   * *********  * *  
    *  *   ** *       * *** *  *  *  **    *  ******    * *** *  * is not a prefix of %s",p,s);
  * * ***** * ***        ********
 ***** * *** *  * ****** ****  * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.33
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users