0 like 0 dislike
9.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited

edited by | 9.9k views
0 0
12345

27 Answers

0 like 0 dislike
Hidden content!
#include * **** * * *
#include ** * ** * *

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
** ***** ** ** ***
 
** **** *** * ** * *** * ** * * ** *
******* *** *** * **
* ** * * ** ** * * ** * * ** *** * ***** == s2[i])
*** ***** ** * *** * **** * **** * ****** ** *
* * **** ***** *** ** * * *** * ** ** ** ** * *** * * * * * ***
* * * ** ** **** * ** * ** * * *** *** *
 
** * **** * * * **** ** *
 
* *** * ** * ** * *** * *** == length)
* **** ** * ** * * * ** * *
* ** * * * ** * ** ** * * * ** *** * * *** * ****** **** ** is a prefix of %s",s1,s2);
* * ** * * ** * * ** * *
 
***** ** ** ******** *** **
* ** ** * * ** * * *
** * * * *** * *** ** ** * ** **** ** * * * * * * ** * * * is not a prefix of %s",s1,s2);
* ** **** * ******* ****
 return 0;
**** ***** * * ******** *
 }

int main(void)
{
**** ****** * * ** * *** * * s1[100];
*** ***** ** * ** ** ** * s2[100];
* ** * **** * * * *** i,j;
* ***** *** * * ***
*** ** ** ** * **** ** * * * ** * s1);
** *** * * * *** **** * *** * * s2);
* * * ** ** ** * * ** * * **
* ** ** * **** * *** ** *
* * ********** ** **
* * ** *** * * *** * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include ** ***** *
#include * * * **

int prefix (char st1[],char st2[]){
*** ****** * * * *** len=0, i, cnt=0;
* **** * *** *
* * ** * ** * ***** = (unsigned)strlen(st1);
** * ******** ** *** * * **
** * *** ** ** * *** *** ** (i=0;i<len;i++)
* **** * ** * ****
*** * * * (st1[i]==st2[i]){
* * * * * * ** ***** ***** * ** * ****** ** *** * * ** ** * * **
** ** **** ** * ** ******** *** **
* * ** ** *** ** *
* ** * * **** * * (cnt == len){
* * *** ** * ** * * ** *** * ** **** * ** ** * ** 1;
* **** ** * * ** ** * ***
** * * * ** * * *
* * ** * * **** **** * 0;
*** ** ** *** *** * ** *
}

int main(void) {
* ** * ** ** ** * **** * ** st1[256];
**** * * ** ** *** * * st2[256];
** ** * * * *** * ** ** ** * ** **** st1);
** ** * * * ** * * *** * ** * *** * * * * st2);

* **** ** * ** ** (prefix(st1,st2)){
* * ** ** ** * ** * * **** ** * * * ****** **** * *** * is a prefix of %s", st1, st2);
* ** * * * *** ******** *
* * ******** ** ** **
** * * * * * ** ** * **** * * *** * * * *** * is not a prefix of %s", st1, st2);

* * * ** * **** ** ** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
* ** ** *** * * * **** ** ** * * * *
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
**** * ** * ** ** * *** ** * * ****
** * * ** * * ** * *** *** * *** * *** * ** ** * * * * ** * * * *
** ** **** ** * * ** ***** * * *** *** *** * * ** ** * * ** *** **** * ** **** **** * *
* * *** * ** *** *** **** **** * ***** * ** * * * * ***** ** * *** ** * * * ** *** * * ** * ** ** ****** * * * *** is not a prefix of %s",a,b);
* *** ** * * * *** * *** *** **** ** * **** * ****** *** **** **** ** * *** *** * * * ** * * * ** * *
** ** ** ** *** ** *** *** * * ** ** * * * ** * **** ***** ** **** * * * *
* *** *** * * *** ** * * ** ** * *** *** ** * ** ** * ** **
* ** ** ** *** * ** * * * * * ** *** * * ** ***** * * *** * * ** * * * *** * * * ** ***
*** * *** * *** * ** * ** ** * *** * * * * ******* * * ***** * * * ** * * *** * ******* * ** * ** ****** * * *** * is a prefix of %s",a,b);
**** ****** **** ******* ** ** * * ** * * ** ***** ** ** * * * **** * ****** *** * * * **** ** ** * *** * * ** *
** * *** * *** ** **** **** ** **** ** * ** * ** * * * * * ** ** ** *
** ***** ** ** *** * ** * * * ** * *** **




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
* * * ** ** *** * **** * * * * * **** * *******
** **** *** *** ** ** * * * ****** * *

* *** ** ** ***** * ** * ** ** ***** * * * * ***** ** * * *** 0)
** * ** ** *** * ***** * ** * * ** * * ** ** * * * * * ** * *
* ***** * * ***** ** ** ** * * * *** **** * * * * *** *** ** * * ** * * * * *** is a prefix of %s",pre,str);
** ** * * ** * ** ** **** * * * ** * *** * * ***
** * ** * * * * * * * * ** ** * ** * * **
*** * * *** **** ** ** * *** * * * * * * ** **
*** * * * **** * * * * ******* * * * * *** *** * *** **** * * * * ** * * * * * * **** ** ** is not a prefix of %s",pre,str);
*** * *** * ** * **** * ***** * ** * ******* *** * * * ***** ** ***** *

* * * ** ****** **** * * 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
** * * **** * **** * ** * * a[100];

*** ** ** ** ** * **** b[100];

** ** * * ** * * ** * * i = 0;

* * ** ** * ***** ** * * prefix = 1;

** ****** * ******* ** * * * * * *** * * a, b);

** *** *** ** ** * * len = strlen(a);

*** **** *** * * ** ** * * = 0; i < len; i++)
* * * ** *** * * **** *
* *** * * * ** * * * * * *** *** * **** *** * != b[i])
** ** * * ****** ***** ** * * * * *** * * * ** *
* * ** ******* ******* **** * ******** ***** * * *** *** * * * ** ** * = 0;

* ** ***** * ** ** * *** * * *** * ***** ** ** *** * * * * ** *** *** *** **** * is not a prefix of %s", a, b);

* * ** ****** ** * ** * ****** ** ** * * **** * ***** ****** * * ** **** *
*** ** * **** * ** * * *** * *** ** ** * ** *
* * ***** * ****
** * **** * * * **** * ** == 1)
* * * ** ** * *** **
** * ***** ** * * * ********* ** *** * * * * * *** * is a prefix of %s", a, b);

*** **** *** ** ***** *
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include * * * *
#include * * *** ****

int main()
{
***** * * * ** * ***** a[100],b[100];
* ** ** * *** **** ** i,j,prefix = 1;
** * ***** ******* * **** %s",a,b);
** * ** ** * *** *** ** len = strlen(a);
** ** ** * ** * **** = 0 ; i < len ; i++)
** * * * ** * * * *
*** ** * ***** ** * * ** ** * * * **** * * ** != b[i])
** * * ** * * * * * * *** * ** ** * * * ** *
** * *** * * * **** * * ****** ******* * * *** ******** ****** ** * * * = 0;
** ** * ***** ** ** *** ***** ****** ** ** *** * *** ** *** * is not a prefix of %s",a,b);
*** ** * * * *** * * *** ** ** * ** * * * ** * ** * *** ***** ** **
** * **** * *** *** * ***** * * * ** * * * * ****

* ** * * * **
********* ** * * * * *** *** * == 1)
* ** * * * ** * * * * * * ** * * ** * ** is a prefix of %s",a,b);

 
** * *** * * * ** * * 0;
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * *****
#include **** * ** **

int main()
{
* ********* * * ** *** ** a[100],b[100];
* *** * * ** **** *** i,j,prefix = 1;
* * * ** ** *** * * * ** %s",a,b);
*** * *** ** *** ***** len = strlen(a);
* * **** * * ** ** ** *** = 0 ; i < len ; i++)
* * * * * *** *** ** * **
*** ** * **** * ** * ***** * * * ** *** *** ** *** != b[i])
*** ***** ** ** * ** * * ** ***** ***** *
* *** * * *** *** *** *** **** * **** ** ** ** * *** * ****** *** ** = 0;
* ** ** ***** * *** * *** * ** ***** ** * ** * * * **** * ** * is not a prefix of %s",a,b);
* * * ** ** ** * ** * * ** * * * * * *** * **** * *** * *** ** *
** **** * **** * ** ** * ** * ** ** * * *

*** ** * ** *** **** * ** *
* * * * ** * ** *** * == 1)
*** ** ** *** ** *** * * * * *** ** ** * * ***** * * is a prefix of %s",a,b);


** **** * ****** * ** ****** **** *** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include ** * *******
#include *** * * * ****

int prefix(const char *pre, const char *str)
{

* * * *** * ** **** *** * ***** * ** *** * *
** ** * ** ** * *** ** *** * ********* ** * ** 0;
** * *** ** * * ***** *** ** ** * * **
***** **** ** * * * *** ** * * ** * * *** 1;
* *** * ** ** ** * return 0;


}

int main()
{
* * ** *** * ** *** * ****** * pre[100],str[100];
* * *** ** * * **** *
* * * ** * ** *** ** * **** **** **** **
* ** * *** * ** * * * ***** ***
******* *** * * * * ** * * *** * * *** ** *** * is a prefix of %s",pre,str);
***** **** * * ** * *** *
******* * ** ** * * ** * * ** * * * ** *** * ***** is not a prefix of %s",pre,str);
* ** **** * * * * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
**** ** *** ** * *** * * c;
* * * * * * *** **** ** ** * *** * * *
* ** *** ** ** **** ** * * * * *** ** * * ****** 0;
* ** * ********* ** **** ****
** * * **** ** * ** ** *** *
* ** ***** ** * *** * ** * * * * *** ***** * * *** * of a string
* * * ***** ** * ** * ***** * ** *** *** *** * * * * * * ** *** * **** * *
***** * * * ** ** ** ** * *** ** ** ** ****** ** *** ** *** * ** * *** * * * * ** * * ** * 0;
* *** * ******* * ** * * * ** * * ***
** ** * **** ** ********* ***** * **** * ** *** 1;
    }
}

int main(){
* * ** *** * ***** a[100],b[100];
*** *** *** * ** * * %s",a,b);
**** ** * * * *** * ** *
* ** * * * ** ** ** * ** * * * * ** *** * * ** * *** is a prefix of %s",a,b);
* * * * * * * ****
******* ***** * **** * ** ** * * * * * * * * * ** is not a prefix of %s",a,b);
***** * ** *** *** * * ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** * * * ** * **** ** * *** p[100],s[100],a[100]={};
*** * **** * * ** *** t;
** ** * ** ** * * * * * * * ***
* * * **** ** * * *** * ** *
*** ** ******* * ***** ** *** ******* %s",p,s);
*** * * * * * *** * * *
* * ** *** *** *** ** * ** ** **
** * ** *** **** * ** * *
******** * *** *** * * ** *
* * * ** * * * ** ** ** * ** * *
***** * * ***** ***** ** **** * ****** * ** * ** ****** * is a prefix of %s",p,s);
** * * **** *********
** * ******* ***** ***
* ** *** * * * * * ** * * ** ****** * ** *** * * is not a prefix of %s",p,s);
* * *** * ** * ** * * *
** **** * * * ** * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.228
©2016-2025

Related questions

0 like 0 dislike
57 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited
| 14.5k views
0 like 0 dislike
29 answers
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited
| 10.1k views
0 like 0 dislike
53 answers
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited
| 13.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users