1-11 Exercise 3: Prefix of a string

Question

13.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited Jan 11, 2018 by semicolon | 13.8k views

27 Answers

Page:

Diyiel · Answer 1 · 2018-01-13 00:58:32

Hidden content!
#include *  * * * * * 
#include  * ***     **** 

char prefix(char s1[], char s2[])
 {
 int i;
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}

answered Jan 13, 2018 by Diyiel (-193 points)

Stephen Richards · Answer 2 · 2018-01-13 00:46:20

Hidden content!
#include *** ** ** *  ***
#include  *****  *** **

int prefix (char st1[],char st2[]){
***     * * ******** **       len=0, i, cnt=0;
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*   ****       * *  ** * **
***   * *** *  **          * 0;
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}

int main(void) {
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* *     ****  *********     *** ** 0;
}

answered Jan 13, 2018 by Stephen Richards (323 points)

ryan · Answer 3 · 2018-01-11 22:07:28

Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
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}

answered Jan 11, 2018 by ryan (-301 points)

Headshake · Answer 4 · 2018-01-11 21:22:34

Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
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* *   *   ***** *** * *     **  ** * *      * * ***** * ***    ****   **    ** **     * 

 ** *** **  *   *** ******* * 0;
}

answered Jan 11, 2018 by Headshake (-281 points)
edited Jan 13, 2018 by Headshake

Sabrina Lin · Answer 5 · 2018-01-11 21:03:22

Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
 *  *    ***    ********   *   a[100];

*  * * **  * ** ***   ***     *** b[100];

  ** * *****  *****  **   i = 0;

  *   *   * *** *****  **  * prefix = 1;

 * ** *      *  ** **  *   ***  *** *   * ** * ** a, b);

**  ***     ***   * * *    len = strlen(a);

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**** **   *** ****   ***   ** * ******** * * * * ** 
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***   **  ***** *  ***** *****
}

answered Jan 11, 2018 by Sabrina Lin (-285 points)
edited Jan 11, 2018 by Sabrina Lin

watty1998871108 · Answer 6 · 2018-01-11 21:00:46

Hidden content!
#include *****   *    *** 
#include * *  ** **  * *   

int main() 
{ 
*  **     ****   ***** ***    *    a[100],b[100]; 
 * ** ** ****     ** ** **  ** i,j,prefix = 1; 
*** **  * * * *  ***          * %s",a,b); 
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 * *******      **** *** **  * 0; 
}

answered Jan 11, 2018 by watty1998871108 (-127 points)
edited Jan 17, 2018 by watty1998871108

prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'

commented Jan 17, 2018 by The Judge (4.3k points)

prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'

commented Jan 17, 2018 by The Judge (4.3k points)

Sammi0208 · Answer 7 · 2018-01-11 21:00:08

Hidden content!
#include <stdio.h>
#include  * ***      *****
#include * ****  *  *

int main()
{
     **   *     * *** *  * *** a[100],b[100];
 *  *  *     *** *   ****    **** i,j,prefix = 1;
* ***   *** ** ** * * * **     ** %s",a,b);
 *   *   *    * * ** ***** **  len = strlen(a);
* * *** * *    * *  * * * **  *** = 0 ; i < len ; i++)
***  *  **    ***** ** *  *****
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 ***** * ***   **  * ******  * * *    **** ** * ***** 
  **      * ***    * * * **     *  **  * ** *   *** * ** * *       **  *     = 0;
  *     ** *  *   ** *  * **** **   **  ** *   ******* * *** ****    * *  ** **  *   **** *  is not a prefix of %s",a,b);
***    ***** **  ***  * **      * * **  ** ***   *****   ***** **   * * *  *   * * 
** ** ** **   ***   **  *  *  *  * *******  ** ** **   

 *       *   ** *   ** 
**      ** *  ** *     ** * ******   == 1)
* ** * **  *** *  * ***   *****  * ***** * *    **   ** ***    **** is a prefix of %s",a,b);


  **   *  *  *** *  ** **  ** * 0;
}

answered Jan 11, 2018 by Sammi0208 (-255 points)
edited Jan 11, 2018 by Sammi0208

410530022 · Answer 8 · 2018-01-11 20:46:02

Hidden content!
#include   * *  *     *
#include   * *  *** ****  

int prefix(const char *pre, const char *str)
{

  ***   *    * ***** **    * *    *   * *   ** * *** 
*    *    **  * ** * *   *  ** ** * * ***  *  * **    ** 0;
  *         ******   *  * **  ***  ** ** **  * ***   **  ***
* *  ** *   **  *  * *    **** *   **    ** **** ** *** * 1;
 *    **** **   * *  *  return 0;


}

int main()
{
  **** ***   * *     ** *  * pre[100],str[100];
  * **  **    ***  ** *  
  *   ** * *  * * *         ***  *    ***  * ** ** ***
*** **  * * ******** **** * *   * *
  * **    *   ** *** ****** **    * ** * *** *****      *   *    ****  *** is a prefix of %s",pre,str);
*  *  **  * *  ***  *    ***
**   * *** ** * * **    *   ** *      ** *****    ****   * * * * * is not a prefix of %s",pre,str);
 *  ***   * *  *  *** * **  ** * *  0;
}

answered Jan 11, 2018 by 410530022 (-196 points)
edited Jan 11, 2018 by 410530022

LinJingYao · Answer 9 · 2018-01-11 20:28:50

Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
*  ***  ************  **  c;
*  *  ******    *  ** ***** * *  * *****  *
 **     * *  *    ** **** ***** **      *** *  ** **  ** 0;
        **  * *****  ******
 **   * * ****  **  **   * ***   
 *  * ***  *    ***  **  *  * * *  *   **  *   * *     *** *  * **    * * * *** **   of a string
 *  ******* ** *  **  ** **** *****   * **  * *  *  * *** ******  *  ****      *   ****  * 
 **** **** * *** **  *******  *** **    *******    *   *** *     *  **  **    ** * ** ** * **  *  *** **** *****    *****  0;
* *     ****  * **  **** * ** ***  * **  **     *
* *  ** ****  **  * **      *    *** ** * *   * **   **  ** * *  1;
    }
}

int main(){
**   * * ** **   *** ** *       a[100],b[100];
 *********** *  * ** **** * *** ** ***   * %s",a,b);
***** **  * *  ***    *** *  * ** *  ** 
** ** **  ** **  *  *      **    * **** **  * * *  * **  ***  *   is a prefix of %s",a,b);
    **** ***    **** ******    
* ** *   *   *   * **   **** **** * * *  **   *   **  *  *  ***  * is not a prefix of %s",a,b);
   * ** *  ** ** * *** 0;
}

answered Jan 11, 2018 by LinJingYao (-498 points)
edited Jan 17, 2018 by LinJingYao

VincentXV · Answer 10 · 2018-01-11 20:05:37

Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
**    ******* **  **  ** * ** p[100],s[100],a[100]={};
   ******* ********* ** ** * t;
   * *   *    * ****     ** ***    *  **
  *** *******   *  *    * **   *  * *  *
  **  ** *    **  **   *   *   * **** *** %s",p,s);
 **** * * ******* *  *** ** ** *  *
*   *    ** *  * ** *    * *      ***
   *  ********   **  *     * *   **  
*  *   * ******  * *      *  *  ** *  * **
*   *  *  *  *** ***  * ** ** **   * ***** 
**  *** **** *   *     *  *    ***  *   *  * **   *******    ** ** is a prefix of %s",p,s);
*  ***  ***   **** ** ***  * ***
**   * **** ***  * ** *  ** *
 *** **** ***   *** ***    *  * * * *      *     *  * * ****   ****  is not a prefix of %s",p,s);
 * *      *    *   * *  **   * 
 **   * *  *  *  * * *   * * 0;
}

answered Jan 11, 2018 by VincentXV (54 points)

1-11 Exercise 3: Prefix of a string

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