1-11 Exercise 3: Prefix of a string

0 like 0 dislike
10.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 10.7k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include      *** * ***
#include * **** ***  *   *   

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
*  ** **  ***    *** * ***
 
   *     * * * *  * ****    ***     * *    **   *   *
      * * * * **  * **  *      
* *** **   * **  ** *  * *   *** *  * * * * ** ** **  * ** == s2[i])
***  *** * *      ***  *    *  **   *** * * *  * *
*****  ****  *** **      *  ** *********    *    *  *** * ***  *    ****    *   ***   ***
** **** **** *   *** **  *     ***** * *    * ** **
 
* **  *   ******  *     *  * *  *  **   
 
 *******  *  *  ***  * ** ** *** ****** == length)
*****  * * *  ****** ** *  ** 
 **   **** * * *** **    ***  **** * ** ** ** **  *    *** *    * **  *  *  is a prefix of %s",s1,s2);
* *  ** *  *     * * **    * * *
 
*  * * *  ****** * * *  ** ********
**  * *   *   *  ***   ** * **  
 * * * *** *****    * ** *** *** **  *  ***    * *****    **** * * * is not a prefix of %s",s1,s2);
** *     * **** **  *** **    ****
 return 0;
*   * * **     ** *    *  *    * 
 }

int main(void)
{
** **   **   *    ** *  *    s1[100];
    **   *******  *  ***       s2[100];
    * ** **    *** ****       ***  i,j;
**   * **   *** ***    *    ***
*  *      **    *  *  *   **** ** *   * * ** *  s1);
     * ***** * *** * **  * * *******   *** s2);
* **  *** * * **  ** *  ***  
 * **  * *   **  *  ********  *     
** *** *  ** ******** * ** *
 * **  * *   *     * ***  *  *   0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * *****     
#include *  ** ***   **  *

int prefix (char st1[],char st2[]){
  *****  *   *****     *  *** len=0, i, cnt=0;
* ***      ** ****       * * **
******  ***  ***    * * = (unsigned)strlen(st1);
* *  **   *  *    *    *  ** ** * 
  **  **  *  *** *** ***  **  (i=0;i<len;i++)
   *  *** *   * ** ***  *** * 
 *** ** * * *** (st1[i]==st2[i]){
 *    *   *** * **********  *  *  *    ** **** *   * ** *     * *       * **
**** **      *   ****  * **    ********  *** **  
  ***** **  ***   * ** *
** *** **** * ** ****  (cnt == len){
**  * **** ** * ** *  **** ***   *  *  ** ***  ******  *   ** *    1;
* **** **  *    ** * * ***      *
 *****  ***   * * *  **
 *  ** *       * *** *  ***    0;
 *      ** *  ***  *  **
}

int main(void) {
**   *  *   *** **  * *** **** st1[256];
   ** *   ****      * * * ** st2[256];
****  *  * * ****  * **  *  ** ** **** * **   **  * st1);
  **** *    **   * * ***  *  * ** *      **** st2);

  **  ***** **    *        (prefix(st1,st2)){
* **      *** **  **     * **     **  *     ***** * * *** ****   is a prefix of %s", st1, st2);
 ****     * **    * * *   ***  
 *  ****** * *  *  *****  * *
** * ** *** *  ** ** *   * *** *  ***  ** ****   * * *    ***  *   is not a prefix of %s", st1, st2);

     ** * * *****  **  *  *  * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
 *     ** *  **   ***  *   * ** *** *   * *   *   *   
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
*******  *  ** **  *    * *  ******     *  *****  **   ***
** ** *    * *  * ***    *  * **   **       * **  *    *     **   ****  * * *****   **  ******  
 *  ** * **  *  *  ***      **    *  *  *  *** ********* *   *  * ** * *  *    ** ****  *** *   **
   ****   *  *  * * ****     ****** **   ** ****    * *** *  *   * **    *   * ** *       * * ***     * * ** * ** ** ***  * * ** **  ***    ** * *  **   is not a prefix of %s",a,b);
** * ******          ***  ** **  **  *  * *** *  *** * *** **  *   ** ***  ** ****    * *   * *****    **   **  * * **  ** **  ** *   *  * * 
*  ** *** ***  *** ** *  *   *    *  ****  ** * ** *   * ** *    **** **    *      ***  **    ***   **   * *
 ** *** **** ***    * ***** *    ***   ****   ************* *   *** ***   * * *  * ** * * *
 * *** ***   *  ** *      ***     * * *      *  *     ** ** ***     * ** *             *  * * *    
****   ****  ** ** ** **      *   *** **  * *  **** *  ** ** *** ****** **   * * ** *  *  **  * ***  *   * * ***    ***  *******     * **  **   is a prefix of %s",a,b);
 *** * *  * * *  * ** *   *  *** *  ** *** * *****  ** ** **  ***  ***** ***  *    **** *** *******  **  * *  * *   **     ** * * *
   * * *   ** **       * ******   *** *   * *  ** *    ***  ***   ** * ** *  * *** *  *  * ** **    ** ***    *  * 
* *  *  ********* *  **   * ** * * * *  *  **** *** ** 




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
** * *  * * ** ****  *     * *** **** ** * ****  
  * ** *    *** *** * ** *   **** * ** * ** * * * * *  * *

*********  **** *    * *****     ** * **    *  ** ***  *** *** ** * ** **   *** 0)
 **    *   *      *******        *  *    *** * **  ** *    ***  **
  **   * ** ** * *   *   *    *  *  *  ****    * *****   *** ** **   * *   *******    * *  * * *      ** *    * is a prefix of %s",pre,str);
* ***    * *     * **   *****    * *  **  ***  ** * *   *  ** ***  ***     *
* * **    *****  *** *   **  ****  * **  ******  **  * **
**  *   **  ****  ****    ** * * ******* *****        *   * * **     * *    ******
*  * *  *  **  ***   ****   * **       ***   *   ******  *  ****  * **    **  *****    **    * * **  *  ***  * * ** ** ** * *   is not a prefix of %s",pre,str);
  *  *  *        **   **  *   * ***   ** ***** *   *   * ***  *    * ***** * **

 * *  ** **  *   **    ***      0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
      * * **  *** **   **** **  a[100];

  *  * ** *** * ***   ** **  * b[100];

** ** * * **      *  *   * i = 0;

    ***   **  **    ******   *  prefix = 1;

   **  *  ** * * * *   *********   ***  ***** a, b);

   *  *     **  *   ***   *  len = strlen(a);

* **  *** ** **   *    *** = 0; i < len; i++)
 * *  * * **  *  *** ***  
****  *  ***       ******   * * ** ***     *      ***  * != b[i])
**  *  ** ***      * * ** ** ** *** ** *   *   **
    ******* * *    **   ***** *  *  * ** * ** **  *  ***** ** ** ** **  * * *  ***  *  = 0;

*  *  * *** *     ***   *  **  *****  * ***  ******   ***** *   *   * ** ** ***** **** *** *  *   * is not a prefix of %s", a, b);

 ** ** **   * **** **   ***** *** **    *  **  * * * ** ***  ***** *     ** *** *  ***  ***
  ****    ****  *    * **   *** **** **     * *   
   *** * **  *  *** * *****  
   *** ** **** * ***  * **  ** * * == 1)
**   ****      *       ** 
  **   * ** * * ***  **   *    ** **********  *  ** **    *****  is a prefix of %s", a, b);

  **  *  *   ***   ** ***
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * ***** ** 
#include  *  *  *   **    

int main() 
{ 
 ** ***************  *** *   a[100],b[100]; 
 ** *     * *  *     ****** i,j,prefix = 1; 
 * ***  * **  *****   * **  ** * ** **  %s",a,b); 
  **    *   *    * * ****  len = strlen(a); 
 *   **      *  * ***** * * *  = 0 ; i < len ; i++) 
** ** * *******  * * 
*  **  ** ******  *      ******* *** * * * * * *** * ******   *** != b[i]) 
 * *  **  **  *  ****  * **   **   ** * *   **  **    ** **** 
      ** ** ****  *  ** * * **   ****      **** * **  ** ****  *   ** ** = 0; 
* *  ** * **        * *  **  *  *   *** **** *****   ** *  * *      **  ** ** * *** * * ***  *    is not a prefix of %s",a,b); 
   ** *   ** **** * * * ** *     ***** ** **   **** ***** ** * ***** *  ** ** * * 
 ** ** *   **  ***   ** * *   ** * **  **    * **  ** * *** 

 ***      * ****  ****    
*  *  * * * *   ******   * ** == 1) 
*** *  **   *   **   * ******   * ****   **  *  ** *   *** *** is a prefix of %s",a,b); 

 
* **   ** ******  ** *******  * *   0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * ******* * ***   **
#include  *  *     *    **  * *

int main()
{
**  ** ***** * *** **** **** * a[100],b[100];
**   **  **  *    * *  * *  ** i,j,prefix = 1;
***   ** **   * *  ****  **** * **  * %s",a,b);
  *    ****      * *   * *  len = strlen(a);
  **  *** ****** * ** *   * = 0 ; i < len ; i++)
     * **  * **  ***    *** 
*** **  ***  * *** ******   * **     ***        * * *   * != b[i])
*** *    ***    ****  * **  **    **   * *  *** *** *** *
 *  *  ***   **  * **   ***   *    ***     ***** **  ****  ***   *  ** *  ****  ** ****  **  = 0;
   *   ***    ****   * *** * *  * * *   **     * * * ** ** **** *** *    ***  ******   is not a prefix of %s",a,b);
***  ** * *** **  ** * ***   *    *****  **  *      *    * ***   *  **  **  
  **  * ** ****  * ***** * *  * *  *** * *     ** * **** *

   * ** * * *** *  ** *  *****
*                     *  *  *  *    == 1)
***   *     **   **   *** ***     * * **  *      *    * **   ** **  *****  is a prefix of %s",a,b);


**** **  * *  * ** **    ******* ** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ***  ***    *
#include  *** * ***    *  *

int prefix(const char *pre, const char *str)
{

 * *     *   * *   * * * * **** ******    * *** *  
  **  **  **  * ** * * * *  **  **    ** * *  ** *    *  0;
   * * ****  *********   **   *  ***  *       
***  **    ****  **** *** **   *   *    ***** * * ****  * * * *  1;
*  *   ***  *  ****   *  **  return 0;


}

int main()
{
  **  *        * * ***  *  pre[100],str[100];
      ** ** *  **   ****  *
* **   ** *** *  * ****      ***  ****  ** * **  *    
***     ***** *** * **  ** ** *  *** 
 ***  *  * **  ****** * ******* **  * ***  * **  **  *    *  *  is a prefix of %s",pre,str);
* **  **  * *         *  * *
*   * *****  ** *   * *****  *****    * * *  ** ****  *  **  * ****   is not a prefix of %s",pre,str);
 *  **   **** ** *   *    0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
** ** * *  ***** *   ***** **  c;
**     * * **  * ** * *  *   * * *  * ** **** *  *  
** **** **  *  **  ******   * **  ***   * *** * *  *   0;
  ** **** **  * **** ***   * 
*    *  *   * **    ** **
***   ***    ****** * ***  * **  **  * * *       ** *  *   ***** ** *   ***   **  * of a string
**  *   *   *  *  *  ****  * * * ***  *****   *   * ***      ** * **** **** * *   ******
 * ***  *  * ** * ***  ** ** * ** ** **** ***    *  *  *** ** *****  ** * * *********   **  * *****  ***    ** **** *  0;
 * * * *   ** ** * *  **  *  *        **   ** ***  *  ***
**   *   *** ***   * *  ******   *****     *   *     *  1;
    }
}

int main(){
*  *  ** ***   * ***** ****** a[100],b[100];
*  *** *  * * * **** *****  ** **** * * *  %s",a,b);
*  ** * **    * ****** *  * **   ***  
***  ** *   * **  ****  * * * ** **** * ** **     * ** * *  *     ****  is a prefix of %s",a,b);
*   * **   **  ***  * ***  *
 * ***    * *   * ** * **  ** ***  * * * **   * *** * * * *  *   ** is not a prefix of %s",a,b);
    ***** *  ***  * * *    *   **  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*  ***    *   *****  * **   ****** p[100],s[100],a[100]={};
  *** **     *   **  *       t;
*  ****   *   **    **     ** *  * *  * ***  
  *  **  *   * * **  ***** * **   *** 
  ** *     *    * ** * *     ***      %s",p,s);
** * *  ***    **  ****** *  ** *
  * *    * ****  * ** *** *        *
*   **   **   **     **** * **  **    *
 *   *** *  *   *** ** ****** *** ***    
***  **** *       *  * *  *   * **  ** 
        *  * *  *   *  *   * ***      * * ****** **     ***   * * * ***** * * is a prefix of %s",p,s);
 ** ** *  * **  ** *        *
* ** ** ***  * * *  ** ** ** 
  *   *****    ** **** * * **** *** ** *  *   ***    * *  ****    is not a prefix of %s",p,s);
*  ** ***   *  * ***  ** *
*** ** * *  ***** *     * **** **  0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.217
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 15.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 10.7k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 14.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users