1-11 Exercise 3: Prefix of a string

0 like 0 dislike
6.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 6.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include *  *  ** * * **   *
#include *    *** *   ***

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
  ***  ***  *  * **    *  
 
* * ***    * ** **    * * **   ***    *****   * * *   
 * **** * *** ** * *   *  ** ****     **
    *  ****  *  **** ****      *  *** * *   ***      ** * *  == s2[i])
   *  * *****  *  *  * *   * **** **  ****  ** *   
* *  **  *** **   ** *   ***  **  ** ** * *    **    ***** ** **** **** * ** ** ****  
   ***     *  ******** *     ** *   * *  *  *    *
 
*        ** *** **   *    ****    
 
  **      * * * *     ***  *  *****  *****  == length)
 ** **** ***** ****** *** * ** * 
*   **** **  *  **  * *****   **  * ** *** **   ******   ***   * *  * is a prefix of %s",s1,s2);
  * ** ***** * **    ****** 
 
  ***   ***** * *  * * **   * *****  ** 
* * * *****  *****    * **  ***   * *
*** ***    *** **** ** **   **** *    * ** *   * ****   * ***    ***   *   ** is not a prefix of %s",s1,s2);
  *  * *** ****   **  * ** **  *     **
 return 0;
 *  ****   * *      * ** * **  
 }

int main(void)
{
       ** * *   ** *****     **   s1[100];
   **  *** ** ***** *  *** * s2[100];
 * **** * *   *   ******* i,j;
 ****   * *  ***  * *   
 *    *  *   *** * **     **     * **  *  * **   s1);
**** * * * ***   * ****   *  * * * * * ***** s2);
 * * *  **  * * **   * 
*** *** *****   *  ** *** *   *****  
 **** * **  **  ** *  * * 
***  ** *  * ** ***  * *  * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * *  *  *
#include * * *       * 

int prefix (char st1[],char st2[]){
**** **  *  *   **   ** ** ** len=0, i, cnt=0;
   *  ******** * *  *   ** *     *
    ** ***  **    * *** ** = (unsigned)strlen(st1);
*** **    *  * *      ******  
* **** ** *  * *     *** (i=0;i<len;i++)
 ****  *** *****  **** *  **
**  * **** ***  (st1[i]==st2[i]){
    *  * ** * * **   ** *   *   * *  ** ******** *  *    *  **  ** * ***** *   ***
*  ****  * *    **  ********      *  **   ***    *** *  * **
 ****  * * ** *      **** * **
* * *  ****  * ***        *  *  (cnt == len){
 ****** ** * ***** * ***    ** * ***** * *     *  *** *** 1;
**** *   **** ****** *  *
  **  * * **  * ****   *** 
  *** ***  * *   * * *** * ** 0;
 *    ****  * *  * *
}

int main(void) {
*  *   * *** **** *  * *  * * st1[256];
* **  ***** ** ** *** ** *** ** *  st2[256];
** ******  *   * ** * ***  **** *  *  ** *     * *   st1);
*  *** * **** ** **  *****     **** * *    **  st2);

*   * ** * * ***  *   ** **    (prefix(st1,st2)){
  ***** * *     **  ** * *    *   * ****  **  **** * **    * ** ** * is a prefix of %s", st1, st2);
  *   *    *  * **  * *  ****
*  * *     *   * *** *   **     *
***   * * ** *   *****      ** **** * * * ***   * * * ****  ** * *** * is not a prefix of %s", st1, st2);

* *   ****   ***      * ***   0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
* *** *  *   **** * * *  * *    **   ** ** ****
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
** * ** ********    ** * *   * *** * ***** **** *  * ** *
** *    *    * **  *  *** *  *   **   *   **   *  ** *     * ** *****   *  * **** 
 ** ***    ***  ****  * *    **  *       *   ** * * *   * **   * ***** * ** ** *    * * *** **  *    **
  ** *****  * **   ** * **   *  *  * *     * *   * *   **** **  *  * ****    *** *  **   *     *  **  * ** ****** **  *   **    ****   *   *    * * *  is not a prefix of %s",a,b);
* *  *  *  *** *  **** **  * **  * *      *   * *     *  *     * ***  ** ****** * * * *    * *****   **  * **      *** * ** *  ****    * *   *** 
 * **  *  * ** *     **   * *  * *   * **   **  * * *  * * ** * *    * **  **     *  ** **  * *  *  ****
 *****   * ****  * *  **  ***    ** * *  * *** ****** ***    **  **  ** *** * **  
 *  **  ** *     ** *     *      **   * * *   *******  *    * *  **  **  ***** ***  ** * *******  *  *  
*  ** ****** * *  **********   * * *** *   * * ***       *    * *         *  * **    *  *** * *** ******* *     ** ***  **  *******  ***     *** * is a prefix of %s",a,b);
 *******    *** *** ***     ***  * * *  *   * * **     *    **** * ** *    * * ***** *    *  **  *   * *   **      * **    ***** *  
  * * * *   *** * *  *    **  **      * ** *   * *** *  ** ******      *     ** ** * * ** ** *   **    * 
 **  *  **** *  *    **  * **     *  * ****   ****   * * 




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
***  * *****     ****  ***  *   **  *  * *  *
 * ****** *  ** ****   * ****  ****         **  ******* 

 ****  *     *  ** **      ** *  *   **  * * *    **  ****   * *  ****  0)
 **    * **   ** ** ****    *   * *  *  * *** ** **  *    **   *    * *   **  * *
**  **** *    * **** *  **   *  *** *** **  *  * **  **   * *** ***  ***  *  * **  **  * *  *** ****   ** * is a prefix of %s",pre,str);
 *****      * * *   ****** * * ** * **  * ** ** *  * ** *  *   * * * * ** ** *
 ***        * ***  *** * ****   **  *******   * ***** **  
 ****  * * ** *    * ****  *****   * * **     **   **     * *      * * ******
***  **** *   ****  *  **  * *** ** **  * ** ** **  **      * ** ** * * *  ***  *  ** ******  *     *** *    ** ** is not a prefix of %s",pre,str);
 **  ***    * * *   ****     ** *  *  * ***  ** ***    **    *****  ** * *

***    ***  **  *  **   ****    0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
** * ****  *** ***  *  ** ***  ** a[100];

** * * **  * * *** ** *** *  ***  b[100];

  * **  ***   * **  *  ****   i = 0;

  *  ***  ********* *** ** prefix = 1;

   *** * *   **     *    **  * ** *  **    **** a, b);

  **** ****   ***   *  * * *  len = strlen(a);

*   *  *****    *  * *   ** = 0; i < len; i++)
 * * ** * *    *** ***   *
******** *  *  * * *   * **     *** ** ****  ***        *   != b[i])
* *    ** ***  ** * ***  *   *  **** *** **   * *     **** *
  * *** *  ****** *      *   ***** *  **  * ***** *  * *  ** ** **** *   * **** ** *** = 0;

** **  * *** **** **   ** ** *** ** * ***   *  ** * ***   *   * **  * ********  ****  * * ***** is not a prefix of %s", a, b);

* * ***     *  * * ** ** * * ***   **  *   * **  *    ****** **     ***  **** **** *  ***
*          * *  *** *    * ***   ** * **** * *******  
     ** **  *   **    *  *****
**   **** * ***** * *  *   *  ** == 1)
**** * **  *  *   ****   * * *
  *** * ***     *   * * *** *   ** ****   * * * ***    **   is a prefix of %s", a, b);

** *  *   * **** * **  ** *  
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * * * *  * *  
#include  *     * * 

int main() 
{ 
 ***       **   ** * **   *    *  a[100],b[100]; 
********      ***  ** ***  *  * * i,j,prefix = 1; 
***  ******   * **   **  **   *    %s",a,b); 
*  **  *** * *    *   len = strlen(a); 
     **   *** ** **** * * *  ** * = 0 ; i < len ; i++) 
* **  *  ** ****   *  
        *     *  * * *  **      *   * * *** *  *** *** != b[i]) 
 ** ** *  ***********  * **   *  ***  * * **    * **    
  * *  *****   *** *  ** **  *    *   *  *  **  *** *  *  **** *  ** *   *******  = 0; 
 **   * ** ****** *    * * * * ***** **** *   ***  *****    * ***  ****    ** * ***   * *    *  *  is not a prefix of %s",a,b); 
 * * ** * **  **  ** *   * * * * *******      * ** *      * *   *   * **  
 ** *   **** ***   ***** *  *  *  *   *  ***  *   

*   ** ******* **   ***       ** * 
** *   * ** **   **    *    **   ** == 1) 
**     *** *****   ***     *** * ** * *  **  *  * *** *********** *     is a prefix of %s",a,b); 

 
   **** * ****    *  * *      0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    *  * * 
#include  ** ***   * * *

int main()
{
** ****** *  ** * *      ** *     *  a[100],b[100];
  * *  **  **** * * *  ** * *** i,j,prefix = 1;
   **   ***       ** * * ** * **    * ****  %s",a,b);
 ********  *   ** **     * len = strlen(a);
  *  ** *  * * ** * *  * *** ** *  = 0 ; i < len ; i++)
*  * *   ******** * **** * **
*** ***  *  *** * *  ***** **    **  *  **   ****    *** != b[i])
* ***  *  *   *  *        * *** *  ***   * *  * * *  *  ** *
*** ** * ** **  ** * *    **   **  ** **   *  **  * *     ****     *  *   **** = 0;
*    **    *   **** **  *    *       *   *  * * *** *  ** ** *** **  * * *** *    * *** is not a prefix of %s",a,b);
   * ****** **  *  *  *  * * *  * * *****       ** * ***  ******  ** * *   ***  *  ***     
*  ***  * ****   **  ** ****        *  **** *    ** * 

*  ****  *  ***   *** **   **
* **  *   *   **** ** * **    == 1)
 **** *** *** * * *  **    **** * ** *****      **      * is a prefix of %s",a,b);


***  * ** ****** **    ** ** 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    **  ** * **
#include    **    *    ** * 

int prefix(const char *pre, const char *str)
{

* *** * *   *   ****  *  ** ** * * * **** ** ******* * *
**     *  * ** * **  ***** * ******* ** *   * **     * * **  *    ** 0;
****   **** ***    *     ** **  * * *     
 **    * *  ***  *    * **    * * *   ** **    * *  *  ** 1;
 ** **   ***** *   *  **       return 0;


}

int main()
{
*** * ** *** ***    ****  **** pre[100],str[100];
**  *  * **  *  ** *  *   *
 * *** *   *** * ******  **  *****  ***** * *   
**   ********  *   *  ** ***       *   
**    * **  * * *  ** *   **  ***** *  * * *  **  *  * ****** *** is a prefix of %s",pre,str);
   * * ** *** *****  * **  **  ** 
* ***  **      *****  *** * * *  **** ****     * * * *   **  *    is not a prefix of %s",pre,str);
* **    ** ***  ***    * 0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
  ****** * ***  *  **** * *** c;
*  * *** ***  *    *  ** **  *    * * **** ** * 
* *** ****   *  **  ****  ** * * ** ***  * *  * * * *  * ** 0;
         *   *   ***  ** ** *
*******  * * *  ******  *  *
  * *  *** *****  *  *   ***  * ***** ** ***   **        ** * **** *    of a string
 **** ** * *    *******    *     **  *** ** **********  * **   ***  *** ****    ** *   
* ******  **  * ******     ******* * *   * *    * *  *    *    * * *** **  **  **    * *  *   *   * ** *   ** 0;
** * *  *** * **   * *       *    **  ***  **    ***  *
*     *****  *     *   *** ****   ** * *    **   * * 1;
    }
}

int main(){
*     **    * ** *     ** a[100],b[100];
 ***  *  *  ****** *  *  *** *** ** **  * %s",a,b);
**        *    *  ***    **    *** *** 
 *  **** * * *  **  ***  *******   ***  **  *  *  *   ********    is a prefix of %s",a,b);
***    ********  * **  ** * 
* *  *  **   ** **** * **      *  *   ***  * ******    *  *  *****  is not a prefix of %s",a,b);
*** **  * * *   *  ** *     ******  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 **    * **   * ****  * ** *    p[100],s[100],a[100]={};
 *** ** *   *  ** **** * t;
*  ***   **    **   ***   ****  *    ** * *
*    ** **   ** *    *   *  * **   ***  ** 
*   ****   *  **   ****    *****  %s",p,s);
*       *** ***   **   **** * *  * * *
** ****** * ******   ****  *  * 
***  * *  * ** *** *   **    *
  * * *  *** *  * **    ** * *** *  **  
*****  *  * ** **  ****  **   *  ***** *   * 
*  *     *   *   *** ******   *      * * * *      *  ** *     *** is a prefix of %s",p,s);
 * *  ** * **    * ** **** 
 *   **  **** ** *     **** **   ***
*   *** *  * * *** *  ** **  **   *** **** * ****  * ***  **  *   is not a prefix of %s",p,s);
***    *  * *   *  *   ****  
     ***  *   *  *** **** * *  0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.195
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 8.8k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 5.9k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 8.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users