1-11 Exercise 3: Prefix of a string

0 like 0 dislike
12.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 12.2k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include   ***   **   * 
#include  ** **    **  * * * 

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
***    * **** **    *****
 
*** *   * ****  * ** **    * ** * * ****  ** * ***  *
**      *  *  ** *** *  * *** ** *
 * ** ** *  **      * * *   *** * *  ****      *** *****   * * == s2[i])
 *** *** ***  *** * *   *  **   *   **    ***   * ** * 
 *   * *    *  ** **    * *   **     ****   * ** *  *    ** ******  * ** *** ** *** **** * 
 *** ***      ****  ** **  *  *     ****     * **** ***  * * *
 
*   *    ** * ***    *  *  * *    *  
 
 ** ***  ***  ****   * ******** *   == length)
 **  ** *   *******     * *     ** **
* * *   * **  *** *  *  **    **  *   *   *** **  *   ***    ***  **  *    is a prefix of %s",s1,s2);
   *****     * *** * *     * *
 
* *  * * *** ***  *  * *   * *  *** **     
      *****  **      * ** *   *  **     
*   * **   ****  ****  * **      * **    *   ***** *   ** * *  *     **  is not a prefix of %s",s1,s2);
 ** * ** *  * **** **  *   ** * ** ** 
 return 0;
 ******      * **   *** * **
 }

int main(void)
{
* * ***   *** *  **    * ** ****  s1[100];
** **   ****** **  **   **** *  s2[100];
* **** * ** ****** *   i,j;
****  * * ***   * ** ** 
* **  *** * *** *     ****  * * *    *   * s1);
 **  ** ***   *** *  *******   * *** *** *** s2);
****     **** *  * *  *    
 **   * * *****  *  * ** *     ** *   *
         *  ***** **  *** * *
***  *     * **   ** *** ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **   *     **  
#include  *  ***     * **  *

int prefix (char st1[],char st2[]){
* *  **     * **   *   len=0, i, cnt=0;
   ** * * *   * * **     ** *
 *  ****** *  * * ** ** ***   = (unsigned)strlen(st1);
   *   *   *** * *** * 
 * ** **  **   ** **   * ** **   (i=0;i<len;i++)
    *   *  *  ****      *
** * ** *  **** (st1[i]==st2[i]){
 ***** *******       **  ** ******* * **   *    * *   * * ****** ** ****  *  * **   * 
*    * ** *  ** ***** *    ***   * ** * ***  ****     ** * **  * * 
*** **** **** ** * *    *
*   **  *** ****  **** (cnt == len){
 *   *   *    * * **  *  ** *   *    **        *** ***   1;
*** * * **   ***     *****
**  ** *  *  *  * * *  *** 
******* **** ** * **      ** **  ** 0;
    *** * * *  ** ** * *    * 
}

int main(void) {
* *****  ***  *** ** *    *  * * st1[256];
 ***    *    *  **       ** st2[256];
* *        *   * ****   ****  *     ***  **  ** *  st1);
*  ***   * **  ** ***** ** *   ** **  *   *  st2);

 **  ** *     *   **  *   (prefix(st1,st2)){
  ******  **  *   *  *****     *   * * *  ****  *******   *****   * is a prefix of %s", st1, st2);
 ** *    *** *     *   **  
   *    ***     * **** **** ****** 
******   * *   * *  *  **      * *  **  * **  * *****   ****  *** **  * is not a prefix of %s", st1, st2);

** * *  * *    *  ***   * **   ** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
  *****  **** * * **** *  ****  **   ******  
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
***** *    *** * *** * *     ***  **  *   ** *  *  * 
  ****  *   *   *  ***  *** **    ****  ** * *  * *** *  * *   * *    * ****  *     
*** ** *   *  * * ** * * **  * *  **** *  **  ** * ** *       *** *  *  ** *** **  *** *   ***  **   ****
  **      * *  **  * * *  * ***  *   ***  ****    **    ***   *   * **   *****  **   **  ****** **            **   * *   *  **  ** * ***    *  * ***** is not a prefix of %s",a,b);
*     ****    **** ***     * * ***  *     ** *  ** ***   *    *****  **    * *******   * * * *  *** *  **** * *  * *   *    *     ***** *   * ***  ** ** 
**** *   *    * *** *** *   *  *** ***** **  * *   * ** * *     ** *  *** *** *******   *** * * * ** 
      *    * * ** **       **** **    *  **  ** * ***   *    *  *  **      ** ***   
   ***  ******** **** * * ****** *    *** *** *  **      *  * ******  * **      **    * **  *   *  * 
 *** **** ***  *   *   * *** * ***       ****   *****  *    ** *  *  **   ***   ** *******  ***  **  *  ****  ******   *  ** *  * *    ** is a prefix of %s",a,b);
  ** * *  **** ** ****  *  ***** ******  **         *    *****  **  **  **    ** ** *    ** **  **  **** *****  ** ****  **  *  **** *
*  ** **   ****  **    *    * *    ** **** * * * *     **  * * **   **  *  **     ** ** * **       
*     *  **  * ** *   **  *  **  *   * **  ******




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
 * *    *  **  *** **   ****   * *******  * *** *
*******     * ***  *    *     *** *  *   ****  **

 **  ***  *  ** * * * *    * * * *** *** *  * ***  ** *   ** ** *******     *  * ** ***   * 0)
***    ** ****  * ** *  *  ***   * **   ** **  ****** ** *  *   ***   *
 ***** *     *   *      *   * * *** * ***  ***** * **   ****  ** * *   ***  * * * *  **   * *  * * is a prefix of %s",pre,str);
* * * *  **  ** ***  *  * ** *  ** ** **     *    *  ***   *     * 
** *       * **  ** **** *   **     **    *** ****  ***
** * * *   * *   ** ********* *  ****  ******* **  **  * *   ** ** ** * * **** *
* * *   * ****     *   *  *****  **    *  *     *** * ****   **  * *** *  * * * * * **  ** * *** ****   ****  *  *****  is not a prefix of %s",pre,str);
****  *   **   * * * *** *  *  *      *    *  *   * *   *   *  ******* *   *   

 ***   *   * *** * * * *  *  0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
 * *  *  *  *  *** *** *    * a[100];

    * ***   *  *****  **  * * b[100];

** *   ****   *   *   i = 0;

***  **       * * * *  **   *  * * prefix = 1;

  *  * ******* ** *   ** *       ** ***  ******  a, b);

**     * *   * * *   *  **     len = strlen(a);

     **  ** *** *** ***   *  *** = 0; i < len; i++)
** *** *****  * * *** * ***** 
   *** ** **** * * **   **  * *    * *    **** *  **  != b[i])
****   **  ***   *  * **   ** *  *** *** * * *    *****  
  *   *   ****  *   *  ** ** *** * * ***  * ** ***** * **  * ** * * ***  *** ***   * * * * = 0;

*** **   *  *    *    ** ** * * ** *   ***  * **** ***  ***** *  **  ***     * *   **   *  is not a prefix of %s", a, b);

   *     *  *** ** **  * * * ** **     ** ** * *  ** * * **** ***    *  **  * ** *  
** ***** ** **  *  * ***  **   ***       *     * **   * * *
*   **  *   ***  *   ** *  ** 
*** *****   ****** * ** * ****  == 1)
** *****     * * *   *** *  *
        *** * * *****  *  ****    **  *  ******  *  * **    **  is a prefix of %s", a, b);

      *  *  * *   * * * * 
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** * * ** 
#include ****   **** ** 

int main() 
{ 
* **  *  * **     *     * *  * a[100],b[100]; 
    * ** *  * *   *** *    ** i,j,prefix = 1; 
   *   *      * **   **  * * **    * %s",a,b); 
*   **   * *   **   ***  len = strlen(a); 
* **  **  * * * ***  ** * *** *** * = 0 ; i < len ; i++) 
    **     *    *  *  *  *  
* *  ****** ** *   *      *** *  *** *   ** * * ** *    **  * * != b[i]) 
 *    *     ** ****** *    *** **** *  ** ** **  *   * ** * 
**       *  *   ** **    ** * *** *****  ** **  *  *  **   **  **   **  ****    ** * **  = 0; 
**    **  *** *  * ** *** ** ***  * * * * ** * *** *  ** * **  * * *** *  **** *  ** *** * *  * * is not a prefix of %s",a,b); 
 **  ***   * *** **     *** **     ***  *  *** ** *  * ** * ***** ** *** * * * ** * ** 
*** ****    *** *** * * ** **   ***  ****  * * *  ** **     

  *  **   ** ** ** *  * *   *  
*  *    ***  **** * ***  ** * ****   == 1) 
 * *******  **  *****  *  ** * ** ****    **  **     **     ** **  is a prefix of %s",a,b); 

 
***** **  *  * * * **** * 0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **  ** *  * **
#include * **   **  * ***

int main()
{
* * **     * * * * ***   a[100],b[100];
   *  ****   ** * ***   **    *  i,j,prefix = 1;
     * *** * * ** ***      * * **  ** %s",a,b);
  *****  * *** **** * * *   **  len = strlen(a);
  **    *** * *****  * ***  * * = 0 ; i < len ; i++)
  * **** * * *    *   ** 
  *** ** **** * ***  **  * *   *** * *  ** * * *  *  * ***   *   != b[i])
 ** **  *  *  **    *** *********   *     *    ***  *
**  ** * *    * * ** *  ***** ** *     ****  *** ****    **  **    *** **  * ****   = 0;
    *  *    * *      * **   * ** *** *  **      *  * ** ******  * * * * **   ** *  ****** is not a prefix of %s",a,b);
  * * *  ****       ***    *   * *  **** ***    *     * *        *    ***  *  ** **  ** 
*  **   ************ *****    *  *  * * *** ** ** ** *   * 

* **  * *** * ***    * *    
*** **  *  ** * * *  *** *   * == 1)
***  *  * *** ** **  *  *   ******   **  ** * *     ***      *    ****  is a prefix of %s",a,b);


 * ***    **   * *  *** **    0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *****   * **  
#include  * **  **   ** * **

int prefix(const char *pre, const char *str)
{

***     *    *    ** **** **         * ** ****  **    
**  **** *** ****     **** **** *  ** * ***   *  **** 0;
 **  *   ***   **    *  *   * *    * **  *** *  
*   *   **  ** ** * *  *   *  ** * * * *  *  *        * *  1;
 * **** *** ** **  * **** *  ***  return 0;


}

int main()
{
  * * ** *    * *  *******  ******* pre[100],str[100];
****** * **** *  * 
 *        *  *** ***  * * *   *** *    *  * *** * 
*** *** *  *  ****  ****   * ****   ***    
   **** **** ** ** *  *** ***    **  * *  ****** *   ********   **  is a prefix of %s",pre,str);
* * * **** ***     ** *  
 *** *** ** ***    *** *   **    *  *    *  *   ***** * ** *  *   is not a prefix of %s",pre,str);
**    ****  ** * *   ****   *  *   0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
  * *  *   * **  *** **  * *  c;
 ******  *    ** ** ***     *****  **  * *****   
****** ** ** *** *  ** ** * * *  **  ** * **   ******* ** *** 0;
 * * * ** *****  ****  *** **  *
 **** ** * * ****** * *** **  *
***** *** *** **      ***** ******  *  * **  *****  **    * *** *  ******* *   *   of a string
 * *    * **     ** ** **     *      **  ** * * *  ** *   * **   *  **  *  *  **    **
 * *****  **** * *   *** ** *** ***** ***   ***  * *      * ****  *  *      * **  *****  * *** *    ** **** *** ** * ** *** *** 0;
**** *** *  * ** * ** * **    *  * ** * * *   **** *
 **   *       * ****  ***  * *  **********   **** **  ** 1;
    }
}

int main(){
   ** **   * ** *   * * * * * **** * a[100],b[100];
**  **  * **  *   **     * *  * **  * * *   %s",a,b);
 *  ** *   **  *     *   * *  *** * 
**** ***    *  *  *   * ****   * * *   ** *** *  *     **  * *     is a prefix of %s",a,b);
    ****    *** * *  *   ****
 * **    * **  *   **  *** * *  * **   *    ***   *  * *  *  * * is not a prefix of %s",a,b);
****    * *       * ** ***  * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
   *   * ***   ** * **  ** p[100],s[100],a[100]={};
  *  *    ***  *    *   * ** t;
*** *  * *** *** *   ** * ** *   * * * * *
 **  ***** * *  **  **  **      ***     *
*** **  * *  * ***  ** ****  * *  ***  ** %s",p,s);
 ** **  * **  ***** **** ****** *  ** 
 * ** *    * ** *   *  ** * ** **    
**  * ** ** *     **** *     *      
 *   *  * ** *** *  ** * * * * ****** *   **  * *
  * * ** * *  *   *   ***  *   *  
****  *  **  ** **   ** *  **   *  ** * *  **  * ** ** *  is a prefix of %s",p,s);
 *  *  *** ******  *  ***   
* * *    * ** * *  * *     *****
*  * * *       * * ** ** *      *  * ****  *** *** ** * **   * * is not a prefix of %s",p,s);
 *  * ***  * * ***** *  *  **
*   * * **    *  ***  ** ****    0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.65
©2016-2026

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 17.6k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 11.6k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 15.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users