1-11 Exercise 3: Prefix of a string

0 like 0 dislike
9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 9k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include   **      *
#include ** ** *    * *  

char prefix(char s1[], char s2[])
 {
 int i;
 int length;
 int count=0;
 
     ****  *   **   *  **
 
** ** **** *   * *  * * **   *** *******  *   ** **
   * * *  ****    * **  *  *******   
 *        * *** ***   **   **** ** ***  ***  ***** ** *** *      == s2[i])
 **** ***   * *  *    *  *****  * ***  * ** ***  * * 
 ** ** * * *  ** *****     **** * ***    *****      * **** * *  * * **    ** * 
   ** *  * *  *** *  ****** *  *  *  * * **** *   ** 
 
* ** ** * **    *     **  ** *   *
 
** ** * * *   **** * **** * **  *  *       == length)
 ***  * **    *** *  * ** **  ***  
*  *  ***        ***** *   *** * *  *   *   **  ***   * * ** *  * ***   *** is a prefix of %s",s1,s2);
 ***  ***   * ***  *     *      *
 
**   ***  * **** * * *** ** ** **  
  *   *    * *  * *  **   * *  * *   
*** * * ***  ***  * *** **** *  ** * *  * ** *  ** ******** **     is not a prefix of %s",s1,s2);
*  * * *  * * *******  ***   *   *
 return 0;
*  ** ** **  ** * *     * * ** **
 }

int main(void)
{
*** ****   ********** * **   *** ** s1[100];
 * *** *    ******  *** **  ***** s2[100];
*** **  ** *    ***** **** * i,j;
   * * * * **** * **   **   *  *
 * **** ** ** * * * * * ****  * **   *** *  *  ** s1);
** * *             * **   *****  * ** *  *   *   s2);
    * * ****    **  * * 
 ** *    * *  *** **  * ******* **
*** * ***** *  *  *   **  
 * **    **  **  **** *****  **  * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   * **   *  *
#include   ****  *  * *  

int prefix (char st1[],char st2[]){
 * ***  *   ** *  ***  **   len=0, i, cnt=0;
* *  *  * ****   * ** * ***
 **   **** **  *  **   **** ** = (unsigned)strlen(st1);
 *  **** * *   *  **      **
********  ***** * **  **** **  (i=0;i<len;i++)
*     ****** ***** *    **
** **    * ******* (st1[i]==st2[i]){
***   *  * *  ***  ****   **   * *  ** **    *  ** **  ** ** * ******* **  * *   **
 ** *     * **  * ***** * *** ** *** * **** * *  * **  *
****     **  **    *  *  ******
  * * *  **      ** **    **  *  (cnt == len){
*  *   * *  **  * * ** ** * * **   ** ** *   * ** ***  **   1;
*   ****** **  ***  *   * * 
 *    *  **   *  ***** * *  
 *  ***** *  *******  **  ** 0;
 *    * **   * * **  *  * *   
}

int main(void) {
***  *** *  ***  ****  * *  ***** ** st1[256];
* *  ** *    * ** ********** *   st2[256];
****   * *  **  * **** *    *** *   *  *  *  ** *  st1);
* *  ** *  * ***      *  *  * *      ****** ** * * st2);

*  **   ***  *  * *  *** * *  (prefix(st1,st2)){
* ****     *  ** ** *  **** **** * *   * *   ** ** *  **   *   * * is a prefix of %s", st1, st2);
** * *    *** * * *** ** 
*   ** ** ******  *    *    *  *   
 ** ***** *** * ** ***  * ****   ****   * * *   ***   *    * is not a prefix of %s", st1, st2);

**   **     *** * ** ****     * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,j;
    char a[100], b[100];
*   * *****   *   ** * * *  * * ** * ***      * *  
    scanf("%s",b);
    j=strlen(a);
    for(i=0;i<j;i++)
*   * * *  ** *** ** **    ***  *  *  *      * ****
 ** *  ***** ** ******* **  **  * * **    * **   * *     **    **** *  * ****   * *  * 
* *  *  *  ****  ***  ** * ** * *    * * ** * ** *    * *****  *** **** *   ** **  ****  ***  ***    ** *     
** * *   *      * * * **  * * **** ** **   *****   *  ** **  ****    *  **** ** *  *  * **    ** *** *** *  ****  * * * *  * **  ****  ****   **    ****  *** *   is not a prefix of %s",a,b);
****   ** **    ** * *** *  *    * *** *  **  **  *** *  * * * *  *  *  **   *  ** *   ** *  *    * * ****   *    **   *  ****** *   *******  ****
 ** *  * * ***  **      *  ****  ***** *    ****   *   *   *      *  **  *     ** *  *  *  ***    ** **   *
*** **  **** *  ***** **    ** * * *  **    * ** **   *  * ******   *   * ** ****** * **  
***   * ** * *   **   *** * * *   ** * ***   * *    ** *  ** * ** **  * * * *   *** *   * **  * ** * ** ***
****    *  * *   * ***  *     ***   * ** * **      * *     *     * *   *    ** ***  *   * * *******  * **  ** * ****  * *  *  * **  *  **  * *   ** * *  * * **  is a prefix of %s",a,b);
*     *******    **  ** *   *    *** **  *  *  *  * *    ***   * **  *** *** ** ** *** * *          ****  *   *** *  ********  * * *  **  *
 ** *  ** ***** *   *  *   ** * *  ** **  ** * *  ***  ***    ***  ****   ****  **  * * ****  *** **  ***  * ***   * 
  *     **       * *  **   **      * * *    ****   * 




}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main(void)
{
    char pre[100], str[100];
    int i;
 *  ********  *** * *  **   ****** **  **  *     * *
*    **  *     * * **   **     ** **** *  * **** **

   *     **    * * ***       * ** * *   *  * * *  ** ******  * *  **    0)
 **** * ** **        *  **  *  *  * ****       **  * * **     ***  * * ** *  **
 * ***** *  *   *** **  *  ***  * **   **    *  **** ****** * *      *** *  **** *   ** *    * ***  **  ** * *   *** is a prefix of %s",pre,str);
  **  * *  **  * ** *** *   * *     * *  *  *    *  ***   * * *  *  *** * 
*      ****   ***** * *  *  ***  * * **  * ***    *   *****   
* ***   * ***  ***  *    *   ****   ******  *    **** * * * *** ***  **     *
** ** * ****** * ** ** **         **     **       *    *******   *  ***   ***  ****     ** ** * **  *     * ** *  *    ** ***  is not a prefix of %s",pre,str);
   *  * **   *** ** * ****** *   ******   * ** *  *** *    * * *  * *  ******     

*  *  * *** ** * ** * **  * * * ***   0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main()
{
*  *** ** *   *    *     * *  a[100];

* ** * ***  *  ** **   *   b[100];

 * * * ****  **   * *      i = 0;

 *   ***  * * *** *   *      **  * prefix = 1;

*  **  *****   **  * ******  * * * * * ***  * * * *  a, b);

 * *** * ** ** *** * * ** *** ***** * len = strlen(a);

*  *    *** * * **  *   ****   = 0; i < len; i++)
 ** *   *** ***    ***   **  
 **  *   *  *  *    ****  *** ****** * **** *** **  ** *   * != b[i])
***   ** * *** * ** * ** ***    ****  ** * * *   * ** **
*     **  *****   * **     *** *  ***  * ** **  ***  *******      ****  *  **  *  **    = 0;

**   * *   *      *  * **     *  **** *  * * ****   ***    *  *  *      ***** **** * **  *     *    * is not a prefix of %s", a, b);

*  ****  * * *    * **   ****       *  * ** **  *  *    * ** *   *      *     *****    *
 * ** *  * * *  ***** ** **     * * * ***   **  *   ***
 *********   *   * ***    *** 
  **    * * ******  ** * ** * *******  == 1)
  *  * * * *** *    *   *** 
    ** ****  * * **   ***    *   *** * ** **  ** * *  * * **** * * is a prefix of %s", a, b);

**    *****    *    *  **  
}
answered by (-285 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    *      * * 
#include **              

int main() 
{ 
*  * *  *** *  * **   **  *     ** *  a[100],b[100]; 
* ****** ** *** ***** *   * * *  i,j,prefix = 1; 
* * ** ** **  * *   ** *  *** ** * ***  %s",a,b); 
 ***** ***** *  *         * len = strlen(a); 
*     * * ** **    **** * ***** = 0 ; i < len ; i++) 
 ** * *  * * *  * **  **  *   * 
*  * ** *** *** ***   *  ***  * ** *   * *   * * ***     != b[i]) 
*** *  * ***       *   **  ***    ***   *     
  *   ***  *   *   * *      ** **    **   **** *  ** *  ***   **  ** **   = 0; 
***    * ** **  * * *   **  ***** *** * **** ***  ****   ******  **   * *** ** **       **** * *   ***    is not a prefix of %s",a,b); 
 ** * *** *    **  **      **  *******   **  ** **** *  ****  **      **   * * 
 *  * * * **  * **   ** ** * *  *        **  **        

*****  ****   *   * ** **  *  
 * *    **  *  * ** * *** *        == 1) 
    **  * *   ***    * *****  ***  ** *** **   **  ****      ***  is a prefix of %s",a,b); 

 
*  * * *** * * *******    **   *  0; 
}
answered by (-127 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:9:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:11: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%s %s",a,b);
     ^~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:15:13: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
             printf("%s is not a prefix of %s",a,b);
             ^~~~~~
prog.c:15:13: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:15:13: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: warning: incompatible implicit declaration of built-in function 'printf'
         printf("%s is a prefix of %s",a,b);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include **     *****   * **
#include **** ** *    ***

int main()
{
*          ** **  *  *  *** *  a[100],b[100];
 ** *  * *** *  * ***    ***** *  i,j,prefix = 1;
 *   *******   **    *    * *** **   %s",a,b);
* *   * * *  *  * ** * ** *  len = strlen(a);
  *  * ** *      * ***** * * = 0 ; i < len ; i++)
* ***      *   * ***  **
  * *** *  **    * ***  *  **   **      **    * ***   **   ******** != b[i])
 *     ***  **    * *     **     * * *     * *  *  * * * 
  *** **    * ** ***  *  ** * **  *  ***   **** * *  *   **  ****        ***  ***** = 0;
 **  *  * ***   *****        * ***     *** *** * *** * *    *** *  *  ** ****  *** *   is not a prefix of %s",a,b);
*  *   * * * * * **** * * **   *** * ** * ** *        *  *  * ***   **  *  *  ***** * * 
   *  **  *******    *  * * * *  *   **  *   *  ** *

 * * *  *    *    * *    * * 
      *    ***   ********   *****  ***  ** == 1)
* *  ** **  ***  *     * *** *  * ****   ** *** **  * *****  is a prefix of %s",a,b);


     ** **  * ***   * * ***    0;
}
answered by (-255 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **   * * *** ** 
#include * * *** **** * **** 

int prefix(const char *pre, const char *str)
{

*   *** **   *  ** * * * *  ** *** *   **  ** **    * * 
  ***  *****  ***   *       **   **   *   *** *     **      0;
**  ** * *   *  **** *     *        *** **   **  
  * ** *     **** *  *  * ***   ** *  *    **           *    ** * 1;
  * ** * *  ** *** *  ***     return 0;


}

int main()
{
 *  * *** ** *  * *** ***  *   *  pre[100],str[100];
* **   * * ** **   * 
*** * ***  ***       * * * **** * *** **  ** ***   * ** 
* * * * * **    *   **  *** **   *    *
** **   ** *    ** *  *  * * ** ****** ***     *   *  *     is a prefix of %s",pre,str);
  ** * * ** **  ****** ***    
** *    ******  * *** *      **   * *  *********  *   *** *  * *    ***   is not a prefix of %s",pre,str);
    *  ****  * * **** ***  ***  0;
}
answered by (-196 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int perfix(char *a,char *b){
 * * ****** * **    *   * *    * c;
 * * * *  ****** * *  * * *  *** * ****    *   *   
 * ** * * **    ** *  ***   ******* * * *    * **   ***  **  *  0;
 * ** * * *** *    *      *
  *  **  * ** * **  ********  *
     **   ****   *  *  *****   **  * ** *    *  **  ** *   *    **  *** *  * *  ** of a string
 ** *  **  **** * *  *****   ***   * *  *  *  * * * ***** * *  * ** * *****    *  * **
   *    *  *  *    * *  * **  *   ** ** ****  *  ***  ** *      **  * *  * *     *****  ****      ** * *    0;
*    * * *  ***  * **** *** **  ** ** * *  **** *** * ****** **
***    **   ** *  *   **   *  *****   **   ***** *    ** *  1;
    }
}

int main(){
 * **  *********   ** ***  **  ** * a[100],b[100];
**  ************ **  *** **** ***   *   * %s",a,b);
** ** ****  ** ** **    **
* ***  **   *  *       * * ****** **  *  **   ***      ***  is a prefix of %s",a,b);
****       ** **       **** 
    *  **  * *     * ****  **  **   * * **  *     * **       ****  **   **** is not a prefix of %s",a,b);
* **  ** * *   * * ******* * ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
**** *** *  * * *** *  *   **   p[100],s[100],a[100]={};
*      *****  * * *    ** t;
*  **   *  * * * **** *    ****    * * 
*** * ** *     *   * ** ***  ** **  
* *** * ***  ******     * *  ***    * * %s",p,s);
*  ** * * **** * ***   ***   * **** 
*** * **   * ** ** **  ** * *** ***  ***
**  *  *   *   *    ** **  * *****  ****
*     *** ** *  * ** **  **   **** ** **** 
  **  ** * *     ** **** *******  ****
* * **** ***    ** * ** ** ** * ** **** *  *** *** *****  ** *   ** is a prefix of %s",p,s);
 ** * * * * ** *   * **** *
*  *  **  *   *  *  ****** *    *
 * *  *  * *      * * *   * *** * * * ****   *  *  **  *  *   is not a prefix of %s",p,s);
** **  **  *   ****  * * * * 
***    * **   * ** *  **  ***     0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.203
©2016-2025

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 13.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 8.8k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 12k views
12,783 questions
183,442 answers
172,219 comments
4,824 users